the answer is 1024 because 7²+25²=b²
factor out the square which gives you
(7+25)²=b²
32²=b²
squaring 32 gives 1024
Answer:
24 units
Step-by-step explanation:
i just took the quiz
Find the equation of the line through point (2,2) and parallel to y=x+4. Use a forward slash (i.e.”/“) for fractions (e.g. 1/2 for
Answer:
The equation of the line is, y = x
Step-by-step explanation:
The constraints of the required linear equation are;
The point through which the line passes = (2, 2)
The line to which the required line is parallel = y = x + 4
Two lines are parallel if they have the same slope, therefore, we have;
The slope of the line, y = x + 4 is m = 1
Therefore, the slope of the required line = 1
The equation of the required lime in point and slope form becomes;
y - 2 = 1 × (x - 2)
∴ y = x - 2 + 2 = x
The equation of the required line is therefore, y = x
8. Find an equation in standard form for the ellipse with the vertical major axis of length 16 and minor axis of length 4
Hello,
If center is (0,0)
x²/a²+y²/b²=1 for a half horizontal axis of a, and a half vertical axis of b
Here
a=2 ==> a²=4
b=8 ==> b²=64
[tex]\boxed{\dfrac{x^2}{4}+ \dfrac{y^2}{64}=1}\\[/tex]
Where do i move the graph (new points)?
Answer:
l
Step-by-step explanation:
Find the missing side of the right triangle if two sides are 6, and 10
WILL MARK BRAINLIEST
Please help solve problems with common tangents.
Thank you.
Answer:
sorry I don't know but can u PLEASE MARK ME AS BRAINLIEST.
Step-by-step explanation:
.......
===========================================================
Explanation:
Let's start with what the hint gives us. So the first sub-goal is to prove triangle ABE is similar to triangle DCE.
Since points A and D are points of tangency, this means the radii of each of those circles is perpendicular to the common internal tangent. So angles EAB and EDC are 90 degrees each.
Due to the vertical angle theorem, we also know that angles AEB and DEC are the same (we don't know the measure but we know they're equal angles).
So we have two pairs of congruent corresponding angles between the triangles, which is sufficient to let us use the AA (angle angle) similarity theorem. Therefore, the triangles have been proven to be similar. Triangle DCE is a reduced scaled down copy of triangle ABE. Or in reverse, triangle ABE is an enlarged copy of triangle DCE.
-----------------------
Since the triangles are similar, we can form the proportion below and solve for x
AB/AE = DC/DE
x/18 = 4/6
x*6 = 18*4 .... cross multiplication
6x = 72
x = 72/6
x = 12
Therefore, segment AB is 12 units long, and this is the radius of circle B.
1.) What is the domain and range of the function in the graph?
2.) What is the average rate of change over the interval [1, 0]?
Answer:
Domain → (-∞, ∞)
Range → (-2, ∞)
Step-by-step explanation:
1). Domain of a function is defined by the input values (set of x-values) and Range of the function is defined by the output values (set of y-values).
From the graph attached,
Function is defined for all real values of x.
Therefore, domain of the function will be (-∞, ∞).
On y-axis values of the function vary from -2 (excluding 2) to positive infinity.
Therefore, range of the function will be (-2, ∞).
2). Average rate of change of a function in the interval (a, b) is defined by,
Average rate of change = [tex]\frac{f(b)-f(a)}{b-a}[/tex]
By using this expression we can find the average rate of change in the given interval.
Please give the correct interval for which the average rate of change is to be calculated.
Can someone help me with this math homework please!
Answer:
DOMAIN
input values belong to domainset of values for the independent variable is called the domainRANGE
output values belong to range set of values for the dependant variable is called the rangePls help ASAP
Compare and contrast how to graph: x=2 and y= -4
Answer:
plotting x = 2
see the x- axis look for the point x = 2(on right side of the origin ). Mark that point and draw a straight line parallel to the y- axis.
This is the graph of x = 2
plotting y = -4
see the y- axis and then look for the point y= -4 (that must be 4 units below the origin). Mark that point and draw a straight line parallel to the x- axis.
This is the graph of y = -4
we see that, the graph x = 2 is parallel to the y-axis whereas the graph y = -4 is parallel to the x- axis.
