To sketch the graph we have to solve the function with each value of x to get the coordinates.
f(x) = x² − 4x − 5
−2 ≤ x ≤ 6
This inequality represents the domain for x. Therefore x is greater than equal to -2 but less than equal to 6.
The range of x is as follows:
x = -2, -1, 0, 1, 2, 3, 4, 5, 6
We already have the values for x therefore, we must substitute the values of x into the function f(x) = x² − 4x − 5 to find the y values.
Solutions:
For x = -2
f(x) = x² − 4x − 5
= -2² − 4(-2) - 5
= 4 + 8 - 5
= 7
Point = (-2,7)
For x = -1
f(x) = x² − 4x − 5
= -1² - 4(-1) - 5
= 1 + 4 - 5
= 0
Point = (-1,0)
For x = 0
f(x) = x² − 4x − 5
= 0² - 4(0) - 5
= 0 - 0 - 5
= -5
Point = (0,-5)
For x = 1
f(x) = x² − 4x − 5
= 1² - 4(1) - 5
= 1 - 4 - 5
= -8
Point = (1,-8)
For x = 2
f(x) = x² − 4x − 5
= 2² - 4(2) - 5
= 4 - 8 - 5
= -9
Point = (2,-9)
For = 3
f(x) = x² − 4x − 5
= 3² - 4(3) - 5
= 9 - 12 - 5
= -8
Point = (3,-8)
For x = 4
f(x) = x² − 4x − 5
= 4² - 4(4) - 5
= 16 - 16 - 5
= -5
Point = (4,-5)
For x = 5
f(x) = x² − 4x − 5
= 5² - 4(5) - 5
= 25 - 20 - 5
= 0
Point = (5,0)
For x = 6
f(x) = x² − 4x − 5
= 6² - 4(6) - 5
= 36 - 24 - 5
= 7
Point = (6,7)
Coordinates for graph = (-2,7) , (-1,0) , (0,-5) , (1,-8) , (2,-9) , (3,-8) , (4,-5) , (5,0) , (6,7)
These are the points to sketch the quadratic graph.
Situation:
Find the age of
A student in Greece discovers a pottery
bowl that contains 28% of its original
amount of C-14.
Ent
N= Noekt
No
= inital amount of C-14 (at time
t = 0)
N = amount of C-14 at time t
k = 0.0001
t = time, in years
Answer:
Step-by-step explanation:
I'm assuming you need the age of the bowl. Start with the fact that you have remaining 28% of the original amount before any of it decayed. You always start with 100% of something unless you're told differently. That means that the equation looks like this:
[tex]28=100e^{-.0001t}[/tex] and begin by dividing both sides by 100 to get
[tex].28=e^{-.0001t}[/tex] . To solve for t we have to be able to bring it down from its current position of exponential. To do this we would either take the log or the natural log since the rules for both are the same. However, the natural log is the inverse of e, so they undo each other. We take the natural log of both sides which allows us to pull down the -.0001t. At the same time remember that the natural log and e are inverses of each other so they are both eliminated when we do this.
ln(.28) = -.0001t Now it's easy to solve for t.
[tex]\frac{ln(.28)}{-.0001}=t[/tex] and
[tex]\frac{-1.272965676}{-.0001}=t[/tex] so
t = 12729.65676 years or rounded, 12730 years.
On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and point Z is at (5, 5).
What is the perimeter of rhombus WXYZ?
StartRoot 13 EndRoot units
12 units
StartRoot 13 EndRoot units
20 units
Answer:
[tex]P = 4\sqrt{13}[/tex]
Step-by-step explanation:
Given
[tex]W = (7, 2)[/tex]
[tex]X = (5, -1)[/tex]
[tex]Y = (3, 2)[/tex]
[tex]Z =(5, 5)[/tex]
Required
The perimeter
To do this, we first calculate the side lengths using distance formula
[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2[/tex]
So, we have:
[tex]WX = \sqrt{(5- 7)^2 + (-1 - 2)^2[/tex]
[tex]WX = \sqrt{13}[/tex]
[tex]XY = \sqrt{(3-5)^2 + (2--1)^2}[/tex]
[tex]XY = \sqrt{13}[/tex]
[tex]YZ = \sqrt{(5-3)^2 + (5-2)^2}[/tex]
[tex]YZ = \sqrt{13}[/tex]
[tex]ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}[/tex]
[tex]ZW = \sqrt{13}[/tex]
The perimeter is:
[tex]P = WX + XY + YZ + ZW[/tex]
[tex]P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}[/tex]
[tex]P = 4\sqrt{13}[/tex]
Answer:
C on edge 2021
Step-by-step explanation:
I took the cumulative exam
A nunber when divided by 12 gives remainder 7 if the same number is divided by 6 the remainder must be ?
