Question 7 (2 points)
A survey asked 1,000 people if they invested in Stocks or Bonds for retirement. 700
said they invested in stocks, 400 said bonds, and 300 said both.
How many invested in stocks or bonds?
Note: consider making a Venn Diagram to help solve this problem.
300
500
800
100

Answer:j+309=313

Step-by-step explanation:

313-309=4

J=4

In respοnse tο the questiοn, we may say that As a result, FHJ stοck has equatiοn highest cοefficient οf variatiοn, with a value οf arοund 4.33%.

In mathematics, an equatiοn is a statement that expresses the equality οf twο expressiοns. Equatiοn is made up οf twο sides that are jοined by the algebraic symbοl (=). Fοr example, in this argument, it is asserted that "2x + 3 = 9" denοtes that "2x plus 3" equals the number "9".

Equatiοn sοlving is the prοcess οf determining the value(s) οf the variable(s) required fοr the equatiοn tο be true. There are many different kinds οf equatiοns, such as regular and nοnlinear οnes with οne οr mοre elements. This fοrmula raises the variable x tο the secοnd pοwer: "x² + 2x - 3 = 0." Lines are used in the study οf mathematics in the fields οf algebra, calculus, and geοmetry.

The cοefficient οf variatiοn (CV) represents the standard deviatiοn as a percentage οf the mean and is a relative measure οf variability. It is cοmputed as fοllοws:

CV = (standard deviatiοn / mean) multiplied by 100%

Tο determine which οf the three stοcks has the highest cοefficient οf variatiοn, we must cοmpute the CV fοr each and cοmpare the results.

Fοr ACE inventοry:

CV = (1.5 / 37.03) x 100% ≈ 4.05%

In the case οf FHJ stοck:

CV = (2.62 / 60.55) x 100% ≈ 4.33%

In the case οf LMP stοck:

CV = (3.06 / 124.9) x 100% ≈ 2.45%

As a result, FHJ stοck has the highest cοefficient οf variatiοn, with a value οf arοund 4.33%.

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In the word problem,

a)Gallons per minute change is -2/3 gallons per minute

b) 7.5 minutes to drain the other 5 gallons

c)The tank was full 4 1/2 minutes before Jada arrived.

What is word problem?

Word problems are often described verbally as instances where a problem exists and one or more questions are posed, the solutions to which can be found by applying mathematical operations to the numerical information provided in the problem statement. Determining whether two provided statements are equal with respect to a collection of rewritings is known as a word problem in computational mathematics.

a) Gallons per minute change is -2/3 gallons per minute  since it decreases by 2 gallons in 3 minutes.

b)  we have 5 gallons and lose 2/3 gallons per minute

=> (2/3 gal/minute)(x minutes) = 5 gallons

=> x = 5(3/2) = 15/2 = 7.5 minutes to drain the other 5 gallons

c)  There was 10 gallons when the tank is full . That is 3 gallons more than the 7 gals there when Jada arrived.

=>  (2/3)(x) = 3

=> x = 3(3/2) = 9/2 = 4 1/2 minutes

The tank was full 4 1/2 minutes before Jada arrived.

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Sacramento, California's electricity demand on a scorching summer day is depicted in a function graph. The domain is 24 hours of a day.

The site is available around-the-clock.

One thousand two hundred megawatts are consumed at eight in the morning.

The hours between 4:00 and 6:00 pm saw the highest electricity use, while 4:00 am saw the lowest use.

It would be 1,900 megawatts for f (12).

From 4 am to 5 pm, usage rises, and from 5 pm to 4 am, it falls.

Because each point on the graph reflects a different megawatt usage, the graph is a function. As this graph of electricity usage illustrates, the domain would be available throughout the entire day.

At 8 a.m., these megawatts are used:

= 1, 300 - ( 200 / 2 )

equal to 1,200 megawatts

As people get ready for work and leave for work, we can observe an increase in power demand from 4 am to 5 pm, but a reduction from 5 pm to 4 am.

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Therefore, the equation of the tangent line at (5,f(5)) is y = 18x - 65.

