Solve the following linear program graphically (each line represents one unit). The feasible region is indicated by the shading and the corner points have been listed for you. Determine the objective function value at the corner points and indicate the optimal solution (if any). Minimize: Z

Answer:

Select SUM(HOURS), SUM(CHARGES) from employees

Explanation:

The table structure is not given. So, I will assume that the table name is "employees", the columns to retrieve are "hours" and "charges"

Having said that, the function to retrieve the total of column is the sum() function.

So, the query is as follows:

Select ----> This means that the query is to retrieve from the table

SUM(HOURS), SUM(CHARGES) --- This represent the records to retrieve

from employees ---- This represents the table to retrieve from.

In a relational database, the three basic operations used to develop useful sets of data are:

[tex]\sf\purple{a.\: Select, \:project,\: and\: join. }[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]

The basic operations used to develop useful sets of data in relational database are Select, Project and Join.

Hence, the basic operations are select, project, and join.

Learn more : https://brainly.com/question/14760328

Answer:

The summary of the given query would be summarized throughout the below segment. The output of the question is attached below.

Explanation:

Given values are:

here,

inp = input

By utilizing the below formula, we get

⇒ [tex]\frac{GM}{d^2}[/tex]

Now,

⇒ [tex]accel \ gravity=\frac{G\times M}{dist \ center**2}[/tex]

⇒ print("Acceleration of gravity: {:.2f}".format(accel_gravity))

Answer:

Here is the code.

Explanation:

#include <iostream>

#include <cstdlib>

#include <string>

#include <iomanip>

using namespace std;

class Employee

{

private:

string employeeName;

int employeeNumber;

int hireDate;

public:

void setemployeeName(string employeeName);

void setemployeeNumber(int);

void sethireDate(int);

string getemployeeName() const;

int getemployeeNumber() const;

int gethireDate() const;

Employee();

};

void Employee::setemployeeName(string employeeName)

{

employeeName = employeeName;

}

void Employee::setemployeeNumber(int b)

{

employeeNumber = b;

}

void Employee::sethireDate(int d)

{

hireDate = d;

}

string Employee::getemployeeName() const

{

return employeeName;

}

int Employee::getemployeeNumber() const

{

return employeeNumber;

}

int Employee::gethireDate() const

{

return hireDate;

}

Employee::Employee()

{

cout << "Please answer some questions about your employees, ";

}

class ProductionWorker :public Employee

{

private:

int Shift;

double hourlyPay;

public:

void setShift(int);

void sethourlyPay(double);

int getShift() const;

double gethourlyPay() const;

ProductionWorker();

};

void ProductionWorker::setShift(int s)

{

Shift = s;

}

void ProductionWorker::sethourlyPay(double p)

{

hourlyPay = p;

}

int ProductionWorker::getShift() const

{

return Shift;

}

double ProductionWorker::gethourlyPay() const

{

return hourlyPay;

}

ProductionWorker::ProductionWorker()

{

cout << "Your responses will be displayed after all data has been received. "<<endl;

}

int main()

{

ProductionWorker info;

string name;

int num;

int date;

int shift;

double pay;

cout << "Please enter employee name: ";

cin >> name;

cout << "Please enter employee number: ";

cin >> num;

cout << "Please enter employee hire date using the format \n";

cout << "2 digit month, 2 digit day, 4 digit year as one number: \n";

cout << "(Example August 12 1981 = 08121981)";

cin >> date;

cout << "Which shift does the employee work: \n";

cout << "Enter 1, 2, or 3";

cin >> shift;

cout << "Please enter the employee's rate of pay: ";

cin >> pay;

info.setemployeeName(name);

info.setemployeeNumber(num);

info.sethireDate(date);

info.setShift(shift);

info.sethourlyPay(pay);

cout << "The data you entered for this employee is as follows: \n";

cout << "Name: " << info.getemployeeName() << endl;

cout << "Number: " << info.getemployeeNumber() << endl;

cout << "Hire Date: " << info.gethireDate() << endl;

cout << "Shift: " << info.getShift() << endl;

cout << setprecision(2) << fixed;

cout << "Pay Rate: " << info.gethourlyPay() << endl;

system("pause");

return 0;

}

Answer:

Following are the response to the given question:  

Explanation:

Build a spring, sink, vertices, and vertices for each car for a household. Every unit in the stream is a human. Attach the source from each vertical of a family with such a capacity line equivalent to the family size; this sets the number of members in each household. Attach every car vertices to the sink with the edge of the car's passenger belt; this assures the correct number of people for every vehicle. Connecting every vertex in your household to any vertex in your vehicle with a capacity 1 border guarantees that one family member joins a single car. The link between both the acceptable allocation of people to vehicles as well as the maximum flow inside the graph seems clear to notice.

