Answer:
-4
Step-by-step explanation:
f(-1) = 2(-1) - 2 = -4
Which one of these relations are functions ?
Please helpppp fast
Answer:
the 4th and 6th one
Step-by-step explanation:
A function is when there are x- and y-values but each x value has only 1 y-value
Simple: If the x-value is repeated its not a function
Answer:
Step-by-step explanation:
1,2,3
Shea made 11 of her first 17 free-throw attempts. What is the minimum number of her next 20 free-throw attempts that she must make for her overall success rate to be at least $80\%$? Express your answer to the nearest whole number.
Answer:
19 throws.
Step-by-step explanation:
For her success rate to be 80% in 37 throws she must make 0.8 * 37
= 29.6 throw - that is 30 to nearest throw.
So for the next 20 throws she must make 30 - 11 = 19 throws.
Solve the equation for X (If possible please show work)
Answer:
the correct answer is x=5
Gavin is selling water bottles at a baseball game to help raise money for new uniforms.
Before the game, he buys 48 water bottles for a total of $18.50. At the game, he sells all of
the bottles for $1.25 each. How much profit does Gavin make?
The profit made by Gavin at the end of the game is $0.87 per bottle.
How to calculate profit?The profit can be calculated by taking the difference of selling price and the cost price.
Given that,
The number of bottles bought for $18.50 is 48 and sold for $1.25 each.
Then, the cost for one bottle is 18.50/48 = $0.38.
As per the question the profit made can be calculated as the difference of selling price and cost price as,
Profit = Selling price - Cost Price
= 1.25 - 0.38
= $0.87
Hence, the profit earned by Gavin is given as $0.87 for each bottle.
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3-2(x-1)=2+4x
How do you solve
Answer:
x = 1/2
Step-by-step explanation:
3 - 2(x - 1) = 2 + 4x
3 - 2x + 2 = 2 + 4x
-2x + 5 = 2 + 4x
-2x - 4x = 2 - 5
-6x = -3
x = -3/-6
x = 1/2
Find the distance between points K(−1, −3) and L(0, 0). Round to the nearest tenth.
Answer:
d = √10
Step-by-step explanation:
[tex]K(-1, -3) , L(0, 0).\\\\d=\sqrt{((x_2-x_1)^2+ (y_2-y_1)^2) } \\\\x_1 =-1\\\\y_1 =-3\\\\x_2 =0\\\\y_2 =0 \\\\d = \sqrt{(0-(-1))^2+(0-(-3))^2}\\\\ d = \sqrt{(0+1)^2+(0+3)^2}\\\\ d = \sqrt{(1)^2 + (3)^2}\\\\ d = \sqrt{1 + 9}\\\\ d = \sqrt{10} \\[/tex]
Answer:
[tex]\huge\boxed{|KL|=\sqrt{10}\approx3.2}[/tex]
Step-by-step explanation:
METHOD 1:The formula of a distance between two points (x₁; y₁) and (x₂; y₂):
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
We have K(-1; -3) and L(0; 0). Substitute:
[tex]|KL|=\sqrt{(0-(-3))^2+(0-(-1))^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}}[/tex]
METHOD 2:Look at the picture.
We have the right triangle with the legs 3 and 1.
Use the Pythagorean theorem:
[tex]leg^2+leg^2=hypotenuse^2[/tex]
substitute:
[tex]3^2+1^2=|KL|^2\\\\|KL|^2=9+1\\\\|KL|^2=10\to|KL|=\sqrt{10}[/tex]
-7p+2(5p-8)=6(p+6)-7
Answer:
-15
Step-by-step explanation:
-7p+10p-16=6p+36-7
3p-16=6p+29
3p-6p=29+16
-3p=45
p=45/-3
p=-15
The quotient of x^2+x-6/x^2-6x+5*x^2+2x-3/x^2-7x+10 has ___ in the numerator and ______ in the denominator.
Answer:
So the quotient of [tex]\frac{x^{2} + x - 6}{x^{2} -6x + 5} X \frac{x^{2} + 2x - 3}{x^{2} -7x + 10}[/tex] has (x + 3)² in the numerator and (x + 5)² in the denominator.
