Solve for x. Round to the nearest tenth, if necessary.

Answer:

[tex](13)\ 1 <x < 15[/tex]

[tex](14)\ 6 <x < 18[/tex]

Step-by-step explanation:

Question 13:

[tex]a,b = 8,7[/tex] -- the two sides

Using triangle inequality theorem, we have:

[tex]a + b > x[/tex]

[tex]a + x > b[/tex]

[tex]x + b > a[/tex]

So, we have:

[tex]a + b > x[/tex]

[tex]8 + 7 > x[/tex]

This gives:

[tex]15 > x[/tex]

[tex]a + x > b[/tex]

[tex]8 + x > 7[/tex]

Collect and evaluate like terms

[tex]x > -1[/tex]

[tex]x + b > a[/tex]

[tex]x + 7 > 8[/tex]

Collect and evaluate like terms

[tex]x > 1[/tex]

Ignore the inequality with a negative value.

So, we have:

[tex]x > 1[/tex] and [tex]15 > x[/tex]

Rewrite as:

[tex]1< x[/tex] and [tex]x < 15[/tex]

Merge

[tex]1 <x < 15[/tex]

Question 14:

[tex]a,b = 12,6[/tex] -- the two sides

Using triangle inequality theorem, we have:

[tex]a + b > x[/tex]

[tex]a + x > b[/tex]

[tex]x + b > a[/tex]

So, we have:

[tex]a + b > x[/tex]

[tex]12 + 6 > x[/tex]

This gives:

[tex]18 > x[/tex]

[tex]a + x > b[/tex]

[tex]12 + x > 6[/tex]

Collect and evaluate like terms

[tex]x > -6[/tex]

[tex]x + b > a[/tex]

[tex]x + 6 > 12[/tex]

Collect and evaluate like terms

[tex]x > 6[/tex]

Ignore the inequality with a negative value.

So, we have:

[tex]x > 6[/tex] and [tex]18 > x[/tex]

Rewrite as:

[tex]6< x[/tex] and [tex]x < 18[/tex]

Merge

[tex]6 <x < 18[/tex]

Answer:

Explanation is in the attachment

hope it is helpful to you

[tex]\boxed{ \sf{Answer}} [/tex]

[tex]3(x + 11) + 5 = 68 \\ 3x + 33 + 5 = 68 \\ 3x + 38 = 68 \\ 3x = 68 - 38 \\ 3x = 30 \\ x = \frac{30}{3} \\ x = 10[/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

[tex] \huge\boxed{\mathfrak{Answer}}[/tex]

[tex]3(x + 11) + 5 = 68 \\ 3 \times x + 3 \times 11 + 5 = 68 \\ 3x + 33 + 5 = 68 \\ 3x + 33= 68 - 5 \\ 3x + 33= 63 \\ 3x = 63 - 33 \\ 3x = 30 \\ x = \frac{30}{3} \\ x = 10[/tex]

Answer:

To change a number from scientific notation to standard form, move the decimal point to the left (if the exponent of ten is a negative number), or to the right (if the exponent is positive). You should move the point as many times as the exponent indicates. Do not write the power of ten anymore

Answer:

In step 2, the subtraction property of equality was applied

In step 4, the division property of equality was applied

Step-by-step explanation:

Jerry has been stressing a lot for getting into his favorite college. The symptom by which he is reacting to stress is 'upset stomach'.

Stress can lead to a lot of emotional and physical negative responses in the body. This includes difficulty breathing, panic attacks, blurred eyesight or sore eyes, sleep problems, fatigue, muscle aches and headaches, chest pains and high blood pressure, Indigestion or heartburn, constipation, feeling sick, dizzy or fainting.

When Jerry stayed up late at night to get in some extra study time, had a mental burden of passing an entrance exam, a lot of stress was built. He reacted to it with an upset stomach just like others.

Learn more about reacting to stress here

https://brainly.com/question/14973731

#SPJ2

Answer:

I think it's 155 cm

Step-by-step explanation:

=(5×5×3)+(5×2×4)

= 75+40

= 155 cm2

Answer: hello there here is your answer:

7%

Step-by-step explanation:

if you divide the difference between the two numbers it will give you a decimal ....you need to convert that decimal into a percent which is 7%

hope this help have a good day bye

Answer:

the other person is correct

Step-by-step explanation:

Answer:

- 2 and - 2

Step-by-step explanation:

let the 2 numbers be x and y , then

x + y = - 4 → (1)

x - y = 0 → (2)

Add the 2 equations term by term to eliminate y

2x + 0 = - 4

2x = - 4 ( divide both sides by 2 )

x = - 2

Substitute x = - 2 into either of the 2 equations and solve for y

Substituting into (1)

- 2 + y = - 4 ( add 2 to both sides )

y = - 2

The 2 numbers are - 2 and - 2

Answer:

[tex]x1 = \frac{ - 3 - \sqrt{33} }{2} \\ x2 = \frac{ - 3 + \sqrt{33} }{2} [/tex]

Step-by-step explanation:

[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ = \frac{ - 3 + - \sqrt{9 + 24} }{2} \\ x1 = \frac{ - 3 - \sqrt{33} }{2} \\ x2 = \frac{ - 3 + \sqrt{33} }{2} [/tex]

Answer:

<ABD = 42 degrees

<ABC = 84 degrees

Step-by-step explanation:

<ABC = 42 + 42 = 84

Answer:

1) Less than

2) greater than

Step-by-step explanation:

Equation of the first line:

(y+7)/(-13+7) = x/-1

(y+7))/-6 = -x

y+7 = 6x

y= 6x - 7

Equation of the second line:

A (4/3,0) ; B (0,8)

y/8 = (x-4/3)/-4/3

y/8 = (x-4/3) * -3/4

y/8 = -3/4x + 1

y = -6x + 8

Answer:

prime numbers only have two factors...

7 is the only prime in the list

Step-by-step explanation:

Answer:

UJ

Step-by-step explanation:

The side that is opposite angle E is  UJ

Since this is a triangle, we use the corners that do not touch the angle, U and J and the segment is the one that connects them

Answer:

The two answers would have to be equivalent

Step-by-step explanation:   6  30  8  13

Paul  x + y = 30

Steve a + b = 30       are not the same but are equivalent

Their answers could be the same ratio

Paul  4x + 4y = 120

Steve x + y = 30         again not the same but are equivalent

Answer:

Daylily: $9

Geranium: $2

Step-by-step explanation:

1 daylily costs x.

1 geranium costs y.

11x + 4y = 107

4x + 12y = 60

Multiply the first equation by 3 and subtract the second equation from it.

29x = 261

x = 9

4x + 12y = 60

4(9) + 12y = 60

12y = 24

y = 2

Answer:

Daylily: $9

Geranium: $2

Answer:

1) Set up a system of equations. Assign each plant a variable. I used X for Daylillies and Y for Geraniums. In this case:

11x + 4y = 107

4x + 12y = 60

2) Get one variable by itsef. You can choose to either get the X or the Y by itself. For the sake of ease, I'll go with achieving X.

3) Using the equation 4x + 12y = 60, isolate the 4x.

4x = -12y + 60

4) Divide both sides by 4.

x = -3y + 15

5) X is isolated. Now plug in that isolated X into another remaining equation in order to isolate Y. Don't forget to combine like terms.

11(-3y + 15) + 4y = 107

-33y + 165 + 4y = 107

-29y + 165 = 107

-29y = -58

y = 2

6) You have your Y, which means that each Geranium costs $2 each. Now, you need to find X. Plug in Y into any of the first two equations that we started with.

4x + 12(2) = 60

4x + 24 = 60

4x = 36

x = 9

7) You now have both X and Y. Daylillies cost $9 each, and Geraniums cost $2 each.

8) You can double-check your answers by plugging in your final X and Y values into any of the first equations you wrote. If it comes out equal, it works.

Answer:

-4/15

Step-by-step explanation:

Mathematically, we know that;

alpha= -b/a and beta = c/a

a refers to the coefficient of the x^2 which is 2

b is the coefficient of x which is 3

c is the last number which is 5

alpha = -b/a = -3/2

beta = c/a = 5/2

1/alpha = -2/3

1/beta = 2/5

so we have the sum as;

-2/3 + 2/5

= -5(2) + 3(2)/15 = (-10 + 6)/15 = -4/15

Step-by-step explanation:

solve for what ?? do you mean graph the function??

Answer:

The height of the school building is approximately 21.06 meters

Step-by-step explanation:

The method of Geometry Tyler is using to determine the height of his school building is through the property that similar triangles have a common ratio of corresponding their sides

The given parameters for the triangle formed by Tyler and the mirror are;

The distance from Tyler's eyes to the ground = 1.15 meters

The horizontal distance between Tyler and the mirror at X = 0.8 m

The parameters of the triangle formed by the height, h, of the school building and the mirror at X are;

The horizontal distance between the school building and the mirror = 14.65 m

The height of the school building = h

Therefore, we have;

[tex]\dfrac{The \ distance \ from \ Tyler's \ eyes \ to \ the \ ground}{The \ height \ of the \ school \ building} =\dfrac{Tyler's \ horizontal \ distance \ from \ mirror }{The \ building \ to \ mirror \ horizontal \ distance }[/tex]Therefore;

[tex]\dfrac{1.15 \, m}{h} = \dfrac{0.8 \ m}{14.65 \ m}[/tex]

[tex]h = \dfrac{1.15 \, m \times 14.65 \, m }{0.8 \, m} = 21.059375 \ m[/tex]

The height of the school building h to the nearest hundredth meter ≈ 21.06 m.

Step-by-step explanation:

this is the correct answer you wanted to know

please mark brainliest

Answer:

[tex] \boxed{y = 2x\: – \: 5} [/tex]

Answer:

2nd option

{(-8, -2), (-4, 1), (0, -2), (2, 3), (4, -4)}

Step-by-step explanation:

For a function to exist, every value of input must have exactly one value of output.

The rest of the relations(1, 3, and 4) have 2 outputs for 1 input so they dont make a function.

Answer:

(B)

Step-by-step explanation:

If you noticed, all the other input values have one input value that has two output values. This doesn't represent a function. Only (B) has one output for each input.

Hope that helps (●'◡'●)

Answer:

[tex]V=34.64\ cm^3[/tex]

Step-by-step explanation:

Given that,

The side of an equilateral prism = 4 cm

The altitude of the prism = 5 cm

We need to find the volume of the prism. The formula for the volume of a prism is as follows :

[tex]V=A\times h[/tex]

Where

A is the area of equilateral triangle, [tex]A=\dfrac{\sqrt3}{4}a^2[/tex]

So,

[tex]V=\dfrac{\sqrt3}{4}a^2\times h\\\\V=\dfrac{\sqrt3}{4}\times 4^2\times 5\\\\V=34.64\ cm^3[/tex]

So, the volume of the prism is equal to [tex]34.64\ cm^3[/tex].

Answer:

100

Step-by-step explanation:

add positive numbers. then subtract the negative numbers.

Answer:

[tex]A) - \frac{1}{4} + \frac{2}{3} \\ \frac{ - 3 + 8}{12} \\ = \frac{5}{12} [/tex]

[tex]B) \frac{1}{2} - \frac{3}{5} - \frac{1}{2} \\ \frac{5 - 6 - 5}{10} \\ = \frac{ - 6}{10} [/tex]

[tex]C) \frac{3}{4} of \frac{2}{9} \\ \frac{3}{4} \times \frac{2}{9} \\ \frac{6}{36} = \frac{1}{6} [/tex]

[tex]D) \frac{2}{5} \times \frac{7}{12} \\ = \frac{14}{60} = \frac{7}{30} [/tex]

Answer:

C

Step-by-step explanation:

1,2 are both supplementary

Answer:

Range D = {-7, 1, 9, 17}

Step-by-step explanation:

f(x) = 4x + 9

4(-4) + 9 = -7

4(-2) + 9 = 1

4(0) + 9 = 9

4(2) + 9 = 17

Answer: [tex]312.5\ cm^2[/tex]

Step-by-step explanation:

Given

A and B are two similar shape with  lengths of 12 cm and 15 cm

A has an area of [tex]200\ cm^2[/tex]

For similar figures, ratio of the square of corresponding length is equal to the ratio of the area

[tex]\Rightarrow \dfrac{200}{A_b}=\dfrac{12^2}{15^2}\\\\\Rightarrow A_b=\dfrac{15^2}{12^2}\times 200\\\\\Rightarrow A_b=312.5\ cm^2[/tex]