Answer:

a,b,c,d,f,g are true only e is false

Answer:

which language is this

Explanation:

Chinese or Korea

Answer:

Explanation:Algorithms are aimed at optimizing everything. They can save lives, make things easier and conquer chaos. Still, experts worry they can also put too much control in the hands of corporations and governments, perpetuate bias, create filter bubbles, cut choices, creativity and serendipity, and could result in greater unemploymen

Answer: The algorithm must have an infinite number of steps because there are an infinite number of integers greater than one. It will run forever trying to count to infinity. Every algorithm must reach some operation that tells it to stop.

Answer:

The pseudo-code describes steps in an algorithm or another system in plain language. Pseudo-Code is often designed for human reading rather than machine reading with structural conventions of a normal language of programming.

Natural languages consist of phrases, usually declarative phrases, with a sequence of information.

Explanation:

Answer:

The table are linked together

Answer:

The function is as follows:

def get_win_percentage(self):

       return self.team_wins / (self.team_wins + self.team_losses)

Explanation:

This defines the function

def get_win_percentage(self):

This calculates the win percentage and returns it to main

       return self.team_wins / (self.team_wins + self.team_losses)

See attachment for complete (and modified) program.

Answer: def get_win_percentage(self):

Explanation: got it right on edgen

Answer:

Here the code is given as follows,

Explanation:

Code:

public class Ramanujan {  

   public static void main(String[] args) {  

       // check cmd argument

       int n = Integer.parseInt(args[0]);  

       // checking a^3 + b^3 = c^3 + d^3  

       // outer loop

       for (int a = 1; (a*a*a) <= n; a++) {  

           int a3 = a*a*a;  

           // no solution is possible, since upcoming a values are more

           if (a3 > n)  

               break;  

           // avoid duplicate

           for (int b = a; (b * b * b) <= (n - a3); b++) {  

               int b3 = b*b*b;  

               if (a3 + b3 > n)

                   break;  

               // avoid duplicates

               for (int c = a + 1; (c*c*c) <= n; c++) {  

                   int c3 = c*c*c;  

                   if (c3 > a3 + b3)

                       break;  

                   // avoid duplicates

                   for (int d = c; (d * d * d) <= (n - c3); d++) {  

                       int d3 = d*d*d;  

                       if (c3 + d3 > a3 + b3)  

                           break;  

                       if (c3 + d3 == a3 + b3) {

                           System.out.print((a3+b3) + " = ");

                           System.out.print(a + "^3 + " + b + "^3 = ");  

                           System.out.print(c + "^3 + " + d + "^3");  

                           System.out.println();

                       }

                   }

               }

           }

       }

   }

}

Answer:

The program in C++ is as follows:

#include <bits/stdc++.h>

using namespace std;

int main(){

string sentence,word="";

getline (cin, sentence);

vector<string> for_reverse;

for (int i = 0; i < sentence.length(); i++){

 if (sentence[i] == ' ')  {

  for_reverse.push_back(word);

  word = "";  }

 else{    word += sentence[i];}  }

for_reverse.push_back(word);

sentence="";

for (int i = for_reverse.size() - 1; i > 0; i--){

 sentence+=for_reverse[i]+" ";}

sentence+=for_reverse[0];

cout<<sentence<<endl;

return 0;

}

Explanation:

This declares sentence and word as strings; word is then initialized to an empty string

string sentence,word="";

This gets input for sentence

getline (cin, sentence);

This creates a string vector to reverse the input sentence

vector<string> for_reverse;