The incubation time for Rhode Island Red chicks is normally distributed with mean of 22 days and standard deviation of approximately 3 days. Of 1000 eggs are being incubated, how many chicks do we expect will hatch in 19 to 28 days
Answer:
We should expect 818 chicks to hatch in 19 to 28 days
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with mean of 22 days and standard deviation of approximately 3 days.
This means that [tex]\mu = 22, \sigma = 3[/tex]
Proportion between 19 and 28 days:
p-value of Z when X = 28 subtracted by the p-value of Z when X = 19.
X = 28
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{28 - 22}{3}[/tex]
[tex]Z = 2[/tex]
[tex]Z = 2[/tex] has a p-value of 0.977.
X = 19
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{19 - 22}{3}[/tex]
[tex]Z = -1[/tex]
[tex]Z = -1[/tex] has a p-value of 0.159.
0.977 - 0.159 = 0.818
Out of 1000:
0.818*1000 = 818
We should expect 818 chicks to hatch in 19 to 28 days
Help please... What is the measurement of arc AC?
Answer:
D) 88 degrees
Step-by-step explanation:
Angle ABC is 1/2Arc AC (Inscribed angle theorem)
Someone to give me the answer on the number line please
Answer:
Step-by-step explanation:
Equation for the total volume of the bucket has been given as,
V = 4 + 2t
Here V = Total volume
t = elapsed time
Table for the input-output values,
t 0 1 2 3 4
V 4 6 8 10 12
Therefore, line passing through the given points in the table will be the graph for the equation.
Help pls I’ll mark you brainliest
Answer:
Step-by-step explanation:
If the 2 lines are parallel
then x = 70 cos ( alternate interior angle)
but if not sorry man I just in grade 9 its my best effort
Really sorry. <3
:(
Which of the following inequalities matches the graph?
Answer:
second one
Step-by-step explanation:
just read where the purple line finishes on the x axis, in this case it’s 5 so it’s greater than 5 or equal to it.
do linear relationships have a constant rate of change
Answer:
Yes my son they do so yeah
Step-by-step explanation:
Cuz I know
Dose 4(x+1)= 3x+4 have a solution
Answer:
x = 0
Step-by-step explanation:
First, multiply 4 by x+1
4x + 4 = 3x + 4
Subtract 3x on both sides
x + 4 = 4
Subtract 4 from both sides
x =
this is x = 0, since x = nothing.
Answer:
x=0
Step-by-step explanation:
4(x+1)= 3x+4
Distribute
4x+4 = 3x+4
Subtract 3x from each side
4x-3x+4 =3x-3x+4
x+4 = 4
Subtract 4 from each side
x+4-4 = 4-4
x=0
Use the equation of the water level of the river represented by the equation y = −4x + 170, where x represents the number of years and y represents the total feet. What points are located on the line? Check all that apply. (170, 0) (0, 170) (12, 126) (50, 30) (5, 150) (60, –70)
Answer:
(0, 170) (5, 150) (60, -170)
Step-by-step explanation:
Plug each x value into the equation. The point is located on the line if the y values match.
Ex. -4 (170) + 170 = -510 this point is not on the line
-4 (0) + 170 = 170 this point is on the line because it is a "true" statement
Answer:
(0, 170) (5, 150) (60, -170)
Step-by-step explanation:
HELP I AM TIMED. Determine whether the equation is an identity or not an identity.
Answer:
It is not an identityStep-by-step explanation:
There are 10 common trig identities which I am aware of.
Some are in the image attached
The first image is known as b
Basic Identities
The second are known as Trigonometric / Pythagorean Identities .
The third : Co-function identities
and many more.
I'm only allowed to post five images so that's all I have.
A number cube has faces numbered 1 to 6.
What is true about rolling the number cube one time?
Answer:
All numbers have an equal chance of being landed on.
A small bag can hold 40 packets of crackers and a large bag can hold 90
packets of crackers. If the total number of bags exceeds 300 and the total
number of packets of crackers exceeds 1500, represent the situation using a
system of linear inequalities.
Answer:
s + l > 300
40 * s + 90 * l > 1500
Step-by-step explanation:
Let's say the amount of small bags is equal to s and the amount of large bags is equal to l.
