Shandra bought some belts online for $67. She used a coupon code to get a 20% discount. The website also applied a 5% processing fee to the price after the discount. How much was the discount, in dollars and cents?

Answer:

absolute value

coefficient

constant

counterexample

equation

expression

evaluate

inequality

I hope that helps maybe give brainliest if it does!

Love,

-Banana

Answer:

Both triangles are congruent.

so 30/36 = 5/6 = 0.83333333333...

35/x  should also be 0.83333333333.. so 35/0.83333333333.. is x

x = 42

Answer:

Part A

The two variables are the amount of pounds that we dont know yet for the nuts and the almonds so we would have to put x for the amount of pounds for pecans and y for the amount of pound for nuts

Part B

2x + 4.50y = 15.25

Step-by-step explanation:

Step-by-step explanation:

x = pounds of pecans bought

y = pounds of almonds bought

x + y = 6

x×2 + y×4.5 = 15.25

x = -y + 6

(-y+6)×2 + y×4.5 = 15.25

-2y + 12 + 4.5y = 15.25

2.5y = 3.25

y = 3.25 / 2.5 = 3 1/4 / 2 1/2 = 13/4 / 5/2 = 13×2 / 4×5 =

= 26/20 = 13/10 = 1.3 pounds

x = -y + 6 = -1.3 + 6 = 4.7 pounds

Cody could buy 4.7 pounds of pecans and 1.3 pounds of almonds.

Answer:

free energy, in thermodynamics, energy-like property or state function of a system in thermodynamic equilibrium. Free energy has the dimensions of energy, and its value is determined by the state of the system and not by its history.

Answer:

4.79 or 4.789

Step-by-step explanation:

the first answer is if you need to round to the nearest hundredth, the second if you need to round to the nearest thousandth. you didn't tell us which was correct so I put both

Answer:

$1.76

Step-by-step explanation:

First we need to figure out the cost of one apple.

To do this, divide the cost by the amount.

That's .65/3, which equals .216666, but we should round that number to .22

So if one apple is 22 cents, and we need to know how much money 8 apples is, we times .22 by 8, which gives us 1.76

Hope this helps :))

At the grocery shop, the cost of 3 apples is $0.65 then the cost of 8 apples is $1.76.

Mathematical actions are called expressions if they have at least two terms that are related by an operator and include either numbers, variables, or both. Adding, subtraction, multiplying, and division are all reflection coefficient operations. A mathematical operation such as reduction, addition, multiplication, or division is used to integrate terms into an expression.

The given information in the question,

The cost of 3 apples = $0.65

The cost of 1 apple = $0.65/3 = $0.22

The cost of 8 apples = $0.22 × 8 = $1.76.

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Answer:

a)x²

5²=25

b] (x+3)²

(5+3)²

(8)²=64

Suppose that one of sides is x :

Area = x²

thus :

[tex]146.41 = {x}^{2} [/tex]

[tex]x = \sqrt{146.41} [/tex]

[tex]x = 12.1[/tex]

_____________________________________________

Perimeter = 4x

[tex]p = 4 \times 12.1[/tex]

[tex]p = 48.4[/tex]

The Perimeter of Square is 48.4 m.

The Area of square is the product of the side.

Area of Square = side x side

and, The Perimeter of Square is 4 times the side of square

Perimeter of Square = 4 x side

Given:

Area of Square = 146.41 m²

Now, Area of Square = side x side

Area of Square  = side²

side² = 146.41 m²

side = √146.41 m²

side = 12.1 m

Now, the Perimeter of Square = 4 x side

                                                   = 4 x 12.1

                                                   = 48.4 m.

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What? hold up my brain hurts! you made me confused!!

Answer:

There are no leaves in the winter except on evergreens and those are green.

Step-by-step explanation:

Answer:

4 1/90

Step-by-step explanation:

I did It so yeah thats it

Answer:

8200/1000 = 8.2 so each time a class selss 8.2 bars, they receive 1 dollar.

