selling price =$1518 and loss=$132​

Answers

Answer 1

Answer:

1,386

Step-by-step explanation:

Answer 2

Answer:

$1386

Step-by-step explanation:

I need the whole question but I am guessing this is what I need to do:

$1518 - $132 = $1386

Have a nice day! :-)


Related Questions

Najat needs to make a total of 80 deliveries this week. so far She has completed 68 of them . what percentage of her total deliveries has Najaf completed?​

Answers

85%

Hope this helps! :)

______________

Answer:

68/80×100%=85%

hope it helps!!!

Solve for x Log2 x=-5

Answers

i went through the process and got 6

Suppose the mean height in inches of all 9th grade students at one high school is estimated the population standard deviation is 4 inches the height of 7 randomly selected students are 69,74,66,66,62,64,and 74 what is the margin of error at 99% confidence level

Answers

Answer:

1.474

Step-by-step explanation:

Given that :

Population standard deviation, σ = 4

Sample size = 7

Confidence level = 99%

Since we ore using the population standard deviation, the we use the Z distribution table:

The margin of error :

Zcritical * σ/√n

Zcritical at 99% = 2.58

The margin of error :

2.58 * 4/√7

2.58 * 0.5714285

= 1.474

7.46 rounded to the nearest tenth

Answers

Answer:

7.5

Step-by-step explanation:

I just want to make sure or is it b?

Answers

I believe the answer should actually be

C.) It is a one to one function

A one to one function is a function in which the x and y values never repeat. Each value of x is different every time, and they never have the same values of y.

I need help like really bad in the next 10 mins or I fail math please help me-

Answers

The answer should be 16!!

Answer:

5(×) - 3(×)

5(²) - 3(²)

25 - 9

16

PLEASE HELPPPPPPPPPPPPPPPPPPPP

Answers

Answer:

18 sq.m

Step-by-step explanation:

Area of the part with cement = area of backyard - area of grass part

Backyard:

length = l = 6m  ; Width = w = 4 m

Area of backyard = l * w = 6*4 = 24 sq. m

Grass part:

l = 3 m ; w = 2 m

Area of the grass part = 3*2 = 6 sq.m

Area of the part with cement = 24 - 6 = 18 sq.m

which one would be a better choice and why? please tell me how u got the answer :)

Answers

Answer:

I would roll with option B.

Step-by-step explanation:

If I understand it correctly, I would opt for option B here's why:

Suppose the pizza or pie is $20 each.

For option A,  If me and two of my friends order individually we would each only get 10% discount. So 10% of 20 is $2 so we would each pay $18 for each pizza ($54 in total for all of us).

For option B, if we order in same check that means we get 30% of our total order. Our total order is $60 (b/c each pizza is $20 so 20*3= 60). Taking 30% off of $60 is getting discount of $18 bucks which means we would pay $42 only.

Hence, comparing option A and option B, we can clearly see that opting for option B, will save 54-42 = $12.

the value of each square root

Answers

Answer:

root 324=18

root 441=21

root 529=23

Step-by-step explanation:

root 324 = 18

root 441 = 21

root 524 = 23

g(x) = 3x -1. Find x such that g(x)= 2​​0​.
g​(x)= 3x+1. Find x ​​​such that g(x)= 22​​​​.​

g(x)= ​2x-5. Find g(1/2) and g(a)=9​​​​​​9.
g(x)=x+5/2. Find g(3), g(0), g(-3) and g(x)=0​​​​​​​​​​

Please solve this quickly. I need it right now​​​​​. No silly answer will not be allowed.

Answers

Step-by-step explanation:

i. 3x-1=20

or, 3x= 21

x= 7

ii. 3x+1= 22

3x= 21

x= 7

iii. 2x-5=99

2x= 104

x=52

iv. g(3)= 3+5/2= 11/2

g(0)= 0+ 5/2=5/2

g(-3)= -3+5/2 = -1/2

x+5/2= 0

so, x= -5/2

Find the range of the graphed function.
10
10
M
-101
O A. O sys 10
O B. yis all real numbers.
O C. y20
OD. -9 sys5

Answers

Answer:

-9≤y≤5

Step-by-step explanation:

The range is the values that the output can take

The smallest value that the output takes is -9 and the largest value is 5

-9≤y≤5

ANSWER ASAP

What are the solutions of the quadratic equation 2x2 - 4x = 3?

Answers

Answer:

option c

Step-by-step explanation:

2x² - 4x = 3

2x² - 4x - 3 = 0

a = 2, b = - 4, c = -3

      [tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\\\x = \frac{4 \pm \sqrt{16 + 24 }}{4} \\\\x = \frac{4 \pm \sqrt{40}}{4} \\\\x = \frac{4 \pm \sqrt{4 \times 10} }{4} \\\\x = \frac{4 \pm 2\sqrt{10} }{4} \\\\x = 1 \pm \frac{\sqrt{10}}{2}[/tex]

Please help i'm struggling with this!

Answers

Answer:

second option is correct (for question no 20)

Step-by-step explanation:

coordinate points are:

(3,1) = (x1,y1)

(5,9) = (x2,y2)

slope (m) = y2-y1/x2-x1

=9-1/5-3

=8/2

=4

Now using slope intercept form

y=mx + b

y=4x + b

since the line passes through the point (3,1) it satisfies the equation

y=4x + b

1=4*3 + b

1-12 = b

-11 = b

substituting the value of b in equation

y=4x + b

y=4x +(-11)

y=4x - 11

What would the equation be if the points were 6,18 and -12,3

Answers

Answer:

[tex]y=\frac{15}{18} x+13[/tex]

Step-by-step explanation:

Use a graphing calculator,

hope it helps

Find the product
and
3
8
17

Answers

Answer:

1/6

Step-by-step explanation:

-4/9 * - 3/8

A negative times a negative is a positive

Rewriting

4/9 * 3/8

4/8 * 3/9

Simplifying

1/2 * 1/3

1/6

Answer:

Third Option: [tex]\frac{1}{6}[/tex]

Step-by-step explanation:

When there are two negatives, the answer has to be positive, so it cannot be the first and second options. This fraction can be reduced, so:

-[tex]\frac{1}{3}[/tex] × -[tex]\frac{1}{2}[/tex] =  [tex]\frac{1}{6}[/tex]

---------------------------------------------------------------------------------------------------------------

Have a great summer :)

PLEASE HELP ASAP, THIS IS A TIMED MATH QUESTION!!!
I'LL MARK BRAINLIEST FOR CORRECT ANSWERS!

Answers

There’s no question

Help out please !!!!

Answers

Answer:

B maybe

Step-by-step explanation:

I belive the answer would be b

A projectile is fired straight upward from the Earth's surface with an initial speed of 33.3m/sec. What is it's speed after 2.8secs?

Answers

Answer:

let's write it as an equation

speed in m/sec (s) = 33.3 -9.81s

speed in m/sec (2.8) = 33.3 -9.81*2.8 = 5.832

9.81 is the deceleration due to earth's gravity.

the speed changes that ammount per second.

Suppose the population of a small town is 567 in 2011. The population DECREASES at a
rate of 5% every year. What will be the population of the town in 2021? Round your answer
to the nearest whole number.

Answers

Answer:

2011: 567 2012: 567*(1-.015) 2013: 567*(1-.015)*(1-.015) 2014: 567*(1-.015)567*(1-.015)*(1-.015) you see the pattern; and, if so, you can build an little equation giving you the answer

Answer:

339

Step-by-step explanation:

a = 567 (.95)¹⁰

a = 339.4838445482

Rounded

339

In the diagram find the value of x

Answers

Answer:

[tex]KN\times~JN=LN\times~MN[/tex]

[tex](x-1)(x+20)=(x+11)(x+2)[/tex]

[tex]x^2+19x-20-x^2+13x+22[/tex]

[tex]7x=42[/tex]

[tex]x=6[/tex]

-----------------------

hope it helps...

have a great day!!

HELlLlLlPllLl is it
10

2

1

9

Answers

Answer:

2

Step-by-step explanation:

Answer: 2
As you can see, In the list of Numbers there are TWO SETS of 8.5 (As shown, I circled the two) meaning you should put 2 "x's" over 8.5. If you need more of an explanation, please let me know.

