Answer:
3.5 yards of fabric
Step-by-step explanation:
Find 2/3 of 5 1/4:
5 1/4(2/3)
= 3.5 yards of fabric
NEED ASAP I WILL GIVE BRAINLEYEST What is the value of the expression 22 + 82 ÷ 22? 8 10 17 20
Answer:
Exact Form:
283 /11
Decimal Form:
25. 72
Mixed Number Form:
25 8 /11
Step-by-step explanation:
Answer:
17
Step-by-step explanation:
Can any one help me with this
Answer: C
Step-by-step explanation:
Since this is an isosceles triangle as indicated by the markers on QP and PR, we know that QS and SR are equivalent.
To find the value of n, we set QS and SR equal to each other.
6n+3=4n+11 [combine like terms]
2n=8 [divide both sides by 2]
n=4
Now that we know n=4, we know that A is incorrect. What we can do is use the value of n to solve for QS, SR, and QR.
QS
6(4)+3=13
Since the length of QS is 13, we know B is incorrect.
SR
4(4)+11=27
Since SR is 27, C is a correct answer.
QR
13+27=40
Since QR is 40, the only correct answer is C.
The following is the number of minutes to commute from home to work for a group of 25 automobile executives. 35 36 39 43 37 35 34 30 36 34 30 39 37 40 38 33 31 28 39 35 35 36 41 24 36 How many classes would you recommend? What class interval would you suggest? (Round up your answer to the next whole number.) Organize the data and plot a frequency distribution on a piece of paper. Comment on the shape of the frequency distribution. It is not symmetric. It is fairly symmetric, with most of the values between 24 and 43. It is not very symmetric, but most of the values lie between 24 and 43.
Answer:
It is not symmetric, but skewed left. Data appears more to be on the left side.
Step-by-step explanation:
The smallest value is 24 and the largest is 43 . The difference between these two values is 19 which can be divided into into intervals of 4.
19/4= 4.75 It will be rounded to 5.
The class interval can of 5. Starting from 20 we get class intervals and frequency distribution as
Class Intervals Data Frequency
20-24 24 1
25- 29 28, 1
30-34 34,30,34,30,33,31, 6
35-39 35,36,39,37,35,36,39,37, 14
38,39,35,35,36,36
40-44 43,40,41 3
The class intervals are inclusive of both upper and lower limits. The difference between the lower limits of two consecutive classes or upper limits of two consecutive classes must be the same.
As we see the difference here is that of 5 between the two upper or lower limits of consecutive classes.
The histogram is attached which shows the class intervals along x- axis and data frequency along y- axis.
The graph below represents the function f.
f(x)
if g is a quadratic function with a positive leading coefficient and a vertex at (0,3), which statement is true?
А.
The function fintersects the x-axis at two points, and the function g never intersects the x-axis.
B
The function fintersects the x-axis at two points, and the function g intersects the x-axis at only one point.
c.
Both of the functions fand g intersect the x-axis at only one point.
D
Both of the functions fand g intersect the x-axis at exactly two points.
Answer: А.
The function f intersects the x-axis at two points, and the function g never intersects the x-axis.
Step-by-step explanation:
In the graph we can see f(x), first let's do some analysis of the graph.
First, f(x) is a quadratic equation: f(x) = a*x^2 + b*x + c.
The arms of the graph go up, so the leading coefficient of f(x) is positive.
The vertex of f(x) is near (-0.5, -2)
The roots are at x = -2 and x = 1. (intersects the x-axis at two points)
Now, we know that:
g(x) has a positive leading coefficient, and a vertex at (0, 3)
As the leading coefficient is positive, the arms go up, and the minimum value will be the value at the vertex, so the minimum value of g(x) is 3, when x = 0.
As the minimum value of y is 3, we can see that the graph never goes to the negative y-axis, so it never intersects the x-axis.
so:
f(x) intersects the x-axis at two points
g(x) does not intersect the x-axis.
The correct option is A.
Answer:
The answer is A.) The function f intersects the x-axis at two points, and the function g never intersects the x-axis.
Step-by-step explanation:
I took the test and got it right.
