QUICK PLEASE
Factor 2x^2+19x+12

Answer:

400 + .03(250,000) = $7900

Step-by-step explanation:

Answer:

True

Step-by-step explanation:

Each f(x) value increases by 5 so therefore this function would be linear

Hope you understand :)

Answer:

Step-by-step explanation:

[tex]hope \: it \: helps[/tex]

CarryOnLearning

Answer:

[tex]DE \cong GF[/tex]

Step-by-step explanation:

Given

See attachment for quadrilateral

Required

What proves DEFG as isosceles trapezoid

The non-parallel sides of an isosceles trapezoid are similar and equal.

From the attached quadrilateral, the non-parallel sides are: DE and GF

Hence, for DEFG to be an isosceles trapezoid;

[tex]DE \cong GF[/tex]

Answer:DE ≅ GF

Step-by-step explanation:

cause i said so

Answer:

Step-by-step explanation:

If J can paint a room in 3 hours, in 1 hour she gets [tex]\frac{1}{3}[/tex] of the job done.

If A can paint a room in 4 hours, in 1 hour she gets [tex]\frac{1}{4}[/tex] of the job done. We need to find out how long it takes them if they paint together. The equation for this is:

[tex]\frac{1}{3}+\frac{1}{4}=\frac{1}{x}[/tex] where x is the number of hours it takes them to get the job done together. Multiply everything through by 12x to get

4x + 3x = 12 so

7x = 12 and

x = 1.7 hours to get the room painted together.

Answer:

a = 0.0040 m/s², v = 14.4 m/s.

Step-by-step explanation:

Given that,

The distance between Kathmandu and Khanikhola, d = 26 km = 26000 m

Time, t = 1 hour = 3600 seconds

Let a is the acceleration of the bus. Using second equation of motion,

[tex]d=ut+\dfrac{1}{2}at^2[/tex]

Where

u is the initial speed of the bus, u = 0

So,

[tex]d=\dfrac{1}{2}at^2\\\\a=\dfrac{2d}{t^2}\\\\a=\dfrac{2\times 26000}{(3600)^2}\\\\a=0.0040\ m/s^2[/tex]

Now using first equation of motion.

Final velocity, v = u +at

So,

v = 0+0.0040(3600)

v = 14.4 m/s

Hence, this is the required solution.

Answer:

[tex]8^{298} \\8^{3(n-1)+1}[/tex]

Step-by-step explanation:

Answer:

8^298

Step-by-step explanation:

n = 1, 8^(1 + 0 * 3)

n = 2, 8^(1 + 1 * 3)

n = 3, 8^(1 + 2 * 3)

n = 4, 8^(1 + 3 * 3)

The exponent of 8 is 1 added to product of 1 less than the term number multiplied by 3.

n = n, 8^(1 + [n - 1] * 3) = 8^(1 + 3n - 3) = 8^(3n - 2)

For n = 100, the exponent is

3n - 2 = 3(100) - 2 = 300 - 2 = 298

Answer: 8^298

Answer:

65 solve theprob

Step-by-step explanation:

sinolove ko po yan paki brainly

Answer:

[tex]3x^{2} -3x-11 = 0[/tex]

Step-by-step explanation:

Answer: 3x - 2

Step-by-step explanation:

First to solve this, we need to know some basic information such as:

1. (-) × (-) = +

2. (+) × (-) = -

3. (+) × (+) = +

Therefore, 6x-(3x+2)​

= 6x - 3x - 2

= 3x - 2

The answer to the question after removing the bracket will be 3x - 2.

Answer:

1822

Step-by-step explanation:

The fraction 1822 is equal to 911 when reduced to lowest terms.

18

22

is equivalent to 9

11

because 9 x 2 = 18 and 11 x 2 = 22

27

33

is equivalent to 9

11

because 9 x 3 = 27 and 11 x 3 = 33

36

44

is equivalent to 9

11

because 9 x 4 = 36 and 11 x 4 = 44

Answer:

18/22

Step-by-step explanation:

You can choose any number and if you multiply the top number (numerator) and the bottom number (denominator) by that same number, the fractions are equivalent.

If you choose the number 2, then multiply 9 x 2 = 18, and 11 x 2 = 22

Or multiply by 7. Then you would get an equivalent fraction of 63/77  

Answer: [tex]y=\sqrt[3]{\frac{x}{10} }[/tex]

Step-by-step explanation:

[tex]f(x)=10x^{3}\\y=10x^{3}[/tex]

switch the x and y:

[tex]x=10y^{3}[/tex]

Now solve for y:

[tex]x=10y^{3} \\\frac{x}{10} =y^{3} \\\sqrt[3]{\frac{x}{10} } =y\\[/tex]

Therefore, the inverse of that function is: [tex]y=\sqrt[3]{\frac{x}{10} }[/tex]

Answer:

5 points per post and 2 points per replies

Answer:

from math import comb

n = 100

x = 20

p = 0.26

q = 0.76

print(comb(n, x)*(p**x)*(q**(n-x)))

Step-by-step explanation:

Given that :

Number of trials, n = 100

P(success), p = 26% = 0.26

P(success)' = 1 - p = 1 - 0.26 = 0.74

Chance that sample has 20 successes = x

This problem meets the condition for a binomial probability distribution :

p(x = 20)

Recall :

P(x = x) = nCx * p^x * q^(n-x)

Using python :

comb is an built in function which calculate the combination of two arguments it takes ; and returns the combination value.

** mean raised to the power and

* is used for multiplication

The Python code as per the given question is provided below.

Program explanation:

The number of trials,

Probability of success,

Size of array generated,

The output that shows chances of 20 success,

Program code:

import numpy as np

S=sum(np.random.binomial(100,0.26,2000)==20)/2000

S

Learn more about Python expression here:

https://brainly.com/question/21645017

Answers:

=============================================

Explanation:

The angle theta is between pi and 3pi/2, excluding both endpoints.

This places theta in the third quadrant (Q3) between 180 degrees and 270 degrees. The third quadrant is in the southwest.

Plot point A at the origin. 12 units to the left of this point, will be point B. So B is at (-12,0). Then five units lower is point C at (-12,-5). Refer to the diagram below. Notice how triangle ABC is a right triangle.

The angle theta will be the angle BAC, or simply angle A.

Since cos(theta) = -12/13, this indicates that

AB = -12 = adjacent

AC = 13 = hypotenuse

Technically, AB is should be positive, but I'm making it negative so that we can then say

cos(angle) = adjacent/hypotenuse

cos(theta) = AB/AC

cos(theta) = -12/13

------------------

If you apply the pythagorean theorem, you should find that BC = 5, which I'll  make negative since we're below the x axis. Then we can say

sin(theta) = opposite/hypotenuse

sin(theta) = BC/AC

sin(theta) = -5/13

------------------

If you divide sine over cosine, then you'll get 5/12. The 13's cancel out. This is the value of tangent.

Or you could say

tan(theta) = opposite/adjacent

tan(theta) = BC/AB

tan(theta) = (-5)/(-12)

tan(theta) = 5/12

------------------

To find csc, aka cosecant, you apply the reciprocal to sine

sin = -5/13 which means csc = -13/5

sec, or secant, is the reciprocal of cosine

cos = -12/13 leads to sec = -13/12

and finally cotangent (cot) is the reciprocal of tangent

tan = 5/12 leads to cot = 12/5

------------------

Note: everything but tan and cot is negative in Q3.

Answer:

1d = -3

2b = 2

2c = 1

3a = 3

3d = 4

Step-by-step explanation:

Polynomial 1: [tex]x^2-8x+15[/tex]

Multiply the leading coefficient, 1, and the last term, 15. You get: 15.

Then, list out the factors of 15 and the addends of -8 until you get two of numbers that are the same:

Factors of 15: -5 * -3

Addends of -8: -5 + -3

Replace the -8x with -5x - 3x:

[tex]x^2-5x-3x+15[/tex]

Put parentheses around the first 2 terms & last 2 terms and factor like so:

[tex](x^2-5x)-(3x+15)[/tex]

[tex]x(x-5)-3(x-5)[/tex]

[tex](x-5)(x-3)[/tex]

Looking at the answer (ax + b)(cx + d), d would correspond with -3.

