PLEASE simplfy 8^15÷8^−3

Answers

Answer 1

Answer:

8^18

Step-by-step explanation:

We know that a^b ÷ a^c = a^(b-c)

8^15÷8^−3

8^(15 - -3)

8^(15+3)

8^18


Related Questions

If f(1) = 4 and f(n) = f(n − 1) + 5 then find the value of f(5).

Answers

Answer:

25

Step-by-step explanation:

f(5)=5(5-1)+5

f(5)=5(4)+5

f(5)=20+5

f(5)=25

Answer:

f(5) = 24

Step-by-step explanation:

f(1) = 4

f(n) = f(n − 1) + 5

Let n = 2

f(2) = f(2 − 1) + 5 = 4+5 = 9

Let n = 3

f(3) = f(3 − 1) + 5 = f(2)+5 = 9+5 = 14

Let n = 4

f(4) = f(4 − 1) + 5 = f(3)+5 = 14+5 = 19

Let n = 5

f(5) = f(5 − 1) + 5 = f(4)+5 = 19+5 = 24

if the cost of 2:dozen copies is Rs 720 , find the cost of 72 copies .

Answers

Answer:

Rs 2160

Step-by-step explanation:

1 dozen = 12 copies

2 dozen = 24 copies ( 2*12)

72÷12 = 6 dozen

72 copies = 6 dozen

1 dozen = Rs 720÷2

1 dozen Rs 360

6 dozen = 360*6

6 dozen = 72 copies = Rs 2160

I just need the numbers can anyone help me with this ??

Answers

Step-by-step explanation:

Hello!

In order to graph this, a point would have to go through (-6, 1). Then, since it says it needs a slope of 5 (or, to make things a bit easer, we could see it as 5/1) we'd need the next point to be 5 up and 1 across.

One possible solution:

(-6, 1) -> (-5, 6)

One possible solution (-6,1) —-> (-5,6)

can i get some help please

Answers

The sum of the interior angles in a triangle is 180 degrees.

72 + 35 + <1 = 180

107 + <1 = 180

<1 = 73 degrees

Hope this helps!

Answer:

<1 = 73

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

72+ 35+ <1 = 180

Combine like terms

107 + <1 =180

Subtract 107 from each side

<1 = 180-107

<1 = 73

What is the value of the expression below when y = 8 y=8? 2 y + 7 2y+7

Answers

Answer:

23

Step-by-step explanation:

[tex]2 y + 7[/tex]

Replace y with 8

[tex]= 2 (8) + 7\\= 16+ 7\\= 23[/tex]

Therefore, the value of the expression when y=8 is 23.

I hope this helps!

Simplify for me please

Answers

6^21

it would equal about 2.19^10 just as the original equation

hope this helps:))

Given that the point (-2,8) is on the graph of an equation that is symmetric with respect to the x-axis, what other point is on the graph?

(Type an ordered pair)

Answers

(-2, -8) Imagine the point (-2,8) being reflected in a mirror, where the x axis is the mirror. Since the point is 8 above the x axis, the reflected point will be 8 below.

Help please, I need with the question​

Answers

Answer: [tex]\frac{4}{3}[/tex]

Step-by-step explanation:

tangent of ∠PLM = [tex]\frac{opposite}{adjacent} =\frac{4}{3}[/tex]

Answer:

PLM=4/3

Step-by-step explanation:


[tex]2 |3 \sqrt{2} - 2 \sqrt{3} | + |3 \sqrt{8} - 8 \sqrt{3} | + 2 \sqrt{12} [/tex]
.......................​

Answers

Answer:

hope it helps

Step-by-step explanation:

Answer:

SEE THE IMAGE FOR SOLUTION..

Finding an irrational number between which given pair of numbers supports the idea that irrational numbers are dense in real numbers? 3.14 and pi 3.33 and 1/3 e squared and square root of 5 square root of 64 over 2 and square root of 16

Answers

Answer:

So, we need to find irrational numbers between the given pairs.

Remember that the sum between an irrational number and an rational number is irrational.

For example, for the first case, we want a irrational number between:

3.14 and pi:

pi = 3.14159265.... is irrational

pi - 0.0001 = 3.14159265... - 0.0001 = 3.14149265...

So this number:

3.14149265...

is an irrational number larger than 3.14 and smaller than pi.

Second cacse:

3.33 and 1/3

(here the range would be actually:

1/3 = 0.33 and 3.33

So we want an irrational number larger tan 0.33 and smaller than 3.33

here we can just use pi = 3.141592...

third case:

e^2 and √5

Firs let's write these numbers so we can see how they look.

e^2  =7.389...

√5 = 2.236

So we want a number larger than 2.236... and smaller than 7.389...

Again, here we can use pi = 3.141592...

2.236... < 3.141592... < 7.389...

final case:

√(64/2) and √16

we have:

√(64/2) = 5.65

√16 = 4

So we want an irrational number larger than 4 and smaller than 5.65

Again, let's use our beloved number pi.

we have that:

pi + 1  is an irrational number:

pi + 1 = 3.14159265... + 1.0 = 4.14159265....

