Professor Goodheart has two exams, exam 1 and exam 2. The exam 1 weights 40% and the exam 2 weights 60% of the final grades. Put the grades on the exam 1 on the horizontal axis and the grade on the exam w on the vertical axis. What kind of preference a student should have for these two grades

Answer:

Step-by-step explanation:

Answer:

Angle of elevation = ∠4

Step-by-step explanation:

Angle of elevation of a point point from another point is the angle formed between the line joining these points and the horizontal line.

Therefore, angle of elevation of point B from a point C = ∠4

Option with angle 4 will be the answer.

b) ( 7, 21)

Step-by-step explanation:

5(7)=2(21)-7

35=42-7

35=35

Answer:

None of them

Step-by-step explanation:

a: 5*0=2*6-7 False

b: 5*21=2*7-7 False

c: 5*18=2*8-7 False

d: 5*4=2*-3-7 False

Answer:

60

Step-by-step explanation:

To get the value of x;

3x:90

(90/3) = 30

x = 30

To get the value of 2x;

(2×X);

2 × 30

=60

Answer:

I think it's a

Step-by-step explanation:

hsjshbwibs hshhsvsu hshsbsbus

Answer:

1. Multiply by 3

2. Multiply by 1/3

Step-by-step explanation:

6x - 3y = 3

-2x + y = -14

1. In order to eliminate the x-terms, they would both have to equal the same number with opposite signs (positive and negative). Since we are only touching the second equation, how can we get from 2 to 6? We can multiply 2 by 3 to get to 6 (negative 6 in the end.) This would result as follows:

6x - 3y = 3

-6x + 3y = 42

2. In order to eliminate the y-terns through multiplying with the first equation, we have to figure out how to make 3y into 1y. We can do this by adding its reciprocal, 1/3. 1/3 × 3 = 1. This would result as follows:

2x - y = 1

(x-h)²+(y-k)²=r²

(3-h)²+(3-0)²=5²

h²-6h+9+9=25

h²-6h-7=0 —> (h-7)(h+1)=0

h=7 , h=-1

h=7 —> (x-h)²+y²=r² —> (x-7)²+y²=25 —>

x²-14x+49+y²=25 —> x²+y²-14x+24=0

h=–1 —> (x-h)²+y²=r² —> (x+1)²+y²=25 —>

x²+2x+1+y²=25 —> x²+y²+2x–24=0

I hope it helped you ^_^

We know

[tex] \\ \sf \longmapsto \: new \: length = length + increased \: length \\ \\ \sf \longmapsto \: new \: length = 11.4 + 2.25 \\ \\ \sf \longmapsto \: new \: length = 13.65in[/tex]

Answer:

19:1

Step-by-step explanation:

There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights. The ratio is 9500:500 or 19:1

The ratio of defective headlights to non-defective headlights will be 19:1.

The Percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.

In mathematics, ratios are used to determine the relationship between two numbers it indicates how many times is one number to another number.

There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights.

The ratio will be calculated as below:-

Ratio = 9500:500

Ratio = 19:1

Therefore, the ratio of defective headlights to non-defective headlights will be 19:1.

To know more about percentages follow

https://brainly.com/question/24304697

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x + y = 32 (1)

3x + 4y = 120 (2)

x = 8; y = 24

Step-by-step explanation:

Total students = 120

Number of groups = 32

If the number of three person groups = x

Number of four person groups = y

write a system of equations that models this situation

x + y = 32 (1)

3x + 4y = 120 (2)

From (1)

x = 32 - y

Substitute x = 32 - y into (2)

3(32 - y) + 4y = 120

96 - 3y + 4y = 120

- 3y + 4y = 120 - 96

y = 24

Substitute y = 24 into (1)

x + y = 32

x + 24 = 32

x = 32 - 24

x = 8

x = 8; y = 24

tienees que fijartelos extrreemos

Answer:

B.

Step-by-step explanation:

Other equations don't have any value of x.

Answer:

Because if you see.. The component of x will get canceled in each of the other 3 options.. ( 2x - 2x) which means no solution.. In option B.. 2x + 2x will give 4x..= 31-31 = 0..

-------------------------

Hope it helps...

Have a great day!!

