Simplify:
a.5³×5‐²×5⁴.
b.a⁴×a‐²×x³.
c.(x⁵)²×(y⁵)³
__________
(x³)³×(y²)²
​

Answer:

f(g(x)) =

[tex] {x}^{6} + 6 {x}^{4} + 8x^{2} + 2[/tex]

Step-by-step explanation:

put g(x) instead of any x in f(x)

[tex] {(x ^{2} + 2) }^{3} - 4( {x}^{2} + 2) + 2[/tex]

Answer:

Step-by-step explanation:

x : 100 = 7740 : 98 000 000

x = (7740 * 100)/98 000 000

x = 0.007898 %

A percentage is a hundredth of a number      Then                                                    [tex]\displaystyle\bf \frac{7740}{98\cdot10^6} \cdot100=\frac{387}{49000} \approx 0,00789\%[/tex]                                                      

the way to do these recurring decimals is by firstly separating the repeating part or recurring part and then multiply it by some power of 10 so we move it to the left, lemme show

[tex]3.5\overline{41}\implies \cfrac{35.\overline{41}}{10}\qquad \stackrel{\textit{say that the repe}\textit{ating part is }~\hfill }{x = \overline{0.41}\qquad \qquad \textit{so that }35.\overline{41}=35+\overline{0.41}=35+x}[/tex]

now, let's multiply that repeating part by some power of 10 that moves the 41 to the left, well, we have two repeating decimals, 4 and 1, so let's use two zeros, namely 100 or 10², thus

[tex]100\cdot x = 41.\overline{41}\implies 100x - 41+\overline{0.41}\implies 100x = 41+x\implies 99x=41 \\\\\\ \boxed{x =\cfrac{41}{99}}\qquad \qquad \textit{so then we can say that}~~\cfrac{35.\overline{41}}{10}\implies \cfrac{35+\frac{41}{99}}{10} \\\\\\ \cfrac{~~\frac{3506}{99}~~}{10}\implies \cfrac{~~\frac{3506}{99}~~}{\frac{10}{1}}\implies \cfrac{3506}{99}\cdot \cfrac{1}{10}\implies \cfrac{3506}{990}\implies \blacktriangleright \stackrel{\textit{which simplifies to}}{\cfrac{1753}{495}} \blacktriangleleft[/tex]

Answer:

not sure, sorry : p

Step-by-step explanation:

Answer:

3264:221

Step-by-step explanation:

If by last year there were 221 students and 12 teachers at Hilliard School, then;

221students = 12teachers

To find the equivalent ratio for 272students, we can say;

272students = x teachers

Divide both expressions

221/272 = 12/x

Cross multiply

221 * x = 272 * 12

221x = 3264

x = 3264/221

x = 3264:221

This gives the required proportion

Answer:

[tex]x = \dfrac{1 + i\sqrt{47}}{6}[/tex]   or   [tex]x = \dfrac{1 - i\sqrt{47}}{6}[/tex]

Step-by-step explanation:

[tex] x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]

We have a = 3; b = -1; c = 4.

[tex] x = \dfrac{-(-1) \pm \sqrt{(-1)^2 - 4(3)(4)}}{2(3)} [/tex]

[tex]x = \dfrac{1 \pm \sqrt{1 - 48}}{6}[/tex]

[tex]x = \dfrac{1 \pm \sqrt{-47}}{6}[/tex]

[tex]x = \dfrac{1 + i\sqrt{47}}{6}[/tex]   or   [tex]x = \dfrac{1 - i\sqrt{47}}{6}[/tex]

Answer: D) Increase the sample size and decrease the confidence level.

Step-by-step explanation:

A reduced interval width means that the data is more accurate. This can only be achieved if the sample size is increased because a larger sample size is able to capture more of the characteristics of the variables being tested.

A smaller confidence interval will also lead to a reduced interval width because it means that the chances of the prediction being correct have increased.

Answer:

its to pixelated

Step-by-step explanation:

Answer:

The equation of the line is y=7x

Answer: I believe but not 100% sure

1) C

2) B

Step-by-step explanation:

The pH value of the apple juice is 3.5, option C) is the correct answer.

The pH value of the ammonia is 8.9, option D) is the correct answer.

The pH of a solution is defined as the logarithm of the reciprocal of the hydrogen ion concentration  [H+] of the given solution.

From the formular;

pH = -log[ H⁺ ]

Given the data in the question.

For the Apple juice;

pH = -log[ H⁺ ]

pH = -log[ 0.0003 ]

pH = 3.5

The pH value of the apple juice is 3.5

Option C) is the correct answer.