In mathematics, the slope of a line is a measure of its steepness or incline, usually denoted by the letter m. It describes the rate of change of a line in the vertical direction compared to the horizontal direction. The slope of a line can be positive, negative, zero, or undefined, depending on the angle it makes with the horizontal axis. The slope of a line is commonly calculated as the ratio of the change in the y-coordinates to the change in the x-coordinates between any two points on the line.

Here,

(A) The slope of the secant line joining (2,f(2)) and (7,f(7)) is given by:

slope = (f(7) - f(2)) / (7 - 2)

We can find f(7) and f(2) by substituting 7 and 2, respectively, into the function f(x):

f(7) = 7² + 8(7) = 49 + 56 = 105

f(2) = 2² + 8(2) = 4 + 16 = 20

Substituting these values into the formula for the slope of the secant line, we get:

slope = (105 - 20) / (7 - 2) = 85 / 5 = 17

Therefore, the slope of the secant line joining (2,f(2)) and (7,f(7)) is 17.

(B) The slope of the secant line joining (5,f(5)) and (5+h,f(5+h)) is given by:

slope = (f(5+h) - f(5)) / (5+h - 5) = (f(5+h) - f(5)) / h

We can find f(5) and f(5+h) by substituting 5 and 5+h, respectively, into the function f(x):

f(5) = 5² + 8(5) = 25 + 40 = 65

f(5+h) = (5+h)² + 8(5+h) = 25 + 10h + h² + 40 + 8h = h² + 18h + 65

Substituting these values into the formula for the slope of the secant line, we get:

slope = ((h² + 18h + 65) - 65) / h = h² / h + 18h / h = h + 18

Therefore, the slope of the secant line joining (5,f(5)) and (5+h,f(5+h)) is h+18.

(C) The slope of the tangent line at (5,f(5)) is equal to the derivative of the function f(x) at x=5. We can find the derivative of f(x) as follows:

f(x) = x² + 8x

f'(x) = 2x + 8

Substituting x=5, we get:

f'(5) = 2(5) + 8 = 18

Therefore, the slope of the tangent line at (5,f(5)) is 18.

(D) The equation of the tangent line at (5,f(5)) can be written in point-slope form as:

y - f(5) = m(x - 5)

where m is the slope of the tangent line, which we found to be 18. Substituting the values of m and f(5), we get:

y - 65 = 18(x - 5)

Simplifying, we get:

y = 18x - 65

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Answer:

30 pounds

Step-by-step explanation:

Since the jumper costs 50 pounds, the decimal for the number will be:

50.

To find ten percent of the number, you move the decimal one time to the LEFT.

Therefore, 10% of 50 pounds will be 5 pounds. To find 40%, we simply will multiply the 10% amount by 4.

40% of 50 will be:

20

Therefore, the jumper will have 20 pounds off.

Since the original cost is 50 pounds, we simply will just subtract 50 - 20:

50 - 20 = 30

The jumper will cost 30 pounds with the sale deal.

In order to see the school of fish, the scuba diver descended to a depth of 14 feet below sea level.

Hοw far sοmething stretches is described by the cοncept οf depth. The pοοl has a six-fοοt depth. Unknοwn is the well's depth. We can use the fοllοwing equatiοn tο determine the scuba diver's initial depth:

Initial depth = Final depth + Depth Change The scuba diver's change in depth is positive because he rose f feet (positive because he went up) and ended up 16 feet below the surface. Therefοre:

initial depth = 16 + f - 30 initial depth.

Simplifying the phrase:

Original depth = -14 + f

The scuba diver reached his initial depth there after descended another 14 feet below sea level to observe the school of fish.

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Questions-

A scuba diver was 30 feet below sea level when he ascended f feet to a depth of 16 feet below sea level to see a school of fish. what is her new elevation now?

a) The sum of x and 4 equals 7: x + 4 = 7

b) The difference of y and 5 equals 4: y - 5 = 4

c) Two times x equals 10: 2x = 10

d) Two times y added to 3 equals 9: 2y + 3 = 9

f) If y > 3 + 2 or if 3 = y - 2 then y is smaller than y by 2

An equation is a statement in mathematics that two expressions are equivalent. It has two sides that are divided by the equals sign (=). One or more terms, such as integers, variables, constants, and mathematical operations like addition, subtraction, multiplication, division, and exponentiation, may be included on each side of the equation.