Answer:
1
Step-by-step explanation:
Let the number be n.
We are given:
n/12=q1+(7/12) where q1 is the quotient
n/6=q2+(?/6) where q2 is the quotient and ? is the remainder value we are trying to find.
? must be a integer between 0 and 5, inclusive. A remainder cannot be bigger than or equal to the divisor.
Let's rewrite the first equations
Multiply equation 1 on both sides by 2:
n/6=2q1+7/6
Remainder cannot be 7.
Rewrite again.
6 goes into 7 1 time with remainder 1.
n/6=2q1+(1+1/6)
n/6=(2q1+1)+1/6
So q2=2q1+1 and the remainder is 1 when dividing n by 6.
For fun. What is a number n with such conditions on it?
So what number has remainder 7 when divided by 12 and a remainder 1 when divided by 6.
n=12q1+7
n=6q2+1
If q1=1, we find a number right away that works.
19/12=1+7/12
19/6=3+1/6
Joshua is 1.45 meters tall. At 2 p.m., he measures the length of a tree's shadow to be 31.65 meters. He stands 26.2 meters away from the tree, so that the tip of his shadow meets the tip of the tree's shadow. Find the height of the tree to the nearest hundredth of a meter .
Answer:
height of the tree ≈ 8.42 m
Step-by-step explanation:
The diagram given represents that of two similar triangles. Therefore, the corresponding lengths of the similar triangles are proportional to each other.
height of tree = h
Therefore:
1.45/h = (31.65 - 26.2)/31.65
1.45/h = 5.45/31.65
Cross multiply
h*5.45 = 1.45*31.65
h*5.45 = 45.8925
h = 45.8925/5.45
h ≈ 8.42 m (nearest hundredth)
If 260 people donated $10.00 to an organization how much money would said organization have received in total?
Answer:
$ 2,600
Step-by-step explanation:
It's given that 260 People donated $10 is to an organisation . We need to find the total money received by the organisation .
Here we just need to the number of people with the amount each person gave , that is ;
[tex]\implies \rm Total \ amount = \$ 10 \times 260 \\\\\rm\implies Total \ amount = \$ 2,600 [/tex]
Hence the total money received by the organisation is $ 2600 .
Two particles have positions at time t given by s1=4t-t^2 and s2=5t^2-t^3. Find the velocities
Step-by-step explanation:
Given that,
The positions of the first particle,[tex]s_1=4t-t^2[/tex]
Velocity,
[tex]v_1=\dfrac{ds_1}{dt}\\\\v_1=\dfrac{d(4t-t^2)}{dt}\\\\v_1=4-2t[/tex]
Position,
[tex]s_2=5t^2-t^3[/tex]
[tex]v_2=\dfrac{ds_2}{dt}\\\\v_2=\dfrac{d(5t^2-t^3)}{dt}\\\\v_2=10t-3t^2[/tex]
Hence, this is the required solution.
Which of the following composition of transformations would create an
image that is not congruent to its original image?
A rotation of 45° followed by a reflection across the x-axis
A translation 2 units to the left followed by dilation by 1/2
A reflection across the y-axis followed by a rotation of 60°
A rotation of 135º followed by a translation of 4 units to the right
Click on the photo! Needing help ASAP please!♥️
=============================================================
Explanation:
Choice B has the GCF x we can factor out like so
10x^4-5x^3+70x^2+3x = x(10x^3-5x^2+70x+3)
Showing that choice B is not prime. If a polynomial can be factored, then we consider it not prime. It's analogous to saying a number like 15 isn't prime because 15 = 3*5, ie 15 can be factored into something that doesn't involve 1 as a factor.
In contrast, we consider 7 prime because even though 7 = 1*7, there aren't any other ways to write this integer as a factorization if we don't involve 1.