For the ammonia;

pH = -log[ H⁺ ]

pH = -log[ 1.3 × 10⁻⁹]

pH = 8.9

The pH value of the ammonia is 8.9

Option D) is the correct answer.

Learn more about pH & pOH here: brainly.com/question/17144456

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Answer:

[tex]y\ =\ \ \tan\theta\ +2[/tex]

Step-by-step explanation:

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

[tex]R_{3}[/tex] = (x) = (e^z /4!)x^4

Since the aim is [tex]R_{3}[/tex](x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Answer:

Okay

Step-by-step explanation:

Answer:

[tex]Height = 12cm[/tex]

Step-by-step explanation:

Given

[tex]Volume = 1200cm^3[/tex]

The dimension of the base is:

[tex]Base =10cm[/tex]

[tex]Sides = 13cm[/tex]

See comment for complete question

Required

The height of the base

To do this, we make use of Pythagoras theorem where:

[tex]Sides^2 = (Base/2)^2 + Height^2[/tex]

So, we have:

[tex]13^2 = (10/2)^2 + Height^2[/tex]

[tex]13^2 = 5^2 + Height^2[/tex]

[tex]169 = 25 + Height^2[/tex]

Collect like terms

[tex]Height^2 = 169 - 25[/tex]

[tex]Height^2 = 144[/tex]

Take square roots of both sides

[tex]Height = 12cm[/tex]

Answer:

x = 11

Step-by-step explanation:

I assume you want x, so I simply rearranged the terms, subtracted, and simplified.

Answer:

[tex]P(pink) = P(pink |\ female) = 0.6[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccc}{} & {Male} & {Female} & {Pink} & {156} & {72} \ \\ {Yellow} & {104} & {48} \ \end{array}[/tex]

Required

Why [tex]prefers\ pink\ lemonade[/tex] and [tex]female[/tex] are independent

First, calculate [tex]P(pink |\ female)[/tex]

This is calculated as:

[tex]P(pink |\ female) = \frac{n(pink\ \&\ female)}{n(female)}[/tex]

[tex]P(pink |\ female) = \frac{72}{48+72}[/tex]

[tex]P(pink |\ female) = \frac{72}{120}[/tex]

[tex]P(pink |\ female) = 0.6[/tex]

Next, calculate [tex]P(pink)[/tex]

[tex]P(pink) = \frac{n(pink)}{n(Total)}[/tex]

[tex]P(pink) = \frac{156 + 72}{156 + 72 + 104 + 48}[/tex]

[tex]P(pink) = \frac{228}{380}[/tex]

[tex]P(pink) = 0.6[/tex]

So, we have:

[tex]P(pink) = P(pink |\ female) = 0.6[/tex]

Hence, they are independent

Answer:

P(pink lemonade | female) = P(pink lemonade) = 0.6.

Step-by-step explanation:

A

Answer:

Step-by-step explanation:

Because of the Isosceles Triangle Theorem, the angles across from the congruent sides will be congruent. That means that the angle x also measures 42 degrees.

Answer:

f(x) = (x + 4)^2 - 5

Step-by-step explanation:

Parent function: f(x) = x^2

To show this in a way that may look more familiar, f(x) = 1(x - 0)^2 + 0

Vertex form: f(x) = a(x - h)^2 + k

We know a = 1, because the slope is the same as the parent function.

Vertex: (h,k)

We can see that the vertex of the graph is (-4, -5)

So h = -4 and k = -5

Now all we need to do is plug the variables into our equation.

f(x) = a(x - h)^2 + k

f(x) = 1(x + 4)^2 - 5

f(x) = (x + 4)^2 - 5

Answer:

Step-by-step explanation:

x²-4=0

(x+2)(x-2)=0

x=-2,2

solution is x∈{-2,2}

Answer:

OP = discount amount × 100 / discount %

Step-by-step explanation:

if I understand this correctly, the actual sale price was 36% (100-64) of the originally marked price.

original price (OP) = 100%

64% of OP = 30

1% of OP = 30/64

OP (100%) = 100 × 30/64

this could be simplified to 100 × 15/32, but this hinders is finding the global formula :

OP = discount amount × 100 / discount %

Answer:

29/20 or 1 9/20 or 1.45

Answer:

[tex]\frac{1}{5}+\frac{3}{4}+\frac{1}{2}[/tex]

lease common multiplier of 5,4,2 is 20

[tex]\frac{4}{20}+\frac{15}{20}+\frac{10}{20}[/tex]

[tex]Add\: 4+15+10= 29[/tex]

[tex]1/5+3/4+1/2=29/20[/tex]

[tex]Answer :\frac{29}{20}[/tex]

--------------------------

hope it helps

have a great day!!