If available please give me a Branliest. It would be much appreciated, and it would also help me answer more and more difficult questions! Good luck.

-MathHotdog •~•

Help Please!! Find the surface area of the composite figure.

Answers

644 is the answer
3x3=9
3x8=24 -> 24x4 = 96
7x10=70 -> 70x2 =140
7x12=84 -> 84x2=168
10x12=120 -> 120x2-9=231

What is the quotient? StartFraction 3 y + 2 Over 3 y EndFraction divided by StartFraction 6 y squared + 4 y Over 3 y + 2 EndFraction

Answers

Answer:

[tex]\frac{3y+2}{6y^2}\\[/tex]

Step-by-step explanation:

Given the expression

[tex]\frac{3y+2}{3y}/\frac{6y^2+4y}{3y+2} \\= \frac{3y+2}{3y} * \frac{3y+2}{6y^2+4y}\\= \frac{3y+2}{3y} * \frac{3y+2}{2y(3y+2)}\\= \frac{3y+2}{3y} * \frac{1}{2y}\\= \frac{3y+2}{6y^2}\\[/tex]

Cuánto es -2+(-3)+4-(-3)-5

Answers

Answer:

1

Step-by-step explanation:

Which graph represents the solution to the system of linear inequalities x>3 and y ≤ 2?​

Answers

Answer:

E I think sorry if this was the wrong one

Tom save $3400 a week.how much money he save in 1 year.​

Answers

Answer:

176800 per year

Step-by-step explanation:

There are 52 weeks in 1 year

3400 per week * 52 weeks per year

176800 per year

Answer:

$176,800

Step-by-step explanation:

3400 x 52 = 176,800

Please help me. The answer in the booklet says it’s R=3, but I need working out because I don’t get it.

Answers

Answer:

3.

Step-by-step explanation:

R = √[(2)^2 + (√5)^2]

= √(4 + 5)

= √9

= 3.

Answer:

3

Step-by-step explanation:

[tex]R =\sqrt{a^{2}+b^{2}}\\\\= \sqrt{2^{2}+(\sqrt{5})^{2}}\\\\= \sqrt{4+5}\\\\=\sqrt{9}\\\\= \sqrt{3*3}\\\\= 3[/tex]

Hint:  (√5)² = [tex]\sqrt{5}*\sqrt{5} = \sqrt{5*5}=5[/tex]

two third of a number is 30. find the number​

Answers

Answer:

The number is 45

Step-by-step explanation:

Let number = x

2/3 x = 30

x = 30/2/3

x = 30×3/2

x = 90/2 = 45

The number is 45

2/3 ×45= 90/3 = 30

PLEASE HELP !! I'm desperate

Answers

Answer:

see below

Step-by-step explanation:  6  23  17  30

the length CD is  the square root of the delta X value squared + the delta Y value squared

a² + b² = c²   is the common form for this problem use

ΔX² + ΔY² = CD²

ΔX = X2 - X1        ΔY = Y2 - Y1

ΔX = 2 - (-2)        ΔY = 5 - (-5)

ΔX = 4                ΔY = 10

4² + 10² = CD²

16 + 100 = CD²

116  = CD²

√116  =  √CD²  = CD

√(4 × 29)  = CD

2√29  = CD    the first option

Aria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there were 80 million cars in year 1 of her study, how many more cars were on the road in year 3 compared to year 2? 8,000,000 8,800,000 88,000,000 96,800,000

Answers

Answer:

8,800,000cars

Step-by-step explanation:

Given the initial amount of cars = 80,000,000

If there is 10 % increase in the first year;

Increment = 10% of 80,000,000

Increment = 0.1 * 80,000,000

Increment = 8,000,000

Amount of car in year 2 = 80million + 8million = 88million

Year3;

Amount of car in year 3 = 88,000,000+(10%of88million)

Amount of car in year 3 = 88,000,000+8,800,000

Amount of car in year 3 =96,800,000

Differences in the number of cars = 96,800,000 - 88,000,000

Differences in the number of cars = 8,800,000cars

Hence there are 8,800,000cars in years 3 than year 2

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