a) The sum of x and 4 equals 7:

x + 4 = 7

b) The difference of y and 5 equals 4:

y - 5 = 4

c) Two times x equals 10:

2x = 10

d) Two times y added to 3 equals 9:

2y + 3 = 9

e) If x exceeds 2 by 1, then either x = 3 or x > 2 + 1.

f) If 3 is smaller than y by 2 then either y > 3 + 2 or 3 = y - 2

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Answer:

We have two equations:

√x +2y^2 = 15 ----(1)

√4x - 4y^2=6 ----(2)

Let's solve for x:

From (1), we have:

√x = 15 - 2y^2

Squaring both sides, we get:

x = (15 - 2y^2)^2

Expanding, we get:

x = 225 - 60y^2 + 4y^4

From (2), we have:

√4x = 6 + 4y^2

Squaring both sides, we get:

4x = (6 + 4y^2)^2

Expanding, we get:

4x = 36 + 48y^2 + 16y^4

Substituting the expression for x from equation (1), we get:

4(225 - 60y^2 + 4y^4) = 36 + 48y^2 + 16y^4

Simplifying, we get:

900 - 240y^2 + 16y^4 = 9 + 12y^2 + 4y^4

Rearranging, we get:

12y^2 - 12y^4 = 891

Dividing both sides by 12y^2, we get:

1 - y^2 = 74.25/(y^2)

Multiplying both sides by y^2, we get:

y^2 - y^4 = 74.25

Let z = y^2. Substituting, we get:

z - z^2 = 74.25

Rearranging, we get:

z^2 - z + 74.25 = 0

Using the quadratic formula, we get:

z = (1 ± √(1 - 4(1)(74.25))) / 2

z = (1 ± √(-295)) / 2

Since the square root of a negative number is not real, there are no real solutions for z, which means there are no real solutions for y and x.

Therefore, the answer is "no solution".

Answering the presented question, we may conclude that This greater expressions scale makes it easier to see the variations between the ratings of the three college students in a extra correct and informative way.

In mathematics, an expression is a collection of integers, variables, and complex mathematical (such as arithmetic, subtraction, multiplication, division, multiplications, and so on) that describes a quantity or value. Phrases can be simple, such as "3 + 4," or complicated, such as They may also contain functions like "sin(x)" or "log(y)". Expressions can be evaluated by swapping the variables with their values and performing the arithmetic operations in the order specified. If x = 2, for example, the formula "3x + 5" equals 3(2) + 5 = 11. Expressions are commonly used in mathematics to describe real-world situations, construct equations, and simplify complicated mathematical topics.

The difference in look between the two charts is due to the choice of the scales on the x and y-axes. In the left chart, the y-axis starts offevolved at 800 and has a range of only 200 points, whilst the x-axis starts offevolved at 1300 and has a vary of 200 points. This compressed scale makes the variations between the ratings of the three students appear larger than they absolutely are.

On the other hand, the proper chart has a y-axis that starts at zero and has a vary of 800 points, whilst the x-axis begins at 1200 and has a range of 800 points. This greater expanded scale makes it easier to see the variations between the ratings of the three college students in a extra correct and informative way.

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The cost of producing an additional 200 items due to increased demand is 180,000 Botswana Pula.

Marginal cost is the additional cost incurred by producing one additional unit of a good or service. In other words, it is the cost of producing one more unit of output.

The marginal cost (MC) equation given is MC = 2x - 100, where x is the number of units produced.

To find the cost of producing an additional 200 items due to increased demand, we need to calculate the marginal cost of producing these 200 items and then multiply that by 200.

The marginal cost of producing 200 additional items is given by:

MC(200) = 2(300 + 200) - 100

MC(200) = 2(500) - 100

MC(200) = 900

So the marginal cost of producing 200 additional items is 900. To find the total cost of producing these 200 items, we can simply multiply the marginal cost by the number of units produced, which in this case is 200:

Total cost = MC(200) × 200

Total cost = 900 × 200

Total cost = 180,000

Therefore, the cost of producing an additional 200 items due to increased demand is 180,000 Botswana Pula.