Step-by-step explanation:
[tex]\frac{x^{2} + x - 6}{x^{2} -6x + 5} X \frac{x^{2} + 2x - 3}{x^{2} -7x + 10}[/tex]
Factorizing the expressions we have
[tex]\frac{x^{2} + 3x -2x - 6}{x^{2} -x - 5x + 5} X \frac{x^{2} + 3x - x - 3}{x^{2} -2x -5x + 10}[/tex]
[tex]\frac{x(x + 3)- 2(x + 3)}{x(x -1) - 5(x - 1)} X \frac{x(x + 3) - 1(x + 3)}{x(x - 2) - 5(x - 2)}[/tex]
[tex]\frac{(x + 3)(x - 2)}{(x - 5)(x - 1)}X\frac{(x + 3)(x - 1)}{(x - 2)(x - 5)}[/tex]
Cancelling out the like factors, (x -1) and (x - 2), we have
[tex]\frac{(x + 3)(x + 3)}{(x - 5)(x - 5)}[/tex]
= [tex]\frac{(x + 3)^{2} }{(x + 5)^{2} }[/tex]
So the quotient of [tex]\frac{x^{2} + x - 6}{x^{2} -6x + 5} X \frac{x^{2} + 2x - 3}{x^{2} -7x + 10}[/tex] has (x + 3)² in the numerator and (x + 5)² in the denominator.
hello :) why is the first one wrong?
Answer:
The cube only belongs to the x and not 2x.
The statement will only be true if there is a bracket around the 2x.
log₃(2x)³= 3log₃2x
logarithm power rule:
logₐ(x)^y = y ∙ logₐ(x)
Answer:
see explanation
Step-by-step explanation:
Given
[tex]log_{5}[/tex] 2x³
= [tex]log_{5}[/tex] 2 + [tex]log_{5}[/tex] x³
= [tex]log_{5}[/tex] 2 + 3[tex]log_{5}[/tex] x
The speed of a car going 50 miles per hour is equivalent to a speed of 80 kilometers per hour. At this rate, what is the speed, in kilometers per hour, of a car that is going 30 miles per hour?
Answer:
48 km/h
Step-by-step explanation:
80/50*30=48 km/h
the cube root of 2 to the seventh power
Answer:
4 2^(1/3) or 5.0396841995794926590688424291129134022810058588060319203279004486... decimal
Step-by-step explanation:
Simplify the following:
(2^(1/3))^7
Hint: | For all a>=0, (a^(1/3))^m = a^(m/3). Apply this to (2^(1/3))^7.
Multiply exponents. (2^(1/3))^7 = 2^(7/3):
2^(7/3)
Hint: | Separate the exponent of 2^(7/3) into integer and fractional parts.
2^(7/3) = 2^(6/3 + 1/3) = 2^(6/3)×2^(1/3):
2^(6/3) 2^(1/3)
Hint: | Divide 6 by 3.
6/3 = (3×2)/3 = 2:
2^2 2^(1/3)
Hint: | Evaluate 2^2.
2^2 = 4:
Answer: 4 2^(1/3) or 5.0396841995794926590688424291129134022810058588060319203279004486... decimal
Ikyume is 62m away from Amadi, on a bearing of 012°. Becky is 42m away from Ikyume and on bearing of 082°. How far is Amadi from Becky, and on what bearing?
Answer:
Amadi is 86m far from Becky
Amadi is on the bearing of 78° .
Step-by-step explanation:
From the information given ,
let I represent Ikyume
A represent Amadi and B represent Becky
From the information in the diagrammatic expression shown below:
Using cosine rule;
i² = a² + b² - 2ab cos (I)
i² = 42² + 62² - 2(42×62) cos (110°)
i² = 1764 + 3844 - 5208 (- 0.342)
i² = 1764 + 3844 - ( - 1781.136)
i² = 1764 + 3844 + 1781.136
i² = 7389.136
i = [tex]\mathtt{\sqrt{7389.136}}[/tex]
i = 85.96
i [tex]\simeq[/tex] 86 m
Amadi is 86m far from Becky
From point I , 12° = 12° at point A (alternate angles)
In that quadrant = 90 - 12° = 78°
Therefore, Amadi is on the bearing of 78° .
Pick out the set of numbers that is not Pythagorean triple
9 40 46
16 30 34
10 24 26
50 120 130
Answer:
[tex]\huge\boxed{9,40,46}[/tex]
Step-by-step explanation:
Let's check it using Pythagorean Theorem:
[tex]c^2 = a^2 + b^2[/tex]
Where c is the longest sides, a and b are rest of the 2 sides
1) 9 , 40 , 46
=> [tex]c^2 = a^2 + b^2[/tex]
=> [tex]46^2 = 9^2 + 40^2[/tex]
=> 2116 = 81 + 1600
=> 2116 ≠ 1681
So, this is not a Pythagorean Triplet
2) 16, 30 and 34
=> [tex]c^2 = a^2 + b^2[/tex]
=> [tex]34^2 = 16^2 + 30^2[/tex]
=> 1156 = 256 + 900
=> 1156 = 1156
No need to check more as we've found the one which is not a Pythagorean Triplet.