This number, 4.14159265..., is irrational, is larger than 4 and is smaller than 5.65, so we found the irrational number between the given pair of numbers.

Answer:

3.33 and 1/3

Step-by-step explanation:

I need help solving this

Answers

Answer:

E. 248

Step-by-step explanation:

1 to 500 in set A, 250 to 750 in set B

500 - 250 = 250

100 and 200 are divisible by 100.

250 - 2 = 248

The solution of this equation has an error. Which of the following steps has an error?

Step 1: -2x + 8 - 3x = 7
Step2:–5x+8=7
Step3:-5x = 15
Step4:
x = -3

O Step 2

O Step 1

O Step 3

Answers

3rd step

Solution:-

[tex]\\ \sf\longmapsto -2x+8-3x=7[/tex]

[tex]\\ \sf\longmapsto -2x-3x+8=7[/tex]

[tex]\\ \sf\longmapsto -5x+8=7[/tex]

[tex]\\ \sf\longmapsto -5x=7-8[/tex]

[tex]\\ \sf\longmapsto -5x=-1[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{-1}{-5}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{1}{5}[/tex]

PLEASE HELP! URGENT. the law of cosines is a2+b2-2abcosC=c2. Find the value of 2abccosC.

Answers

Answer:

D

Step-by-step explanation:

2ab*cos(C)=a^2+b^2-c^2

2ab*cos(C)=5^2+4^2-2^2=25+12=37

Answer:

The answer is 37

Step-by-step explanation:

Based on the graph of the trigonometric function,
what is the period?

Answers

Answer:

[tex]\displaystyle 4[/tex]

Explanation:

[tex]\displaystyle y = 3sin\:(\frac{\pi}{2}x + \frac{\pi}{2}) \\ y = 3cos\:\frac{\pi}{2}x[/tex]

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{4} \hookrightarrow \frac{2}{\frac{\pi}{2}}\pi[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{4} \hookrightarrow \frac{2}{\frac{\pi}{2}}\pi[/tex]

You will need the above information to help you interpret the graph. So, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-5, 0],[/tex] from there to [tex]\displaystyle [-1, 0],[/tex] they are obviously [tex]\displaystyle 4\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle 4.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex] in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Which equation represents a parabola that has a focus of (0,0) and a directix of y = 2?​

Answers

Answer: D

Step-by-step explanation:

[tex]a=0,\ b=0,\ k=2\\equation\ of\ the\ parabola:\\\\y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\\\y=-\dfrac{x^2}{4}+1 \\\\x^2=-4(y-1)\\\\Answer\ D[/tex]

if the hypotenuse of an isosceles right triangle has a length of 5 centimeters what is the length of one of the legs

Answers

Answer:

a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]

Step-by-step explanation:

[tex]a^{2} +b^{2} = 5 ^{2}[/tex]

a = b

[tex]2a^{2} = 5 ^{2}[/tex]

[tex]2a^{2} = 25\\[/tex]

[tex]a^{2} = \frac{25}{5}[/tex]

a = [tex]\frac{5}{\sqrt{5} }[/tex]

must rationalize...

a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]

help me...............​

Answers

Answer:

Brainliestgive o020201000

Manish writes the functions g(x) = ^3 sqrt - x - 72 and h(x) = -(x+72)^3

Which pair of expressions could Manish use to show that g(x) and h(x) are inverse functions?

Answers

Here we want to find the expressions we need to use to see if the functions g(x) and h(x) are inverses of each other.

The correct option is the last one, counting from the top.

∛((x + 72)^3) - 72  and -(∛(-x) - 72 + 72)^3

Two functions f(x) and g(x) are inverses if:

f( g(x) ) = x

g( f(x) ) = x

In this case, we have the functions:

g(x) = ∛(-x) - 72

h(x) =  -(x + 72)^3

Then the expressions we need to check are:

g( h(x) ) = ∛(-h(x)) - 72 = ∛(+(x + 72)^3) - 72 = (x + 72) - 72 = x

h( g(x) ) = -(g(x) + 72)^3 = -(∛(-x) - 72 + 72)^3 = -(∛(-x) )^3 = x

So we found that the two expressions needed are:

∛((x + 72)^3) - 72  and -(∛(-x) - 72 + 72)^3

Then the correct option is the last one, counting from the top.

If you want to learn more, you can read:

https://brainly.com/question/10300045

Answer:

GUYS ITS C THAT IS THE ANSWER

tìm kiếm x y z
x-1/y =1
y-1/z =1
z-1/x =1

Answers

y - 1/z = 1   ==>   y = 1 + 1/z

z - 1/x = 1   ==>   z = 1 + 1/x

==>   y = 1 + 1/(1 + 1/x) = 1 + x/(x + 1) = (2x + 1)/(x + 1)

x - 1/y = x - (x + 1)/(2x + 1) = (2x ² - 1)/(2x + 1) = 1

==>   2x ² - 1 = 2x + 1

==>   2x ² - 2x - 2 = 0

==>   x ² - x - 1 = 0

==>   x = (1 ± √5)/2

If you start solving for z, then for x, then for y, you would get the same equation as above (with y in place of x), and the same thing happens if you solve for x, then y, then z. So it turns out that x = y = z.

