Print the two-dimensional list mult_table by row and column. Hint: Use nested loops.
Sample output with input: '1 2 3,2 4 6,3 6 9':
1 | 2 | 3
2 | 4 | 6
3 | 6 | 9
How can I delete that whitespace?

Answer:

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Answer: D. all of the above are correct

Explanation:

The correct statements regarding the decentralized (distributed) access control on a LAN include:

• no centralized access process exists, and therefore each connected station has the responsibility for controlling its access

• data collisions are possible, therefore mechanisms such as CDMA/CD are required

• when a data collision occurs, the nearest station detecting the collision transmits a jamming signal.

Therefore, the correct option is all of the above.

Answer:

He belongs to the nation

Using the concepts of public and private domains, it means that the photograph of the president can be used by anyone without asking for permission.

---------------

Public and private domains:

A similar question is given at https://brainly.com/question/12202794

Answer:

A.

the final keyword is used to denote constants. It can be used with variables, methods, and classes. Once any entity (variable, method or class) is declared final , it can be assigned only once.

B.

Static variables are declared in the same place as instance variables, but with the keyword 'static' before the data type. While instance variables hold values that are associated with an individual object, static variables' values are associated with the class as a whole.

Answer:

Hence the answer is given as follows,

Explanation:

Base Case:-  

If (num == 0) //This is the base case for the given recursive method  

return 1;  

If(num % 2!=0) checks whether num is odd.  

The above condition is true for all odd numbers and false for even numbers.  

if the remainder is not equal to zero when we divide the number with 2 then it is odd.  

The method:-  

The above recursive method calculates the product of odd numbers up to the given range(that is num)  

For num=5   => 15(5*3*1).  

For num=7   => 105(7*5*3*1).  

For num=10 => 945(9*7*5*3*1).

Answer:

it would have to be flow control which would be C.

Explanation:

Flow Control is restricts the ability for individuals to reveal information present in some part of the database. Hence, option C is correct.

The management of data flow between computers, devices, or network nodes is known as flow control. This allows the data to be processed at an effective rate. Data overflow, which occurs when a device receives too much data before it can handle it, results in data loss or retransmission.

A design concern at the data link layer is flow control. It is a method that typically monitors the correct data flow from sender to recipient. It is very important because it allows the transmitter to convey data or information at a very quick rate, which allows the receiver to receive it and process it.

The amount of data transmitted to the receiver side without any acknowledgement is dealt with by flow control.

Thus, option C is correct.

For more information about Flow Control, click here:

https://brainly.com/question/28271160

#SPJ5

Answer:

The Arduino boards can be programmed in assembly. All you need is an ICSP Cable (In Circuit Serial Programmer) and the AVR toolchain (free from ATMEL) to write to the board. You then get the advantage of on board debugging.

As you suggested, you can just slap an ATMEL chip on a breadboard and go to town.

Explanation: cause i said so

Answer:

1. Wrong as per my knowledge, SQLite may be an electronic database software that stores data in relations(tables).

2. Wrong. Content provider interface controls the flow of knowledge from your android application to an external data storage location. Data storage is often in any database or maybe it'll be possible to store the info in an SQLite database also.

3.Right. SQLite uses one file to store data. It also creates a rollback file to backup the stored data/logs the transactions.

4. Wrong. The queries are almost like a traditional electronic database system, the queries are going to be answered as per the conditions given and should return a group of answers or one answer depending upon the info and sort of query used.

5. Right. A cursor helps to point to one entry within the database table. this may be very helpful in manipulating the present row of the query easily.

Answer:

A triangle on the Clock input.

Answer:

[tex](a)\ 14"."43[/tex]

[tex](b)\ 0"0"7[/tex]

[tex](c)\ 2"8 - 2"611[/tex]

[tex](d)\ 7"(1 + 1)"46[/tex]

[tex](e)\ "1"23"4"30"7"17[/tex]

Explanation:

Required

Evaluate each expression

The simple rules to follow are:

(1) All expressions in bracket will be evaluated based on its data type

(2) Divisions will return only integer values

(3) Integers immediately after string values will be concatenated (not added)

So, the results are as follows:

[tex](a)\ 4 + 1 + 9 + "." + (-3 + 10) + 11 / 3[/tex]

Evaluate till a string is encountered

[tex]4 + 1 + 9 = 14[/tex]

Followed by "."

Then:

[tex](-3 + 10) = 7[/tex]

[tex]11/ 3 = 3[/tex]

[tex]"." + (-3 + 10) + 11/3 = "."73[/tex] -- because expressions after string operations are concatenated.

