plz help me with this question ​

Answer:

no idea what this means

Explanation:

yeah

[tex]\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{100-0}{20}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{100}{20}[/tex]

[tex]\\ \sf\longmapsto Acceleration=5m/s^2[/tex]

Answer:

[tex]initial \: velocity \: = 0 \\ final \: velocity \: 100 \frac{m}{s} \\ time = 20 \\ here \: we \: want \: to \: find \: accelaration \\ accelaration \: = \frac{final \: velocity - initial \: velocity}{time} \\ accelaration \: = \frac{100 - 0}{20} = \frac{100}{20} = 5 \frac{m}{ {s}^{2} } \\ thank \: you[/tex]

Answer:

One must drive [tex]$41 \cdot 8\,miles$[/tex] north and [tex]$68 \cdot 24\,miles$[/tex] south, in order to travel from Atlanta to Macon.

Explanation:

• The distance of an object can be defined as the complete path travelled by an object.

• To find the distance, find its north component.

• For reference see the below graph:

[tex]$$\[\begin{align}& D_{south} = 80\sin \left( {58 \cdot {5^ \circ }} \right) \\& D_{north} = 80\cos \left( {58 \cdot {5^ \circ }} \right) \\\end{align}\]$$Since, $\sin \left( {58 \cdot {5^ \circ }} \right) = \cdot 853$ and $\cos \left( {58 \cdot {5^ \circ }} \right) = \cdot 5224$: therefore,$$\[\begin{align} D_{south} &= 80 \times \left( { \cdot {{853}^ \circ }} \right) \\ \Rightarrow {D_{south}} &= 68 \cdot 24\,miles \\ \end{align}\]$$[/tex]

And

[tex]$$\[\begin{align} D_{north}& = 80 \times \cdot 5224 \\ \Rightarrow D_{north}& = 41 \cdot 8\,miles \\ \end{align}\]$$[/tex]

• Hence, one must drive [tex]$41 \cdot 8\,miles$[/tex] north and [tex]$68 \cdot 24\,miles$[/tex] south, in order to travel from Atlanta to Macon.

Learn more about distance here:

https://brainly.com/question/12356025

Answer:

117.06 A

Explanation:

V = IR

2650 = 66(R)

2650/66 = R

40.15 = R

V = IR

4700 = I(40.15)

4700/40.15 = I

117.06 = I