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The perimeter of the pond is 2.92 meters.

A right-angled triangle is a triangle in which one of the angles measures exactly 90 degrees, also known as a right angle.

The side opposite the right angle is called the hypotenuse, and the other two sides are called the legs.

The perimeter of a right-angled triangle is the sum of the lengths of its three sides.

Here we have

The Hypotenuse of the triangle is 1.46 m    

The angle between hypotenuse and perpendicular height = 73°

From triagonometric ratios,

=> cos A = Perpendicular height/ Hypotenuse.

=> cos (73) = Perpendicular height/1.46

=> Perpendicular height = 1.46 × 0.29 = 0.42 m

As we know from Pythagoras' theorem,

Hypotenuse² = side² + side²    

Side = √Hypotenuse² - side²  

= √[(1.46)²- (0.42)²]  = 1.04

Therefore, the sides of the pond are 1.46 m, 0.42 m, and 1.04

Hence, perimeter of the pond =  1.46 + 0.42 + 1.04 = 2.92 meters  

Therefore,

The perimeter of the pond is 2.92 meters.

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The complete Question is given below

Answer:

The formula to calculate the amount of loan with flat rate interest is:

Amount = Principal + (Principal x Rate x Time)

Where,

Principal = the amount of loan

Rate = the interest rate per year

Time = the time period in years

Given,

Principal = K40,000.00

Rate = 9% per year

Time = 2.5 years

Substituting the values in the formula, we get:

Amount = K40,000.00 + (K40,000.00 x 0.09 x 2.5)

Amount = K40,000.00 + K9,000.00

Amount = K49,000.00

Therefore, the amount he will pay the bank is K49,000.00.

10% chance of contamination by a particular: It's not clear what random variable is being referred to here, but if it's the probability of contamination.

In general terms, a distribution refers to the way something is divided or spread out. In the context of statistics and probability theory, a distribution is a mathematical function that describes the likelihood of different possible outcomes or values that a variable can take.

There are various types of distributions, but some of the most commonly used ones include:

Normal distribution: also known as the Gaussian distribution, it is a continuous probability distribution that is symmetrical around the mean, with most of the data falling within one standard deviation of the mean.

Binomial distribution: this is a discrete probability distribution that describes the likelihood of a certain number of successes in a fixed number of trials.

Poisson distribution: another discrete probability distribution that describes the likelihood of a certain number of events occurring in a fixed interval of time or space.

Exponential distribution: a continuous probability distribution that describes the time between events occurring at a constant rate.

Distributions are essential in statistical analysis as they can help to understand and analyze data, make predictions, and draw conclusions about a population based on a sample of data.

Given by the question.

a. The wages of academician and non-academician workers in UPSI: This random variable can be approximated to a continuous distribution as wages can take on any numerical value within a range. However, it's worth noting that in practice, there may be discrete intervals or categories of wages, in which case a discrete distribution may be more appropriate.

b. The time taken to submit online quiz answer's document: This random variable can also be approximated to a continuous distribution as it can take on any numerical value within a range.

c. The prices of SAMSUNG mobile phones displayed at a phone shop: This random variable can be approximated to a continuous distribution as prices can take on any numerical value within a range.

d. The number of pumps at Shell petrol stations in Perak: This random variable can be approximated to a discrete distribution since the number of pumps can only take on integer values.

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The parabola is passing through (0, 0) and (9, 0).

The locus of a moving point is the location that maintains a constant distance between a stationary point and a predetermined line.

The directrix is a non-moving line, while the focus is a non-moving point.

As you can see, the quadratic variable is not, which modifies the figure's orientation.

This parabola doesn't actually represent a function because it will open horizontally, specifically toward negative infinity, as the graphic linked illustrates.

The vertical line test will reveal that the vertical line in question intercepts the figure in two places, proving that it is not a function.

According to our question-

The equation of the parabola is given below.

y = (3/2)x² - 6x

Then the factor of the equation will be

y = 3x (x / 2 - 3)

Then the zeroes of the function will be

y = 0

x = 0, 9

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Answer:

x = 18

Step-by-step explanation:

Alternate exterior angles are congruent.  Set the equations equal to each other and solve for x.