A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack of crackers to the number of calories in each snack pack of trail mix. A number line goes from 65 to 115. Crackers's whiskers range from 70 to 100, and the box ranges from 75 to 85. A line divides the box at 80. Cookies's whiskers range from 70 to 115, and the box ranges from 90 to 105. A line divides the box at 100. Which statement is true about the box plots
OPTIONS:
A. The interquartile range of the trail mix data is greater than the range of the cracker data.
B. The value 70 is an outlier in the trail mix data.
C. The upper quartile of the trail mix data is equal to the maximum value of the cracker data.
D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
Answer:
D.
Step-by-step explanation:
With the given information about how the box plot looks like, let's examine each option to see if they are true or not.
Option A: "The interquartile range of the trail mix data is greater than the range of the cracker data."
The interquartile range of trail mix data = 105 - 90 = 15
Range of cracker data = 100 - 70 = 30
Option A is NOT TRUE.
Option B: "The value 70 is an outlier in the trail mix data."
This is NOT TRUE. There are not outliers as 70 is the minimum value if the ranges of the data set for the trail mix.
Option C: "The upper quartile of the trail mix data is equal to the maximum value of the cracker data."
Upper quartile of the trail mix data = 105
Max value of cracker data = 100
This statement is NOT TRUE.
Option D: "The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers."
The greater the range value, the greater the variation. Thus,
Range value of the trail mix data = 115 - 70 = 45
Range value of the cracker data = 100 - 70 = 30
This is statement is correct because trail mix data have a greater range value, hence, it has a greater variation in the number of calories.
Answer: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
Pimeter or area of a rectangle given one of these...
The length of a rectangle is three times its width.
If the perimeter of the rectangle is 48 cm, find its area.
Answer:
A=108 cm²
Step-by-step explanation:
length (l)=3w
perimeter=2l+2w
P=2(3w)+2w
48=6w+2w
width=48/8
w=6
l=3w=3(6)=18
l=18 cm , w=6 cmArea=l*w
A=18*6
A=108 cm²
Which algebraic expression means “three more than a number squared”? 2 n + 3 2 n minus 3 n squared + 3 n squared minus 3
The algebraic expression that means "three more than a number squared" is n² + 3, where n is the number.
What is the algebraic expression?Algebraic expressions are mathematical statements with a minimum of two terms containing variables or numbers.
The statement is given in the question, as follows:
“three more than a number squared”
The expression n² represents the square of the number, and the expression + 3 represents the addition of three more to the square of the number.
So, n² + 3 represents the value of the square of the number plus three.
Thus, the algebraic expression that represents "three more than a number squared" is n² + 3.
Learn more about the algebraic expression here :
brainly.com/question/21751419
#SPJ6
The following data shows the number of home runs hit by the top 12 home run hitters in Major League Baseball during the 2011 season.
43 41 39 39 38 37 37 36 34 33 33 32
The lower limit for determining outliers for a box-and-whisker plot is______.
a. 23.75.
b. 20.0.
c. 22.5.
d. 25.25.
Answer:
d. 25.25.
Step-by-step explanation:
A whisker plot is a type of box plot which is graphical representation of five number summary. It is used for explanatory data analysis. The baseball league has data set whose median is 45. When the outliner are present in data set the median measures central tendency.
Need Assistance
Please Show Work
Answer:
3 years
Step-by-step explanation:
Use the formula I = prt, where I is the interest money made, p is the starting amount of money, r is the interest rate as a decimal, and t is the time the money was borrowed.
Plug in the values and solve for t:
108 = (1200)(0.03)(t)
108 = 36t
3 = t
= 3 years
Examine the diagram. Triangle M P L. Angle P is 90 degrees and angle L is (4 x + 6) degrees. The exterior angle to angle M is 136 degrees. What is the value of x?
Answer:
x = [tex]10^{0}[/tex]
Step-by-step explanation:
From Δ MPL given that; <P = [tex]90^{0}[/tex], exterior angle to M = [tex]136^{0}[/tex] and <L = [tex](4x+6)^{0}[/tex].
