Question is in the image

Answer:

mcd(28,48) = 4

Para encontrar el mcd de 28 y 48:

Los factores de 28 son 28, 14, 7, 4, 2, 1.

Los factores de 48 son 48, 24, 16, 12, 8, 6, 4, 3, 2, 1.

Los factores en común de 28 y 48 son 4, 2, 1, los cuales intersectan los dos conjuntos arriba.

En la intersección de los factores de 28 ∩ factores de 48 el elemento mayor es 4.

Por lo tanto, el máximo común divisor de 28 y 48 es 4.

Hello,

The first transform E1 is the homothetie of center (0,0) and ratio=2

The second transform E2 is the homothetie of center (0,0) and ratio=3/2

P=(3,k)

P'=E1(P)= E1((3,k))=(2*3,2*k)=(6,2k)

P''=E2(P')=E2(6,2k)=(3/2*6,3/2*2*k)=(9,3k)=(9,12)

==> 3k=12

k=4

Answer: ∠p and ∠s, ∠q and ∠r

Step-by-step explanation:

From the lines on the angles indicate which ones are corresponding, for example angles p and s both have 2 lines, while angles q and r both have one line.

The sets of angles are corresponding angles are; ∠p and ∠s, ∠q and ∠r

It can be defined as, corresponding means pair wise angles. Like the right corner angles of two triangles etc. But usually we take them as:

For two similar figures, the pair by pair similar angles of those two similar figures are called corresponding angles. They are of same measurement.

From the lines on the angles indicate which ones are corresponding, for example angles p and s both have 2 lines, while angles q and r both have one line.

We can conclude the sets of angles that are corresponding angles;

∠p and ∠s, ∠q and ∠r

Learn more about  angles here:

https://brainly.com/question/2882938

#SPJ1

Answer:

850/28=30 miles a gallon

Step-by-step explanation:

mark as brainlist

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as [tex]x + 2y\geq 1200[/tex].​

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are [tex]\$600[/tex] a term.

So, the fees for [tex]x[/tex] day students are [tex]\$600x[/tex] a term.

The fees for a boarding student are [tex]\$1200[/tex] a term.

The fees for [tex]y[/tex] boarding student are [tex]\$1200y[/tex] a term.

Total fees for [tex]x[/tex] day students and [tex]y[/tex] boarding student is:

[tex]\text{Total fees}=600x+1200y[/tex]

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

[tex]600x+1200y\geq 720000[/tex]

[tex]600(x+2y)\geq 720000[/tex]

Divide both sides by 600.

[tex]\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}[/tex]

[tex]x+2y\geq 1200[/tex]

Hence proved.

Answer:

16,500

Step-by-step explanation:

Just use a calculator-simple

What do you mean "let me y"?

Answer:

the answer is 16500 or sixteen thousand five hundred

Step-by-step explanation:

:)

Answer:

c: y=(x-1)(x-3)

Step-by-step explanation:

Answer:

329.6=1/3×16.97r

5.66r=329.6/÷5.66

r=58.23

Answer:

g(-2.3) = 3.6

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

g(x) = 2|x| - 1

Step 2: Evaluate

Answer:

(- 1, - 1 )

Step-by-step explanation:

Given the 2 equations

x = 4y + 3 → (1)

2x + y = - 3 → (2)

Substitute x = 4y + 3 into (2)

2(4y + 3) + y = - 3 ← distribute parenthesis and simplify left side

8y + 6 + y = - 3

9y + 6 = - 3 ( subtract 6 from both sides )

9y = - 9 ( divide both sides by 9 )

y = - 1

Substitute y = - 1 into (1) for corresponding value of x

x = 4(- 1) + 3 = - 4 + 3 = - 1

solution is (- 1, - 1 )

Answer:

Answer:

The first choice.

Step-by-step explanation:

3(x + 2) is equal to 3 * x + 3 * 2.

Simplify that, and you would get 3x + 6.

Answer:

A. or 3(x+2) = 3x + 6

Step-by-step explanation:

A. 3(x+2) = 3(x) + 3(2)

               = 3x + 6

Which is correct!.