So, we have:

[tex]4 + 1 + 9 + "." + (-3 + 10) + 11 / 3 = 14"."43[/tex]

[tex](b)\ 8 + 6 * -2 + 4 + "0" + (2 + 5)[/tex]

Evaluate till a string is encountered

[tex]8 + 6 * -2 + 4 =0[/tex]

[tex]"0" + (2 + 5) ="0"7[/tex]

So, we have:

[tex]8 + 6 * -2 + 4 + "0" + (2 + 5) = 0"0"7[/tex]

[tex](c)\ 1 + 1 + "8 - 2" + (8 - 2) + 1 + 1[/tex]

Evaluate till a string is encountered

[tex]1 + 1 = 2[/tex]

[tex]"8 - 2" + (8 - 2) + 1 + 1 = "8 - 2"611[/tex]

So, we have:

[tex]1 + 1 + "8 - 2" + (8 - 2) + 1 + 1 = 2"8 - 2"611[/tex]

[tex](d)\ 5 + 2 + "(1 + 1)" + 4 + 2 * 3[/tex]

Evaluate till a string is encountered

[tex]5 + 2 =7[/tex]

[tex]"(1 + 1)" + 4 + 2 * 3 = "(1 + 1)"46[/tex] --- multiply 2 and 3, then concatenate

So, we have:

[tex]5 + 2 + "(1 + 1)" + 4 + 2 * 3= 7"(1 + 1)"46[/tex]

[tex](e)\ "1" + 2 + 3 + "4" + 5 * 6 + "7" + (8 + 9)[/tex]

Since a string starts the expression, the whole expression will be concatenated except the multiplication and the expressions in bracket.

So, we have:

[tex]"1" + 2 + 3 + "4" + 5 * 6 + "7" + (8 + 9) = "1"23"4"30"7"17[/tex]

Answer:

Here the code is given as follows,

Explanation:

class Example:

   def _init_(self, val):

       self.val = val

   def _gt_(self, other):

       return self.val > other.val

   def _sub_(self,other):

       return abs(len(self.val) - len(other.val))

def main():

   obj1 = Example('this is a string')

   obj2 = Example('this is another one')

   print(obj1 > obj2)

   print(obj1 - obj2)

main()

Output:-

Answer:

Explanation:

The code provided worked for the most part, it had some gramatical errors in when printing out the information as well as repeated values. I fixed and reorganized the printed information so that it is well formatted. The only thing that was missing from the code was the input validation to make sure that no negative values were passed. I added this within the getMonths() method so that it repeats the question until the user inputs a valid value. The program was tested and the output can be seen in the attached image below.

import java.io.*;

import java.util.*;

class Rainfall

{

   Scanner in = new Scanner(System.in);

   private int month = 12;

   private double total = 0;

   private double average;

   private double standard_deviation;

   private double largest;

   private double smallest;

   private double months[];

   public Rainfall()

   {

       months = new double[12];

   }

   public void setMonths()

   {

       for(int n=1; n <= month; n++)

       {

           int answer = 0;

           while (true) {

               System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );

               answer = in.nextInt();

               if (answer > 0) {

                   months[n-1] = answer;

                   break;

               }

           }

       }

   }

   public void getTotal()

   {

       total = 0;

       for(int i = 0; i < 12; i++)

       {

           total = total + months[i];

       }

       System.out.println("The total rainfall for the year is " + total);

   }

   public void getAverage()

   {

       average = total/12;

       System.out.println("The average monthly rainfall is " + average);

   }

   public void getLargest()

   {

       double largest = 0;

       int largeind = 0;

       for(int i = 0; i < 12; i++)

       {

           if (months[i] > largest)

           {

               largest = months[i];

               largeind = i;

           }

       }

       System.out.println("The largest amount of rainfall was " + largest +

               " inches in month " + (largeind + 1));

   }

   public void getSmallest()

   {

       double smallest = Double.MAX_VALUE;

       int smallind = 0;

       for(int n = 0; n < month; n++)

       {

           if (months[n] < smallest)

           {

               smallest = months[n];

               smallind = n;

           }

       }

       System.out.println("The smallest amount of rainfall was " + smallest +

               " inches in month " + (smallind + 1));

   }

   public static void main(String[] args)

   {

       Rainfall r = new Rainfall();

       r.setMonths();

       r.getTotal();

       r.getSmallest();

       r.getLargest();

       r.getAverage();

   }

}

Answer:

Explanation:

The code that was provided in the question contained a couple of bugs. These bugs were fixed and the new code can be seen below as well as with the solution for the number of one-dollar bills included. The program was tested and the output can be seen in the attached image below highlighted in red.

amount_to_change = int(input())

num_fives = amount_to_change // 5

#Your solution goes here

num_ones = amount_to_change % 5

print('Change for $' + str(amount_to_change))

print(num_fives, 'five dollar bill(s) and', num_ones, 'one dollar bill (s)')

Answer:

All of these.

