Answer:
graph c
Step-by-step explanation:
it is the longest one
simplify the following radical expression -7√2 + 10 √2
Answer:
3√2
Step-by-step explanation:
* means multiply
-7√2 + 10 √2
take √2 out of the expression
√2 (-7 + 10)
√2 (3)
3√2
ABC ~ DEF
What is the value for x, the length of side BC?
Answer:
17.5
Step-by-step explanation:
as the triangles are similar, when oriented in the same direction they have the same angles, and the lengths of all sides of DEF are the lengths of the sides of ABC but multiplied by the same scaling factor f for all sides.
so, we see that
A ~ D
B ~ E
C ~ F
and therefore
AB ~ DE
BC ~ EF
CA ~ FD
that means
DE = AB × f
EF = BC × f
FD = CA × f
we know DE and AB.
so,
4 = 10 × f
f = 4/10 = 2/5
and now we know
EF = 7 = BC × f
BC = 7/f = (7/1) / (2/5) = (5×7)/(2×1) = 35/2 = 17.5
Answer:
17.5
Step-by-step explanation:
Please help me!!
I just don’t understand it!!
Answer:
(12, 2 )
Step-by-step explanation:
Given (x, y ) on the graph of f(x) , then on the inverse function
(x, y ) → (y, x ), then
(2, 12 ) → (12, 2 ) ← point on g(x) the inverse function
factories ((x+2)+3x+6. 2a(a-1)-a+1
Answer:1. = 4x+8
2. 2a²-a+1
Step-by-step explanation:
1. ((x+2)+3x+6. 2. 2a(a-1)-a+1
((x+2)+3x+6
= x+2+3x+6
= 4x+8
2a(a-1)-a+1
2a²-2a-a+1
2a²-a+1
PLEASE ANSWER ASAPPP
Answer:
the answer is 2035.75 cm³
Step-by-step explanation:
comment if you want explanation
c) Which of these numbers is a square number?
A
4 x 105
B
9 x 104
С
4 x 103
D
9 x 103
ax + by = c and mx + ny = d and an # bm then these simultaneous equations have a) Only one common solution. b) No solution. c) Infinite number of solutions. d) Only two solutions.
Answer:
a) Only one common solutionStep-by-step explanation:
The first line has slope of a/b and the second one has slope of m/n.
As an ≠ bm ⇒ a.b ≠ m/n, the slopes are different.
Since the slopes are different the lines are not parallel, hence they intersect at one point.
This means there is one solution only.
ax + by = c and mx + ny = d and an # bm then these simultaneous equations have Only one common solution.
[tex]\sf{ }[/tex] [tex]\sf{ }[/tex]
Solve for x. Round to the nearest tenth, if necessary.
Answer:
X would be 63.9
Hope it helps
Step-by-step explanation:
The value of the variable 'x' using the cosine formula will be 63.9 units.
What is a right-angle triangle?It's a form of a triangle with one 90-degree angle that follows Pythagoras' theorem and can be solved using the trigonometry function.
Trigonometric functions examine the interaction between the dimensions and angles of a triangular form.
The value of 'x' is given by the cosine of the angle ∠QSR. And the cosine of an angle is the ratio of the base and hypotenuse of the right-angle triangle. Then we have
cos 35° = x / 78
x = 63.9
The value of the variable 'x' using the cosine formula will be 63.9 units.
More about the right-angle triangle link is given below.
https://brainly.com/question/3770177
#SPJ7
Urgenteeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Use the elimination method to solve the system of equations.
A. (1.5,-8)
B. (-6,-13)
C. (0,0)
D. (4.5,-6)
Answer:
(4.5,-6)
Step-by-step explanation:
[tex]2x-3y = 27\\4x+3y = 0[/tex]
6x = 27
x = 27/6=4.5
9-3y = 27
-3y = 18
y = -6
[tex]2 ^{2x + 1} - 9.2 ^{x} + 4 = 0[/tex]
pleas I need this answer. I want to submit it now.
[tex]\displaystyle\bf 2^{2x+1}-9\cdot 2^x+4=0 \quad ; \qquad \boxed{ 2^x=t \; ; \; 2^{2x}=t^2} \\\\2t^2-9t+4=0 \\\\D=81-32 =49 \\\\ t_1=\frac{9+7}{4} =4 \\\\ t_2=\frac{9-7}{4} =\frac{1}{2} \\\\1) \ 2^x=4 \Longrightarrow x_1=2 \qquad 2) \ 2^x=2^{-1}\Longrightarrow x_2=-1 \\\\Answer: \boxed{x_1=2 \quad ; \quad x_2=-1}[/tex]
Consider the graph of f(x) = 5x + 1. Explain how to find the average rate of change between x = 0 and x = 4.