Polynomial 2: [tex]2x^3-8x^2-24x[/tex]

First factor out the x:

[tex]x(2x^{2}-8x-24)[/tex]

Divide the polynomial inside by 2 and place the 2 outside with the x:

[tex]2x(x^2-4x-12)[/tex]

Then find the factors of 1*-12 and the addends of -4 and see which two numbers match:

Factors of -12: -6 * 2

Addends of -4: -6 + 2

Replace the -8x with -6x + 2x:

[tex]2x(x^2-6x+2x-12)[/tex]

Put parentheses around the first 2 terms & last 2 terms and factor like so:

[tex]2x((x^2-6x)+(2x-12))[/tex]

[tex]2x(x(x-6)+2(x-6))[/tex]

[tex]2x((x+2)(x-6))[/tex]

[tex]2x(x+2)(x-6)[/tex]

Looking at the answer (2x)(ax + b)(cx + d), b & c would correspond with 2 & 1.

Polynomial 3: [tex]6x^2+14x+4[/tex]

Divide the polynomial by 2:

[tex](2)(3x^2+7x+2)[/tex]

Find the factors of 3*2 and the addends of 7 and see which two numbers match:

Factors of 6: 6 * 1

Addends of 7: 6 + 1

Replace the 7x with 6x + x:

[tex](2)(3x^2+6x+x+2)[/tex]

Put parentheses around the first 2 terms & last 2 terms and factor like so:

[tex](2)((3x^2+6x)+(x+2))[/tex]

[tex](2)(3x(x+2)+(x+2))[/tex]

[tex](2)((3x+1)(x+2))[/tex]

[tex](2)(3x+1)(x+2)[/tex]

Then multiply the 2 with the (x+2) and here's your final answer:

[tex](3x+1)(2x+4))[/tex]

Looking at the answer (ax + b)(cx + d), a & d correspond with 3 & 4.

Hope that helps (●'◡'●)

(This took a while to write, sorry about that)

Answer:

D. Unimodal

Step-by-step explanation:

We can immediately tell the data is not symmetrical. That leaves B, C, D. The data of this histogram is also not uniform because the numbers vary- eliminating answer choice B. There are three modes of data distribution; unimodal, multimodal, and bimodal. The one demonstrated here is unimodal because there is one "hump" in the data distribution of the histogram and one mode.

The three modes of data distribution for visual context:

Answer:

3/8.

Step-by-step explanation:

First convert days to hours:

2 days = 2 * 24 = 48 hours.

The greatest common factor of 18 and 48 = 6 so the required fraction is

18/48

= (18/6) / (48/6)

= 3/8.

Answer:

Top left: not a function

Top right: not a function

Bottom left: function

Bottom right: not a function

Step-by-step explanation:

A function is a relationship where each x value has it's own y value ( note that domain = x values and range = y values)

For the one on the top left.

S and n have more than one y value.

Because s and n have more than one y value the relation is not a function

For the one of the top right.

There x value "c" has multiple y values therefore the relation is not a function

For the one on the bottom left

Each x value has it's own y value therefore it is a function ( note that the y values can repeat. It's only the x values that can't repeat. )

For the one on the bottom right

The x value "-5" has multiple y values therefore the relation is not a function

Answer:

B."5, -3, -4, 1, -1, 6, -4"

Step-by-step explanation:

We are given that

13,5,4,9,7,14,4

We have to find the deviation.

Mean=[tex]\frac{sum\;of\;data}{total\;number\;of\;data}[/tex]

Using the formula

[tex]Mean,\mu=\frac{13+5+4+9+7+14+4}{7}[/tex]

[tex]Mean,\mu=\frac{56}{7}=8[/tex]

Deviation=[tex]x_i-\mu[/tex]

         [tex]x_i-\mu[/tex]

13          5

5           -3

4           - 4

9            1

7             -1

14            6

4            - 4

Hence, option  B is correct.

Answer:

-18

Step-by-step explanation:

B=-6 C=2 P.E.M.D.A.S.

b - 6(c)

-6 - 6(2)

-6 - 12 . The negatives cancel out, adding each other

-6 + -12

= -18 :)

Answer:

b - 6c

= -6 - 6x2

= -6 x( 1+2)

= -6x3

= -18

Answer:

75.5

Step-by-step explanation:

First, the picture is not to scale.