Answer:
[tex] \boxed{ \huge{ \boxed{ \sf{ \blue{9 , \: 40 \:, 46 \: }}}}}[/tex]Option A is the correct option.
Step-by-step explanation:
1. Let h , p and b are the hypotenuse , perpendicular and base of a right - angled triangle respectively.
From Pythagoras theorem,
[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]
Here, we know that the hypotenuse is always greater than perpendicular and base,
h = 46 , p = 40 , b = 9
⇒[tex] \sf{ {46}^{2} = {40}^{2} + {9}^{2} }[/tex]
⇒[tex]2116 = 1600 + 81[/tex]
⇒[tex] \sf{2116 ≠ 1681}[/tex]
Thus , the relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is not satisfied by h = 46 , p = 40 , b = 9
So, The set of numbers 9 , 40 , 46 is not Pythagorean triple.
------------------------------------------------------
2. 16 , 30 , 34
h = 34 , p = 30 , b = 16
[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]
⇒[tex] \sf{ {34}^{2} = {30}^{2} + {16}^{2} }[/tex]
⇒[tex] \sf{1156 = 900 + 256}[/tex]
⇒[tex] \sf{1156 = 1156}[/tex]
The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and b i.e h = 34 , p = 30 , b = 16
So, the set of numbers 16 , 30 , 34 is a Pythagorean triple.
------------------------------------------------------
3. 10, 24 , 26
h = 26 , p = 24 , b = 10
[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]
⇒[tex] \sf{ {26}^{2} = {24}^{2} + {10}^{2} }[/tex]
⇒[tex] \sf{676 = 576 + 100}[/tex]
⇒[tex] \sf{676 = 676}[/tex]
The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and h i.e h = 26 , p = 24 , b = 10
So, the set of numbers 10, 24 , 26 is the Pythagorean triple.
-----------------------------------------------------
4. 50 , 120 , 130
h = 130 , p = 120 , b = 50
[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]
⇒[tex] \sf{ {130}^{2} = {120}^{2} + {50}^{2} }[/tex]
⇒[tex] \sf{16900 = 14400 + 2500}[/tex]
⇒[tex] \sf{16900 = 16900}[/tex]
The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and b i.e h = 130 , p = 120 , b = 50
So, the set of numbers 50, 120 , 130 is the Pythagorean triple.
-----------------------------------------------------
In this way, to satisfy the Pythagoras Theorem , the hypotenuse ( h ) , perpendicular ( p ) and the base ( b ) of a right - angles triangle should have the particular values in order. These values of h , p and b are called Pythagorean triple.
Hope I helped!
Best regards!!
Convert the following: 2 liters is equivalent to ounces (rounded to the nearest hundredth)
Answer:
67.63 oz
Step-by-step explanation:
1 liter = 33.814 oz
2 litres = 2 x 33.814 oz = 67.628 oz
B) What is the value of f(n-1)?
Answer:
Add information
Step-by-step explanation:
According to mu understanding, this is the part (B) of the question. If you could provide the first part, I can complete it because some useful information is left out.
Hellllllllllppppppppppp please
Answer:
As x decreases in value.f(x) decreases in value.......
Y=-5x+30 x=10 what is the solution to the system of equations 1)(-20,10) 2)(10,-20) 3)(10,4) 4)(4,10)
Answer:
2) (10, -20)Step-by-step explanation:
y = - 5x + 30 and x = 10 ⇒ y = -5•10 + 30 = -50 + 30 = -20
x = 10 and y = -20 ⇒ (10, -20)
Answer:
Its B. (10, –20)
Step-by-step explanation:
I just took the quiz on edge
Helppp thanksss!!!!!!
Answer:
1 mile
Step-by-step explanation:
in 20 minutes Stuart has gone 1 mile
in 20 minutes Brandy has gone 4 miles
therefore they meet 1 mile from Stuart's house
Answer:
1 mile
Step-by-step explanation:
What is a discrete probability distribution? What are the two conditions that determine a probability distribution? What is a discrete probability distribution? Choose the correct answer below. A. A discrete probability distribution exclusively lists probabilities. B. A discrete probability distribution lists each possible value a random variable can assume, together with its probability. C. A discrete probability distribution lists each possible value a random variable can assume. D. None of the above
Answer:
The answers to the question above are given below:
Step-by-step explanation:
Question: What is a discrete probability distribution?