In the triangle, the exterior angle is equal to the sum of the two adjacent interior angles. So that;
[tex]136^{0}[/tex] = [tex]90^{0}[/tex] + [tex](4x+6)^{0}[/tex]
= [tex]90^{0}[/tex] + 4[tex]x^{0}[/tex] + [tex]6^{0}[/tex]
[tex]136^{0}[/tex] = [tex]96^{0}[/tex] + [tex]x^{0}[/tex]
⇒ 4[tex]x^{0}[/tex] = [tex]136^{0}[/tex] - [tex]96^{0}[/tex]
4[tex]x^{0}[/tex] = [tex]40^{0}[/tex]
Divided both sides by 4 to have;
[tex]x^{0}[/tex] = [tex]10^{0}[/tex]
The value of x is [tex]10^{0}[/tex].
Answer:
The correct answer is in fact 10 degrees.
Step-by-step explanation:
I hope this helps!
Have a great day! :)
Question 2 Rewrite in simplest radical form 1 x −3 6 . Show each step of your process.
Answer:
√(x)
Step-by-step explanation:
(1)/(x^-(1/2)) that's 3 goes into -3 leaving 1 and goes into 6 leaving 2
1/2 is same as 2^-1
so therefore we can simplify the above as
x^-(-1/2)
x^(1/2)
and 4^(1/2)
is same as √(4)
so we conclude as
√(x)
Hugo scored 18 points in a recent basketball game, which was 5 points fewer than
Toby scored. Write an equation for this situation, where tis the number of points
Toby scored, and find how many points Toby scored.
A) 18 = t + 5, Toby scored 13 points
B) 18 = t-5, Toby scored 23 points
C) 18 = t - 5, Toby scored 13 points
D) 18 = t + 5, Toby scored 23 points
Transform the Cartesian (rectangular) equation to a polar equation: x = -9. The selected answer is incorrect.
Answer:
Solution : Option C
Step-by-step explanation:
We have the equations r² = x² + y², x = r cos(θ), and y = r sin(θ) that can be used to solve this problem. In this case we only need the second two equations ( x = r cos(θ), and y = r sin(θ) ) as we don't need to apply the concept of circles etc here.
Given : x = - 9,
( Substitute r cos(θ) for x )
r cos(θ) = - 9,
r = - 9 / cos(θ)
( Remember that sec is the reciprocal of cos(θ). Substitute sec for 1 / cos(θ) )
r = - 9 sec(θ)
Therefore the third option is the correct solution.
There were 120 planes on an airfield. if 75% of the plane took off for a flight, how many planes took off?
Answer:
90 planes
Step-by-step explanation:
Take the total number of planes and multiply by the percentage of planes that took off
120 * 75%
120 * .75
90
Given the following three points, find by hand the quadratic function they represent.
(0,6), (2, 16), (3, 33)
(1 point)
f(x) = 4x2 + 3x + 6
f(x) = -42? +212 + 6
f(x) = -472 – 3r +6
f(1) = 4x2 – 3x + 6
let the function be [tex]y=ax^2+bx+c[/tex]
put $x=0, \, y=6$ , to get $c=6$
put $x=2, \, y=16$ , $16=4a+2b+6\implies 2a+b=5$
put $x=3, \, y=33$ , $33=9a+3b+6\implies 3a+b=9$
subtract the two equation, to get $a=4$
now substitute $a$ in first equation, to get $b=5-2\cdot4=-3$
so, $f(x)=4x^2-3x+6$
reciprocal of dash and dash remains same
Answer:
-1 and 1
Step-by-step explanation:
Reciprocal means "one divided by...".
1/-1 = -1 and 1/1 = 1
In rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=10 and BC=2, what is the area of the shaded region? Answer as a decimal, if necessary. Little confused on this one.
Answer:
10 units²
Step-by-step explanation:
Consider the unshaded region to consists of 2 triangles, ∆AED and ∆BEC, which are both of equal dimensions. Their bases and heights are both the same. Both triangles are embedded inside a rectangle ABCD.