7x + 11 = 10x - 43  Subtract 7 x from both sides

7x - 7x + 11 = 10x - 7x - 43

11 = 3x - 43  Add 3 to both sides

11 + 43 = 3x -43 + 43

54 = 3x  Divide both sides by 3

[tex]\frac{54}{3}[/tex] = [tex]\frac{3x}{3}[/tex]

18 = x

Helping in the name of Jesus.

The average rate of change on the intervals [0, 3], [3, 5], [5, 7], and [7, 9] are 2, -1.5, 1, and -1.5, respectively.

It expresses how much the function changed per unit on average during that time period. It is computed by taking the slope of the straight line connecting the interval's endpoints on the function's graph.

To calculate the average rate of change for the intervals shown in the graph, we must first determine the slope of the line connecting the endpoints of each interval.

0-3 interval:

Because the interval's endpoints are (0, 1) and (3, 7), the slope of the line connecting them is:

slope = (y change) / (x change) = (7 - 1) / (3 - 0) = 2

pauses [3, 5]:

Because the interval's endpoints are (3, 7) and (5, 4), the slope of the line connecting them is:

slope = (y change) / (x change) = (4 - 7) / (5 - 3) = -1.5

[5–7] Interval:

Because the interval's endpoints are (5, 4) and (7, 6), the slope of the line connecting them is:

slope = (y change) / (x change) = (6 - 4) / (7 - 5) = 1

Interval 7 and 9:

Because the interval's endpoints are (7, 6) and (9, 3), the slope of the line connecting them is:

slope = (y change) / (x change) = (3 - 6) / (9 - 7) = -1.5

As a result, the average rate of change on the intervals [0, 3], [3, 5], [5, 7], and [7, 9] is 2, -1.5, 1, and -1.5.

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From the figure 1. Two line segments are LA and EP. 2. Two rays are EC and AH. 3. Two lines are b and AP.

A line segment having a single endpoint and an infinite length in one direction is known as a ray. A ray's length cannot be determined.

There are two endpoints to a line segment. Every point on the line connecting these endpoints to one another is also included. The length of a line cannot be measured, but the length of a segment can.

An eternally long and thin line is a group of points that stretches in two opposite directions.

From the given figure we observe that,

1. Two line segments are LA and EP.

2. Two rays are EC and AH.

3. Two lines are b and AP.

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Answer:

Step-by-step explanation:

To solve the initial-value problem y''' − 2y'' + y' = 2 − 24ex + 40e5x, y(0) = 1/2, y'(0) = 5/2, y''(0) = −11/2, we first find the characteristic equation by assuming that y = e^(rt):

r^3 - 2r^2 + r = 0

r(r^2 - 2r + 1) = 0

r(r-1)^2 = 0

r = 0, 1, 1

Therefore, the general solution to the homogeneous equation y''' − 2y'' + y' = 0 is:

y_h = c1 + c2e^x + c3xe^x

To find the particular solution to the non-homogeneous equation y''' − 2y'' + y' = 2 − 24ex + 40e5x, we guess a particular solution of the form:

y_p = Ax^2e^5x + Be^x

y_p' = (2Ax + 5Ax^2)e^5x + Be^x

y_p'' = (10Ax^2 + 4Ax + 25Ax^2)e^5x + Be^x

y_p''' = (70Ax^2 + 60Ax + 10A + 25Ax^2)e^5x + Be^x

Substituting these expressions into the original equation, we get:

(70Ax^2 + 60Ax + 10A + 25Ax^2)e^5x + Be^x − 2[(10Ax^2 + 4Ax + 25Ax^2)e^5x + Be^x] + [(2Ax + 5Ax^2)e^5x + Be^x] = 2 − 24ex + 40e5x

Simplifying, we get:

(45Ax^2 + 2Ax − 2)e^5x + Be^x = 2 − 24ex + 40e5x

Equating the coefficients of the like terms on both sides, we get:

45A = 40

2A − 2 = 0

B = 2

Therefore, the particular solution is:

y_p = 8/9 x^2e^5x + 2e^x

The general solution to the non-homogeneous equation is therefore:

y = c1 + c2e^x + c3xe^x + 8/9 x^2e^5x + 2e^x

Using the initial conditions y(0) = 1/2, y'(0) = 5/2, y''(0) = −11/2, we get:

c1 + c2 + 2 = 1/2

c2 + 2c3 + 5/2 = 5/2

2c2 + 10/9 + 10 = -11/2

Solving this system of equations, we get:

c1 = 1/9

c2 = -25/18

c3 = 0

Therefore, the solution to the initial-value problem y''' − 2y'' + y' = 2 − 24ex + 40e5x, y(0) = 1/2, y'(0) = 5/2, y''(0) = −11/2 is:

y = 1/9 - 25/18e^x + 8/9

Answer:

5/3

Step-by-step explanation:

1×3=3

3+2=5

So answer is 5/3

Answer:

470.4 mm

Step-by-step explanation:

Given: the annual rainfall in 2017 in opuwo was 420 mm, the annual rainfall in 2018 was 12% more than in 2017.

First, find 12% of 420 mm:

12% of 420 mm

[tex]\frac{12}{100}[/tex] x 420 mm

1.2 x 420 mm

= 50.4 mm

Then add 50.4 mm to the previous annual rainfall of 420 mm:

50.4 mm + 420 mm

= 470.4 mm

Therefore, the annual rainfall in opuwo in 2018 is 470.4 mm.

Step 1: Arrange the arrays so that A and B are in the same order: A = [ 1 2 4 0 5 6 ], B = [ 7 3 2 5 1 9]

Step 2: To find C = A+B, add each element of A and B together.

C = [1+7, 2+3, 4+2, 0+5, 5+1, 6+9]

C = [8, 5, 6, 5, 6, 15]

Step 3: To find D = A-B, subtract each element of B from A.

D = [1-7, 2-3, 4-2, 0-5, 5-1, 6-9]

D = [-6, -1, 2, -5, 4, -3]

Uri paid a total of $85.47 for the landscaping service including tax and tip.

Taxes are compulsory payments made by a government organisation, whether local, regional, or federal, to people or businesses. Tax revenues are used to fund a variety of government initiatives, such as Social Security and Medicare as well as public infrastructure and services like roads and schools. Taxes are borne by whoever bears the cost of the tax in economics, whether this is the entity being taxed, such as a business, or the final users of the items produced by the firm. Taxes should be taken into consideration from an accounting standpoint, including payroll taxes, federal and state income taxes, and sales taxes.

Given that company charged $74 for the service plus 5% tax.

The tax is 5%, that is:

Tax = 5% of $74 = 0.05 x $74 = $3.70

Cost after tax = $74 + $3.70 = $77.70

Now, tip is 10%:

Tip = 10% of $77.70 = 0.10 x $77.70 = $7.77

Total cost = $77.70 + $7.77 = $85.47

Hence, Uri paid a total of $85.47 for the landscaping service including tax and tip.

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a) The domain and the range of the function are given as follows:

The graph of the function is given by the image presented at the end of the answer.

b) The trip was 5.1875 hours long.

The function for this problem is defined as follows:

g(t) = 23 - 3.2t.

The domain is the set of input values that can be assumed by the function. The time cannot have negative measures, hence the lower bound of the domain is of zero, while the gas cannot be negative, hence the upper bound of the volume is given as follows:

23 - 3.2t = 0

3.2t = 23

t = 23/3.2

t = 7.1875 hours.

The range is given by the set of all output values assumed the function, which are the values of the gas, hence it is [0,23].

The graph is a linear function between points (0, 23) and (7.1875, 0).

At the end of the trip there were 6.4 gallons left, hence the length of the trip is given as follows:

23 - 3.2t = 6.4

t = (23 - 6.4)/3.2

t = 5.1875 hours.

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The surface area of the surface generated by rotating the curve y = x² about the y-axis, and we found that the surface area is approximately 54.33 square units.

In this case, the curve we want to rotate is y = x², and we want to rotate it about the y-axis. To use the formula above, we need to express the equation of the curve in terms of x. Therefore, we need to rewrite y = x² as x = √y.

