Some important and basic points:
Unit of time is second (s).
Unit of mass is kilogram (kg).
Unit of distance/displacement is meter (m).
P.S. Displacement and distance are nearly same things, their unit is same.
Speed/velocity = distance/time
So, its unit is m/s.
Acceleration = (final velocity-initial velocity)/time.
So, its unit is m/s² or m.s^-2
We know from the formula that,
Force = mass × acceleration
=> F = ma
Putting units:
Newton = kg.m/s² or kg.m.s^-2 _____(1)
Putting dimensions:
Newton = M.L.T^-2
________________________
We know from the formula that,
Work = force × displacement
=> W = Fs
Putting units:
Joule = Newton.m
=> Joule = kg.m.s^-2.m [from (1)]
=> Joule = kg.m².s^-2 ______(2)
Putting dimensions:
Joule = M.L².T^-2
________________________
We know from the formula that,
Power = work/time
Putting units:
Watt = joule/s
=> Watt = kg.m².s^-2/s [from (2)]
=> Watt = kg.m².s^-3 ______(3)
Putting dimensions:
Watt = M.L².T^-3
________________________
We know from the formula that,
Horsepower = 746 watt
=> Horsepower = 746kg.m².s^-3 [from (3)]
Putting dimensions:
Horsepower = 746M.L².T^-3
Hope it helps!!The dimension of Watt, Newton and horsepower are ML²T⁻³, MLT⁻² and ML²T⁻³ respectively
Units and dimensionUnits are measure of a quantity. Dimensions are derived from the units. Gi
Force = mass × acceleration
For Newton:
Another representation for unit of Newton is kg.m/s². Writing in terms of the dimension
Newton = MLT⁻²
For Watts;
The unit of Watt is also kg.m².s⁻²/s which is equivalent to kg.m².s⁻³
In terms of dimension
Dimension of Watt = ML²T⁻³
For Horse power:
The unit of horse power is kg.m².s⁻³
Dimension of horsepower = ML²T⁻³
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Determine the dimensions for R if R = m V / (d^2 Q) where m is a mass, V is a velocity, d is a diameter, and the dimensions of Q are M/(LT).
No dimensions
M / (L T^2)
M L / T^2
M
L / T
Answer:
No dimension
Explanation:
The given equation is [tex]R = \dfrac{m \cdot V}{d^2 \cdot Q}[/tex], where;
m = Mass
V = Velocity
d = A diameter
The dimension of mass quantity = M
The dimension of the velocity quantity = L/T
The dimension of the dimeter quantity = L
The given dimension of Q = M/(L·T)
Therefore, we get;
[tex]The \ dimension \ of \ R = \dfrac{M \times L/T}{L^2 \times (M/LT)} = \dfrac{M \times L/T}{L \times M/T} = 1[/tex]
Therefore, R has no dimensions
9. SAFELY BACKING UP YOUR VEHICLE INCLUDES ALL OF THE FOLLOWING
EXCEPT:
A. Looking over your right shoulder as you back up
O B. Checking behind your vehicle before you get in
C. Tapping your horn before you back up
Pls help me Extra points
Represent each of the following units as a combination of primitive
dimensions where M=mass, L=length, T=time
Kilometer
Quart
Pascal
Watt
Newton
Horsepower
Kilometer = 1000m
Quart = 0.000946m³
Force = mass × acceleration
=> F = ma
Putting units:
Newton = kg.m/s² or kg.m.s^-2 _____(1)
Pressure = force/area
Putting units:
Pascal = Newton/m²
=> Pascal = kg.m.s^-2.m² [from (1)]
=> Pascal = kg.m^-1.s^-2
Work = force × displacement
=> W = Fs
Putting units:
Joule = Newton.m
=> Joule = kg.m.s^-2.m [from (1)]
=> Joule = kg.m².s^-2 ______(2)
Power = work/time
Putting units:
Watt = joule/s
=> Watt = kg.m².s^-2/s [from (2)]
=> Watt = kg.m².s^-3 ______(3)
Horsepower = 746 watt
=> Horsepower = 746kg.m².s^-3 [from (3)]
Hope it helps!!The low-pressure fuel system is being discussed. Technician A says that the system must provide an adequate volume of fuel to the high-pressure fuel injection system. Technician B says that the system must provide fuel at a minimum pressure to the high-pressure fuel injection system. Which technician is correct
Answer:
Hence Both technicians A and B are correct that is Technician A says that the system must provide an adequate volume of fuel to the high-pressure fuel injection system. Technician B says that the system must provide fuel at a minimum pressure to the high-pressure fuel injection system are true.
Explanation:
The low-pressure fuel system contains the fuel filters; A fuel level sending unit/tank pick-up; A transfer pump. So from considering both technicians statements both are applicable.
Explanation:
MARK ME AS A BRIANLIEST .........what is 222 divided by 11.2
Answer:
The answer of this question is 19.89142857
Answer:
The number 222 is called the numerator or dividend, and the number 11 is called the denominator or divisor.
The quotient of 222 and 11, the ratio of 222 and 11, as well as the fraction of 222 and 11 all mean (almost) the same:
222 divided by 11, often written as 222/11.
Read on to find the result of 222 divided by 11 in decimal notation, along with its properties.
Explanation:
True or false: Units and dimensions are interchangeable words that describe the same concept.
True
False
Answer:
The answer to this is false
Explanation:
It is FALSE that units and dimensions are interchangeable words that describe the same concept.
What are units and dimension?Units is defined as a measure of quantity while dimension specify the measure of a line or curve.
Both terms cannot be used interchangeably even though the dimensions of a quantity is derived from its units.
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George is replacing a burned out resistor in a circuit board. The board has a 10, a 20, and a 40 on resistor, all in parallel. When George has sided in the new component in the circuit is fixed, he checks his multimeter. What reading does he get?
Answer:
5.71 ohms
Explanation:
put it in the calculator