Area of the shaded region = Area of rectangle - area of the 2 triangles.
Area of rectangle = l*w
l = 10
w = 2
[tex] Area_R = 10*2 = 20 units^2 [/tex]
Area of the 2 triangles = 2(½*b*h)
b = 2
h = 5
[tex]Area_T = 2(\frac{1}{2}*2*5)[/tex]
[tex] Area_T = 1*2*5 = 10 units^2 [/tex]
Area of shaded region = 20 - 10 = 10 units²
In a stable matching problem, if every man has a different highest-ranking woman on his preference list, and given that women propose, then it is possible that, for some set of women's preference lists, all men end up with their respective highest-ranking woman.a. Trueb. False
Answer:
True
Step-by-step explanation:
The statement given above in the question is correct. It is mentioned that men are free to create a list of women's according to their preferences. There will be order sequence of women and men places them in queue of their preference. The men proposes the women with highest ranking in the list then it is possible that all men gets their preferred choice.
The distance a bike travels varies directly as the amount of time the bike has been ridden. Angela is riding her bike. If she travels a distance of 60 miles in 2 hours, how far has Angela traveled in 7 hours?
Answer:
420 miles
Step-by-step explanation:
60 ×7=420
thank
Answer:210 miles
Step-by-step explanation:because there is 7 hours so you need to multiply up to six hours so 60 x 3 = 180 or 6 hours + 1 hour = 30 miles so 180+30= 210
Please help with this
Answer:
A. 120
Step-by-step explanation:
The rest of the answers are acute.
120 is the only one that matches the type of angle <V is.
Always pay attention to the type of angle it is.
Ashton needs to rent a car while on vacation. The rental company charges $19.95, plus 18 cents for each mile driven. If Ashton only has $50 to spend on the car rental, what is the maximum number of miles she can drive?
Answer:
166.9 miles or 166 miles
Step-by-step explanation:
We can form an equation like this:
19.95 + .18x = 50
In this equation, "x" is the number of miles.
=> 19.95 - 19.95 +.18x = 50 -19.95
=> .18x = 30.05
=> .18x/.18 = 30.05/.18
=> x = 166.9
Ashton can drive 166.9 miles.
**Note: We cannot round the answer to 167, as she would not have enough money to drive the extra 0.1 mile.
Chapter: Simple linear equations Answer in steps
Answer:
6x-3=21
6x=24
x=4
........
6x+27=39
6x=39-27
6x=12
x=2
........
8x-10=14
8x=24
x=3
.........
6+6x=22
6x=22-6
x=3
......
12x-2=28
12x=26
x=3
.....
8-4x=16
-4x=8
x=-2
.....
4x-24=3x-3
4x-3x=24-3
x=21
....
9x+6=6x+12
9x-6x=12-6
3x=6
x=2
Answer:
Step-by-step explanation:
1. 3(2x - 1) = 21
= 6x - 3 = 21
= 6x = 24
= x = 24/6 = 4
------------------------------
2. 3(2x+9) = 39
= 6x + 27 = 39
= 6x = 39 - 27
= 6x = 12
= x = 12/6 = 2
--------------------------------
3. 2(4x - 5) = 14
= 8x - 10 = 14
= 8x = 14+10
= x = 3
-------------------------------
I suck at math, online school is really hard I need to find a tutor, can this be explained?
Answer:
its [c] if Bradley serves 4 tables he will earn an average of $25
Step-by-step explanation:
A carpenter is making doors that are 20582058 millimeters tall. If the doors are too long they must be trimmed, and if they are too short they cannot be used. A sample of 1010 doors is made, and it is found that they have a mean of 20462046 millimeters with a standard deviation of 1515. Is there evidence at the 0.050.05 level that the doors are too short and unusable
Answer:
Z= 0.253
Z∝/2 = ± 1.96
Step-by-step explanation:
Formulate the null and alternative hypotheses as
H0 : u1= u2 against Ha : u1≠ u2 This is a two sided test
Here ∝= 0.005
For alpha by 2 for a two tailed test Z∝/2 = ± 1.96
Standard deviation = s= 15
n= 10
The test statistic used here is
Z = x- x`/ s/√n
Z= 2058- 2046 / 15 / √10
Z= 0.253
Since the calculated value of Z= 0.253 falls in the critical region we reject the null hypothesis.