If a class sold 16 bars, the class receives 2 dollars, if it sold 82 bars, it receives 10 dollars and so on.

Answer: The radius increases by 0.032 cm/minute.

Step-by-step explanation:

The volume, V, of a sphere is V = (4/3)πr^3.

For the volume to increase at a rate of 10cc (cubic centimeters) per minute, the radius must increase such that the additional radius (r)^3 = 10

V = (4/3)πr^3

V = (4/3)π5^3

V = 524 cc

We add 10 cc to have the balloon hold 544 cc.  We calculate the increase in radius:

534=(4/3)*pi*x^3

We can now calculate the new radius, x.

x = 5.032 cm

The radius increased by 0.032 cm/minute.

Answer:

y=m+p

Step-by-step explanation:

take the p to the other side.

p crosses = sighn and becomes +

hence ans = y=m+ p

Answer:

A woman got on the elevator on the fourth floor. The elevator went down 2 11 floors. Then, the woman got off the elevator. On which floor did the woman exit the elevator

Answer:

The answer is 11 your welcome

Answer:

11

Step-by-step explanation:

Answer:

y= 8

Step-by-step explanation:

y= -x +5

To find the value of y when x= -3, substitute -3 into x and solve the equation.

When x= -3,

y= -(-3) +5

y= 3 +5

y= 8

Answer:

67

Step-by-step explanation:

We plug the 7 for x and -4 for y.

The equation is 9x-y.

So it becomes; 9(7)-(-4)

This will simplify to; 63+4

Which is 67, your answer.

67 is the answer bro good luck

Answer:

below

Step-by-step explanation:

All we need to do is substitute the x values given in the table to find each value of y thats blank.

When x = -1,

y = 2(-1) + 4

y = -2 + 4

y = 2

When x = 1,

y = 2(1) + 4

y = 2 + 4

y = 6

Whe x = 2,

y = 2(2) + 4

y = 4 + 4

y = 8

Best of Luck!

Answer:

4.2

Step-by-step explanation:

simplify 12 and 20 to 6 and 10 then divide 6 by 10 and multiply by 7 to get the answer.

The unit rate or rate of change of gallons per week will be 4.2 gallons/week.

The rate of change is the change of a quantity over 1 unit of another quantity.

Most of the time the rate of change is the change with respect to time.

For example the speed 3meter/second.

As per the given,

12 gallons in every 20 days,

The unit rate per day will be as,

12/20 = 0.6 gallons per day

It is known that, 1 week = 7 days,

Unit rate per week = 0.6 x 7 = 4.2 gallons/week

Hence "The unit rate, often known as the rate of change, will be 4.2 gallons per week".

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Answer:

Step-by-step explanation:

Initial value of house is $478000

Change in value is 8% greater:

We need 8% of Value

[tex]\\ \sf\longmapsto 8\%\:of\;478000[/tex]

[tex]\\ \sf\longmapsto 0.08(478000)[/tex]

[tex]\\ \sf\longmapsto 38240\$[/tex]

Current value:-

[tex]\\ \sf\longmapsto 478000+38240=516240[/tex]

Answer:

1 2/3, and -1 2/3

Step-by-step explanation:

Im wondering how old you are, and since you seem young just based off the math you're asked to do, please listen to the explanation and teach yourself this. This skill in particular is SOOO important to the rest of the math world. So since your number line is already divided into thirds, there are two ways you could find your answer. One, you can count 5 thirds away from zero, or two, you could simplify 5/3 from an improper fraction to a mixed number (1 2/3) and find your spot from there. "and the opposite" means not only the point 5/3 Away from zero on the Right, but also 5/3 away from zero on the Left. start from zero again and count the same amount away but in the opposite direction. With negatives it can help to think of how all numbers are just descriptions of how far left or right a number is from zero. i hope this helped lol, negatives are a confusing batch, but they're so so important to math as a whole.

Answer:

Approximately 11.1666666667 rows

Step-by-step explanation:

134/12= 11.1666666667

Answer:

  12 rows

Step-by-step explanation:

  (134 students) / (12 students/row) = 11 2/12 rows

The 6th-graders will need 12 rows of seats. The last row will not be filled.

Answer:

6250

Step-by-step explanation:

62 hundreds is the same as 62 X 100 which equals 6200.

5 tens is the same as 5 X 10 which equals 50.

And if we add these together, we get a total of 6250

Answer:

Line 1 & 2 is Perpendicular

Line 1 & 3 is Neither

and Line 2 & 3 is Neither

The lines that are parallel continuously have equal distances from each

other and perpendicular lines form 90° angle at their intersection.

The correct responses are;

Reasons:

Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular

[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel where; Slope of [tex]\overline{AB}[/tex] = Slope of [tex]\overline{CD}[/tex]

[tex]\displaystyle \overline{AB} \ and \ \overline{CD} \ are \ perpendicular\ where; \ Slope \ of \ \overline{AB} = -\frac{1}{Slope \ of \ \overline{CD}}[/tex]

[tex]1. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{\frac{13 - 3}{-2 - 0}} = \frac{10}{-2} = -5[/tex]

[tex]\geq \displaystyle Slope \ of \ \overline{CD} = \frac{3 - 0}{10 - (-5)} = \frac{1}{5}[/tex]

[tex]\displaystyle \mathbf{Slope \ of \ \overline{AB}} = -\frac{1}{Slope \ of \ \overline{CD}}[/tex], [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular

[tex]2. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{\frac{7- 1}{3 - (-6)}} = \frac{6}{9} =\frac{2}{3}[/tex]

[tex]\geq \displaystyle Slope \ of \ \overline{CD} = \frac{-5 - (-1)}{-6 - 0} = \frac{-4}{-6}=\frac{2}{3}[/tex]

Slope of [tex]\mathbf{\overline{AB}}[/tex] = Slope of [tex]\overline{CD}[/tex] , [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel

[tex]3. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{ \frac{2- 4}{-6 - (-2)} = \frac{-2}{-4}} =\frac{1}{2}[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \frac{11 - (-7)}{-1 - 5} = \frac{18}{-6}=-3[/tex]

[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neither parallel or perpendicular

[tex]4. \ \displaystyle Slope \ of \ \overline{AB} = \frac{8- 3}{-3 - 2} = \frac{5}{-5} =-1[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \frac{6 - 2}{-4 - (-8)} = \frac{4}{4}=1[/tex]

[tex]\displaystyle Slope \ of \ \overline{AB} = \mathbf{-\frac{1}{Slope \ of \ \overline{CD}}}[/tex], [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular

[tex]5. \ \displaystyle Slope \ of \ \overline{AB} = \frac{-1 - 2}{-8 - (-4)} = \frac{-3}{-4} =\frac{3}{4}[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \mathbf{\frac{-3 - 6}{0 - 12}} = \frac{-9}{-12}=\frac{3}{4}[/tex]

Slope of [tex]\overline{AB}[/tex] = Slope of [tex]\overline{CD}[/tex] , [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel

[tex]6. \ \displaystyle Slope \ of \ \overline{AB} = \frac{5 - (-1)}{6 - 3} = \frac{6}{3} =2[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \mathbf{\frac{-5 - 7}{2 - (-4)}} = \frac{-12}{6}=-2[/tex]

[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neither parallel or perpendicular

Directions: To determine if the equations are parallel or perpendicular

Solution:

The equations are parallel if when expressed in the form, y = m·x  + c, the value of m are equal

The equations are perpendicular, when we have;

[tex]\displaystyle The \ value \ of \ \mathbf{m} \ in \ one \ equation = -\frac{1}{The \ value \ of \ \mathbf{m} \ in \ the \ other\ equation }[/tex]