PLZ MARK ME BRAINLIEST.

Answer:

Answer:Functions in C+

The integer variable n is the input to the function and it is also called the parameter of the function. If a function is defined after the main() .....

Answer: 52

Explanation:

Following the information given in the question, we are informed that a process needs 103 KB of memory in order to run and that the system on which it is to run uses paging with 2KB pages, then the number of frames in memory that are needed will be:

= 103/2

= 51.5

= 52 approximately

Therefore, 52 frames in memory are needed.

Answer:

caca

Explanation:

Answer:

The program in Python is as follows:

def ASCIIsum(str1,str2):

   asciisum1 = 0;    asciisum2 = 0

   for chr in str1:

       asciisum1 += (ord(chr) - 96)

   for chr in str2:

       asciisum2 += (ord(chr) - 96)

   if asciisum1 > asciisum2:

       return True

   else:

       return False

str1 = input("Enter first string: ")

str2 = input("Enter second string: ")

if ASCIIsum(str1,str2) == True:

   print(str1,"has a higher ASCII value")

else:

   print(str2,"has a higher ASCII value")

Explanation:

This defines the function

def ASCIIsum(str1,str2):

This initializes the ascii sum of both strings to 0

   asciisum1 = 0;    asciisum2 = 0

This iterates through the characters of str1 and add up the ascii values of each character

   for chr in str1:

       asciisum1 += (ord(chr) - 96)

This iterates through the characters of str2 and add up the ascii values of each character

   for chr in str2:

       asciisum2 += (ord(chr) - 96)

This returns true if the first string has a greater ascii value

   if asciisum1 > asciisum2:

       return True

This returns false if the second string has a greater ascii value

   else:

       return False

The main begins here

This gets input for first string

str1 = input("Enter first string: ")

This gets input for second string

str2 = input("Enter second string: ")

If the returned value is True

if ASCIIsum(str1,str2) == True:

Then str1 has a greater ascii value

   print(str1,"has a higher ASCII value")

If otherwise

else:

Then str2 has a greater ascii value

   print(str2,"has a higher ASCII value")

Answer:

Explanation:

The following code is written in Java. It creates the Rainfall class with two constructors, one that passes the entire array of rainfall and another that initializes an array with 0.0 for all the months. Then the class contains a method to add rain to a specific month, as well as the three methods requested in the question. The method to add rain validates to make sure that no negative value was added. 8 Test cases were provided, and any methods can be called on any of the 8 objects.

class Brainly {

   public static void main(String[] args) {

       Rainfall rain1 = new Rainfall();

       Rainfall rain2 = new Rainfall();

       Rainfall rain3 = new Rainfall();

       Rainfall rain4 = new Rainfall();

       Rainfall rain5 = new Rainfall();

       Rainfall rain6 = new Rainfall();

       Rainfall rain7 = new Rainfall();

       Rainfall rain8 = new Rainfall();

   }

}

class Rainfall {

   double[] rainfall = {0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0};

   public Rainfall(double[] rainfall) {

       this.rainfall = rainfall;

   }

   public Rainfall() {

   }

   public void addMonthRain(double rain, int month) {

       if (rain > 0) {

           rainfall[month-1] = rain;

       }

   }

   public double totalRainfall() {

       double total = 0;

       for (double rain: rainfall) {

           total += rain;

       }

       return total;

   }

   public double averageRainfall() {

       double average = totalRainfall() / 12;

       return average;

   }

   public double rainiestMonth() {

       double max = 0;

       for (double rain : rainfall) {

           if (rain > max) {

               max = rain;

           }

       }

       return max;

   }

}

Answer:

Following are the code to the given question:

#include<stdio.h>//include header file  

int main() //defining a main method

{  

   int a[100],k,x,s; //defining integer variable and an array  

   printf("Input the number of element want to insert array: ");  //print message

   scanf("%d",&x);  //input value

   printf("Enter array value: \n"); //print message  

   for(k = 0; k<x; k++)  //defining a loop that inputs values

   {  

       scanf("%d",&a[k]);  //use array to input value

   }  

   s = a[0]; //holding first array value in array

   for(k=0;k<x;k++)  //use for loop

   {  

       if(a[k]<s)  //use if block to check the smallest array value

       {  

         s=a[k];//holding smallest array value

       }  

   }  

   printf("smallest number= %d",s);//print smallest value

}  

Output:

Please find the attached file.

