Plz help me find zero x on the triangle and show work thanks​

Answer:

10.5

Step-by-step explanation:

In the picture if you think about it, it has to be a number less than 15 since CB is 15. I picked 12.3 and got it wrong therefore it has to be 10.5.

Answer:

A) 10.5

Step-by-step explanation:

Answer:

There are two intersections.

(-3,1) and (-1,-3)

Step-by-step explanation:

Answer:

They intersect at (-3,1), and also (-1,-3)

Step-by-step explanation:

Graph:

Answer:  Choice A.   [tex]-x^2+2x+8[/tex]

Work Shown:

[tex](f - g)(x) = f(x) - g(x)\\\\(f - g)(x) = (2x+1) - (x^2-7)\\\\(f - g)(x) = 2x+1 - x^2+7\\\\(f - g)(x) = -x^2+2x+(1+7)\\\\(f - g)(x) = -x^2+2x+8\\\\[/tex]

which shows the answer is choice A.

Side note: be sure to distribute the negative to every term inside the second set of parenthesis. So you wouldn't say -(x^2-7) = -x^2-7. If you did this error, then you'd get to the wrong answer choice C.

Answer:

hope it helps u plz mark me brainliest mate

Step-by-step explanation:

(f-g)(x)=2x+1-(x^2-7)

(f-g)(x)=2x+1-x^2+7

(f-g)(x)= -x^2+2x+8

this is the correct answer

9514 1404 393

Answer:

  (b)  f(x) = (-x)^(1/2)

Step-by-step explanation:

The square root is only defined for argument values that are non-negative. Hence the domain of ...

  f(x) = (-x)^(1/2)

is all values of x less than or equal to zero. This is not "all values of x."

Answer:

can you please send me another one

Answer: [tex]y^\frac{1}{8}[/tex]

Step-by-step explanation:

Ok so when taking roots the number in the little corner at the left of the radical sign (if there is one) is the root you take. It could be the 4th root, 6th root, or the x root. You don't have to use the radical sign though, you can use an exponent to write it. All you have to do is take the reciprocal of the number to find what to write for the exponent. So for those examples it would be [tex]\frac{1}{4}, \frac{1}{6} ,\frac{1}{x}[/tex]. The number in the top left of the radical sign is 8 so the answer would be [tex]y^\frac{1}{8}[/tex]

f(5) = -50

Hope it helps you...

Answer:

[tex]{ \tt{m.n = |m| |n| \cos( \theta) }} \\ { \tt{ (3 \times 2) + (4 \times - 1) = (5)( \sqrt{5}) \cos( \theta) }} \\ { \tt{ \cos( \theta) = \frac{0.4}{ \sqrt{5} } }} \\ \theta = 79.7 \degree[/tex]

Answer:

3

Step-by-step explanation:

Given the data:

1405, 1121, 1339, 1096, 1299, 1401, 1138, 1149, 1223, 1071, 1399, 1400, 1242, 1318, 1101, 1065, 1428, 1225, 1350, 1358, 1312

Using the intervals:

Class interval ___ Frequency

1049–1118 ________ 4

1119–1188 ________ 3

1189–1258 ________3

1259–1328 _______ 3

1329–1398 _______ 3

1399–1468 _______ 5

From the table ; the fifth class is the interval :

1329 - 1398 and it has a frequency of 3

Answer:

5×789/3

Step-by-step explanation:

According to the question you could simplify the above numbers .

Answer:

789

Step-by-step explanation:

let the number=x

[tex]\frac{5x}{3}=1315\\5x=1315 \times 3=3945\\x=\frac{3945}{5}=789[/tex]

Answer:

yefeihuerijohiftv3ugrhoerfujfy

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

Starting from right to left...

9 is in the ones place

8 is in the tenths place

4 is in the hundreds place

7 is in the thousands place.

I hope this helps!

Answer:

(0.123 ; 0.277)

Step-by-step explanation:

Given :

Sample size, n = 180

x = 36

Proportion, p = x / n = 36/180 = 0.2

Confidence interval for sample proportion :

Confidence interval :

p ± Zcritical * √p(1 - p) / n

Zcritical at 99% = 2.576

0.2 ± 2.576 * √0.2(1 - 0.2) / 180

0.2 ± 2.576 * 0.0298142

0.2 ± 0.0768013792

(0.123 ; 0.277)

y=-4x²-8x+1

а<0 so we will be looking for maximum

х=-b/2a=8/-8=-1

у=4+8+1=13

Maximum point (-1;13)

Answer:

$150

Step-by-step explanation:

discount=60%

let the price=x

(100-60)% of x=$60

40% of x=60

x=60×(100/40)=150

Answer:

(8.608, 9.392)

Step-by-step explanation:

We have the following information

Population standard deviation = 1.8

Sample mean = 9 hours

Sample n = 81

C I = 95%

So level of significance

Alpha = 1-0.95

= 0.05

Z critical at 0.05/2

Z(0.025) = 1.96

The 95% c.i =

9+-(1.96)(1.8/√81)

9+-(1.96)(0.2)

(9-0.392)(9+0.392)

(8.608, 9.392)

This is the confidence interval at 95%.

I hope you find my solution useful. Good luck!!!