-----------------------------------
Choice C is a similar story. This time we can factor out 3
3x^2 + 18y = 3(x^2 + 6y)
So we can rule this out as well.
-----------------------------------
Choice D is a bit tricky, but we can use the difference of cubes factoring rule
a^3 - b^3 = (a-b)(a^2+ab+b^2)
where in this case a = x and b = 3y^2
Note how b^3 = (3y^2)^3 = 3^3*(y^2)^3 = 27y^(2*3) = 27y^6
All of this means choice D can be factored and it's not prime either.
------------------------------------
We've ruled out choices B through D. The answer must be choice A.
If you let w = x^2, then w^2 = x^4
The polynomial w^2+20w-100 is prime because setting it equal to zero and solving for w leads to irrational solutions. I'm assuming your teacher wants you to factor over the rational numbers.
Because w^2+20w-100 can't be factored over the rational numbers, neither can x^4+20x^2-100. This confirms that choice A is prime.
Hi can i please get help on this question
Find the volume of this sphere.
Round to the nearest tenth.
16 ft
Formulas for Spheres
[? ] ft
Enter
Answer:
2144
formula us v = 3/4 × pi × half of the diameter (radius)
Find the length of AC. Round to the nearest hundredth if necessary.
i belive the answer is c
A solid wooden block in the shape of a rectangular prism has a length, width and height
Step-by-step explanation:
Volume of the block
[tex] = lbh[/tex]
[tex] = \frac{3}{8} \times \frac{1}{8} \times \frac{5}{8} [/tex]
[tex] = \frac{3 \times 5}{ {8}^{3} } [/tex]
[tex] = \frac{15}{512} [/tex]
Complete the function for this graph.
Answer:
[tex]y=|x-(-2)|+2[/tex]
Step-by-step explanation:
Hope this is helpful.
The required absolute function is given as y = |x - 2| + 2.
Given that,
From the graph, y = |x - h| + k, values of h and k is to be determined,
Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.
Here,
In the graph and function, h represents the shift on the x-axis, which 2 units left so the value of h is 2, while k is given the shift of the function over the y-axis which 2 units up means that k = 2
Thus, The required absolute function is given as y = |x - 2| + 2.
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The Marked price of an article was fixed to Rs 1380 by increasing 15% on its actual price. Find the actual price.
Answer:
The actual price of the article was Rs. 1200.
Step-by-step explanation:
mp (marked price)
ap (actual price)
[tex]mp = 1380[/tex]
[tex]mp = ap + 15\%(ap)[/tex]
[tex]1 380 = ap + \frac{15}{100} ap[/tex]
[tex]1380 = \frac{100}{100} ap + \frac{15}{100} ap[/tex]
[tex]1380 = \frac{115}{100} ap[/tex]
[tex]1380 \div \frac{115}{100} = ap[/tex]
[tex]1380 \times \frac{100}{115} = ap[/tex]
[tex] \frac{138000}{115} = ap[/tex]
[tex]1200 = ap[/tex]
The actual price of the article is given by the equation A = $ 1,200
What is an Equation?
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the actual price of the article be A
Now , the equation will be
The marked price of the article be = $ 1380
The percentage of increase from the actual price = 15 %
So , the equation is
The actual price + percentage of increase from the actual price = 1380
Substituting the values in the equation , we get
A + ( 15/100 )A = 1380 be equation (1)
( 115/100 ) A = 1380
Multiply by 100 on both sides of the equation , we get
115A = 138000
Divide by 115 on both sides of the equation , we get
A = $ 1200
Therefore , the value of A is $ 1200
Hence , the actual price of the article is $ 1200
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Question 5 can I have as much as you can do please
Answer:
x = 12
Step-by-step explanation:
The sum of angles in a triangle is 180°
Thus,
(x + 20) + (10x) + (x + 16) = 180°
Collect like terms
x + 10x + x + 20 + 16 = 180°
12x + 36 = 180°
12x = 180 - 36
12x = 144
Divide both sides by 12
x = 144 ÷ 12
x = 12
Substitute the value of x into the question
Therefore,
x + 20 = 12 + 20
= 32°
10x = 10(12)
= 120°
x + 16 = 12 + 16
= 28°
Find the distance between each pair of points. Round to the nearest tenth if necessary.