Answer:

[tex]\{0, 1, 2, 3\}[/tex] is a partition of Z

Step-by-step explanation:

Given

[tex]$$A _ { 0 } = \{n \in \mathbf { Z } | n = 4 k$$,[/tex] for some integer k[tex]\}[/tex]

[tex]$$A _ { 1 } = \{ n \in \mathbf { Z } | n = 4 k + 1$$,[/tex] for some integer k},

[tex]$$A _ { 2 } = { n \in \mathbf { Z } | n = 4 k + 2$$,[/tex] for some integer k},

and

[tex]$$A _ { 3 } = { n \in \mathbf { Z } | n = 4 k + 3$$,[/tex]for some integer k}.

Required

Is [tex]\{0, 1, 2, 3\}[/tex] a partition of Z

Let

[tex]k = 0[/tex]

So:

[tex]$$A _ { 0 } = 4 k[/tex]

[tex]$$A _ { 0 } = 4 k \to $$A _ { 0 } = 4 * 0 = 0[/tex]

[tex]$$A _ { 1 } = 4 k + 1$$,[/tex]

[tex]A _ { 1 } = 4 *0 + 1$$ \to A_1 = 1[/tex]

[tex]A _ { 2 } = 4 k + 2[/tex]

[tex]A _ { 2} = 4 *0 + 2$$ \to A_2 = 2[/tex]

[tex]A _ { 3 } = 4 k + 3[/tex]

[tex]A _ { 3 } = 4 *0 + 3$$ \to A_3 = 3[/tex]

So, we have:

[tex]\{A_0,A_1,A_2,A_3\} = \{0,1,2,3\}[/tex]

Hence:

[tex]\{0, 1, 2, 3\}[/tex] is a partition of Z

Answer:

A. 96.0 square units

Step-by-step explanation:

The formula for the area of a triangle when we know the side length of two sides and the measure of an included angle of a triangle is given as:

A = ½*a*b*Sin C

Where,

a = 13

b = 15

C = 80°

Plug in the values into the formula

A = ½*13*15*Sin 80

A = 96.0187559

A = 96.0 square units (nearest tenth)

Answer:A

Step-by-step explanation: I took the test

Answer:

a) 83,b) -4,c) 48,d) 16,e) 8

Answer:

94 cm^2

Hope it helps!

Answer:

hello!

where are you from ?

Step-by-step explanation:

option 4 is correct ...there is no constant ratio.

Answer:

yes is correct 6/6 = 1 / 3*2=6 =1

Answer:

nonsense. what's the difference between 6/6 or 1 .

Answer:

There is no actual question here, this is just a statement.

re-read the question .... i assume it says "what is the highest that she will get during a dive?"

highest point is at t = 33/32  

– 16(33/32)^2 + 33(33/32) + 4 =

62.015625

Step-by-step explanation:

Lindsey will be 30 feet in the air at approximately 1.09 seconds and 2.48 seconds.

To find the time at which Lindsey will be 30 feet in the air, we need to solve the quadratic equation y = -16x² + 33x + 45 for x when y = 30.

Setting y equal to 30, we have:

30 = -16x² + 33x + 45

Rearranging the equation, we have:

16x² - 33x - 15 = 0

To solve this quadratic equation, we can factor or use the quadratic formula. In this case, factoring might be more challenging, so we'll use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Plugging in the values from our equation, we have:

x = (-(-33) ± √((-33)² - 4(16)(-15))) / (2(16))

Simplifying, we get:

x = (33 ± √(1089 + 960)) / 32

x = (33 ± √(2049)) / 32

Calculating the square root of 2049, we have:

x = (33 ± √(2049)) / 32

x ≈ 1.09 or x ≈ 2.48

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Complete question is:

Lindsey is a member of the swim team at a local university. She has been working hard to perfect her dive for an upcoming swim meet. Lindsey's dive can be modeled by the quadratic equation y = – 16x² + 33x + 45, where x is time in seconds, and y is Lindsey's height in the air in feet.

At what time will Lindsey be 30 feet in air?

Answer:

Step-by-step explanation:

If a point (x, y) is reflected across y = -x, coordinates of the image point will be,

(x, y)→ (-y, -x)

Following this rule,

Vertices of the triangle will be,

(3, 1) → (-1, -3)

(3, -2) → (2, -3)

(6, -3) → (3, -6)

Therefore, image of the given triangle A will be,

(-1, -3), (2, -3) and (3, -6)