Helpppp Please! Please!

Answers

∠DCA=∠BCA
∠B=∠D
CA=AC
△DCA≌△BCA (AAS)

NO=NQ
OP=QP
NP=PN
△NOP≌△NQP (SSS)

∠FOW=∠KIB
∠OFW=∠IKB
FW=KB
△FOW≌△KIB (AAS)

Hope my answer helped u :)

dilations geometry!

Answers

Answer:

A' (0,20)

B' (30,-20)

C' (-10,-40)

Answered by GAUTHMATH

Please help!!!.......thx

Answers

Step-by-step explanation:

sin and tan are the only ones with p positive valued

Chocolate beans are packed in 250 g and 750 g packages. The number of 250 g packages and 750 g packages are in the ratio 1 : 2. If two of the 750 g packages are replaced into 250 g packages, then the ratio becomes 5 : 3. Find

a) the original number of 250 g packages,

b) the total mass of the chocolate beans.

Answers

Answer:

a) 4 packages

b) 7000 g or 7 kg

Step-by-step explanation:

x is the number of 250g packages and y is the number of 750g packages.

2x = y

3(x + 2 x (750 : 250)) = 5(y - 2)

3(x + 6) = 5(y - 2)

3(x + 6) = 5(2x - 2)

3(x + 6) = 5(2(x - 1))

3(x + 6) = 5 * 2 * (x - 1)

3(x + 6) = 10(x - 1)

3x + 18 = 10x - 10

(3x + 18) + 10 = (10x - 10) + 10

3x + 28 = 10x

28 = 10x - 3x

28 = 7x

x = 28/7

x = 4

y = 2 * 4 = 8

(250 * 4) + (750 * 8) = 7000 g

Solve the following equation using
distribution.
2 (4x – 12) = 5
(3) (4x) – (*) (12) = 5
2x - 6 = 5
+6
+6
2x = 11
.. i need help asap look at pics please i need this class done completely in two hours

Answers

Answer: 5.5

Step-by-step explanation: It is basically already solved the only thing I did was isolate x by itself my moving the 2 over and doing 11 divided by 2 which equals 5.5. This means that x equals 5.5

Is student is reading a book about 370 words per minute convert this rate to words per hour

Answers

answer:
22,200 words per hour
step-by-step explanation:
60 minutes per hour
370 words per minute
370(60)
22,200

Answer: 22,200 words per hour.

Step-by-step explanation:

You can set up a proportion for this: 370 words/per 1 min= x words/ per 60 mins. Cross multiply and you get 22,200=1x which basically equals to 22,200 words per hour or 60 mins.

find the 10 degree value can u help me on it ​

Answers

Solution:-10

As <AGQ and <EQG are corresponding interior angles

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 60°+a=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow a=180-60[/tex]

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow a=120}[/tex]

<AGQ=<PQR=60°<BHF=<PRQ=75°

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow b=75°}[/tex]

According to angle sum property

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow b+c+<PQR=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+75+60=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+135=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c=180-135[/tex]

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow c=45°}[/tex]

The curve y=(k-6)x^2-8x+k cuts the x-axis at two points and has a minimum point. Find the range of values of k.

Answers

Answer:

Hello,

answer:  -2 < k < 8

Step-by-step explanation:

As there are 2 roots: Δ>0

As there is a mininum, k-6 <0 ==> k<6,

minimum :y'=0 ==> (k-6)*2x-8=0 ==> x=4/(k-6)

[tex]\Delta=8^2-4*k*(k-6)\\=64-4k^2+24k\\=-4(k^2-6k+9)+36+64\\=100-4(k-3)^2\\=4(8-k)(k+2)\\\\\Delta\ is\ positive\ for\ -2 < k < 8[/tex]

f(x) = x2 – 12x – 29
f(3) = (x+ ?)+ ?

Answers

Answer:

-6 and - 65

Step-by-step explanation:

X-12x-29, by completing the square we get (x-6)^2-65

please answer this!!​

Answers

triangle is always 180

both sides are equal so both sides are 51
51+51=102

180-102=78

Please help explanation if possible

Answers

5/36/5/6:63636366/6/6/6/6/6/66/6/5/6/66/6/6/6/6/67/Augsburgnzhxhbs. ?)))h$)f;dd5yyhb
$g? Gggzb d

Answer:

Hello,

Step-by-step explanation:

slope of the line=3/7

slope of the perpendicular = -7/3

equation of the perpendicular:

y-3=(x-3)*(-7/3)

or

y=-7/3*x +7+3

or

y=-7/3*x+10

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