This iterates through the sentence

for (int i = 0; i < sentence.length(); i++){

This pushes each word of the sentence to the vector when space is encountered

 if (sentence[i] == ' ')  {

  for_reverse.push_back(word);

Initialize word to empty string

  word = "";  }

If the encountered character is not a blank space, the character is added to the current word

 else{    word += sentence[i];}  }

This pushes the last word to the vector

for_reverse.push_back(word);  

This initializes sentence to an empty string

sentence="";

This iterates through the vector

for (int i = for_reverse.size() - 1; i > 0; i--){

This generates the reversed sentence

 sentence+=for_reverse[i]+" ";}

This adds the first word to the end of the sentence

sentence+=for_reverse[0];

Print the sentence

cout<<sentence<<endl;

Answer:

The immaterial benefits stem from the development of an information system and cannot easily be measured in dollars or with confidence. Potential intangible advantages include a competitive need, timely information, improved planning and increased flexibility in organisation.

Explanation:

Intangible advantages

Lower productivity and the lack of 'think outside' employees and managers as well as greater sales include the intangible costs of such an operational environment. All these factors improve when employees spend less of their time in addressing current methods of operation and are concerned about whether they will have a job or an employer in six months or a year. The automation level envisaged in this new system should enhance the overall efficiency of management. The operative controls and design functions should be simplified by tight system integrations with accessible automated database sources. However, it is difficult to describe the exact form of these simplifications.

Tangible costs of the new system include costs of analysis, design and construction of the system, such as the recruitment of contractors or new employees, and the assignment of existing staff. Also consideration shall be given to hardware, software purchased and operating costs. Intangible costs include disturbances to the current activities caused by development and deployment and potential adverse effects on the morals of employees.

While the new system may feel good in the long term, short-term stress and other negative consequences will still be present. In the way that Reliable does virtually everything, the system is the focus of a major change. An organisation's monumental change has widespread negative effects on operations and employees.

Answer:

The arrange code is as follows:

#include<iomanip>

#include<iostream>

#include<math.h>

using namespace std;

const double PI = 3.14159;

int main(){

double height;

double radius;

cout << "Enter the height of the cylinder: ";

cout << endl;

cin >> height;

cout << "Enter the radius of the base of the cylinder: ";

cout << endl;

cin >> radius;

cout << fixed << showpoint << setprecision(2);

cout << "Volume of the cylinder = "<< PI * pow(radius, 2.0)* height << endl;

cout << "Surface area: "<< 2 * radius * + 2 * PI * pow(radius, 2.0) << endl;

return 0;

}

Explanation:

Required

Rearrange the program

There are no one way to solve questions like this. However, a simple guide is as follows:

All header files must be called first (i.e #include....)

Followed by the namespaces (std)

if the program uses constant, the constant must be declared and initialized.

e.g. const double PI = 3.14159;

Next, all variables and must be declared (e.g. double radius)

Next, all inputs must be taken before the values of the variables can be used (e.g. cin >> height;)

If the inputs used prompts, the prompt must be before the inputs.

Next, perform all computations then output the results

Answer:

Program.java  

import java.util.Scanner;  

public class Program {  

   public static boolean isPalindrome(String str){

       int start = 0, end = str.length()-1;

       while (start < end){

           if(str.charAt(start) != str.charAt(end)){

               return false;

           }

           start++;

           end--;

       }

       return true;

   }  

   public static int countPalindromePairs(String[] inarr){

       int count = 0;

       for(int i=0; i<inarr.length; i++){

           for(int j=i+1; j<inarr.length; j++){

               StringBuilder sb = new StringBuilder();

               sb.append(inarr[i]).append(inarr[j]);

               if(isPalindrome(sb.toString())){

                   count++;

               }

           }

       }

       return count == 0 ? -1 : count;

   }

   public static void main(String[] args) {

       Scanner sc = new Scanner(System.in);

       String line = sc.next();

       String[] inarr = line.split(",");

       int count = countPalindromePairs(inarr);

       System.out.println("RESULT: "+count);

   }

}

Explanation:

OUTPUT:

Answer:

hi

Explanation:

i did not known answers

Answer:

while (quantity >= 50)

Explanation:

Required

Stop when quantity is less than 50

To do this, we make use of a while statement and the syntax is:

while (condition){ }

If the loop should stop when quantity is less than 50; then it means the loop would continue when quantity is greater or equal to 50

So, we have:

while (quantity >= 50)

Answer:

"Portrait orientation" would be the correct answer.

