Solve each system by graphing.

Answer:

(a) 129600 J

(b) 81000 J

Step-by-step explanation:

The work done is given by the product of force and the displacement in the direction of force.

Force, F = 500 N

distance, d = 324 m

(a) friction force, f = 100 N

The work done is

W = (F - f) x d

W = (500 - 100) x 324

W = 129600 J

(b) Friction, f = 250 N

The work done is

W = (F - f) d

W = (500 - 250) x 324

W = 81000 J

Answer:

The answer is "0.1397".

Step-by-step explanation:

[tex]\mu=3511\\\\[/tex]

variance [tex]\ S^2= 253,009\\\\[/tex]

standard deviation [tex]\sigma =\sqrt{253,009}=503\\\\[/tex]

Finding the probability in which the weight will be less than [tex]4617 \ grams\\\\[/tex]

[tex]P(X<4617)=p[z<\frac{4617-3511}{503}]\\\\[/tex]  

                      [tex]=p[z<\frac{1106}{503}]\\\\=p[z< 2.198]\\\\= .013975\approx 0.1397[/tex]

Answer:

[tex]LCM = 21[/tex]

Step-by-step explanation:

Given

[tex]-\frac{3}{5}y + \frac{1}{7}= \frac{1}{3}y -\frac{2}{3}[/tex]

Required

LCM of the constant terms

Collect like terms

[tex]\frac{1}{3}y+\frac{3}{5}y = \frac{1}{7}+\frac{2}{3}[/tex]

The constant terms are on the right-hand side

To combine them, we simply take the LCM of the denominator, i.e. 7 and 3

The prime factorization of 3 and 7 are:

[tex]3 = 3[/tex]

[tex]7 = 7[/tex]

So:

[tex]LCM = 3 * 7[/tex]

[tex]LCM = 21[/tex]

Answer:

[tex]f(x)=\sqrt[3]{x}[/tex]  [tex]3~units\: down[/tex]

[tex]f(x)=\sqrt[3]{x} -3[/tex] [tex]8 \: units \: left[/tex]

[tex]f(x+8)=\sqrt[3]{(x+8)} -3[/tex]

----------------------------

Hope it helps..

Have a great day!!

Answer:

its not B that what i put and i missed it

Step-by-step explanation:

Answer:

Red on the 5th draw = 0.0907

Step-by-step explanation:

The first to fourth selections are all the same.

Blue + white = 12 + 6 = 18

The total number of marbles is 11 + 12 + 6 = 29

P(~ red) for the first four times = (18/29)^4 = 0,1484

Now on the 5th time, the first red is 11/18

So the Probability is 0.1484 * 11/18 = 0.0907

Answer:

n = 2

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 30 = n / 2 sqrt(3)

2 sqrt(3) tan 30 = n

2 sqrt(3) * sqrt(3)/3 = n

2 = n

We have to find,

The required value of n.

Now we can,

Use the trigonometric functions.

→ tan(θ) = opp/adj

Let's find the required value of n,

→ tan (θ) = opp/adj

→ tan (30) = n/2√3

→ n = 2√3 × tan (30)

→ n = 2√3 × √3/3

→ n = 2√3 × 1/√3

→ [n = 2]

Thus, the value of n is 2.

Answer:

There is not enough information to determine the mean, the median is 28.

There is not enough information to determine the mean absolute deviation, the interquartile range is 18

Step-by-step explanation:

The box plot given has a skewed distribution, this means that both the mean and median values are not the same. From a box plot, the median value Can be obtained as the point in between the box.

From the box plot given, the marked point in between the box is 28 cm

Hence, Median = 28 cm

The mean cannot be inferred from the skewed box plot.

There is also not enough information to determine the mean absolute deviation ;

The interquartile range:

(Q3 - Q1)

Q3 = upper quartile, the endpoint of the box = 40

Q1 = the starting point of the box = 22

IQR = Q3 - Q1

IQR = 40 - 22 = 18

the value of Zis 8.

Z =2^3=8

Now we have to,

find the required value of Z.

→ Z = 2^3

→ [Z = 8]

Therefore, value of Z is 8.

Answer:

7x^2 -35x +7

Step-by-step explanation:

7(x^2 – 5x + 1)

Distribute

7x^2 -7*5x +7*1

7x^2 -35x +7

Answer:

c= none of the above

Step-by-step explanation:

-3x- 6/10

This has two separate terms, a term with a variable

-3x  and a term with a constant -6/10

A=3/6x1/10  This has only one term

b=- 3/10x-6  This has a different x term -3/10  which is not -3

c= none of the above

Answer:

A) x = 0.

B) f is concave up for (-∞, 0).

C) f is concave down for (0, ∞).

Step-by-step explanation:

We are given the function:

[tex]f(x)=5+12x-x^3[/tex]

A)

We want to find the x-coordinates of all inflection points.

Recall that inflections points (may) occur when the second derivative equals zero. Hence, find the second derivative. The first derivative is given by:

[tex]f'(x) = 12-3x^2[/tex]

And the second:

[tex]f''(x) = -6x[/tex]

Set the second derivative equal to zero:

[tex]0=-6x[/tex]

And solve for x. Hence:

[tex]x=0[/tex]

We must test the solution. In order for it to be an inflection point, the second derivative must change signs before and after. Testing x = -1:

[tex]f''(-1) = 6>0[/tex]

And testing x = 1:

[tex]f''(1) = -6<0[/tex]

Since the signs change for x = 0, x = 0 is indeed an inflection point.

B)

Recall that f is concave up when f''(x) is positive, and f is concave down when f''(x) is negative.

From the testing in Part A, we know that f''(x) is positive for all values less than zero. Hence, f is concave up for all values less than zero. Our interval is:

[tex](-\infty, 0)[/tex]

C)

From Part A, we know that f''(x) is negative for all values greater than zero. So, f is concave down for that interval:

[tex](0, \infty)[/tex]

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Answer:

  A)  (2, ∞) . . . . or C) (-∞, 0) ∪ (2, ∞) if you don't think about it

Step-by-step explanation:

We want ...

  C(x)/x < 100

  (20x +160)/x < 100

  20 +160/x < 100 . . . . . separate the terms on the left

  160/x < 80 . . . . . . . subtract 20

  160/80 < x . . . . . multiply by x/80 . . . . . assumes x > 0

  x > 2 . . . . . . simplify

In interval notation this is (2, ∞).   matches choice A

__

Technically (mathematically), we also have ...

  160/80 > x . . . . and x < 0

which simplifies to x < 0, or the interval (-∞, 0).

If we include this solution, then choice C is the correct one.

_____

Comment on the solution

Since we are using x to count physical items, we want to assume that the practical domain of C(x) is whole numbers, where x ≥ 0, so this second interval is not in the domain of C(x). That is, the average cost of a negative number of items is meaningless.

Answer:

B

Step-by-step explanation:

The square root function's graph is graph (b). This makes logical sense, because, when taking the square root (the principal root in particular), a general rule is that both the input and the output must be positive. Moreover, if one were to create a table of values to find points on the graph of the function, each of the points can be found on graph (b).

[tex]f(x)=\sqrt{x}[/tex]

x         y

1          1

4         2

9         3

16        4

Therefore graph (B) is the correct answer.

Answer:

13/16 miles per minute

Step-by-step explanation:

Take the miles and divide by the minutes

1/8 ÷ 2/13

Copy dot flip

1/8 * 13/2

13/16 miles per minute

Answer:

t2 = 2.5 hours.

Step-by-step explanation:

The distance is the same.

d = r * t

The rates and times are different so

t1 = 3 hours

t2 = X

r1 = 50 mph

r2 = 60 mph

r1 * t1 = r2*t2

50 * 3 = 60 * t2

150 = 60 * t2

150 / 60 = t2

t2 = 2.5

Answer:

Answer: Travel Time is 2 hours & 30 minutes

Step-by-step explanation:

Original Journey Time is 3 hours, Speed is 50 mph, Distance is 150 miles

Original Distance is 150 miles, New Speed is 60 mph.

Also Combined Distance was 300 miles, Combined Time was 5 hours & 30 minutes. therefore: Average Speed for complete round trip is 54. 54 mph

Answer:

-11

Step-by-step explanation:

I am going to assume that it is -x^2-5y^3.

-(4^2)-5(-1^3)

-16-5(-1)

-16+5

-11

Answer:

- 11

Step-by-step explanation:

If x = 4,  y = -1

then,

        - x^2 - 5y^3 = - (4)^2 - 5(-1)^3

                            = - 16 + 5

                            = - 11

Answer:

Step-by-step explanation:

If we are looking for the time(s) that the ball is at a height of 15, we simply sub in a 15 for the height in the position equation and solve for t:

[tex]15=-16t^2+23t+7[/tex] and

[tex]0=-16t^2+23t-8[/tex]

Factor this however you factor a quadratic in class to get

t = .59 seconds and t = .85 seconds.

This means that .59 seconds after the ball was thrown into the air it was 15 feet off the ground. Then the ball reached its max height, gravity took over, and began pulling it back down to earth. The ball passes the height of 15 feet again on its way down after .85 seconds.

Answer:

[tex]\displaystyle \frac{d}{dx}[x^2] = 2x[/tex]

General Formulas and Concepts:

Calculus

Differentiation

Basic Power Rule:

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle y = x^2[/tex]

Step 2: Differentiate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Answer:

Step-by-step explanation:

The area to be resurfaced is the area of the

whole circle including garden and lanes minus  

the area of the garden.

Area of a circle is (pi)r2

radius of garden is (1/2)diameter = 8 m

Garden area:  (pi)82 = 64(pi) m2

Diameter of garden plus traffic lanes is

16 + 2(6) because we add 6 m to both sides

of the diameter of the garden.

Full diameter = 16+12 = 28 m

Full radius = 28/2 = 14 m

Full area:  (pi)142 = 196(pi) m2

Area to be resurfaced:

196(pi) - 64(pi) = 132(pi) m2  ≅ 415 m2

Answer:

Using the slope intercept formula, we can see the slope of line p is ¼. Since line k is perpendicular to line p it must have a slope that is the negative reciprocal. (-4/1) If we set up the formula y=mx+b, using the given point and a slope of (-4), we can solve for our b or y-intercept. In this case it would be 17.

Answer:

x=10

Step-by-step explanation:

Using the Rational Roots Test, we can say that the potential rational roots are

± (1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90).

Unfortunately, there doesn't really seem to be an easy way to figure out which numbers are actually roots outside of guess and check. Therefore, to solve this, we'll have to go through numbers until we hit something.

To make the process faster, I wrote a Python script as follows:

numbers = [1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90]

negative_numbers = [i * (-1) for i in numbers]

numbers = numbers + negative_numbers

for i in numbers:

   if (i**3 - 10*(i**2) + 9*i-90) == 0:

       print(i)

The result comes out as 10, meaning that 10 is our only rational root. Using the Factor Theorem, we can say that because 10 is a root, (x-10) is a factor of the polynomial. Using synthetic division, we can divide (x-10) from the polynomial to get

10 |   1     -10     9      -90

    |          10     0       90

    _________________

        1       0     9        0

Therefore, we can say that

(x³-10x²+9x-90)/(x-10) = (x²+0x+9), so

x³-10x²+9x-90 = (x-10)(x²+9)

As the only solution to x²+9=0 contains imaginary numbers, x=10 is the only solution to x³-10x²+9x-90 = (x-10)(x²+9) = 0

Answer: (760 - 676. 40) × 100 ÷ 760 = 11%

Step-by-step explanation:

Answer:

11% decrease

Step-by-step explanation:

Concepts:

Solving:

Let's find the percent change by using the formula.

1. Formula for Percent Change

2. Plug in the values of NV and OV

3. Simplify

Therefore, our percent decrease is 11% decrease.

Answer:

732 samples ;

752 samples

Step-by-step explanation:

Given :

α = 90% ; M.E = 0.03 ; p = 0.58 ; 1 - p = 1 - 0.58 = 0.42

Using the relation :

n = (Z² * p * (1 - p)) / M.E²

Zcritical at 90% = 1.645

n = (1.645² * 0.58 * 0.42) / 0.03²

n = 0.65918769 / 0.0009

n = 732.43076

n = 732 samples

B.)

If no prior estimate is given, then p = 0.5 ; 1 - p = 1 - 0.5 = 0.5

n = (Z² * p * (1 - p)) / M.E²

Zcritical at 90% = 1.645

n = (1.645² * 0.5 * 0.5) / 0.03²

n = 0.67650625 / 0.0009

n = 751.67361

n = 752 samples

Complete Question

The quality control manager at a computer manufacturing company believes that the mean life of a computer is 91 months with a standard deviation of 10 months if he is correct. what is the probability that the mean of a sample of 68 computers would differ from the population mean by less than 2.08 months? Round your answer to four decimal places. Answer How to enter your answer Tables Keypad

Answer:

[tex]P(-1.72<Z<1.72)=0.9146[/tex]

Step-by-step explanation:

From the question we are told that:

Population mean \mu=91

Sample Mean \=x =2.08

Standard Deviation \sigma=10

Sample size n=68

Generally the Probability that The  sample mean  would differ from the population mean

P(|\=x-\mu|<2.08)

From Table

[tex]P(|\=x-\mu|<2.08)=P(|z|<1.72)[/tex]

T Test

[tex]Z=\frac{\=x-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]

[tex]Z=\frac{2.08}{\frac{10}{\sqrt{68} } }[/tex]

[tex]Z=1.72[/tex]

[tex]P(|\=x-\mu|<2.08)=P(|z|<1.72)[/tex]

[tex]P(-1.72<Z<1.72)[/tex]

Therefore From Table

[tex]P(-1.72<Z<1.72)=0.9146[/tex]

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Answer:

  3

Step-by-step explanation:

AB is 1 unit long.

A'B' is 3 units long.

The scale factor is the ratio of these lengths:

  scale factor = A'B'/AB = 3/1 = 3

ABC is dilated by a factor of 3 to get A'B'C'.

Hi there!

[tex]\large\boxed{x = 60^o}[/tex]

We know:

∠AGB ≅ ∠DGC because they are vertical angles. They both are 90°.

∠AGE ≅ FGC because they are vertical angles, equal 30°.

∠BGF ≅ ∠DGE are vertical angles, both equal x.

All angles sum up to 360°, so:

360° = 90° + 90° + 30° + 30° + x + x

Simplify:

360° = 240° + 2x

Subtract:

120°  = 2x

x = 60°

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Answer:

  see attached

Step-by-step explanation:

The graph of g(x) is a vertically scaled version of the graph of f(x). The scale factor is 1/2, so vertical height at a given value of x is 1/2 what it is for f(x). This will make the graph appear shorter and fatter than for f(x).

The graph of g(x) is attached.

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Answer:

  C.  h ≥ 1.9 in

Step-by-step explanation:

As the final step, divide both sides of the inequality by 5.3:

  (5.3h)/5.3 ≥ 10/5.3

  h ≥ 1.9

Answer:

XW = 78

Step-by-step explanation:

Both triangles are similar, therefore based on triangle similarity theorem we have the following:

XW/XZ = VW/YZ

Substitute

XW/6 = 104/8

XW/6 = 13

Cross multiply

XW = 13*6

XW = 78