Answer:
Slope = 6
Step-by-step explanation:
Use the slope formula:
[tex]m=\frac{y_1-y_2}{x_1-x_2}\\m=\frac{-4-8}{3-5}\\m=\frac{-12}{-2}\\m=6[/tex]
Answer:
6
Step-by-step explanation:
(3,-4) and (5,8)
To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)
Plug in these values:
(8 - (-4)) / (5 - 3)
Simplify the parentheses.
= (8 + 4) / (5 - 3)
= (12) / (2)
Simplify the fraction.
12/2
= 6
This is your slope.
Hope this helps!
Simplify the expression 35e^9/5e^8
[tex] \frac{35e {}^{9} }{5 {e}^{8} } \ \\ \\ \frac{7e {}^{9} }{e {}^{8} } \\ \\ \\ = 7e[/tex]
Step By Step Explanation:
Reduce: Reduce the fraction with 5Simplify: Simplify the expressionAlternate Forms:
19.02797☆彡Hanna5. Solve: 9(36 – 2) - 2 =
I can’t figure this out
Answer:
The correct answer is:304
Step-by-step explanation:
Use the order of operations to simplify the expression
(5.4)² - 5.4²
Answer:
0
Step-by-step explanation:
(5.4)^2 - 5.4^2
= 5.4^2 - 5.4^2
= 5,4^2(1 - 1)
= 5.4^2(0)
= 0
Let f(x)=x2+10x+37 .
What is the vertex form off(x)?
What is the minimum value off(x)?
Enter your answers in the boxes.
Vertex form: f(x)=
Minimum value of f(x):
Answer:
f(x) = (x+5)^2 +12
The minimum value is 12
Step-by-step explanation:
f(x)=x^2+10x+37
The vertex will be the minimum value since this is an upwards opening parabola
Completing the square by taking the coefficient of x and squaring it adding it and subtracting it
f(x) = x^2+10x + (10/2) ^2 - (10/2) ^2+37
f(x) = ( x^2 +10x +25) -25+37
= ( x+5) ^2+12
Th is in vertex form y = ( x-h)^2 +k where (h,k) is the vertex
The vertex is (-5,12)
The minimum is the y value or 12
Find the area of the circle. Round your answer to the nearest tenth.
Answer:
254.47 mm
Step-by-step explanation:
The measure of angle S is 65 degrees.
What is the measure of angle R?
RS
A
115°
B.
230°
с
65°
D
25°
Answer:
A. 115°
Step-by-step explanation:
180° - 65° = 115°
If f(x)= 10 sin(x) – 3 then f (30%) = ?
A) - square root 3/2 -3
B.) 2
C.) -5/2
D.) 4/3 - square root 3/2
Answer:
The value of f(30) is equal to 2.
Step-by-step explanation:
The given expression is :
[tex]f(x)= 10 \sin(x) - 3[/tex]
We need to find the value of f(30)
Put x = 30 in above expression.
So,
[tex]f(x)= 10 \sin(30) - 3\\\\=10\times \dfrac{1}{2}-3\\\\=5-3\\\\=2[/tex]
Hence, the value of f(30) is equal to 2.
Question 4
1 pts
An initial population of 910 quail increases at an annual rate of 20%. Write an exponential function to model the quail
population.
Answer:
910*(1.2)^t
Step-by-step explanation:
Given data
Initial population= 910 quail
Rate= 20%
Let us use the model below
A= P(1+r)^t
r= 0.2
A= 910(1+0.2)^t
A= 910*(1.2)^t
Hence the expression to model the population is 910*(1.2)^t
An initial population of 910 quail increases at an annual rate of 20%.
So,
910*(1.2)^t
Step-by-step explanation:
Given data
Initial population= 910 quail
Rate= 20%
Let us use the model below
A= P(1+r)^t
r= 0.2
A= 910(1+0.2)^t
A= 910*(1.2)^t
Hence the expression to model the population is 910*(1.2)^t.
What is the exponential function?An exponential function is a mathematical function of the following form: f ( x ) = an x. where x is a variable, and a is a constant called the base of the function. The most commonly encountered exponential-function base is the transcendental number e, which is equal to approximately 2.71828.
Learn more about exponential function at
https://brainly.com/question/2456547
#SPJ2
Write the equation of the trigonometric graph.
Answer(s):
[tex]\displaystyle y = 3sin\: (1\frac{1}{2}x + \frac{\pi}{2}) - 2 \\ y = 3cos\: 1\frac{1}{2}x - 2[/tex]
Explanation:
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{3}} \hookrightarrow \frac{-\frac{\pi}{2}}{1\frac{1}{2}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}\pi} \hookrightarrow \frac{2}{1\frac{1}{2}}\pi \\ Amplitude \hookrightarrow 3[/tex]
OR
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}\pi} \hookrightarrow \frac{2}{1\frac{1}{2}}\pi \\ Amplitude \hookrightarrow 3[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 3sin\: 1\frac{1}{2}x - 2,[/tex] in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{pi}{3}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACK [tex]\displaystyle \frac{\pi}{3}\:unit,[/tex] which means the C-term will be negative, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{3}} = \frac{-\frac{\pi}{2}}{1\frac{1}{2}}.[/tex] So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 3sin\: (1\frac{1}{2}x + \frac{\pi}{2}) - 2.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [0, 1],[/tex] from there to [tex]\displaystyle [1\frac{1}{3}\pi, 1],[/tex] they are obviously [tex]\displaystyle 1\frac{1}{3}\pi\:unit[/tex] apart, telling you that the period of the graph is [tex]\displaystyle 1\frac{1}{3}\pi.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -2,[/tex] in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts horisontally, the midline will ALWAYS follow.
I am delighted to assist you at any time.
Only answer if you're very good at Math.
What is the minimum value of the function g(x) = x^2 - 6x - 12?
A: -21
B: 3-√21
C: 3
D:3+ √21
Answer:
A: -21
Step-by-step explanation:
Vertex of a quadratic function:
Suppose we have a quadratic function in the following format:
[tex]f(x) = ax^{2} + bx + c[/tex]
It's vertex is the point [tex](x_{v}, y_{v})[/tex]
In which
[tex]x_{v} = -\frac{b}{2a}[/tex]
[tex]y_{v} = -\frac{\Delta}{4a}[/tex]
Where
[tex]\Delta = b^2-4ac[/tex]
If a<0, the vertex is a maximum point, that is, the maximum value happens at [tex]x_{v}[/tex], and it's value is [tex]y_{v}[/tex].
In this question:
Quadratic function:
[tex]g(x) = x^2 - 6x - 12[/tex]
So [tex]a = 1, b = -6, c = -12[/tex].
Minimum value:
This is the y-value of the vertex. So
[tex]\Delta = b^2-4ac = (-6)^2 - 4(1)(-12) = 36+48 = 84[/tex]
[tex]y_{v} = -\frac{\Delta}{4a} = -\frac{84}{4} = -21[/tex]
The minimum value is -21, and the correct answer is given by option A.
Given the function f(x) = 4x - 2, explain and show how to find the average rate of change between x = 2 and x = 4.
Answer:
The average rate of change between x = 2 and x = 4 is of 4.
Step-by-step explanation:
Average rate of change:
The average rate of change of a function f(x) in an interval [a,b] is given by:
[tex]A = \frac{f(b)-f(a)}{b-a}[/tex]
In this question:
[tex]f(x) = 4x - 2, b = 4, a = 2[/tex]
Thus:
[tex]f(b) = f(4) = 4(4) - 2 = 16 - 2 = 14[/tex]
[tex]f(a) = f(2) = 4(2) - 2 = 8 - 2 = 6[/tex]
Average rate of change:
[tex]A = \frac{f(b)-f(a)}{b-a}[/tex]
[tex]A = \frac{14-6}{4-2}[/tex]
[tex]A = \frac{8}{2}[/tex]
[tex]A = 4[/tex]
The average rate of change between x = 2 and x = 4 is of 4.
The Grade 8 students had a graduation dinner. They paid a flat rate of $125 for the use of the hall, plus $13 for each student who attended. The total cost for the dinner was $944.
How many students attended the dinner?
a) Write an equation you could use to solve the problem.
b) Solve the equation.
Verify the solution.
CAN SOMEONE GIVE ME THE ANSWERS AND EXPLANATION FOR THIS QUESTION IN SIMPLE FORM PLEASEEEEEEEEE I CANT FAIL
Answer:
65
Step-by-step explanation:
33. Given the following algebraic expression 5x² + 10 Which statement is true?
a. The coefficient is 5
b. The constant is 2
C. The power is 10
d. The constant is 5
Answer:
Given the following algebraic expression 5x² + 10 Which statement is true?
a. The coefficient is 5. ( true)
b. The constant is 2
C. The power is 10
d. The constant is 5
How do i do this math equasion?
Answer:
f(t) = -16t² + 36
Step-by-step explanation:
f(t) = a(t - h)² + k
This is vertex form where (h, k) is the (x, y) coordinate of the vertex
The vertex is give as (0, 36)
f(t) = a(t - 0)^2 + 36
f(t) =at² + 36
use point (1, 20) to find "a"
20 = a(1²) + 36
20 = a + 36
-16 = a
f(t) = -16t² + 36
Write an equation. Let x be the unknown number.
10 is the sum of three and twice a number
Answer:
10 = 3 + 2x
Step-by-step explanation:
twice the number is 2x
the sum of 2x and 3 is written as 2x + 3
2x + 3 =10
Kern Shipping Inc. has a requirement that all packages must be such that the combined length plus the girth (the perimeter of the cross section) cannot exceed 99 inches. Your goal is to find the package of maximum volume that can be sent by Kern Shipping. Assume that the base is a square.
a. Write the restriction and objective formulas in terms of x and y. Clearly label each.
b. Use the two formulas from part (a) to write volume as a function of x, V(x). Show all steps.
Answer:
Step-by-step explanation:
From the given information:
a)
Assuming the shape of the base is square,
suppose the base of each side = x
Then the perimeter of the base of the square = 4x
Suppose the length of the package from the base = y; &
the height is also = x
Now, the restriction formula can be computed as:
y + 4x ≤ 99
The objective function:
i.e maximize volume V = l × b × h
V = (y)*(x)*(x)
V = x²y
b) To write the volume as a function of x, V(x) by equating the derived formulas in (a):
y + 4x ≤ 99 --- (1)
V = x²y --- (2)
From equation (1),
y ≤ 99 - 4x
replace the value of y into (2)
V ≤ x² (99-4x)
V ≤ 99x² - 4x³
Maximum value V = 99x² - 4x³
At maxima or minima, the differential of [tex]\dfrac{d }{dx}(V)=0[/tex]
[tex]\dfrac{d}{dx}(99x^2-4x^3) =0[/tex]
⇒ 198x - 12x² = 0
[tex]12x \Big({\dfrac{33}{2}-x}}\Big)=0[/tex]
By solving for x:
x = 0 or x = [tex]\dfrac{33}{2}[/tex]
Again:
V = 99x² - 4x³
[tex]\dfrac{dV}{dx}= 198x -12x^2 \\ \\ \dfrac{d^2V}{dx^2}=198 -24x[/tex]
At x = [tex]\dfrac{33}{2}[/tex]
[tex]\dfrac{d^2V}{dx^2}\Big|_{x= \frac{33}{2}}=198 -24(\dfrac{33}{2})[/tex]
[tex]\implies 198 - 12 \times 33[/tex]
= -198
Thus, at maximum value;
[tex]\dfrac{d^2V}{dx^2}\le 0[/tex]
Recall y = 99 - 4x
when at maximum x = [tex]\dfrac{33}{2}[/tex]
[tex]y = 99 - 4(\dfrac{33}{2})[/tex]
y = 33
Finally; the volume V = x² y is;
[tex]V = (\dfrac{33}{2})^2 \times 33[/tex]
[tex]V =272.25 \times 33[/tex]
V = 8984.25 inches³
What is the unit rate for the following point?
(7, 1 3/4)
Answer:
Step-by-step explanation:
7
The pyramid shown below has a square base, a height of 7, and a volume of 84 cubic units.
What is the length of the side of the base?
12
36
6
18
Tom drank 5 cups of coffee. How many pints of coffee did he drink?
A. 4.5
B. 3.5
C. 2.5
D. 1.5
Answer:
B .3.5 points of coffee did he drink
hope it helps
Is this the correct answer?
Answer:
Correct.
Step-by-step explanation:
It looks good to me.
Good job!
3. What is the value of LC in the diagram?
A
4x
(2x
B
3x
С
O A. 90°
O B. 60°
O C. 80°
OD. 40°
Answer: B
Step-by-step explanation:
4x+3x+2x=180
9x = 180
x = 20
20x3 = 60
plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz help me i really do need the help
Each of the problems below was solved incorrectly, for each problem, find the mistake in the work/ answer. Explain what the mistake is, and find the correct answer.
Explain the mistake:
Find the correct answer(equation):
2. Find the value of x
Explain the mistake:
Find the correct answer(equation):
3. Find the value of x
Explain the mistake:
Find the correct answer(equation):
Question 1
The mistake is that vertical angles are congruent, and don't always add up to 180 degrees.[tex]5x=100 \longrightarrow x=20[/tex]Question 2
Angles that add to form a right angle add to 90 degrees, not 180 degrees.[tex]3x+39=90 \longrightarrow 3x=51 \longrightarrow x=17[/tex]Question 3
Angles that add to form a right angle add to 90 degrees, not 180 degrees.[tex]3x+39=90 \longrightarrow 3x=51 \longrightarrow x=17[/tex]Need help for this please
Answer:
i think 471.24cm³?
i just found the volume for both the cylinder and cone and added them together.
can someone help me please?! I'll give brainlest for correct answer
Answer:
MBE, REU, XBy, XEW, BER is an acute angle
WRU, RUm, XBM is an obtuse angle
RU, XE, Mm, ME, MU, WE, XB, MB, My is a straight angle
BM, BE, BX, By is an angle of vertex B.
I don’t know (for e)
BER: REB
I don’t know (for g)
EBy and XBM are two supplementary angles.
Step-by-step explanation:
Find the volume V and surface area S of a
rectangular box with length 2 meters, width 6 meters,
and height 9 meters.
Answer:
Surface area add together all 6 sides = 24+36+108=168m^2
Volume L x W x D = 2 x 6 x 9 = 108 m ^3
Step-by-step explanation:
2 x 6 = 12
12 x 2 = 24 base and top
2 x 9 = 18
2 x 18 = 36 identical pair sides
6 x 9 = 54
2 x 54 = 108 identical pair sides
Surface area add together all 6 sides = 24+36+108=168m^2
Volume L x W x D = 2 x 6 x 9 = 108 m ^3
5/6 multiples by 10/11
Answer:
0.757... (recurring)
Step-by-step explanation:
5 10 50
_ x _ = _
6 11 66
50/66 = 0.757...
:D
Answer:
50/66
Step-by-step explanation:
[tex](\frac{5}{6})(\frac{10}{11}) = \frac{50}{66}[/tex]
Have a great day!
Help please this question is hard!
9514 1404 393
Answer:
B, C, A, D
Step-by-step explanation:
The depths are easier to compare if they are all in the same form. Here, it is convenient to use decimal numbers rounded to hundredths. Your calculator can help with the fractions if you are not familiar with decimal equivalents.
A: -1.6 m = -1.60 m
B: -4/3 m ≈ -1.33 m
C: -1.36m = -1.36 m
D: -17/9 m ≈ -1.89 m
Then the least deep site is the one with the depth number closest to 0.
In order from least to greatest depth, the sites are ...
B (-1.33) > C (-1.36) > A (-1.60) > D (-1.89)
Answer:
yeah
Step-by-step explanation:
Which of the following values could be an absolute value?
Answer:
Step-by-step explanation: It could be 8,7, or 2. Because these are all positive
:)
please answer thank you
Answer:
37 / 16
Step-by-step explanation:
_____________________
24)
Evaluate:
(-4) - (-16) + (-10) - (-1) - (14) + (11)
Answer:
I think its 0.
Step-by-step explanation:
Double negatives make a positive, add the like terms. Hope this helps