The Area of the bottom (2) rectangle is 33

base x height = A

11 x 3 = 33      (where did I get 3? Total height of shape is 8. Trapezoid is 5)

                      (8-5 = 3)

Area of the trapezoid:

A = [tex]\frac{h (B_{1} + B_{2}) }{2}[/tex]

  =  [tex]\frac{(5)(6 + 11)}{2}[/tex]

  =  [tex]\frac{5(17)}{2}[/tex]

  = [tex]\frac{85}{2}[/tex]

  = 42.5

42.5 + 33 = 75.5

Answer:

[tex]AC = 87[/tex]

Step-by-step explanation:

Given

[tex]AB = 3x + 4[/tex]

[tex]BC = 4x -1[/tex]

[tex]AC = 8x - 9[/tex]

Required

The value x

Since A, B and C are collinear, then;

[tex]AC = AB + BC[/tex]

This gives:

[tex]8x - 9 =3x+4+4x-1[/tex]

Collect like terms

[tex]8x - 3x - 4x = 9 + 4-1[/tex]

[tex]x = 12[/tex]

We have:

[tex]AC = 8x - 9[/tex]

[tex]AC = 8*12 - 9[/tex]

[tex]AC = 87[/tex]

Answer:

[tex]B = \frac{3V}{h}[/tex]

Step-by-step explanation:

Given

[tex]V = \frac{1}{3}Bh[/tex]

Required

Solve for B

We have;

[tex]V = \frac{1}{3}Bh[/tex]

Multiply by 3

[tex]3V = Bh[/tex]

Make B the subject

[tex]B = \frac{3V}{h}[/tex]

Answer:

the second one

Step-by-step explanation:

Answer:

[tex]\frac{3v}{a^{2}} = h[/tex]

Step-by-step explanation:

[tex]v = \frac{1}{3} a^{2} h[/tex]

[tex]3v = a^{2} h[/tex]

[tex]\frac{3v}{a^{2}} = h[/tex]

Answer:

3/10

Step-by-step explanation:

Total possibilities = 10

favourable possibilities = 3

Answer:

A

Step-by-step explanation:

There is a 1 out of 10 chance that it will land on 2.

There is a 1 out of 10 chance that it will land on 4.

There is a 1 out of 10 chance that it will land on 7.

[tex]\frac{1}{10}\cdot3=\frac{3}{10}[/tex] so the anwser is A.

Parameterize the surface (I'll call it S) by

r(u, v) = (1 - u) (1 - v) i + u (1 - v) j + v k

with 0 ≤ u ≤ 1 and 0 ≤ v ≤ 1.

Take the normal vector to this surface to be

n = ∂r/∂u × ∂r/∂v = ((v - 1) i + (1 - v) j) × ((u - 1) i - u j + k) = (1 - v) (i + j + k)

with magnitude

||n|| = √3 (1 - v)

Then in the integral, we have

[tex]\displaystyle\iint_SG(x,y,z)\,\mathrm ds = \int_0^1\int_0^1 G((1-u)(1-v),u(1-v),v) \|\mathbf n\| \,\mathrm du\,\mathrm dv \\\\= \sqrt3 \int_0^1\int_0^1uv(1-v)^2\,\mathrm du\,\mathrm dv \\\\= \boxed{\frac1{8\sqrt3}}[/tex]

Alternatively, if you're not familiar with parameterizing surfaces, you can use the "projection" formula:

[tex]\displaystyle\iint_S G(x,y,z)\,\mathrm ds = \int_{S_{xy}}G(x,y,z)\sqrt{1+\left(\frac{\partial f}{\partial x}\right)^2+\left(\frac{\partial f}{\partial y}\right)^2}\,\mathrm dx\,\mathrm dy[/tex]

where I write [tex]S_{xy}[/tex] to mean the projection of the surface onto the (x, y)-plane, and z = f(x, y). We would then use

x + y + z = 1   ==>   z = f(x, y) = 1 - x - y

and [tex]S_{xy}[/tex] is the triangle,

{(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1 - x}

Then the integral becomes

[tex]\displaystyle\int_0^1\int_0^{1-x}y(1-x-y)\sqrt{1+(-1)^2+(-1)^2}\,\mathrm dy\,\mathrm dx \\\\= \sqrt3\int_0^1\int_0^{1-x} y(1-x-y)\,\mathrm dy\,\mathrm dx \\\\= \frac{\sqrt3}{24} \\\\= \boxed{\frac1{8\sqrt3}}[/tex]