(4,2) and (-6, -6)
Answer:
Radical (20)
Step-by-step explanation:
Radical ( (4-6)² + (2-6)²)) =radical ( 4+16) = radical (20)
If a plane can travel 510 miles per hour with the wind and 410 miles per hour against the wind, find the speed of the wind and the speed of the plane in still air.
Answer:
Below.
Step-by-step explanation:
Ok so, Since its 510 - x = 410. Speeds equals the wind.
SO?
100=2x
x=50
410+50 = 460!
What is the range of this set of heights in centimeters? {140, 166, 132, 165, 152, 168, 181, 158, 173, 171, 180, 182, 163, 177, 180, 142, 147, 149, 178} 38 41 46 50
Answer:
50
Step-by-step explanation:
Given:
140, 166, 132, 165, 152, 168, 181, 158, 173, 171, 180, 182, 163, 177, 180, 142, 147, 149, 178
Arranging in ascending order (from the lowest to the highest)
= 132, 140, 142, 147, 149, 152, 158, 163, 165, 166, 168, 171, 173, 177, 178, 180, 180 181, 182
Range = highest number - lowest number
= 182 - 132
= 50
Answer:
50
Step-by-step explanation:
None
To solve the equation t? - t = 12 by factoring, you would use
t(t - 1) = 12
Ott - 1) - 12 = 0
(t - 4)(t + 3) = 0
Answer:
it is what it is
Step-by-step explanation:
Can x3 – 3x + 1 be the quotient on division of x5+ 2x3 + x – 1 by a polynomial in x of degree 3? Justify
Answer:
No
Step-by-step explanation:
x⁵ + 2x³ + x - 1 -> degree of the polynomial is 5
So, when x⁵ is divided by x³, the quotient should be x⁵⁻³ = x².
So, x³ - 3x + 1 cannot be a quotient
Solve the inequality:
[tex]4x+3\ \textgreater \ 19[/tex]
Answer:
x > 4
Step-by-step explanation:
4x + 3 > 19
4x + 3 - 3 > 19 - 3
4x > 16
4x/4 > 16/4
x > 4
Hope this helps.
[tex]4x + 3 > 19 \\ = > 4x > 19 - 3 \\ = > 4x > 16 \\ = > x > \frac{16}{4} \\ = > x > 4[/tex]
Answer:
x > 4
Hope you could understand.
If you have any query, feel free to ask.
Solve for x. Round to the nearest tenth of a degree, if necessary.
Answer:
49.6°Step-by-step explanation:
tangent = opposite / adjacenttan x = 40/34x = arctan (40/34)x ≈ 49.6°Step-by-step explanation:
[tex] \rm{tangent \: = \: opposite \:/ adjacent} \\ \rm{tan \: x \: = \: 40 \:/ 34} \\ \rm \: x \: = arctan \: (40 \:/ 34) \\ \: \rm {x \: = \boxed{49. \: 60°}}[/tex]
could someone help im really bad at polynomials
Answer:2x^2 + 7x - 30
Step-by-step explanation:
1. x(2x-3)(x+3)^2
2. x(2x-3)(x+10)
3. 2x^2+10x-3x-30
4. 2x^2+7x-30
Which relation is a function?
Answer:
the function is the solution is done using the operation
Write the trigonometric expression in terms of sine and cosine, and then simplify.
tan θ/(sec θ − cos θ)
Answer:
[tex]\displaystyle \frac{\tan\theta}{\sec\theta - \cos\theta} = \frac{1}{\sin\theta} = \csc\theta[/tex]
Step-by-step explanation:
We have the expression:
[tex]\displaystyle \frac{\tan\theta}{\sec\theta - \cos\theta}[/tex]
And we want to write the expression in terms of sine and cosine and simplify.