There is evidence at the 0.05 level that the doors are too short and unusable.
Write
801
1000
as a decimal number.
Answer:
0.801
Step-by-step explanation:
Answer:
0.801
Step-by-step explanation:
801/1000 = 0.801
In December 2004, a report based on the National Survey on Drug Use and Health estimated that 20% of all Americans aged 16 to 20 drove under the influence of drugs or alcohol in the previous year. We would like to update this information by calculating a 98% confidence interval. How large a sample is necessary in order for the bound on the error of estimation to be 0.04?
Answer:
542
Step-by-step explanation:
We are required to find the sample size at 98% confidence interval in this question
E = 0.04
P* = 20% = 0.20
n = p* x (1-p)(Zα/2÷E)²
α = 1 - 0.98
= 0.02
To get Critical value
= 0.02/2 = 0.01
The critical value at 0.01 is 2.33
Inserting values into formula:
O.2 x 0.8(2.33/0.04)²
= 0.8 x 0.2 x 58.25²
= 542.89
The value of n must be an integer therefore the answer is 542.
Need Help
*Please Show Work*
Hi there! :)
Answer:
y = -2x + 3
Step-by-step explanation:
We can write an equation in slope-intercept form. Use the slope formula to find the rate of change in the table:
[tex]m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Plug in values from the table:
[tex]m = \frac{5 - 7}{-1 - (-2)}[/tex]
Simplify:
m = -2 (rate of change)
Use a point from the table (-2, 7) and the slope to solve for the equation for the linear function:
7 = -2(-2) + b
7 = 4 + b
7 -4 = b
b = 3
Rewrite:
y = -2x + 3 is the equation for the linear function.
Use the order of operations to simplify this expression 1.2x3.5x4.1= What
[tex] 1.2\times3.5\times4.1=[(1+0.2)(3+0.5)](4+0.1)[/tex]
$=[1\times3+1\times0.5+0.2\times3+0.2\times0.5](4+0.1)$
$=(3+0.5+0.6+0.1)(4+0.1)$
$=(4.2)(4+0.1)=(4+0.2)(4+0.1)$
$=4\times4+4\times0.1+0.2\times4+0.2\times0.1$
$=16+0.4+0.8+0.02=17.22$
In a study of 100 new cars, 29 are white. Find and g, where
is the proportion of new cars that are white.
Question
In a study of 100 new cars, 29 are white. Find p and q , where p is the proportion of new cars that are white.
Answer:
p = 0.29 and q = 0.71
Step-by-step explanation:
Given
Total new cars = 100
White new cars = 29
Required
Determine p and q
From the question;
p represents white new cars
Hence;
[tex]p = 29[/tex]
Note that;
[tex]p + q = 100[/tex]
Substitute 29 for p
[tex]29 + q = 100[/tex]
[tex]29 - 29 + q = 100 - 29[/tex]
[tex]q = 100 - 29[/tex]
[tex]q = 71[/tex]
The proportion of p is calculate by dividing p by the total number of new cars (Same process is done for q)
For proportion of p
[tex]Proportion,\ p = \frac{p}{new\ cars}[/tex]
[tex]Proportion,\ p = \frac{29}{100}[/tex]
[tex]Proportion,\ p = 0.29[/tex]
For proportion of q
[tex]Proportion,\ q = \frac{q}{new\ cars}[/tex]
[tex]Proportion,\ q = \frac{71}{100}[/tex]
[tex]Proportion,\ q = 0.71[/tex]
For what values of y: Is the value of the fraction 5−2y 12 always greater than the value of 1−6y?
Answer:
[tex](5 - 2y) \div 12 > 1 - 6y[/tex]
[tex]5 - 2y > 12 - 72y[/tex]
[tex] - 7 > - 70y[/tex]
[tex]7 < 70y[/tex]
[tex]y > 1 \div 10 = 0.1[/tex]