Answer:

100$or 20.4 that is the answer

Step-by-step explanation:

pandemic times: Potential ... - CAF

have shown evidence that the effect of corruption on real GDP per capita is more pronounced in countries with low levels of8

Answer: No, The goal when testing a hypothesis is to to guess a large significant level to possibly have the answer correct based upon evidence. False. It needs to be a large significant level

Step-by-step explanation:

Answer:

third option

Step-by-step explanation:

Brainliest please~

Answer:

4/7 > 2/10

Step-by-step explanation:

4/7 is close to 1/2

2/10 is close to 0

4/7 > 2/10

Answer:

9876

Step-by-step explanation:

7:5

x:4115

To find x mulitply 7 by 823 (because this is what we multiplied 5 by in order to get 4115)

7*823= 5761

Take the sum to find the total number of votes

4115+5761= 9876

Answer:

x≤16

Step-by-step explanation:

1/2x - 3 ≤5

Add 3 to each side

1/2x -3+3 ≤5+3

1/2x≤8

Multiply each side by 2

1/2x*2 ≤8*2

x≤16

Answer:

[tex] \frac{1}{1 + \cos(x) } [/tex]

Step-by-step explanation:

[tex]y = \frac{ \sin(x) }{1 + \cos(x) } [/tex]

differentiating numerator wrt x :-

(sinx)' = cos x

differentiating denominator wrt x :-

(1 + cos x)' = (cosx)' = - sinx

[tex] (\frac{u}{v} )' = \frac{v. \: (u)' - u.(v)' }{ {v}^{2} } [/tex]

here,

[tex] = \frac{((1 + \cos \: x) \cos \: x )- (\sin \: x. ( - \sin \: x) ) }{( {1 + \cos(x)) }^{2} } [/tex]

[tex] = \frac{ \cos(x) + \cos {}^{2} (x) + \sin {}^{2} (x) }{(1 + \cos \: x) {}^{2} } [/tex]

since cos²x + sin²x = 1

[tex] = \frac{ \cos \: x + 1}{(1 + \cos \: x) {}^{2} } [/tex]

diving numerator and denominator by 1 + cos x

[tex] = \frac{1}{1 + \cos(x) } [/tex]

Answer:

The first year in which Clara will see that Investment B's value will exceed Investment A's value will be year 14.

Step-by-step explanation:

Since Clara made two investments, and Investment A has an initial value of $ 500 and increases by $ 45 every year, while Investment B has an initial value of $ 300 and increases by 10% every year, and Clara checks the value of her investments once to year, at the end of the year, to determine what is the first year in which Clara sees that Investment B's value has exceeded investment A's value, the following calculation must be performed:

500 + (45 x X) = A

300 x 1.1 ^ X = B

A = 500 + 45 x 5 = 500 + 225 = 725

B = 300 x 1.1 ^ 5 = 483.15

A = 500 + 45 x 10 = 950

B = 300 x 1.1 ^ 10 = 778.12

A = 500 + 45 x 15 = 1175

B = 300 x 1.1 ^ 15 = 1253.17

A = 500 + 45 x 14 = 1,130

B = 300 x 1.1 ^ 14 = 1,139.25

Therefore, the first year in which Clara will see that Investment B's value will exceed Investment A's value will be year 14.

Answer: x² - (3/4)x + 9/64 = (x + 3/8)²

Step-by-step explanation:

Concept:

Here, we need to know the idea of completing the square.

Completing the square is a technique for converting a quadratic polynomial of the form ax²+bx+c to the form (x-h)²for some values of h.

If you are still confused, please refer to the attachment below for a graphical explanation.

Solve:

If we expand (x - h)² = x² - 2 · x · h + h²

Given equation:

Since [x² - (3/4)x +___] is the expanded form of (x - h)², then (-3/4)x must be equal to 2 · x · h. Thus, we would be able to find the value of h.

Finally, we plug the final value back to the equation.

Hope this helps!! :)

Please let me know if you have any questions

9514 1404 393

Answer:

Step-by-step explanation:

Let x and y represent the weights of the large and small boxes, respectively. Then the two delivery weights give rise to the equations ...

  3x +5y -79 = 0

  12x +2y -199 = 0

Using the "cross multiplication method" of solving these equations, we find ...

  d1 = (3)(2) -(12)(5) = 6 -60 = -54

  d2 = 5(-199) -(2)(-79) = -995 +158 = -837

  d3 = -79(12) -(-199)(3) = -948 +597 = -351

1/d1 = x/d2 = y/d3

x = d2/d1 = -837/-54 = 15.5

y = d3/d1 = -351/-54 = 6.5

The large boxes weigh 15.5 kg; the small boxes weigh 6.5 kg.

_____

Additional comment

My preferred quick and easy way to solve equations like this is using a graphing calculator. In addition to that, an algebraic method is shown.

The "cross-multiplication method" shown here is what I consider to be a simplified version of what you would find in videos. It is a variation of Cramer's rule and the Vedic maths methods of solving pairs of linear equations. I find it useful when "elimination" or "substitution" methods would result in annoying numbers. In such cases, it uses fewer arithmetic operations than would be required by other methods.

Short description: writing the coefficients of the general form equations in 4 columns, where the last column is the same as the first, a "cross multiplication" is computed for each of the three pairs of columns. Those computations are of the form ...

  [tex]\text{column pair: }\begin{array}{cc}a&b\\c&d\end{array}\ \Rightarrow\ d_n=ad-cb[/tex]

The relationship between the differences d₁, d₂, and d₃ and the variable values is shown above.

The required value of m for the given triangle is given as m = 12.

In a right-angled triangle, its sides, such as hypotenuse, and perpendicular, and the base is Pythagorean triplets.

Here,
Applying Pythagoras' theorem,
n² = m² - 6² - - - - (1)

m ² + base² = 24²
base² = 24² - m² - - - - (2)

n² + 18² = base²
From equation 1 and 2
m² - 6² + 18² = 24² - m²
2m² = 24² + 6² - 18²
m = 12

Thus, the required value of m for the given triangle is given as m = 12.

Learn more about Pythagorean triplets here:

brainly.com/question/22160915

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