pls help w this

√2x+1 = 4
In the equation above, what is the value of 2x +1?
A) 3/2
B) 2
C) 4
D) 16

Answers

Answer 1
D :) because you have to square both sides of the equation to get the 2x+1 by itself which would equal 16
Answer 2

Answer:

[tex]\boxed {\boxed {\sf D. \ 16}}[/tex]

Step-by-step explanation:

We are given the following equation and asked to solve for 2x+1.

[tex]\sqrt {2x+1}=4[/tex]

We want to isolate the entire expression of 2x+1. Notice that it is under the square root. If we want to isolate it, we have to perform the inverse operation. The inverse of a square root is a square, so we square both sides of the equation.

[tex](\sqrt{2x+1} )^2= (4)^2[/tex]

[tex]2x+1=(4)^2[/tex]

[tex]2x+1=16[/tex]

We could continue solving for x, then plug the answer back into the expression 2x+1. However, hopefully you notice that we already found the answer!

We only had to do one step to find the answer, but you could complete many other steps to get the same answer:

[tex]2x+1-1=16-1\\2x=15\\2x/2=15/2\\x= 7.5[/tex]      (Solve for x)

[tex]2x+1\\2(7.5)+1\\15+1\\16[/tex]                   (Plug the answer in for x)

The value of 2x+1 is 16 and the correct answer is 16.


Related Questions

Two friends enter a contest. Kelsey scored 200 more points than Jake. Together,
they collected a total of 1250 points. How many points did they each score?

Answers

Subtract the amount Kelsey got more than Jake from the total:

1250 - 200 = 1050

Divide by 2:

1050/2 = 525

Jake got 525

Kelsey got 525 + 200 = 725

What conversion ratio was skipped in this multiple-step conversion? ​

Answers

Answer:

B

Step-by-step explanation:

B was missed. You have to convert this from hours into minutes before you can deal with seconds.

Six liters of paint will cover 50 square meters. How many square meters will nine liters cover?

Answers

Answer:

75 m²

Step-by-step explanation:

Six liters of paint will cover 50 square meters.

  6L ⇒ 50m²

then,

  1L ⇒ 50/6 m²

  9L ⇒ 50 × [tex]\frac{9}{6}[/tex]

       ⇒ 75 m²

Help please guysss will mark as brainliest!

Answers





Im prettyyy sure this is right. y=-6/5x + 2

If z varies jointly as x and y and inversely as w^2?, and
z = 72 when x = 80, y = 30 and
w=5, then find z when x = 20, y = 60 and w=9.

Answers

Answer:

Step-by-step explanation:

z = (k*x*y) / w²

Where,

k = constant of proportionality

z = 72 when x = 80, y = 30 and w = 5

z = (k*x*y) / w²

72 = (k * 80 * 30) / 5²

72 = 2400k / 25

Cross product

72 * 25 = 2400k

1800 = 2,400k

k = 2,400/1800

k = 24/18

= 4/3

k = 1 1/3

k = 1.33

find z when x = 20, y = 60 and w=9

z = (k*x*y) / w²

z = (1.33 * 20 * 60) / 9²

z = (1596) / 81

Cross product

81z = 1596

z = 1596/81

z = 19.703703703703

Approximately,

z = 19.7

What is the multiplicative rate of change for the exponential function f(x) = 21
2

Answers

I’m not sure but you should search it up

Can someone help me with this math homework please!

Answers

Answer:

-7x and -2x

Step-by-step explanation:

because -7x and -2x are on the same side of the equation. the equal sign in the equation, -7x+12-2x = 23+13x is basically a different way of writing -7x+12-2x and 23+13x.

they're kind of like 2 separate equations. hope this helped! :)

When Zero added to any integer, what is the result?​

Answers

Answer:

answer will be the integer only which was added to zero

I need who help .. who can be my lifesaver

Answers

Answer:

Q = G

Step-by-step explanation:

We are already given that angle P = angle H

We are also given that side QP = side GH

Remember if two sides are congruent then so are their opposite angles meaning that the opposite angle of GH ( which would be angle F ) would be congruent to the opposite angle of QP ( which would be angle R )

The remaining angles would be angle q and angle g so the additional information needed would be G = Q

5 + 3bc =
9a + b =
cd + bc =

Answers

Answer:

You can't answer these questons

sorry

Hope This Helps!!!

Write the equation of the line parallel to =12−6 that passes through (2,−3).

Answers

Answer:

y=2-3

Step-by-step explanation:

using a calculator

Solve for x. Round to the nearest tenth, if necessary.

Answers

Use cos,

COS= ADJ/HYP

COS(61)= 5.5/X

Final answer:

X= 5.5/COS(61)

X= 0.1 [rounded to nearest tenth]
X = 0.1 hoped this helped

measured the volume of an object and recorded it as 46 cubic cm
which was 15% high from the actual volume. Find the actual volume.

Answers

Answer:

[tex]40\ cm^3[/tex]

Step-by-step explanation:

Let the actual volume is V.

The measured volume of an object is 46 cubic cm  which was 15% high from the actual volume.

According to the given condition,

[tex]V+\dfrac{15V}{100}=46\\\\\dfrac{115V}{100}=46\\\\V=\dfrac{4600}{115}\\\\V=40\ cm^3[/tex]

So, the actual volume was [tex]40\ cm^3[/tex].


A student draws two parabolas on graph paper. Both parabolas cross the x-axis at (-4, 0) and (6.0). The y-intercept of
the first parabola is (0,–12). The y-intercept of the second parabola is (0, -24). What is the positive difference between
the a values for the two functions that describe the parabolas ? Write your answer as a decimal rounded to the nearest
tenth.

Answers

Answer:

∆a = 1/2

Step-by-step explanation:

parabolas cross the x-axis at (-4, 0) and (6, 0)

y = a(x + 4)(x - 6)

At the y-intercept x = 0

y =  a(0 + 4)(0 - 6)

y = -24a

-----------------------

y-intercept of the first parabola is (0,–12)

-12 = -24a

a = 1/2

-----------------------

y-intercept of the second parabola is (0, -24)

-24 = -24a

a = 1

----------------------

What is the positive difference between the a values

∆a = 1 - 1/2

∆a = 1/2

There is money to send four of nine city council members to a conference in Honolulu. All want to go, so they decide to choose the members to go to the conference by a random process. How many different combinations of four council members can be selected from the nine who want to go to the conference

Answers

Answer:

126

Step-by-step explanation:

There are 9 city council members.

We have to choose 4 of them.

We have to use the combination as :

[tex]$^9C_4$[/tex]

where, 9 is the population size

4 is the sample size.

Therefore, the total number of possible samples without replacement is given as :

[tex]$^9C_4=\frac{9!}{4!(9-4)!}$[/tex]

      [tex]$=\frac{9!}{5! \ 4!}$[/tex]

     [tex]$=\frac{9 \times 8 \times 7 \times 6}{4 \times 3 \times 2 \times 1}$[/tex]

    = 126

A big box can hold 12 marbles and a small box can hold 5 marbles. There are a total of 99 marbles. How many big boxes are there?

Answers

Answer:

7 cajas grandes y 3 cajas pequeñas  

Step-by-step explanatio:

2. Resolve into factors.
a) 8x3 + y3​

Answers

Answer:

(2x + y)(4x² - 2xy + y²)

Step-by-step explanation:

8x³ + y³ ← is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b²) , then

8x³ + y³

= (2x)³ + y³

= (2x + y)((2x)² - 2xy + y²) , that is

(2x + y)(4x² - 2xy + y²)

someone help me please with this algebra problem

Answers

Answer:

D.

Step-by-step explanation:

She cannot buy a negative number of notebooks. She can buy 0 notebooks, or 1 notebook, or 2, or 3, etc. The number of notebooks she buys must be a non-negative integer.

Answer: D.

Find all possible values of α+
β+γ when tanα+tanβ+tanγ = tanαtanβtanγ (-π/2<α<π/2 , -π/2<β<π/2 , -π/2<γ<π/2)
Show your work too. Thank you!​

Answers

Answer:

[tex]\rm\displaystyle 0,\pm\pi [/tex]

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

[tex] \rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma ) [/tex]

factor out tanγ:

[tex]\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)[/tex]

divide both sides by tanαtanβ-1 and that yields:

[tex]\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}[/tex]

multiply both numerator and denominator by-1 which yields:

[tex]\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)[/tex]

recall angle sum indentity of tan:

[tex]\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta ) [/tex]

let α+β be t and transform:

[tex]\rm\displaystyle \tan( \gamma ) = - \tan( t) [/tex]

remember that tan(t)=tan(t±kπ) so

[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi ) [/tex]

therefore when k is 1 we obtain:

[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi ) [/tex]

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

[tex]\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi ) [/tex]

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

[tex]\rm\displaystyle \gamma = - \alpha - \beta \pm \pi [/tex]

isolate -α-β to left hand side and change its sign:

[tex]\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }[/tex]

when is 0:

[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 ) [/tex]

likewise by Opposite Angle Identity we obtain:

[tex]\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 ) [/tex]

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

[tex]\rm\displaystyle \gamma = - \alpha - \beta \pm 0 [/tex]

isolate -α-β to left hand side and change its sign:

[tex]\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }[/tex]

and we're done!

Answer:

-π, 0, and π

Step-by-step explanation:

You can solve for tan y :

tan y (tan a + tan B - 1) = tan a + tan y

Assuming tan a + tan B ≠ 1, we obtain

[tex]tan/y/=-\frac{tan/a/+tan/B/}{1-tan/a/tan/B/} =-tan(a+B)[/tex]

which implies that

y = -a - B + kπ

for some integer k. Thus

a + B + y = kπ

With the stated limitations, we can only have k = 0, k = 1 or k = -1. All cases are possible: we get k = 0 for a = B = y = 0; we get k = 1 when a, B, y are the angles of an acute triangle; and k = - 1 by taking the negatives of the previous cases.

It remains to analyze the case when "tan "a" tan B = 1, which is the same as saying that tan B = cot a = tan(π/2 - a), so

[tex]B=\frac{\pi }{2} - a + k\pi[/tex]

but with the given limitation we must have k = 0, because 0 < π/2 - a < π.

On the other hand we also need "tan "a" + tan B = 0, so B = - a + kπ, but again

k = 0, so we obtain

[tex]\frac{\pi }{2} - a=-a[/tex]

a contradiction.

Which set of ordered pairs does not represent a function? \{(5, -9), (6, -6), (-3, 8), (9, -6)\}{(5,−9),(6,−6),(−3,8),(9,−6)} \{(-6, -4), (4, -8), (-6, 9), (1, -3)\}{(−6,−4),(4,−8),(−6,9),(1,−3)} \{(1, -1), (-5, 7), (4, -9), (-9, 7)\}{(1,−1),(−5,7),(4,−9),(−9,7)} \{(8, -9), (-3, -6), (-4, 4), (1, -5)\}{(8,−9),(−3,−6),(−4,4),(1,−5)}

Answers

Answer:

[tex]\{(-6, -4), (4, -8), (-6, 9), (1, -3)\}[/tex]

Step-by-step explanation:

Given

[tex]\{(5, -9), (6, -6), (-3, 8), (9, -6)\}[/tex]

[tex]\{(-6, -4), (4, -8), (-6, 9), (1, -3)\}[/tex]

[tex]\{(1, -1), (-5, 7), (4, -9), (-9, 7)\}[/tex]

[tex]\{(8, -9), (-3, -6), (-4, 4), (1, -5)\}[/tex]

Required

Which is not a function

An ordered pair is represented as:

[tex]\{(x_1,y_1),(x_2,y_2),(x_3,y_3),..........,(x_n,y_n)\}[/tex]

However, for the ordered pair to be a function; all the x values must be unique (i.e. not repeated)

From options (a) to (d), option (b) has -6 repeated twice. Hence, it is not a function.

Solve the equation to find a positive value of c: 3^2 + 4^2 = c^2

Answers

Answer:

The answer is c=5,-5

c= -5, 5

3^2 + 4^2 = c^2
9 + 16 = c^2
25= c^2
then you square each side and you should get c= -5, 5

Find the values of x and y from the following equal ordered pairs. a) (x,-2) = (4,y) b) (3x, 4) = (6, 2y) c) (2x-1, y + 2) = (-1,2) d) (2x + 4, y + 5) = (3x + 3,6) e) (x + y,y + 3) = (6, 2y) f) (x + y, x - y) - (8,0)​

Answers

Answer:

a)

x=4, y=-2

b)

x=2, y=2

c)

x=0, y=0

d)

x=1, y=1

e)

x=3, y=3

f)

x=4, y=4

Step-by-step explanation:

a) (x,-2) = (4,y)

x=4

y=-2

b) (3x, 4) = (6, 2y)

3x=6 => x=2

2y=4 => y=2

c) (2x-1, y + 2) = (-1,2)

2x-1 =-1 => x=0

y+2 = 2 => y=0

d) (2x + 4, y + 5) = (3x + 3,6)

2x+4 = 3x+3 => x=1

y+5 = 6 => y=1

e) (x + y,y + 3) = (6, 2y)

x+y = 6 => x+3 = 6 => x=3

y+3 = 2y => y=3

f) (x + y, x - y) - (8,0)​

x+y = 8 => 2x=8 => x=4

x-y = 0 => x=y => y=4

You are given the exponential function g(x)=3^x. Which ootion below gives the formula for the new function h created by stretching g by a factor of 3 along the y-axis?

Answers

Answer:

h(x) = 3^(x + 1)

Step-by-step explanation:

The exponential function is;

g(x) = 3^(x)

Now, in transformation of exponential functions of say f(x) = b^(x), when the new function g(x) is created by stretching by a factor of say c along the y-axis, we have;

g(x) = c•b^(x)

In this question, we are told it is stretched by a factor of 3 along the y-axis.

Thus, new function h is;

h(x) = 3 × 3^(x)

Using law of indices, we have;

h(x) = 3^(x + 1)

Please help, im confused ;w;

Answers

Answer:

[tex]x=7\text{ and } m\angle KLM = 34^\circ[/tex]

Step-by-step explanation:

We are given ethat KM and JN are parallel.

And we want to find the value of x.

Notice that ∠JKM and ∠LKM form a linear pair. Linear pairs total 180°. Therefore:

[tex]m\angle JKM + m\angle LKM = 180[/tex]

We know that ∠JKM measures (14x + 8). Substitute:

[tex](14x+8)+m\angle LKM =180[/tex]

Solve for ∠LKM:

[tex]m\angle LKM = 172-14x[/tex]

Next, since KM and JN are parallel, by the Corresponding Angles Theorem:

[tex]\angle JNM \cong \angle KML[/tex]

Since we know that ∠JNM measure (10x + 2), we can conclude that:

[tex]m\angle KML = 10x+2[/tex]

Next, recall that the three interior angles of a triangle must total 180°. Therefore:

[tex]m\angle KLM + m\angle LKM + m\angle KML = 180[/tex]

Substitute:

[tex](5x-1)+(172-14x)+(10x+2)=180[/tex]

Solve for x. Rewrite:

[tex](5x-14x+10x)+(-1+172+2)=180[/tex]

Combine like terms:

[tex](1x)+(173)=180[/tex]

Therefore:

[tex]x=7[/tex]

To find ∠KLM, substitute in 7 for x and evaluate. So:

[tex]m\angle KLM = 5(7) - 1 =34^\circ[/tex]

What is 8 x 3 + 10 - 13 x 2? Show your work.
Will give first answer brainliest

Answers

Hello!

8 × 3 + 10 - 13 × 2 =

= 24 + 10 - 13 × 2 =

= 24 + 10 - 26 =

= 34 - 26 =

= 8

Good luck! :)

Answer:

8

Step-by-step explanation:

According to bdmas rule

First multiply 8 and 3 or 13 and 2

Then, there will be 24 + 10 - 26

Then add 24 + 10, there will be 34

and again minus by 26

Then finally answer will be 8

please help me for 5 points​

Answers

Answer:

275 adults

130 children

Step-by-step explanation:

Answer:

275 adults, 130 children

Step-by-step explanation:

Please help me with this one

Answers

Answer:

240

Step-by-step explanation:

well do *

so 8x6x5 = 240 there's your answer

Answer:

[tex]S.A=1/2(8+8)(9^{2})+8\times 6+8\times 5[/tex]

[tex]=26\times2+48+40[/tex]

[tex]=140 ~cm^{2}[/tex]

-------------------------

HOPE IT HELPS

HAVE A GREAT DAY!!

The daily listening audience of an AM radio station is five times as large as that of its FM sister station. If 144,000 people listen to these two radio stations, how many listeners does the FM station have?

Answers

Answer:

The number of FM listereners are 24000.

Step-by-step explanation:

Let the listeners of FM are p and thus the istereners of AM are 5p.

According to the question,

p + 5 p = 144000

6 p = 144000

p = 24000

The number of FM listereners are 24000.

How to find the domain

Answers

The domain is the x values. So I think the answer is the second choice.

using quadratic equation:
help me solve it
[tex]10x - \frac{1}{x } = 3[/tex]

Answers

Answer:

[tex]10x - \frac{1}{x} = 3 \\ 10x = 3 + \frac{1}{x} \\ 10x = \frac{3x + 1}{x} \\ 10x \times x = 3x + 1 \\ 10 {x}^{2} = 3x + 1 \\ 10 {x}^{2} - 3x - 1 = 0 \\ 10 {x}^{2} - 5x + 2x - 1 = 0 \\ 5x(2x - 1) + 1(2x - 1) = 0 \\ (5x + 1)(2x - 1) = 0 \\ \\ 5x + 1 = 0 \\ 5x = - 1 \\ x = \frac{ - 1}{5} \\ \\ 2x - 1 = 0 \\ 2x = 1 \\ x = \frac{1}{2} [/tex]

hope this helps you.

Have a nice day!

Other Questions
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