Answer:

[tex]y = \boxed0[/tex]

Step-by-step explanation:

we are given a sin function

[tex] \displaystyle h(x) = - 4 \sin(x -\pi /4) [/tex]

we want to figure out the midline of the function graphically The midline of a sinusoidal function is the horizontal line that passes exactly in the midline of its extreme value however since we a function recall that,

[tex] \displaystyle f(x) = a \sin(bx -c) + d[/tex]

where the midline is

to figure out the midline rewrite the function

[tex] \displaystyle h(x) = - 4 \sin(x -\pi /4) + 0[/tex]

therefore the midline is

[tex]y = \boxed0[/tex]

Not enough information to solve..... Please make your question more clear

Answer:

bka bla bla bla sorry I newbie

Answer:

(-3,-6) and (-3,2)

Step-by-step explanation:

A line with an undefined slope is vertical. In this case it must have x coordinates equal to -3

Answer:

The last answer

Step-by-step explanation:

We can check

For example,

a5=-6×a4

a5=-6×(-216)

a5=1296

Given:

Diameter of the tennis ball = 14 inches.

Three tennis balls are fit in a cylindrical tennis ball cane.

To find:

The volume of air left between the balls and the cane​.

Solution:

Diameter of the tennis ball = 14 inches.

Radius of the tennis ball = 7 inches

Radius of tennis ball is equal to radius of cane. So,

Radius of the cane = 7 inches

Height of cane is:

[tex]3\times 14=42[/tex] inches

Volume of a ball is:

[tex]V_1=\dfrac{4}{3}\pi r^3[/tex]

Where, r is the radius of the ball.

So, the volume of 3 ball is:

[tex]V_2=3\times V_1[/tex]

[tex]V_2=3\times \dfrac{4}{3}\times \dfrac{22}{7}\times (7)^3[/tex]

[tex]V_2=4312[/tex]

Volume of the cane is:

[tex]V_3=\pi r^2h[/tex]

Where, r is the radius of the cane and h is the height of the cane.

[tex]V_3=\dfrac{22}{7}\times (7)^2\times 42[/tex]

[tex]V_3=6468[/tex]

Now, the volume of air left between the balls and the cane​ is:

[tex]V=V_3-V_2[/tex]

[tex]V=6468-4312[/tex]

[tex]V=2156[/tex]

Therefore, the volume of air left between the balls and the cane​ is 2156 cubic inches.

Answer:

22

Step-by-step explanation:

The centroid divides a median in two parts that have this ratio = 1/3 and 2/3

In particular the part between the vertex and the centroid is 2/3 of the median.

So we have:

XN = (33 * 2)/3 = 22

Solution :

Given :

Principal amount, P = Rs. 1000

Time period = 12 months

The maturity value = Rs. 12,715

We know that,

[tex]$ SI = \frac{PTR}{100}$[/tex]

[tex]$SI = 1000 \times \frac{n(n+1)}{2 \times 12} \times \frac{R}{100}$[/tex]

[tex]$SI = 1000 \times \frac{12(12+1)}{2 \times 12} \times \frac{R}{100}$[/tex]

SI = 65 R

So we know,

maturity value = principal amount + SI

12715 = 1000 + 65 R

65 R = 12715 - 1000

65 R = 11715

R = 18%        

So the rate is 18%

Answer:

[tex]R=11\%[/tex] p.a.

Step-by-step explanation:

Given:

the principal amount deposited each month, [tex]P=Rs. 1000[/tex]

amount after maturity of one year, [tex]A=Rs. 12715[/tex]

We have the formula as:

[tex]I=\frac{PR}{100}\times\frac{T(T+1)}{2\times 12}[/tex]

where:

R = rate of interest per annum

T = time in months

[tex]A-12P=\frac{PR}{100}\times\frac{T(T+1)}{2\times 12}[/tex]    [since the principal is deposited each month]

[tex]715=\frac{1000\times R}{100}\times \frac{12\times 13}{24}[/tex]

[tex]R=11\%[/tex] p.a.

Answer:

please send the pic again clearly

Answer:

I hope it will help you

Step-by-step explanation:

thank u

Answer:

I don't know how to do please let me I will try solve the question

Answer:

x=6

pqs=82

sqr=59

Step-by-step explanation:

13x + 4 + 10x - 1 = 141

23x + 3= 141

23x = 136

x = 136/23 = 6

~~~~~~~~~~~~~~~

pqs = 13x + 4  = 13(6) + 4 = 78+4 = 82

sqr =  10x - 1 = 10(6)-1 = 60 - 1 = 59

Answer:

x = 6

Angle PQS is 82

Angle SQR is 59

Step-by-step explanation:

13x + 4 + 10x - 1 = 141

Group like terms : 23x + 3 = 141

Subtract 3 from both sides to get 23x = 138

Divide both sides by 23 to get x = 6

Angle PQS: Plug 6 into x  for 13x + 4 = 13 (6) + 4 = 82

Angle SQR: Plug 6 into x for 10x - 1 = 10 (6) -1 = 59

Answer:

A. x = 4

Step-by-step explanation:

[tex]7x-2(x-10)=40\\7x-2x+20=40\\5x+20=40\\5x=20\\x=4[/tex]