Explanation:

Thus the above is the correct answer.

Answer:

Windows button = You can see a Start Menu

Task view = You can view your Tasks

Search Box = You can search any app you want in an instance

Answer:

Please find the attached file for the complete solution:

Explanation:

F = 13

Given:

x = false

y = 5

z = 1

F = (4%2)+2*Y +6/2 +(z&&x)

We solve this arithmetic using the order of precedence:

i. Solve the brackets first

=> (4 % 2)

This means 4 modulus 2. This is the result of the remainder when 4 is divided by 2. Since there is no remainder when 4 is divided by 2, then

4 % 2 = 0

=> (z && x)

This means (1 && false). This is the result of using the AND operator. Remember that && means AND operator. This will return false (or 0) if one or both operands are false. It will return true (or 1) if both operands are true.

In this case since the right operand is a false, the result will be 0. i.e

(z && x) = (1 && false) = 0

ii. Solve either the multiplication or division next whichever one comes first.

=> 2 * y

This means the product of 2 and y ( = 5). This will give;

2 * y = 2 * 5 = 10

=> 6 / 2

This means the quotient of 6 and 2. This will give;

6 / 2 = 3

iii. Now solve the addition by first substituting the values calculated earlier back into F.

F = (4%2)+2*Y +6/2 +(z&&x)

F = 0 + 10 + 3 + 0

F = 13

Therefore, the value of F is 13

Answer:

The program in Python is as follows:

numList = []

num = int(input())

while num != 0:

   numList.append(num)

   num = int(input())

numList.sort()

for num in numList:

   print(num)

Explanation:

This initializes the list

numList = []

This gets input from the user

num = int(input())

This loop is repeated until the user enters 0

while num != 0:

This appends the user input to the list

   numList.append(num)

This gets another input from the user

   num = int(input())

This sorts the list in ascending order    

numList.sort()

This iteration prints the list elements, each on a line

for num in numList:

   print(num)

Answer:

Explanation:

Answer: Pulldown menus

Explanation:

Pulldown menus refer to the graphical control element, that is identical to a list box, which enables user to be bake to select one value from a list.

They're regarded as the menu of options that will appear when an item is selected with a mouse. In this case, the item that the user selected will show at the top of the display screen, while the menu appears will show below it.

Therefore, Alex should use the pulldown menus to hide the long list of hypertext links so that it appears only in response to a tap of a major heading in the navigation list.

Answer:

La electricidad es el conjunto de fenómenos físicos relacionados con la carga eléctrica y los campos eléctricos y también con el electromagnetismo. Dado que la energía eléctrica es una fuente importante de energía en la vida cotidiana, las palabras "electricidad" y "corriente" a menudo se usan indistintamente en el habla cotidiana. Sin embargo, la electricidad también incluye otros fenómenos fácilmente reconocibles como los rayos y la electricidad estática.

La electricidad tiene muchas aplicaciones técnicas. Por lo tanto, la ingeniería eléctrica se explora y se desarrolla más en la ingeniería eléctrica. A diferencia de muchos otros fenómenos físicos, muchos de los fenómenos asociados con la electricidad pueden medirse y calcularse previamente con gran precisión.

La electricidad es un fenómeno natural. La más conocida es la ocurrencia de rayos, que es causada por una diferencia de potencial en la atmósfera. Algunos peces, como la anguila eléctrica, también son capaces de generar electricidad. Además, los sistemas nerviosos animal y humano funcionan con señales eléctricas.

Answer:

Are you talking about the bruce willis is superman basically? Because if so i don't think so because that is a future event that hasn't happened yet also that film sucks.

Explanation:

Answer: scrum

Explanation:

Answer:

The Scrum of Scrums is a time-boxed session in which a representative from each Team shares high-level updates on their respective team's work and articulates their progress and impediments. Ideally, it should follow the various teams' Daily Stand-ups, so that the latest information is communicated.

hope that helps bby<3

Answer:

A.Datasheet

Explanation:

I hope it's helpful