Answer
A discrete distribution is very important in data research as it shows in tabular form the probabilities that can be found in a list of distribution values and their individual probabilities in counted data. Usually, from the pool of distribution of numbers, the discrete distribution shows the probability of having countable numbers out of the pool.
Question: Choose the correct answer below. A. A discrete probability distribution exclusively lists probabilities. B. A discrete probability distribution lists each possible value a random variable can assume, together with its probability. C. A discrete probability distribution lists each possible value a random variable can assume. D. None of the above
The correct answer is: option B "discrete probability distribution lists each possible value a random variable can assume, together with its probability."
Question: What are the two conditions that determine a probability distribution?
The correct answer is:
1. Since each value may not be zero, each probability must include between 0 and 1.
2. When probabilities are totaled, it must give 1.
Kyle rides his bicycle 15 mph for 2 hours how far does he travel
━━━━━━━☆☆━━━━━━━
▹ Answer
30 miles
▹ Step-by-Step Explanation
Multiply mph by hours:
15 mph * 2 hrs = 30 miles
Hope this helps!
CloutAnswers ❁
━━━━━━━☆☆━━━━━━━
what is y ? x=1 y=? y=3x-7
Answer:
-4.
Step-by-step explanation:
y = 3x - 7; x = 1.
y = 3(1) - 7
= 3 - 7
= -4
Hope this helps!
Answer:
y = - 4
Step-by-step explanation:
y=3x-7
Let x =1
y = 3*1 -7
y = 3-7
y = - 4
La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el peso del auto y el cuadrado de la velocidad del mismo. Supongamos que 400 libras de fuerza evitan que un auto que pesa 1600 libras derrape en una curva cuyo radio mide 800 si viaja a 50mph. ¿Cuánta fuerza evitaría que el mismo auto derrapara en una curva cuyo radio mide 600 si viaja a 60mph ?
Answer:
768 libras de fuerza
Step-by-step explanation:
Tenemos que encontrar la ecuación que los relacione.
F = Fuerza necesaria para evitar que el automóvil patine
r = radio de la curva
w = peso del coche
s = velocidad de los coches
En la pregunta se nos dice:
La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.
F ∝ 1 / r
Y luego con el peso del auto
F ∝ w
Y el cuadrado de la velocidad del coche
F ∝ s²
Combinando las tres variaciones juntas,
F ∝ 1 / r ∝ w ∝ s²
k = constante de proporcionalidad, por tanto:
F = k × w × s² / r
F = kws² / r
Paso 1
Encuentra k
En la pregunta, se nos dice:
Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.
F = 400 libras
w = 1600 libras
r = 800
s = 50 mph
Tenga en cuenta que desde el
F = kws² / r
400 = k × 1600 × 50² / 800
400 = k × 5000
k = 400/5000
k = 2/25
Paso 2
¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?
F = ?? libras
w = ya que es el mismo carro = 1600 libras
r = 600
s = 60 mph
F = kws² / r
k = 2/25
F = 2/25 × 1600 × 60² / 600
F = 768 libras
Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.
Jake ran 4 1/4 miles on Monday and 2 2/3 miles on Tuesday. On Wednesday he ran 1 fewer miles then he ran on Monday. How many miles did he run in all? PLEASE SHOW YOUR WORK I WILL MARK YOU BRAINLIEST AND PLEASE EXPLAIN
Answer:
Jake ran 10 1/6 miles in total
Step-by-step explanation:
4 1/4 + 2 2/3 - (4 1/4-1).
v
6 11/12 + 3 1/4
v
6 11/12 + 3 3/12 = 10 1/6
Jake ran 10 1/6 miles in total (Mon, Tues, Wed).
Answer:
61/6 or 10.1666666667
Step-by-step explanation:
Monday = 4 1/4
Tuesday = 2 2/3
Wednesday = Monday - 1
=> Monday = 17/4 miles
=> Tuesday = 8/3 miles
=> Wednesday = 17/4 - 4/4 = 13/4 miles.
=> (17/4 + 13/4) + 8/3
=> 30/4 + 8/3
=> Take the LCM of the denominators.
