Question 3 of 10
What are the domain and range of the function represented by the table?
х
-5
0
5
10
15
|
у
-1
0
1
2
3
O A. Domain: -5 sxs 15
Range:{-1,0, 1, 2, 3}
O B. Domain: {-5, 0, 5, 10, 15}
Range: -1 sys3
O C. Domain: {-1,0, 1, 2, 3}
Range:{-5, 0, 5, 10, 15}
D. Domain:{-5, 0, 5, 10, 15)
Range:{-1,0, 1, 2, 3}
Answers
Given:
The table of values of a function.
To find:
The domain and range of the given function.
Solution:
Domain: The set of input values of x-values is known as domain.
Range: The set of output values of y-values is known as domain.
From the given table it is clear that x-values are [tex]-5,0,5,10,15[/tex] and the y-values are [tex]-1,0,1,2,3[/tex]. So,
[tex]Domain=\{-5,0,5,10,15\}[/tex]
[tex]Range=\{-1,0,1,2,3\}[/tex]
Therefore, the correct option is D.
The domain and range of the function represented by the table is as follows:
Domain: {-5, 0, 0, 5, 10, 15}Range: {-1, 0, 1, 2, 3}What are domain and range of a function?The domain of a function is the set of input values, x, for which a function is defined. The domain is the input of the function. The domain is the sets of all input value that produces the output value.
The domain are likewise called input . The domain are usually the x values
The set of values the function outputs is termed the range of the function. In a simpler term, the range are the output of the function. The range are usually the y values.
Therefore, the domain and range of the function represented by the table is as follows;
Domain: {-5, 0, 0, 5, 10, 15}Range: {-1, 0, 1, 2, 3}learn more on domain and range here; https://brainly.com/question/25173046
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Step-by-step explanation:
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See attachment
Required
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Answers
Given:
[tex]\cos \theta =\dfrac{3}{5}[/tex]
[tex]\sin \theta <0[/tex]
To find:
The quadrant of the terminal side of [tex]\theta[/tex] and find the value of [tex]\sin\theta[/tex].
Solution:
We know that,
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II: Only sin and cosec are positive.
In Quadrant III: Only tan and cot are positive.
In Quadrant IV: Only cos and sec are positive.
It is given that,
[tex]\cos \theta =\dfrac{3}{5}[/tex]
[tex]\sin \theta <0[/tex]
Here cos is positive and sine is negative. So, [tex]\theta [/tex] must be lies in Quadrant IV.
We know that,
[tex]\sin^2\theta +\cos^2\theta =1[/tex]
[tex]\sin^2\theta=1-\cos^2\theta[/tex]
[tex]\sin \theta=\pm \sqrt{1-\cos^2\theta}[/tex]
It is only negative because [tex]\theta [/tex] lies in Quadrant IV. So,
[tex]\sin \theta=-\sqrt{1-\cos^2\theta}[/tex]
After substituting [tex]\cos \theta =\dfrac{3}{5}[/tex], we get
[tex]\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}[/tex]
[tex]\sin \theta=-\sqrt{1-\dfrac{9}{25}}[/tex]
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[tex]\sin \theta=-\sqrt{\dfrac{16}{25}}[/tex]
[tex]\sin \theta=-\dfrac{4}{5}[/tex]
Therefore, the correct option is B.
20 BRLAIFAST
NELS
PURCHASE
BAUNE OF
CUT CARD IN
COUPS
50
Jimmy was given a gift card to
his favorite breakfast restaurant.
What equation represents the
balance of the gift card in
dollars, y, when x amount of
breakfast meals are purchased?
35
20
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5
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From the given figure, We can notice that :
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⇒ ∠BCA = 180° - 110°
⇒ ∠BCA = 70°
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Answers
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------------------------
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Brainliest please
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Answers
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Answer:
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Step-by-step explanation:
One way of doing this problem is to start by reducing the first fraction, 5/25, obtaining 1/5. Then
1 y
---- = -----
5 30
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Answers
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Questions such as these usually involve quite simple calculations, but they are important in being able to convert a scenario described in words into math calculations.
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The shirts all cost the same price.
The cost of each shirt was: 111 ÷ 6 = $ 18.50
Answer:
Each shirt was 18.50
Step-by-step explanation:
The total cost of the 6 shirts was 25+86 = 111
Divide the total by 6 to find the cost of each shirt
111/6 =18.5
Each shirt was 18.50
to the girl who helped me <3 please help me again.
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15 POINTS FOR WHO WILL ANSWER
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