Solve 4(x - 3) - 2(x - 1) > 0.

A. {x | x < -5}
B. {x | x > -5}
C. {x | x > 5}
D. {x | x < 5}

Answers

Answer 1

Answer:

Apply the distributive property.

4

x

+

4

3

2

(

x

1

)

>

0

Multiply

4

by

3

.

4

x

12

2

(

x

1

)

>

0

Apply the distributive property.

4

x

12

2

x

2

1

>

0

Multiply

2

by

1

.

4

x

12

2

x

+

2

>

0

Answer 2
SoLuTiOn➝

Given:- 4(x - 3) - 2(x - 1) > 0.

Solving It:-

4(x - 3) - 2(x - 1) > 0

4x - 12 - 2x + 2 > 0

2x -10 > 0

2x > 10

x > 10/2

x > 5

So Correct Solution Set Will Be:-

C. {x | x > 5}Hope This Helps You

Related Questions

simplify: 5 (6 - ab) + 2 (-7 + 3ab)

Answers

Answer:

30-5ab-14+6ab

16-ab ans

Answer:

[tex] \boxed{ab + 16} [/tex]

Step-by-step explanation:

5 (6 – ab) + 2 (-7 + 3ab)

[distribution property]

(6)(5) – (ab)(5) + (-7)(2) + (3ab)(2)

30 – 5ab – 14 + 6ab

[group like terms]

(6ab – 5ab) + (30 – 14)

ab + 16

Question 6 of 10
How much would $500 invested at 6% interest compounded monthly be
worth after 5 years? Round your answer to the nearest cen
(0) - P(144
A $674,43
B. $886,41
C, 5669.11
D. $512,68

Answers

9514 1404 393

Answer:

  A.  $674.43

Step-by-step explanation:

The account balance is given by ...

  A = P(1 +r/12)^(12t) . . . . . principal P invested at annual rate r for t years

  A = $500(1 +0.06/12)^(12·5) = $500(1.005^60)

  A ≈ $674.43

1. What is the sum of 3/4 and 4/5?

Answers

3/4 + 4/5 =
15/20 + 16/20 = 31/20
= 1 and 11/20

Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0

Answers

Answer:

[tex]{ \tt{ {x}^{2} + {y}^{2} - 6x - 2y + 4 = 0 }} [/tex]

Center:

[tex]{ \tt{(3, \: 1)}}[/tex]

Radius:

[tex]{ \tt{radius = \sqrt{ {g}^{2} + {f}^{2} - c } }} \\ = \sqrt{36 + 4 - 4} \\ = 6 \: units[/tex]

Keith used the following steps to find the inverse of f, but he thinks he made a error
f(x) = 7x + 5

Answers

Answer:

Step-by-step explanation:

[tex]\Large \boldsymbol{} f(x) \ \ inverse \ \ function \ \ (f(x))^{-1} \\\\ y=7x+5 \\\\x=7y+5 \\\\ y=\dfrac{x-5}{7} \ \ or \ \ f(x)^{-1}= \dfrac{x-5}{7}[/tex]

If triangle LMQ is similar to triangle LNP, calculate the length of segment LP.

Answers

Answer:

LP = 15

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

[tex]\frac{LM}{LN}[/tex] = [tex]\frac{LQ}{LP}[/tex] , substitute values

[tex]\frac{4}{10}[/tex] = [tex]\frac{LQ}{LQ+QP}[/tex]

[tex]\frac{2}{5}[/tex] = [tex]\frac{LQ}{LQ+9 }[/tex] ( cross- multiply )

5LQ = 2(LQ + 9) = 2LQ + 18 ( subtract 2LQ from both sides )

3LQ = 18 ( divide both sides by 3 )

LQ = 6

Then

LP = LQ + QP = 6 + 9 = 15

Find the measure of the missing angle using the triangle angle sum theorm.

Answers

Answer:

65°

Step-by-step explanation:

The sum of angles in a triangle =180

53°+62°+?°=180°

115°+?°=180°

?°=180°-115°

Rate the answer If you love everything I did n explanation

Answer:

65 degrees

Step-by-step explanation:

Angles in a triangle add up to 180, so 180 - 53 - 62 = 65.

what is the quotient

Answers

Answer:

The quotient is 4x+5  and  the remainder is -13

Step-by-step explanation:

Using synthetic division

-5        4      25   12

Bringing down the 4 and multiplying

-5        4      25   12

        ↓       -20 -25

    ----------------------

         4        5    -13

The quotient is 4x+5  and  the remainder is -13

Answer:

  4x   +5    [tex]\frac{-13}{x+5}[/tex]

Step-by-step explanation:

          .           4x   +5    [tex]\frac{-13}{x+5}[/tex]

x + 5 | 4x^2 + 25x + 12

        - 4x^2 + 20x

                         5x + 12

                         5x + 25

                               -13

can someone help me with the question?​

Answers

Corndogs broo likeee everyone knows this

Is this true or false

Answers

Answer:

I say it's TRUE

Step-by-step explanation:

I hope this help you

I assume that it’s true

tanA × cosecA = secA​

Answers

Step-by-step explanation:

L.H.S

tanA * cosecA

=sinA/cosA * 1/sinA

now cancel sinA and sinA

then,

1/cosA

= secA

= RHS

hence proved

a) Arrange the following numbers so that the sum of any two neighbouring numbers is a perfect square.
7 , 11 , 9 , 14 , 16 , 2 , 25
Ex. 3+6 = 3^2 and 6+10 = 4^2

b) Find a way to arrange all of the intervenes from 1 to 17 to a list with the property from part a)

Answers

I'll do part (a) to get you started.

One possible answer to part (a) is 25,11,14,2,7,9,16

There are likely other possible answers.

The explanation is below.

==============================================================

Let's say 7 is the anchor value and we want to see which values could be its next door neighbor.

It can't be 11 since 7+11 = 18 isn't a perfect square.But 9 works because 7+9 = 16 is a perfect square (4^2 = 16)14 doesn't work because 7+14 = 21 isn't a perfect square16 doesn't work either since 7+16 = 23 isn't a perfect square2 however does work since 7+2 = 9 is a perfect squareLastly, 25 won't work because 7+25 = 32 isn't a perfect square

To summarize this subsection, the anchor value 7 could have the neighbors 9 and 2.

So we could have 2,7,9 or 9,7,2 as a subsequence. We'll keep this in mind for later.

------------------------------------------------

Now we'll make 11 the anchor. We already checked 7 and it doesn't work.

9 doesn't work either because 11+9 = 20 isn't a perfect square

11+14 = 25 does work11+16 = 27 doesn't work11+2 = 13 doesn't work11+25 = 36 does work

Of that list, only 14 and 25 are possible neighbors of the anchor value 11.

So we could have the subsequence 14,11,25 or 25,11,14.

------------------------------------------------

If 9 is the anchor, then,

9+7 = 16 works like we found earlier (section 1)9+11 = 20 doesn't work9+14 = 23 doesn't work9+16 = 25 does work9+2 = 11 doesn't work9+25 = 34 doesn't work

The values 7 and 16 are possible neighbors of 9. We could have the subsequence 7,9,16 or 16,9,7

Let's go back to the subsequence 2,7,9 and tack 16 at the end to get 2,7,9,16

------------------------------------------------

If 14 is the anchor, then,

7 doesn't work because 14+7 = 2111 does work either because 14+11 = 259 doesn't work because 14+9 = 2316 doesn't work because 14+16 = 302 does work because 14+2 = 1625 doesn't work since 14+25 = 39

We could have the subsequence 11,14,2 or 2,14,11

Let's go with the first option and stick "11,14,2" in front of "2,7,9,16" to end up with the larger subsequence 11,14,2,7,9,16

We can then stick 25 at the front because 25+11 = 36 is a perfect square.

------------------------------------------------

So one possible sequence of values is 25,11,14,2,7,9,16

Here's the verification

25+11 = 36 is a perfect square (6^2 = 36)11+14 = 25 is a perfect square (5^2 = 25)14+2 = 16 is a perfect square (4^2 = 16)2+7 = 9 is a perfect square (3^2 = 9)7+9 = 16 is a perfect square (4^2 = 16)9+16 = 25 is a perfect square (5^2 = 25)

Each pair of adjacent terms add up to a perfect square, so the answer is confirmed.

There are probably other solutions as well.

Side note: The video math channel "Numberphile" has a video discussing this topic in which you might be interested in. Search out "The square sum problem" with quotes (the presenter/teacher in the video is Matt Parker).

Answer:

25, 11, 14, 2, 7, 9, 16.

Step-by-step explanation:

25 + 11 = 6^2

11 + 14 = 5^2

14 + 2 = 4^2

2 + 7 = 3^2

7 + 9 = 4^2

9 + 16 = 5^2

Explain this to me I don't understand

Answers

Answer:

26.124

Step-by-step explanation:

SOH CAH TOA

tan 43 = about 0.933

than times it by 28 and get

26.124

what is 3^-8 x 3^-4 x 3^-2

Answers

Answer:

Value of given expression is 3⁻¹⁴

Step-by-step explanation:

Given expression:

3⁻⁸ x 3⁻⁴ x 3⁻²

Find:

Value of given expression

Computation:

⇒ 3⁻⁸ x 3⁻⁴ x 3⁻²

⇒ 3[⁻⁸⁻⁴⁻²]

⇒ 3⁻¹⁴

Value of given expression is 3⁻¹⁴

*Please Help!*

What is the volume of water, to the nearest tenth of a cubic metre, that would fill this spa tub?

First cylinder= 0.75m diameter, 0.80m height

Cylinder Underneath= 1.25m diameter, 0.70m height

Semi Sphere that holds both cylinders= 3m long

Answers

Answer:

The volume of water that will fill the spa tub is 5.9 cubic meters.

Step-by-step explanation:

Volume of water that would fill the spa tub = volume of semi sphere - (volume of the first cylinder + volume of the second cylinder)

i. volume of first cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h

where r is the radius and h is the height of the cylinder.

r = [tex]\frac{0.75}{2}[/tex] = [tex]\frac{3}{8}[/tex]

 = 0.375 m

h = 0.80 m

volume of the first cylinder = [tex]\frac{22}{7}[/tex] x [tex](\frac{3}{8} )^{2}[/tex] x 0.8

                                        = 0.3536 cubic meters

ii. volume of the cylinder underneath = [tex]\pi[/tex][tex]r^{2}[/tex]h

r = [tex]\frac{1.25}{2}[/tex] = [tex]\frac{5}{8}[/tex]

 = 0.625

h = 0.70 m

volume of the cylinder underneath = [tex]\frac{22}{7}[/tex] x [tex](\frac{5}{8}) ^{2}[/tex] x 0.7

                                                      = 0.8594 cubic meters

iii. volume of the semi sphere = [tex]\frac{2}{3}[/tex] [tex]\pi[/tex][tex]r^{3}[/tex]

where r is the radius = 1.5 m

volume of the semi sphere = [tex]\frac{2}{3}[/tex] x [tex]\frac{22}{7}[/tex] x [tex](1.5)^{3}[/tex]

                                             = 7.0714 cubic meters

Thus,

volume of the water to fill the spa tub = 7.0714 - (0.3536 + 0.8594)

                                                     = 5.8584

The volume of water that will fill the spa tub is 5.9 cubic meters.

please me in the math
Find the H.C.F
[tex] {x}^{2} - 4 \\ {x}^{3} + 8 \\ {x}^{2} + 5x + 6[/tex]
​it so simple

Answers

Step-by-step explanation:

Solution

First equation x ² - 4

= (x+2) (x-2)

Second equation = x ³ +8 + = x³+2^3

= (x-2) (x² + x₁2 +2²) = (x-2) (x² + 2x+4)

3 Third equation = x ² + 5x + 6

= x² + 6x= x +6 = x(x+6)-1(x+6)

(x-1) (x+6)

H.C. F= x-2

Which number produces a rational number when added to 0.25? ​

Answers

The step of adding it to 0.25 (or 25/100, or 1/4) is indeed not relevant. 0.25 is rational.

A rational number added to a rational number gives a rational number. A rational added to an irrational number doesn't.

so effectively the task can be reduced to "wich one of these is a rational number?"

And that's only true for A. 2/9

All others can't be represented as a discrete/finite fraction / ratio.

The sum of two rational numbers is a rational number thus option (A) is correct.

What is an irrational number?

Any real number that cannot be written as the quotient of two integers, p/q, where p and q are both integers, is referred to as an irrational number.

For example, √2, and √3 are irrational numbers because they cannot be written as p/q where p and q both should be integers.

The sum of two rational numbers gives the rational number.

Since 2/9 is written in p/q where 2 and 9 both are integers thus it will be rational.

So, 2/9 + 0.25 = 2/9 + 1/4

(8 + 9)/36 = 17/36 here 17 and 36 both are integers thus it will be rational.

Hence "A rational number is the result of two rational numbers".

For more about the irrational number,

https://brainly.com/question/4031928

#SPJ2

Gary's income and expenses in a month are 4,000 and 3,360 respectively.
a) What percentage of his income are expenses?
b) What percentage of his income is savings?
(SHOW YOUR WORK!)

Answers

Answer:

84%

Step-by-step explanation:

3360/4000=.84

.84=84%

state the dimensions of the matrix. identify the indicated element​

Answers

Answer:

D; 2 * 3; -4

Step-by-step explanation:

The dimension of the matrix refers to the number of elements in a row multiplied by the number of elements is a column

In a row, we have 2 elements, in a column , we have 3 elements

So the matrix is of 2 * 3 dimension

a21, refers to the element in the matrix that is in the row 2 column 1 and that is -4

Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 ​ p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus, 5 p=p=p, equals

Answers

Given:

The given equation is:

[tex]16-3p=\dfrac{2}{3}p+5[/tex]

To find:

The value of p.

Solution:

We have,

[tex]16-3p=\dfrac{2}{3}p+5[/tex]

Multiply both sides by 3.

[tex]3(16-3p)=3\left(\dfrac{2}{3}p+5\right)[/tex]

[tex]48-9p=2p+15[/tex]

Isolating the variable terms, we get

[tex]48-15=2p+9p[/tex]

[tex]33=11p[/tex]

Divide both sides by 11, we get

[tex]\dfrac{33}{11}=p[/tex]

[tex]3=p[/tex]

Therefore, the required solution is [tex]p=3[/tex].

Answer:

p=3

Step-by-step explanation:

i got it right on khan

A block is being dragged along a horizontal surface by a constant horizontal force of size 45 N. It covers 8 m in the first 2 s and 8.5 m in the next 1 s. Find the mass of the block.

Answer: 15kg

Can anyone please explain this sum with proper working? ​

Answers

Answer:

Solution: To determine mass of the block we can use second Newton' law \vec F=m\vec a

F

=m

a

. The force and acceleration according the problem is directed along a horizontal surface, and we can omit the vector sign in Newton's law. The force we know F=45NF=45N, thus we should deduce the acceleration. The problem does not specify the initial speed at which time began to count, so for the first time interval, we may write the kinematics equation in the form

(1) S_1=v_1\cdot t_1+a\frac {t_1^2}{2}S

1

=v

1

⋅t

1

+a

2

t

1

2

, where S_1=8m, t_1=2s S

1

=8m,t

1

=2s , other quantities we don't know. The similar equation we can write for next time interval

(2) S_2=v_2\cdot t_2+ a\frac{t_2^2}{2}S

2

=v

2

⋅t

2

+a

2

t

2

2

. where S_2=8.5m, t_2=1s S

2

=8.5m,t

2

=1s

Note that during the first time interval, the speed of the block increased in accordance with the law of equidistant motion and it became the initial speed of the second interval, i.e.

(3) v_2=v_1+a\cdot t_1v

2

=v

1

+a⋅t

1

Substitute (3) to (2) we get

(4) S_2=(v_1+a\cdot t_1)\cdot t_2+ a\frac{t_2^2}{2}=v_1\cdot t_2+a\cdot t_1\cdot t_2+a\frac{t_2^2}{2}S

2

=(v

1

+a⋅t

1

)⋅t

2

+a

2

t

2

2

=v

1

⋅t

2

+a⋅t

1

⋅t

2

+a

2

t

2

2

From equation (1) and (4) we can exclude unknown quantity v_1v

1

, then remain only one unknown aa. For determine aa we dived (1) by t_1t

1

, (4) by t_2t

2

to find the average speed at time intervals and subtract (1) from (4).

(5) \frac {S_2}{t_2}-\frac {S_1}{t_1}=v_1+a\cdot t_1 +a\frac {t_2}{2}-(v_1+a\frac{t_1}{2})=a\frac{t_1+t_2}{2}-

t

2

S

2

t

1

S

1

=v

1

+a⋅t

1

+a

2

t

2

−(v

1

+a

2

t

1

)=a

2

t

1

+t

2

− For acceleration we get

(6) a=2\cdot ( {\frac{S_2}{t_2}-\frac{S_1}{t_1})/(t_1+t_2)}=2\cdot \frac{(8.5m/s-4m/s)}{3s}=3ms^{-2}a=2⋅(

t

2

S

2

t

1

S

1

)/(t

1

+t

2

)=2⋅

3s

(8.5m/s−4m/s)

=3ms

−2

For mass from second Newton's law we get

(7) m=\frac{F}{a}=\frac{45N}{3ms^{-2}}=15kgm=

a

F

=

3ms

−2

45N

=15kg

Answer: The mass of the block is 15 kg

Urgent i need help!!…….

Answers

Answer:

Step-by-step explanation:

These are similar triangles. We know that because we know that all right triangles are similar. The height of the red one is 8 and the height of the blue one is 4; that means that the red one is twice the size of the blue one; likewise, the blue one is half the size of the red one. That means that ALL the measurements of these triangles exist in that ratio...even the base of the blue one. If the base of the red one is 3, and the red one is twice the size of the blue one, then the base of the blue one is 3/2 or 1.5. I can't see your choices because they are too small.

it should be 1.5……………. if it’s wrong sorry

A cash register at a store contains $277 bills. There are six more $5 bills than $10 bills. The number of $1bills is two more than 24 times the number of $10 bills. How many bills of each kind are there

Answers

Answer: See explanation

Step-by-step explanation:

Your question isn't well written, the store contains $227 and not $277.

let c be the number of $1 bills

let f be the number of $5 bills

let t be the number of $10 bills.

Therefore, the equation will be:

1c + 5f + 10t = 227

Since there are six more $5 bills than $10 bills, therefore,

f = t+6

Also, the number of $1 bills is two more than 24 times the number of $10 bills and this will be:

c = 24t + 2

Now, we substitute the equation for f and c into the main equation and this will be:

1c + 5f + 10t = 277

1(24t + 2) + 5(t + 6) + 10t = 227

24t + 2 + 5t + 30 + 10t = 227

39t + 32 = 227

39t = 227 - 32

39t = 195

t = 195/39

t = 5

Therefore, there are 5 $10 bills

Since c = 24t + 2

c = 24(5) + 2

c = 120 + 2

c = 122

Therefore, there are 122 $1 bills

Since f = t+6

f = 5+6

f = 11

Therefore, there are 11 $5 bills.

What is the perimeter of the rectangular narrow on the aircraft carrier HMS Queen Elizabeth

Answers

Answer:

dddjshsbs zhzusushwbsgzyzhsbssbs s hsbd d dhd ssbshebebs shyshs s sbshss s s

Step-by-step explanation:

shshshsnsnsjzj shsjs s sjsn s s snsnsbzbznnz ssjs s snsnsmkzkxnz

There is meters on the end right over here in the picture I marked could you tell me what the number is there so I could do the problem (comment on this answer and I will reply back) or you could also do it your self I wrote down how to do it on the picture. Let me know if it helps!

v=u + 2at
Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the
acceleration (in m/s?) and t is the time in seconds).
Find v when u is 35 m/s, a is 28 m/s2, and t is 58 seconds.

Answers

Answer:

3283m/s

Step-by-step explanation:

V=U+2at

V=35+2(28)(58)

V=35+3248

V=3283m/s

a line has slope 3 and y-intercept 4

Answers

Answer:

y = 3x+4

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

y = 3x+4

Complete table of values

Answers

Step-by-step explanation:

here's the answer to your question

Explain how to solve 5^(x-2)= 8 using the change of base formula

Answers

Answer:

x = 3.3

Step-by-step explanation:

A equation is given to us and we need to solve out for x. The given equation is ,

[tex]\sf\longrightarrow 5^{x -2}= 8 [/tex]

Take log on both sides with base as " 10" . We have ,

[tex]\sf\longrightarrow log_{10} 5^{x-2}= log_{10}\ 8[/tex]

Simplify using the property of log , [tex]\sf log a^m = m log a [/tex] , we have ,

[tex]\sf\longrightarrow ( x -2) log_{10} 5 = log_{10} 8 [/tex]

Simplify ,

[tex]\sf\longrightarrow ( x -2 ) log_{10}5 = log_{10} 2^3[/tex]

Again simplify using the property of log ,

[tex]\sf\longrightarrow (x-2) log 5 = 3 log 2[/tex]

We know that log 5 = 0.69 and log 2 = 0.301 , on substituting this , we have ,

[tex]\sf\longrightarrow ( x - 2 ) = \dfrac{ 3\times 0.301}{0.69}[/tex]

Simplify the RHS ,

[tex]\sf\longrightarrow x - 2 = 1.30 [/tex]

Add 2 both sides ,

[tex]\sf\longrightarrow \boxed{\blue{\sf x = 3.30}}[/tex]

Hence the Value of x is 3.30 .

Answer:

its actually 3.292 because we round to the nearest thousandth and thats not even the equation you use above

Step-by-step explanation:

For this equation we use the formula log a^m=m (log a) so the equation will be written as log 5 (5^x-2) = log 5 (8). You use the base, which is 5, and use log to base 5 on both sides of the equation. Then you take the exponent " x-2" and write( x-2) log 5 (5) = log 5(8). Since log a =1, you multiply that 1 by x-2, which keeps it x-2. Making the equation x-2 = log 5 (8). Next, we use the change of the base properties with the formula log b^y= log y/ log b. The equation will be written as x-2 = log 8/ log 5, since 5 is the base it stays in the bottom or basement. We then add +2 to both sides of x-2 and log 8/ log 5. To solve this equation, you can find out what log 8 and log 5 are and divide those and add +2 to solve. So log 8 = 0.903 and log 5 = 0.698970 and divide those to get 1.29190 +2 and you get the answer rounded as 3.292. 

Can someone help me with this math homework please!

Answers

Answer:

Below

Step-by-step explanation:

From the graph the first local minimum is -16.18

The local maximum is 3.75

The second local minimum is -3.

Answer:

Over the interval (-3,0), the local minimum is -16.18Over the interval  [0,3], the local maximum is -3.75Over the interval [0,3], the minimum is -3

----------------------

Hope it helps..

Have a great day!!

expand this question (x+5)(x-3)

Answers

X•x + x•-3 + 5•x +5•-3
X^2+-3x+5x+-15
X^2+2x-15
Other Questions
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