Explanation:

In this code an array and another integer variable "a[100], i,n, and s" is is declared, in which the array and n for input the value from the user-end.

In the next step, an "s" variable is declared that inputs the first array element value in s and use a loop to check the smallest array element and prints its value.

Answer:

Following are the responses to these questions:

Explanation:

It employs keywords to autonomously do work tasks. Users can type numbers directly into the formulas or use the following formulae, so any data the cells referenced provide would be used in the form.

For instance, this leadership involves accounting, and Excel is concerned with organizing and organizing numerical data. In this Equation, I can discover all its information in the data. This idea is simple me count the number many cells containing a number, and also the number of integers. It counts integers in any sorted number as well. As both financial analysts, it is helpful for the analysis of the data if we want to maintain the same number of neurons.

Answer:

Explanation:

The statement solution was added to the code and then the code was repeated in order to create the second test case with 9 nickels and 0 dimes. The outputs for both test cases can be seen in the attached image below.

import java.util.Scanner;

class AssigningSum {

    public static void main(String[] args) {

        int numCoins;

        int numNickels;

        int numDimes;

        numNickels = 5;

        numDimes = 6;

        /* Your solution goes here */

        numCoins = numNickels + numDimes;

       System.out.print("There are ");

       System.out.print(numCoins);

       System.out.println(" coins");

//        TEST CASE 2

        numNickels = 9;

        numDimes = 0;

        /* Your solution goes here */

        numCoins = numNickels + numDimes;

        System.out.print("There are ");

        System.out.print(numCoins);

        System.out.println(" coins");

}

}

Answer:

Following are the code to the given question:

import java.util.concurrent.*; //import package

public class Threads //defining a class Threads

{

private Integer s = new Integer(0);//defining Integer class object

public synchronized static void main(String[] args)//defining main method  

{

Threads t = new Threads();//defining threads class object

System.out.println("What is sum ?" + t.s);//print value with message

}

Threads()//defining default constructor

{

ExecutorService exe = Executors.newFixedThreadPool(1000);//defining ExecutorService class object

System.out.println("With SYNCHRONIZATION........");//print message

for(int i = 1; i <= 1000; i++)//defining a for loop

{

exe.execute(new SumTask2());//calling execute method

System.out.println("At Thread " + i +" Sum= " + s + " , ");//print message with value

}

exe.shutdown();//calling shutdown method

while(!exe.isTerminated())//defining while loop that calls isTerminated method

{

}

}

class SumTask2 implements Runnable//calling SumTask2 that inherits Runnable class

{

public synchronized void run()//defining method run

{

int value = s.intValue() + 1;//defining variable value that calls intvalue which is increment by 1

s = new Integer(value);//use s to hold value

}

}

}

Output:

Please find the attached file.

Explanation:

In this code, a Threads class is defined in which an integer class object and the main method is declared that creates the Threads class object and calls its values.

Outside the method, the default constructor is declared that creates the "ExecutorService" and prints its message, and use a for loop that calls execute method which prints its value with the message.

In the class, a while loop is declared that calls "isTerminated" method, and outside the class "SumTask2" that inherits Runnable class and defined the run method and define a variable "value" that calls "intvalue" method which is increment by 1 and define s variable that holds method value.

Answer:

Explanation:

Marketing your product directly over the internet can lead to much greater profits and there are many options that you can choose from in order to target the correct audience. Unfortunately, doing so does require marketing knowledge and is basically like growing a business. If you were to use intermediaries they already have the knowledge necessary to market your product but will take a percentage of the profits, which will ultimately limit your gains. Since Gray London is a race car driver, I am assumming that he does not have any prior technological expertise or marketing expertise, therefore I would recommend using intermediaries.

Answer:

The default return data type in function is int

Answer: Option (b)

Explanation:

The default return data type in a function is int. In other words commonly if it is not explicitly mentioned the default return data type of a function by the compiler will be of an integer data type.

If the user does not mention a return data type or parameter type, then C programming language will inevitably make it an int.

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