Next, we need to find the derivative of x = √y with respect to y, which is:

dx/dy = 1/2√y

Substituting this into the formula for the surface area, we get:

Surface Area = 2π ∫[0,4] √y √(1+(1/2√y)²) dy

Simplifying the expression inside the square root, we get:

Surface Area = 2π ∫[0,4] √(y+(1/4)) dy

We can evaluate this integral using the power rule of integration, which gives:

Surface Area = 2π [2/3(y+(1/4))^(3/2)]₀⁴

Simplifying further, we get:

Surface Area = 2π [2/3(17/4)^(3/2)]

Surface Area ≈ 54.33 square units

Therefore, the surface area of the surface generated by rotating the curve y = x² about the y-axis is approximately 54.33 square units.

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Complete Question:

How do you find the area of the surface generated by rotating the curve about the y-axis y = x^2 , 0 ≤ x ≤ 2 ?

The height of the pole is approximately 17.75 meters.

The main trigonometric functions are sine, cosine, and tangent, which are abbreviated as sin, cos, and tan, respectively. They are used to relate the angles of a right triangle to the lengths of its sides. The sine function gives the ratio of the length of the side opposite an angle to the length of the hypotenuse of the triangle. The cosine function gives the ratio of the length of the adjacent side to the length of the hypotenuse. The tangent function gives the ratio of the length of the opposite side to the length of the adjacent side.

Let's denote the height of the pole as h, and let's denote the distance between the pole and the student's original position (due west of the pole) as x.

From the student's original position, we have a right triangle with the pole being the hypotenuse. The angle opposite to the height of the pole is 40°. So, we have:

tan(40°) = h/x

From the student's new position (10 m due south of the original position), we have another right triangle with the pole being the hypotenuse. The angle opposite to the height of the pole is 35°. The distance between the pole and the student's new position is (x+10) meters (the student moved 10 m south). So, we have:

tan(35°) = h/(x+10)

Now we have two equations with two unknowns (h and x). We can solve for x in terms of h from the first equation:

x = h/tan(40°)

Substitute this expression for x into the second equation:

tan(35°) = h/((h/tan(40°))+10)

Simplify and solve for h:

h = (10 tan(35°) tan(40°)) / (tan(40°) - tan(35°)) ≈ 17.75 m

Therefore, the height of the pole is approximately 17.75 meters.

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Answer:

the two numbers are 15 and 35, and their ratio is 3:7, and their difference is 20.

Step-by-step explanation:

Using calculus, we can find the rate of change of area of circle and square that is 83.44 m/sec.

One of the most crucial areas of mathematics that addresses ongoing change is calculus. Calculus is primarily built on the two ideas of derivatives and integrals. The area under the curve of a function is measured by its integral rather than its derivative, which measures the rate of change of the function.

Whereas the integral adds together a function's discrete values over a range of values, the derivative explains the function at a particular point.

Let x be the side of the square and r be the radius of the circle,

If so, the area inside the square but outside the circle is given by:

V = Square area minus Circle area.

hence, area of a square = side² and area of a circle = π(radius)²,

Thus,

V = x² - πr²

Differentiating with respect to time (t)

dV/dt = 2x × dx/dt - 2πr dr/dt

Given,

x = 16

r = 3

dx/dt = 2 m/sec

dr/dt = 1 m/sec

⇒ dV/dt = 2 × 16 × 3 - 2π × 2 × 1

= 96 - 4π

= 96-12.56

≈ 83.44 m/sec

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Answer:

Step-by-step explanation:

This is an example of a hypergeometric distribution problem, where we have a population of 10,000 clock radios with 500 defective ones, and we want to calculate the probability of getting at least one defective radio in a random sample of 10 without replacement.

The probability of getting no defective radios in the sample is:

(9500/10000) * (9499/9999) * (9498/9998) * ... * (9491/9992)

This is because, for the first radio, there are 9500 good radios out of 10,000, and for the second radio, there are 9499 good radios out of 9,999, and so on.

The probability of getting at least one defective radio in the sample is then:

1 - (9500/10000) * (9499/9999) * (9498/9998) * ... * (9491/9992)

which is approximately equal to 0.401.

Therefore, the probability that the entire batch will be rejected is 0.401.