Thus, let tanθ = sinθ / cosθ and secθ = 1 / cosθ. Substitute:
[tex]=\displaystyle \frac{\dfrac{\sin\theta}{\cos\theta}}{\dfrac{1}{\cos\theta}-\cos\theta}[/tex]
Multiply both layers by cosθ:
[tex]=\displaystyle \frac{\left(\dfrac{\sin\theta}{\cos\theta}\right)\cdot \cos\theta}{\left(\dfrac{1}{\cos\theta}-\cos\theta\right)\cdot \cos\theta}[/tex]
Distribute:
[tex]\displaystyle =\frac{\sin\theta}{1-\cos^2\theta}[/tex]
Recall from the Pythagorean Theorem that sin²θ + cos²θ = 1. Hence, 1 - cos²θ = sin²θ. Substitute and simplify:
[tex]\displaystyle =\frac{\sin\theta}{\sin^2\theta} \\ \\ =\frac{1}{\sin\theta}[/tex]
We can convert this to cosecant if we wish.
A certain polygon has its vertices at the following points: (1, 1), (1, 8), (8, 1), and (8, 8)
Answer:
Can u explain more pls?
Step-by-step explanation:
Answer:
Square
Step-by-step explanation:
The driving distance between Manchester and London is 195 miles. Farris wants to travel from Manchester to London on coach. The coach will leave Manchester at 3:30pm. Farris assumes the coach will travel at an average speed of 50mph. work out Farris's arrival time in London?
Answer:
7:24 pm
Step-by-step explanation:
speed = distance/time
time * speed = distance
time = distance/speed
time = (195 miles)/(50 miles/hour)
time = 3.9 hours
The trip will take 3.9 hours.
3 hours + 0.9 hours = 3 hours + 0.9 hours * 60 minutes/hour =
= 3 hours + 54 minutes
The trip will take 3 hours and 54 minutes.
3:30 pm + 3:54 = 6:84 pm = 7:24 pm
Answer: 7:24 pm
What is the equation of the following line? Be sure to scroll down first to see
all answer options
(0,0)
2,-8)
O A. y=-4x
O B. y = 8x
O C. y=-x
D. y = 8
O E. y = 4x
O F. y = 18
Answer:
A
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (2, - 8) ← 2 points on the line
m = [tex]\frac{-8-0}{2-0}[/tex] = [tex]\frac{-8}{2}[/tex] = - 4
The line crosses the y- axis at (0, 0) ⇒ c = 0 , then
y = - 4x + c , that is
y = - 4x → A
The equation of line passes through the points (0, 0) and (2, -8) will be;
⇒ y = - 4x
What is Equation of line?The equation of line in point-slope form passing through the points
(x₁ , y₁) and (x₂, y₂) with slope m is defined as;
⇒ y - y₁ = m (x - x₁)
Where, m = (y₂ - y₁) / (x₂ - x₁)
Given that;
Two points on the line are (0, 0) and (2, -8).
Now,
Since, The equation of line passes through the points (0, 0) and (2, -8).
So, We need to find the slope of the line.
Hence, Slope of the line is,
m = (y₂ - y₁) / (x₂ - x₁)
m = (- 8 - 0) / (2 - 0)
m = - 8 / 2
m = - 4
Thus, The equation of line with slope - 4 is,
⇒ y - 0 = - 4 (x - 0)
⇒ y = - 4x
Therefore, The equation of line passes through the points (0, 0) and
(2, -8) will be;
⇒ y = - 4x
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From the top of a building, 40 feet above the ground, a construction worker locates a rock at a 12° angle of depression. How far is the rock from the building?
Answer:
188 m
Step-by-step explanation:
[tex] \tan(12) = \frac{40}{x} \\ x = \frac{40}{ \tan(12) } \\ x = 188[/tex]
Answer:
I think that the other answer is WRONG
tan(12) = [tex]\frac{x}{40}[/tex]
x = tan(12)*40 = 8.5
Step-by-step explanation:
[tex]\frac{sin\left(78\right)}{40}=\frac{sin\left(12\right)}{x}[/tex] = 8.5
Solve. Algebra 1
14=4-6x-2
Answer:
Step-by-step explanation:
resolver. Álgebra 1
14=4-6x-2
4-6x-2 : 2
Rpta: 2
Monica purchased adult and youth tickets for the fair. She bought x adult tickets for $28 each and y youth tickets for $15. Write an expression that can be
used to show the total cost, C, of all tickets.
O C = (28 + 15)x
OC = (28 + 15)(x + y)
O C = 28x + 15y
O C = 28y + 15x
Answer: =28x + 15y
Step-by-step explanation:
