plss help, it’s pretty easy tho

Plss Help, Its Pretty Easy Tho

Answers

Answer 1

Answer:

B

Step-by-step explanation:


Related Questions

what is 4xy - 5y² - 3x² from 5x + 3y² - xy ? ​

Answers

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The equivalent expression is ~

[tex] \boxed{ \sf8 {y}^{2} + 3 {x}^{2} + 5x - 5xy}[/tex]

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

Let's solve ~

[tex]5x² + 3 {y}^{2} - xy - (4xy - 5y {}^{2} - 3 {x}^{2} )[/tex]

[tex]5x² + 3 {y}^{2} - xy - 4xy +5 {y}^{2} + 3 {x}^{2} [/tex]

[tex]3 {y}^{2} + 5 {y}^{2} + 3 {x}^{2} + 5x² - xy - 4xy[/tex]

[tex]8 {y}^{2} + 8 {x}^{2} - 5xy[/tex]

solve |8y+4|=2|y-1|
please show the work!

Answers

8y+4 = 2(y-1)
8y+4 = 2y-2
8y-2y+4 = -2
6y+4 = -2
6y = -2-4
6y = -6
y = -1

Julissa is printing out copies for a work training. It takes 4 minutes to print a color copy, and it takes 2 minutes to print a grayscale copy. She needs to print no fewer than 8 copies within 25 minutes.

Which system of inequalities represents the number of color copies, x, and grayscale copies, y, that Julissa can print to meet her goal?

Answers

Answer:

4x  + 2y  ≤  25   ,      x + y ≥  8     is the required system of inequalities to represent the given situation.

Step-by-step explanation:

Here, let  the number of color copies =  x

Now, the time taken to print each color copy = 4 minutes

⇒Time taken to print x color copies = x times ( Time taken by each copy)

= 4 (x)   = 4x

and let  the number gray scale copies =  y

The time taken to print each gray scale copy = 2 minutes

⇒Time taken to print y gray scale copy = y times (Time taken by each copy)

= 2 (y)   = 2y

Total copies printed = x + y

Maximum time taken to print x  color copies and y grayscale copies

= 4x  + 2y

So, according to the question:

4x  + 2y  ≤  25 ( as maximum allotted time is 25 minutes)

and x + y ≥  8      (as minimum number of copies is 8)

hence, the above system is the required system of inequalities to represent the given situation.

I hope this helps.

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