The total amount of bags is equal to the sum of the small bags and large bags, as there can only be small or large bags. Therefore, the total amount of bags is equal to s + l. As the total amount of bags is greater than 300, we can write
s + l > 300
Next, the total number of packets of crackers exceeds 1500. We can find the total number of packets based on the amount of small and large bags. Because each small bag holds 40 packets, we can say that the amount of packets in small bags is equal to 40 * s. Similarly, the total amount of packets in large bags is equal to 90 * l. Therefore, the total amount of packets is equal to
40 * s + 90 * l
and since the total number of packets is greater than 1500, we can say
40 * s + 90 * l > 1500
Apply the distributive property to create an equivalent expression.
\dfrac15(15+10k) =
5
1
(15+10k)=start fraction, 1, divided by, 5, end fraction, left parenthesis, 15, plus, 10, k, right parenthesis, equals
Answer:
3 + 2k
Step-by-step explanation:
Given:
1/5(15 + 10k)
= (1/5 * 15) + (1/5 * 10k)
= (1 * 15)/5 + (1 * 10k)/5
= 15/5 + 10k/5
= 3 + 2k
Therefore,
1/5(15 + 10k) = 3 + 2k
The equivalent expression is 3 + 2k
The value of -9 is __ than the value of -12 because -9 is to the __of -12 on the number line.
Less
Or
Greater
Answer:
Step-by-step explanation:
-9 is greater than the value of -12 because -9 is to the right of -12 on the number line.
An arithmetic sequence follows a specific pattern where a number is _____________ to get from one term to the next.
Answer:
Added
Step-by-step explanation:
For example, take the arithmetic sequence of 3, 5, 7, 9...
Here, the number that gets us from the first number to the second (from 3 to 5), is 2. Meaning, we need to add 2 to 3 in order to get 5. I believe that makes "addition" or "added" the answer. Please let me know if I misunderstood and I will change my answer! Thank you!
Answer:
added or subtracted
Step-by-step explanation:
Solve for x, then choose
the correct graph.
- 3x > 12
answer:
-4
Step-by-step explanation:
-3x>12
x<-4
the correct graph is graph b
Find the value of "x" Wrong answer will be reported and explain please
Answer:
x = 20
Step-by-step explanation:
The consecutive angles in a parallelogram are supplementary, sum to 180°
5x + 4x = 180
9x = 180 ( divide both sides by 9 )
x = 20
Answer:
The value of x is 40⁰.
Step-by-step explanation:
5x + 4x = 360⁰
DUE TO THE SUM OF QUADRATIC ANGLE.
if <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO
Answer:
<BCO = <BAO = 20degrees
Step-by-step explanation:
If <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO
To get <BAO and <BCO, we need to get <AOC first.
From the figure, it can be seen that triangle ABC is an isosceles trinagle. Hence;
<BAC + <BCA + 100 = 180
Since <BAC = <BCA
<BAC + <BAC = 180 - 100
2<BAC = 80
<BAC = 80/2
<BAC = 40
Also;
<BAO = <BCO and <BAO = <BAC/2
<BAO = 40/2 = <BCO
Hence <BCO = <BAO = 20degrees
Please help me with this one
Answer:
2×5×7+2×5×2+2×7×2
70+20+28
108cm^2
[tex] \huge\boxed{\mathfrak{Answer}}[/tex]
[tex]l = 5 \: cm \\ w = 2 \: cm \\ h = 7 \: cm[/tex]
The formula to find SA => 2lh + 2lw + 2hw
[tex]SA => 2lh + 2lw + 2hw \\ = 2 \times 5 \times 7 + 2 \times 5 \times 2 + 2 \times 7 \times 2 \\ = 70 + 20 + 28 \\ = 118 \: \: cm {}^{2} [/tex]
=> The surface area of the rectangular prism is 118 cm².
What is the measure of angle R?
O 37°
O 53°
O 90°
O 97°
HELP PLEASE
The measure of the angle ∠R in the right-angle triangle will be 37°. Then the correct option is A.
What is the triangle?The polygonal shape of a triangle has a number of sides and three independent variables. Angles in the triangle add up to 180°.
We know that the radius of the circle and the tangent line of the circle will intersect at the right angle which is 90°.
And the angles of the triangle will be supplementary angles. Then the equation is given as,
∠P + ∠Q + ∠R = 180°
53 + 90° + ∠R = 180°
∠R = 37°
The measure of the angle ∠R in the right-angle triangle will be 37°. Then the correct option is A.
More about the triangle link is given below.
https://brainly.com/question/25813512
#SPJ7
find 22×28×25×30 in acres?
Answer:
22x 28 x 25 x 30 = 462000
whats are the units.....cm or m
[tex]\huge\text{Hey there!}[/tex]
[tex]\large\textsf{22(28)(25)(30)}\\\large\textsf{22(28) = \bf 616}\\\large\textsf{616(25)(30)}\\\large\textsf{616(25) = \bf 15,400}\\\large\textsf{15,400(30)}\\\large\textsf{ = \bf 462,000}\\\\\\\\\\\\\boxed{\boxed{\large\textsf{Answer: \huge \bf 462,000}}}\huge\checkmark[/tex]
[tex]\large\textsf{Good luck on your assignment and enjoy day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
can someone please help me solve this? thank you!:)
First, we need to set up our two equations. For the picture of this scenario, there is one length (L) and two widths (W) because the beach removes one of the lengths. We will have a perimeter equation and an area equation.
P = L + 2W
A = L * W
Now that we have our equations, we need to plug in what we know, which is the 40m of rope.
40 = L + 2W
A = L * W
Then, we need to solve for one of the variables in the perimeter equation. I will solve for L.
L = 40 - 2W
Now, we can substitute the value for L into L in the area equation and get a quadratic equation.
A = W(40 - 2W)
A = -2W^2 - 40W
The maximum area will occur where the derivative equals 0, or at the absolute value of the x-value of the vertex of the parabola.
V = -b/2a
V = 40/2(2) = 40/4 = 10
Derivative:
-4w - 40 = 0
-4w = 40
w = |-10| = 10
To find the other dimension, use the perimeter equation.
40 = L + 2(10)
40 = L + 20
L = 20m
Therefore, the dimensions of the area are 10m by 20m.
Hope this helps!
Answer:
Width: 10 m
Length: 20 m
Step-by-step explanation:
Hi there!
Let w be equal to the width of the enclosure.
Let l be equal to the length of the enclosure.
1) Construct equations
[tex]A=lw[/tex] ⇒ A represents the area of the enclosure.
[tex]40=2w+l[/tex] ⇒ This represents the perimeter of the enclosure. Normally, P=2w+2l, but because one side isn't going to use any rope (sandy beach), we remove one side from this equation.
2) Isolate one of the variables in the second equation
[tex]40=2w+l[/tex]
Let's isolate l. Subtract 2w from both sides.
[tex]40-2w=2w+l-2w\\40-2w=l[/tex]
3) Plug the second equation into the first
[tex]A=lw\\A=(40-2w)w\\A=40w-2w^2\\A=-2w^2+40w[/tex]
Great! Now that we have a quadratic equation, we can do the following:
Solve for its zeros/w-intercepts.Take the average of the zeros to find the w-variable of the vertex. (The area (A) in relation to the width of the swimming area (w) is what we've established in this equation, and the area (A) is greatest at the vertex. Finding the value of w of the vertex will tell us what the width needs to be for the area to be at a maximum.)Plug this w value into one of the equations to solve for l4) Solve for w
[tex]A=-2w^2+40w[/tex]
Factor out -2w
[tex]A=-2w(w-20)[/tex]
For A to equal 0, w=0 or w=20.
The average of 0 and 20 is 10, so the width that will max the area is 10 m.
5) Solve for l
[tex]40=2w+l[/tex]
Plug in 10 as w
[tex]40=2(10)+l\\40=20+l\\l=20[/tex]
Therefore, the length of 20 m will max the area.
I hope this helps!
look at the image for the question and answers
Answer:
C
Step-by-step explanation:
Answer:
2 units
Step-by-step explanation:
Using the given formula
P = 2(l + w)
= 2([tex]\frac{2}{3}[/tex] + [tex]\frac{1}{3}[/tex] )
= 2(1)
= 2 units