What is the average rate of change?
Answer:
5
Step-by-step explanation:
You divide the change in the output value by the change in the input value.
Input: 0 | 4
Output: 1 | 21
20/4= 5
use r =27 & x =3
[tex]-\frac{r}{9}+ 5x[/tex]
Answer:
12
Step-by-step explanation:
First substitute the equation with the variable replacements given:
-r/9 + 5x <--- Before
-27/9 + 5(3) <--- After
Next Solve the parts of the Equation
-27/9 + 5(3)
-3 + 15 <--- -27 divided by 9 is -3, 5 times 3 is 15.
= 12 <--- 15 - 3 = 12.
I hope this helps!
Answer:
12
Step-by-step explanation:
[tex]-\frac{27}{9}+5(3)[/tex]
- 3 + 15
15 - 3
12
Choose the correct answer from the given four options:In an AP, if a = 3.5, d = 0, n =101 ,then an will be
0
-3.5
3.5
1
Answer:
3.5
Step-by-step explanation:
Tn=a(n-1)d
Tn=3.5+(101-1)0
Tn=3.5+0
Tn=3.5
Helppp and explain pls and thankyou
Answer:
None of both
Step-by-step explanation:
It say y = lxl
so it mean if y = 3 so x = 3 or -3
What is the total value of digit 7 in the number 32.8794
Answer:
hundredth
Step-by-step explanation:
numbers after the decimal point start counting from
tenth
hundredth
Answer:
0.07 or 7 hundredths
Step-by-step explanation:
(12.3456)- I'll use this as my example
1-tens place
2-ones place
3- tenths place
4= hundredths place
5-thousandths place
6- im pretty sure its the 10 thousandths place
Someone tell me where everyone is going right please !!
Answer:
1. 3rd option
2. 4th option
3. 1st option
4. 2nd option
5. 2nd option
Step-by-step explanation:
1.
on changing the signs of an equality the sign gets reveresd
-6 < -2x
6 > 2x
3 > x
2.
2x - 3 > 11 - 5x
adding 5x and 3 to both sides and combining like terms(2x + 5x) + (-3 + 3) > (11 + 3) + (-5x + 5x)
7x > 14
x > 2
put of all the options x = 4 is a value greater than 2 thus satisfying the condition.
3.
6k + 10. 5 = 3k + 12
subtracting 3k and 10.5 from both the sides while combining like terms(6k - 3k) + (10.5 - 10.5) = (3k - 3k) + (12 - 10.5)
3k = 1.5
k = 0.5
4.
y + 3 = -y + 9
adding y and subtracting 3 from both sides(y + y) + (3 - 3) = (-y + y) + (9 - 3)
2y = 6
y = 3
5.
-9x + 1 = -x + 17
adding x and subtracting 1 from both sides
(-9x + x) + (1 -1) = (-x +x) + (17 -1)
-8x = 16
multiplying the equation by -1
8x = -16
diving both sides by 8
x = -2
Answer:
[tex]1. \: \: x < 3[/tex]
[tex]2. \: \: 2[/tex]
[tex]3. \: \: k = 0.5[/tex]
[tex]4. \: \: y = 3[/tex]
[tex]5. \: \: x = 12[/tex]
Step-by-step explanation:
[tex]1. \: \: - 2(5 - 4x) < 6x - 4 \\ - 10 + 8x < 6x - 4 \\ - 10 + 2x < - 4 \\ 2x < 6 \\ x < 3[/tex]
[tex]2. \: \: 2x - 3 > 11 - 5x \\ 7x - 3 > 11 \\ 7x > 14 \\ x = 2[/tex]
[tex]3. \: \: 6k + 10.5 = 3k + 12 \\ 3k + 10.5 = 12 \\ 3k = 1.5 \\ k = 0.5[/tex]
[tex]4. \: \: y + 3 = - y + 9 \\ 2y + 3 = 9 \\ 2y = 6 \\ y = 3[/tex]
[tex]5. \: \: - 9x + 1 = - x + 17 \\ - 8x + 1 = 17 \\ - 8x = 16 \\ x = - 2[/tex]
Hope it is helpful....Q14SIMPLIFY THE EXPRESSION 6ab of2adivided by12x12ab+14a-a
Answer:
25
Step-by-step explanation:
6ab of 2a ÷ 12 × 12ab + 14a - a
= 6ab * 2a ÷ 12 × 12ab + 14a - a
= 12a²b ÷ 144ab + 13a
= 12*a*a*b / 144*a*b + 13*a
= a/12 + 13*a
= 1/12 + 13
= 1/25
Determina el centro,radio y gráfica de la circunferencia:(x+2)2 + (y-3)2=121
Answer:
La ecuación genérica para un círculo centrado en el punto (a, b), de radio R, es:
(x - a)^2 + (x - b)^2 = R^2
Entonces si miramos a nuestra ecuación:
(x + 2)^2 + (y - 3)^2 = 121
Tendremos el centro en:
(-2, 3)
el radio está dado por:
R^2 = 121
R = √121 = 11
La gráfica de esta circunferencia se puede ver en la imagen de abajo.