B. x^2 is nowhere to be found.

C. Doesn't distribute the 3 into the 2 properly.

D.  Doesn't distribute the -3 into the x properly.

Answer:

[tex]slope = \frac{ - 1 - 4}{0 - 2} \\ = \frac{ - 5}{ - 2} \\ = { \tt{ \frac{5}{2} }}[/tex]

Answer:

ok so lets divide 90 by 15 to get 6 so she gets paid 6 per student and that means lisa gets paid 12 so lets just multiply

6*20=120 so mary gets paid 120

and lisa gets paid doable that so 420

but i don't know there base pay so the i can't answer this problem

Hope This Helps!!!

Answer:

Sue candy = 13 - x

Tony candy = 9 + 1/2x

Step-by-step explanation:

Sue candy = 18

Tony candy = 18

Let x = some candy gives to tony

Sue candy = 18 - x

Tony candy = 18 + x

sue then eats five of hers

Sue candy = 18 - x - 5

= 13 - x

tony eats half of his

Tony candy = 1/2(18 + x)

= 18/2 + x/2

= 9 + 1/2x

Expressions for the number of pieces candy sue and tony now have:

Sue candy = 13 - x

Tony candy = 9 + 1/2x

Answer:

a-b  divided into [tex]a^{3} + 0a^{2} b + 0 ab^{2} - b^{3}[/tex]

the reason is that the (a-b) vs (a+b) in the "SOAP"

same, opposite, always a plus the "-" in the "a-b" has to match the

sign between the two cubes

Step-by-step explanation:

Answer:

The removed number is 16

Step-by-step explanation:

Five numbers have a mean of 12.

Now;

Mean = Σx/x

Thus; Σx = 12 × 5 = 60

Now,we are told that if one number is removed, the mean is 11.

Thus;

(60 - x)/4 = 11

60 - x = (11 × 4)

60 - x = 44

x = 60 - 44

x = 16

Thus,the removed number is 16

Answer:

x = -3

Step-by-step explanation:

Here, this is a vertical line

What this mean here is that the x-value remains constant irrespective of the y value

For all the y values, we have a single x-value

so what this mean is to simply locate the x-axis. value and equate it to x

We have this as;

x = -3

Answer:

H

Step-by-step explanation:

lets say the first big square has side s, so the area will be s²

then the side of the small square is s/3, and the area is (s/3)²= s²/3² =s²/9

the area of the smaller square is 1/9 smaller than the area of the big square

Answer:

See Explanation

Step-by-step explanation:

Given

Let

[tex]S \to[/tex] Strawberry

[tex]B \to[/tex] Banana

[tex]S : B = 2 : 3[/tex]

Solving (a):

Complete the table

The table, to be complete, is not given; so, I will generate one myself.

[tex]\begin{array}{cccccc}S & {2} & {3} & {4} & {5} & {6} \ \\ {B} & {3} & {4.5} & {6} & {7.5} & {9} \ \end{array}[/tex]

The table is generated as follows:

[tex]S : B = 2 : 3[/tex]

Multiply by 1.5

[tex]S : B = 2 * 1.5 : 3 * 1.5[/tex]

[tex]S : B = 3 : 4.5[/tex]

Multiply by 2

[tex]S : B = 2*2 : 3*2[/tex]

[tex]S : B = 4 : 6[/tex]

And so on....

In summary, whatever factor is multiplied to S must be multiplied to B; in order to keep the ratio constant

Solving (b): Why the amount are proportion

Because the ratio is constant and it remains unchanged all through.

Answer:

The answer is D.

Step-by-step explanation:

Answer:

(D) 27 - C

Step-by-step explanation:

The "less than" means we are subtracting C from 27, so 27 - C.

Hope it helps (●'◡'●)

Answer:

x = 15, y = 4

Step-by-step explanation:

To solve this, we have to define the triangles first. Since the triangles are congruent by HL, it means that the hypotenuse and the leg of the triangle are defined to be equal. By flipping one of the triangles upsidedown, we can visualize the hypotenuse of the triangles and the leg of the triangles (which are equal).