=> LCM = 12
=> 90/12 + 32/12
=> 122/12
SImplify 122/12
=> 61/6 or 10.1666666667
Suppose y varies jointly as x & z. If y = -180 when z = 15and x = -3,then find y when x = 7 and z = -5.
Answer:
y = - 140
Step-by-step explanation:
Given that y varies jointly as x and z then the equation relating them is
y = kxz ← k is the constant of variation
To find k use the condition y = - 180 when z = 15 and x = - 3, thus
- 180 = k × - 3 × 15 = - 45k ( divide both sides by - 45 )
4 = k
y = 4xz ← equation of variation
When x = 7 and z = - 5, then
y = 4 × 7 × - 5 = - 140
If 4th term of an AP is 0. Prove that 25th term is triple the 11th term
Answer:
The 4th term = a+3d = 0,
or a = -3d.
The 25th term = a+24d = -3d+24d = 21d. ...
the 25th term is 3 times the 11th term. Proved.
Answer:
a^25 = 3 x a^11 .
Step-by-step explanation:
Given a^4 = 0
That is (a + 3d) = 0
⇒ a = - 3d ........... (1)
nth term of AP is given by an = a + (n – 1)d
a^11 = a + 10d = – 3d + 10d = 7d [From (1)]
a^25 = a+ 24d = – 3d + 24d = 21d [From (1)]
Hence
The answer is a^25=3 x a^11
What is the median of the following set of measurements?
"22 kg, 24 kg, 28 kg, 19 kg, 27 kg",
The median of the measurements is kg.
Answer:
24 kg
Step-by-step explanation:
The median can be found by putting the numbers in order and then finding the middle value.
In order from least to greatest:
19, 22, 24, 27, 28
24 is the middle value
So, 24 kg is the median.
Answer:
24 kg
Step-by-step explanation:
The median is the number in the middle of the data set. To find the median, arrange the numbers from least to greatest, then locate the middle number.
1. Arrange the numbers from least to greatest
Numbers: 22 kg, 24 kg, 28 kg, 19 kg, 27 kg
Least to greatest: 19 kg, 22 kg, 24 kg, 27 kg, 28 kg
2. Locate the middle number
Cross one number off each end of the set until the middle is reached.
19 kg, 22 kg, 24 kg, 27 kg, 28 kg
Cross off 19 and 28
22 kg, 24 kg, 27 kg
Cross off 22 and 28
24 kg
The middle number has been reached.
median= 24 kg
The median of the measurements is 24 kilograms.
A study table of length 2 m and breath 1.25 m in decorted with square design of size 10x 10 find the number of such designs???
Answer:
250Step-by-step explanation:
Assuming that the shape of the table be rectangular in nature.
Area of the study table = Length * Breadth
Area of the study table = 2m * 1.25m
Area of the study table = 200cm * 125cm (since 100cm = 1m)
Area of the study table = 25000cm²
If the study table is decorated with square design of size 10cm x 10cm, the area of one square design is 100 cm².
The number of such square designs = Area of the study table/area of one square design
The number of such square designs = 25000cm²/100cm²
The number of such square designs = 250
Hence the number of such design is 250
solving polynomial(-2y-6)(-3y-8)
Answer:
(-2y-6)(-3y-8)
= 6y²+16y+18y+48
= 6y²+ 34 y +48
Hope this helps
if u have question let me know in comments ^_^
Answer:
Here is your answer!!!
Step-by-step explanation:
-2y(-3y-8)-6(-3y-8)
6y^2+16y+18y+48
6y^2+34y+48
Simplify to create an equivalent expression.
5(10k + 1) + 2(2+8k)
Answer:
66k+9
Step-by-step explanation:
Let's simplify step-by-step.
5(10k+1)+2(2+8k)
Distribute:
=(5)(10k)+(5)(1)+(2)(2)+(2)(8k)
=50k+5+4+16k
Combine Like Terms:
=50k+5+4+16k
=(50k+16k)+(5+4)
=66k+9
Answer:
=66k+9
HOPE THIS HELPS!!!!!! :)
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Three whole numbers have an HCF of 3 and an LCM of 180. Two of the numbers are 45 and 60. Find the third number.
Answer:
Step-by-step explanation:
45=3×3×5
60=2×2×3×5
L.C.M=180
2| 180
2|90
3|45
3|15
3|5
180=2×2×3×3×5
third number=2×3=6
or 2×2×3=12
or2×3×3=18
or 2×2×3×3=36
so third number can be one of 6,12,18,36