7. First equation

3·x + 2·y = 6

Therefore; [tex]\displaystyle y = -\frac{3}{2} \cdot x + 3[/tex]

Second equation; [tex]\displaystyle y = \mathbf{-\frac{3}{2} \cdot x + 5}[/tex]

The value of m which is the coefficient of x are both equal to [tex]\displaystyle -\frac{3}{2}[/tex]

Therefore, the equations are parallel

8.  Equation 1; 3·y = 4·x + 15

Therefore;

[tex]\displaystyle y = \frac{4}{3} \cdot x + 5[/tex]

Equation 2; 9·x + 12·y = 12

[tex]\displaystyle y = -\frac{9}{12} \cdot x + 1 = 1 - \frac{3}{4} \cdot x[/tex]

The slope of the equation 2 is the negative inverse of the slope of equation 1, therefore, the equations are perpendicular

9. Equation 1: 8·x - 2·y = 4

Therefore;

y = 4·x - 2

Equation 2: x + 4·y = -12

Therefore;

[tex]\displaystyle y = -\frac{1}{4} \cdot x - 3[/tex]

The slope of the equation 2 is the negative inverse of the slope of equation 1, therefore, the equations are perpendicular.

10. Equation 1: 3·x + 2·y = 10

Therefore;

[tex]\displaystyle y = -\frac{3}{2} \cdot x - 5[/tex]

Equation 2: 2·x + 3·y = -3

[tex]\displaystyle y = -\frac{2}{3} \cdot x -1[/tex]

The slopes of the equation 1 and 2 are not equal, and are not  the negative inverse of each other, therefore, the equations are neither parallel nor perpendicular.

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Answer:

everything but the 4th are true

Step-by-step explanation:

fax

Answer:

B,C,E

Step-by-step explanation:

Answer:

DEF

Step-by-step explanation:

If you turn it and line it up with C on D, B on E, and A on F, the similar line symbols match.

Similar figures are two or more given figures that have some common properties. The answers to the questions are;

14. m<WYZ = [tex]157^{o}[/tex]

15. m<ACB = [tex]87^{o}[/tex]

Two or more figures are said to be similar if they have some common properties. Note that similar figures may not be congruent.

Thus, the solutions to the questions can be determined as follows:

14. Comparing WYZ and VXYZ, we can deduce that:

<WYZ + <YVX = [tex]180^{o}[/tex] (sum of angles on a straight line))

So that;

(16x - 3) + (3x - 7) = [tex]180^{o}[/tex]

19x - 10 = [tex]180^{o}[/tex]

19x = [tex]190^{o}[/tex]

x = [tex]\frac{190}{19}[/tex]

  = [tex]10^{o}[/tex]

Then,

m<WYZ = (16x - 3) = (16(10) -3)

             = [tex]157^{o}[/tex]

The measure of angle WYZ is [tex]157^{o}[/tex].

15. (11x - 2) = (6x + 13)     (similarity property)

11x - 6x = 13 + 2

5x = 15

x = 3

So that;

m<ABC = (6x + 13) = (6(3) + 13)

             = [tex]31^{o}[/tex]

m<ABC = [tex]31^{o}[/tex]

But,

m<BAC + m<ABC + m<ACB = [tex]180^{o}[/tex]  (sum of angles in a triangle)

[tex]62^{o}[/tex] + [tex]31^{o}[/tex] + m<ACB = [tex]180^{o}[/tex]

m<ACB = [tex]180^{o}[/tex] - 93

             = [tex]87^{o}[/tex]

m<ACB = [tex]87^{o}[/tex]

The measure of angle ACB is [tex]87^{o}[/tex].

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Answer:

6x-6

Step-by-step explanation:

(2x+6)+(4x-12)=2x+6+4x-12

                      =6x-6

Answer:

5.83333333333

Step-by-step explanation:  there you go