2m^2-5m-3=0 by factorization
Answer:
M= 6, -1
Step-by-step explanation:
Factoring these numbers, it will result in (m-6)(m+1). So, m= 6,-1
Joe wants to add cucumbers to his garden and knows the rectangular area is represented by x^2 - 4x - 21 square units. What expressions would represent the length and width of the cucumber field?
Given:
The area of rectangular garden is [tex]x^2-4x-21[/tex] square units.
To find:
The length and width of the cucumber field.
Solution:
The area of a rectangle is:
[tex]A=l\times w[/tex]
Where l is length and w is width of the rectangle.
The area of rectangular garden is [tex]x^2-4x-21[/tex] square units.
We need to find the factors of [tex]x^2-4x-21[/tex] to get the length and width.
[tex]A=x^2-4x-21[/tex]
Splitting the middle term, we get
[tex]A=x^2-7x+3x-21[/tex]
[tex]A=x(x-7)+3(x-7)[/tex]
[tex]A=(x-7)(x+3)[/tex]
Area of a rectangle is the product of length and width.
Therefore, the length and width of the rectangle are [tex](x-7)[/tex] units and [tex](x+3)[/tex] units.
Consider the equation 6x +7=3x � 5. Which of the following possible first steps would prevent having to deal with fractions when solving the equation?
Answer:
D. I or II only
Step-by-step explanation:
By a small online search, I've found that the equation is:
6x + 7 = 3x - 5
And the options are:
I. Combining the 6x and 3x terms
II. Combining the 7 and 5
III. Dividing both sides of the equation by 6
A. I only
B. II only
C. III only
D. I or II only
E. I or II or III
So, let's solve the equation in such a way that we can prevent the use of fractions:
6x + 7 = 3x - 5
We can use I and II, combining one in each side, so we get (so we use I and II at the same time)
6x - 3x = -5 - 7
solving these, we get:
(6 - 3)*x = -12
3*x = -12
and -12 is divisible by 3, so if we divide in both sides by 3, we get:
x = -12/3 = -4
x = -4
So we avoided working with fractions, and we used I and II.
Then the first step could be either I or II (the order does not matter)
Then the correct option is:
D. I or II only
the area of a circle is 616 m square find the radius 5 equals to 22/7
Step-by-step explanation:
[tex]here \: is \: your \: solution : - \\ \\ GIVEN \: \: -:- \\ \\ = > \: area \: of \: circle \: = 616 \: m {}^{2} \\ \\ \ = > pi = 22 \div 7 \\ \\ = > we \: need \: to \: find \: radius \: \\ \\ = > area \: of \: circle \: = \pi \: r {}^{2} \\ \\ = > \: \pi \: r {}^{2} = 616 \: m {}^{2} \\ \\ = > \: r {}^{2} \times (22 \div 7) = 616 \\ \\ = > \: r {}^{2} =( 616 \times 7) \div 22 \\ \\ = > \: r { }^{2} = 4312 \div 22 \\ \\ = > r {}^{2} = 196 \\ \\ = > \: r = \sqrt{196} \\ \\ = > \: r = 14 \: \: \: (ANSWER✓✓✓) \\ \\ HOPE \: IT \: HELPS \: YOU \: (◕ᴗ◕✿)[/tex]
Need help~ What is the measure of arc sty in the circle O below
Answer:
50
Step-by-step explanation:
Arc AT the center = angle at the center = 50
Janna is using a cone-shaped cup to fill a cylindrical container. The cup has the same height and radius as the container. How many rimes will she have to fill the cone-shaped cup to completely fill the cylindrical container.
Answer:
3 times
Step-by-step explanation:
Step 1: Express the volume of the cup in terms of "r" (radius) and "h" (height)
The formula for the volume of a cone is:
Vcone = 1/3 × h × π × r²
Step 2: Express the volume of the container in terms of "r" and "h"
The formula for the volume of a cylinder is:
Vcylinder = h × π × r²
Step 3: Calculate how many times the volume of the cone is contained in the volume of the cylinder
Vcylinder/Vcone = (h × π × r²) / (1/3 × h × π × r²) = 3
Craig has a rectengular deck that measures 799 inches and 245 inches premeter and if the addtional deck is 33 inches longer,what legnth would it be? Answer
Answer:
The length of the lights is 2088 inches
Step-by-step explanation:
The question is mixed up with another (See comment for correct question)
Given
[tex]Length = 799in[/tex]
[tex]Width = 245in[/tex]
Required
The perimeter of the deck (this is what the question implies)
The perimeter (P) is:
[tex]P = 2 * (Length + Width)[/tex]
[tex]P = 2 * (799 + 245)[/tex]
[tex]P = 2 * 1044[/tex]
[tex]P = 2088[/tex]
Given a line segment that contains the points A,B, & C in order, if AB = x, BC = x, and AC is equal to 36, then x = _____.
Select one:
a. 18
b. 6
c. 36
d. 12
Answer:
a. 18
Step-by-step explanation:
AB+BC = AC
x + x = 36
2x = 36
x = 36/2
x = 18
A and B are two similar solids...
Answer:
cant download send ss
Step-by-step explanation:
Annapolis Company purchased a $4,000, 6%, 5-year bond at 101 and held it to maturity. The straight line method of amortization is used for both premiums & discounts. What is the net cash received over the life of the bond investment? (all money received minus all money paid, round to nearest whole dollar)
Answer:
The answer is "[tex]\bold{\$1160}[/tex]"
Step-by-step explanation:
Calculating total paid money:
[tex]= \$4000 \times 101\% \\\\= \$4000 \times \frac{101}{100} \\\\=\$40 \times 101\\\\=\$4040[/tex]
[tex]\text{Total received money = Principle on Maturity + Interest for 5 years}[/tex]
[tex]= \$4000 + \$4000\times 6\% \times 5 \\\\= \$4000 + \$4000\times \frac{6}{100} \times 5 \\\\= \$4000 + \$40 \times 6 \times 5 \\\\= \$4000 + \$40 \times 30 \\\\= \$4000 + \$1200 \\\\= \$5200 \\\\[/tex]
Total earnings over the life of the corporate bond
[tex]= \$5200 - \$4040 \\\\=\$1160[/tex]
Find the TWO integers whos product is -12 and whose sum is 1
Answer:
[tex] \rm Numbers = 4 \ and \ -3.[/tex]
Step-by-step explanation:
Given :-
The sum of two numbers is 1 .
The product of the nos . is 12 .
And we need to find out the numbers. So let us take ,
First number be x
Second number be 1-x .
According to first condition :-
[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]
Hence the numbers are 4 and -3
Answer:
[tex] \displaystyle( {x}_{1} , y_{1}) =( - 3,4)\\ (x _{2}, y_{2}) = (4, - 3)[/tex]
Step-by-step explanation:
we are given two conditions
two integers whos product is -12two integers whos sum is 1let the two integers be x and y respectively according to the first condition
[tex] \displaystyle xy = - 12[/tex]
according to the second condition:
[tex] \displaystyle x + y = 1[/tex]
now notice that we have two variables therefore ended up with a simultaneous equation so to solve the simultaneous equation cancel x from both sides of the second equation which yields:
[tex] \displaystyle y = 1 - x[/tex]
now substitute the got value of y to the first equation which yields:
[tex] \displaystyle x(1 - x) = - 12[/tex]
distribute:
[tex] \displaystyle x- {x}^{2} = - 12[/tex]
add 12 in both sides:
[tex] \displaystyle x- {x}^{2} + 12 = 0[/tex]
rearrange it to standard form:
[tex] \displaystyle - {x}^{2} + x + 12 = 0[/tex]
divide both sides by -1:
[tex] \displaystyle {x}^{2} - x - 12 = 0[/tex]
factor:
[tex] \displaystyle ({x} + 3)(x - 4) = 0[/tex]
by Zero product property we acquire:
[tex] \displaystyle {x} + 3 = 0\\ x - 4= 0[/tex]
solve the equations for x therefore,
[tex] \displaystyle {x}_{1} = - 3\\ x _{2} = 4[/tex]
when x is -3 then y is
[tex] \displaystyle y _{1}= 1 - ( - 3)[/tex]
simplify
[tex] \displaystyle y _{1}= 4[/tex]
when x is 4 y is
[tex] \displaystyle y _{2}= 1 - ( 4)[/tex]
simplify:
[tex] \displaystyle y _{2}= - 3[/tex]
hence,
[tex] \displaystyle( {x}_{1} , y_{1}) =( - 3,4)\\ (x _{2}, y_{2}) = (4, - 3)[/tex]