The two equations are the following:

[tex]x + 1 = 4y[/tex]

[tex]x = y + 11[/tex]

If I add 1 to both sides of the second equation, I get the following equation:

[tex]x + 1 = y + 11 + 1 = y + 12[/tex]

By comparing this new equation with the first one, we will get:

[tex]x + 1 = 4y = y + 12[/tex]

We can ignore x+1 for now since y can not be solved.

[tex]4y = y + 12[/tex]

By subtracting both sides of this equation by y, we will get.

[tex]3y = 12[/tex]

This solves for y, where

[tex]y = 4[/tex]

Now, we can re-use one of the equations, which is

[tex]x = y + 11[/tex]

Now that we know y is 4, we can plug it into this equation.

[tex]x = 4 + 11 = 15[/tex]

Given:

[tex]u=(-1,4)[/tex]

[tex]v=(3,-2)[/tex]

The equation is:

[tex]t=u+v[/tex]

To find:

The ordered pair to represent t in the given equation.

Solution:

We have,

[tex]t=u+v[/tex]

Substituting the given values, we get

[tex]t=(-1,4)+(3,-2)[/tex]

[tex]t=((-1)+3,4+(-2))[/tex]

[tex]t=(-1+3,4-2)[/tex]

[tex]t=(2,2)[/tex]

Therefore, the ordered pair to represent t in the given equation is (2,2).

Answer:

1.-dh/dt  =  5.31*10⁻⁵ m/seg

2.-dh/dt =   1.99*10⁻⁵  m/seg

3.-dh/dt  =  1.59*10⁻⁴  m/seg

Step-by-step explanation:PREGUNTA INCOMPLETA NO SE INDICAN LAS FORMAS DE LOS TANQUES.

Asumiremos que los tres tanques son:

el primero cilindro recto     de  Vc = π*r²*h      ( r es radio de la base y h la altura)

el segundo asumiremos que es eliptico recto de Ve = π*a*b*h aqui a y b son los ejes de la elipse y h la altura

El tercero es un cono invertido Vco  = 1/3 *π*r²*h  ( r es el radio de la base.

1.-Caso del cilindro

Vc = π*r²*h

Derivando en ambos miembros de la expresión tenemos:

dV(c) / dt  = π*r²*dh/dt

Sustituyendo

1.5 Lts/seg =  3.14 * (3)²*dh/dt  

1.5/1000 m³/seg  =  28.26 m² dh/dt

1.5/ 28260 m  =  dh/dt

Despejando dh/dt

dh/dt  =  1.5 / 28260    =  5.31*10⁻⁵ m/seg

dh/dt  =  5.31*10⁻⁵ m/seg

2.-La elipse

Ve  = π*a*b*h  

Aplicando el mismo procedimiento tenemos:

DVe/dt  =  1.5 Lts/seg  =  π* 6*4* dh/dt

1.5 /1000   =  75.36 *dh/dt

dh/dt =  1.5 / 75360  m/seg

dh/dt =   1.99*10⁻⁵  m/seg

3. El cono invertido

Vco = (1/3)*π*r²*h

DVco/dt =  (1/3)*π*r²*dh/dt

1.5/1000  =  9.42 *dh/dt

dh/dt  =  1.5/9420

dh/dt  =  1.59*10⁻⁴  m/seg

Answer:

No its doesn't satisfy the equation.

[tex]{ \bf{area = 2(l + w)}} \\ { \tt{48 = 2((x + 10) + (x - 3))}} \\ { \tt{24 = 2x + 7}} \\ 2x = 17 \\ x = 8.5 \\ \\ { \bf{in : \: {x}^{2} + 7x - 78 = 0 }} \\ x = 6 \: \: and \: \: - 13[/tex]

tan=sin/cos so tan=3/5/4/5=3/4

Answer:

SOH CAH TOA

3/5 opposite over hypotenuse

4/5 adjasent over hypotenuse

tan= opposite over adjasent which is 3/4

Step-by-step explanation:

Answer:

Zoe rode [tex]\frac{5}{6}[/tex] of a mile more than she walked.

Step-by-step explanation:

[tex]\frac{11}{12}-\frac{1}{12} =\frac{5}{6}[/tex]

Answer:

.

Step-by-step explanation: