Solve the inequality and write the solution in interval notation:
x-6/x+5 <0

(-5, 6)

[-5, 6)

(-infinity,-5) U [6,infinity)

(-infinity,-5] U (6,infinity)

Answers

Answer 1

Answer:

A

Step-by-step explanation:

Firstly x cannot be -5 because the expression on th left would be undefined so it's only between choices a and c.

Create a number line with makes the expression on left 0 and undefined...so at 6 and -5 this happens.

-------(-5)--------(6)---------

Let's test the 3 intervals by choosing a value from that interval to see if all numbers from that interval will make the expression on left less than 0.

Number before -5 is -6:

(-6-6)/(-6+5)=-12/-1=12 >0 so this interval is not a part of our solution.

Number between -5 and 6 is 0:

(0-6)/(0+5)=-6/5<0 so this interval is a part of our solution

Number after 6 like 7:

(7-6)/(7+5)=1/12>0 so this interval is not a part of our solution.

The winner is everything between-5 and 6 so answer is A.


Related Questions

Write the slope-intercept form of the equation of the line described. Through (-1,-1) parallel to y=6x-2

Answers

Answer:

[tex]\boxed {\boxed {\sf y= 6x+5}}[/tex]

Step-by-step explanation:

We are asked to find the slope-intercept equation of a line. Slope-intercept form is one way to write the equation of a line. It is:

[tex]y=mx+b[/tex]

Where m is the slope and b is the y-intercept.

We are given a point (-1, -1) and the line is parallel to the line y= 6x-2. Since the line is parallel to the other line, they have the same slope, which is 6. We have a point and a slope, so we should use the point-slope formula to find the equation of the line.

[tex]y-y_1= m (x-x_1)[/tex]

Here, m is the slope and (x₁, y₁) is the point. We know the slope is 6 and the point is (-1, -1). Therefore:

m= 6x₁= -1y₁= -1

Substitute the values into the formula.

[tex]y- -1 = 6(x- -1) \\y+1= 6(x+1)[/tex]

Distribute the 6. Multiply each value inside the parentheses by 6.

[tex]y+1 = (6*x)+ (6*1) \\y+1= 6x+6[/tex]

Slope-intercept form requires y to be isolated. 1 is being added to y. The inverse of addition is subtraction. Subtract 1 from both sides.

[tex]y+1-1=6x+6-1 \\y= 6x+5[/tex]

The equation of the line in slope-intercept form is y=6x+5

Can someone help me I need it.

Answers

Answer:

C is the answer 3rd one...

A line of best fit must pass through all data points of a graph.
True or False?

Answers

The answer to this question is false

Kristi finds a shirt for $27.99 at the store.
The sign says that it is 25% off the
original price. Kristi must also pay the 8.5%
sales tax. What is the cost of the shirt
after the sales tax?

Answers

Answer:

Kristi will pay $22.77 for the shirt.

Step-by-step explanation:

First, determine the sales price of the shirt. If the full price is $27.99, a 25% reduction is $7. Subtract the discount from the full price to get a sales price of $20.99 for the shirt.

Next, determine the amount of tax Kristi will pay for the shirt. In her state, the sales tax is 8.5% (0.085). Multiply $20.99 by 0.085 and you will see that the sales tax is $1.78. Add the amount of the tax, $1.78, to the sales price of the shirt, $20.99, and you will get $22.77 as the cost of the shirt after the sales tax is added.

Friends, i need help with this question.

Answers

Answer:

Step-by-step explanation:

The answer is 4.

Once you add 4, you get:

x^2 -2x + 4 = 7.

The left side is factorable:

(x-2)^2 = 7.

There is your perfect square.

Find the missing length of the following trapezoid

Answers

Answer:

1) The length of [tex]DC[/tex] is 20.

2) The length of [tex]PS[/tex] is 17.

Step-by-step explanation:

1) If [tex]DR = RE[/tex] and [tex]CS = SB[/tex], then we can use the following proportionality ratio:

[tex]\frac{DE}{DR} = \frac{32 - x}{26 - x}[/tex] (1)

Where [tex]x[/tex] is the length of segment [tex]\overline{CD}[/tex].

If [tex]DE = 2\cdot DR[/tex], then the value of [tex]x[/tex] is:

[tex]2 = \frac{32-x}{26-x}[/tex]

[tex]52 - 2\cdot x = 32 - x[/tex]

[tex]20 = x[/tex]

The length of [tex]DC[/tex] is 20.

2) If [tex]QV = VP[/tex] and [tex]RW = WS[/tex], then we can use the following proportionality ratio:

[tex]\frac{QP}{QV} = \frac{x-7}{12-7}[/tex] (2)

Where [tex]x[/tex] is the length of segment [tex]\overline{PS}[/tex].

If [tex]QP = 2\cdot QV[/tex], then the value of [tex]x[/tex] is:

[tex]2 = \frac{x-7}{5}[/tex]

[tex]10 = x-7[/tex]

[tex]x = 17[/tex]

The length of [tex]PS[/tex] is 17.

HELPPP MEEEE OUTTTTTT ITS URGENTTTTT!!!!

Answers

Answer:

(x-12)^2+(y-2)^2=4

Step-by-step explanation:

i am thinking of a number.l take away 5. the result is 14 . what number did i think​

Answers

Step-by-step explanation:

First sentence

Let the number be X

second sentence

X-5

Third sentence

X-5=14

X=19

The number is 19

Hi there!  

»»————- ★ ————-««

I believe your answer is:

19

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\text{"I am thinking of a number. l take away 5. The result is 14."}\\\\\text{5 taken away from 'said number' would be 14.}\\\\\boxed{n-5=14}\\\\\\\boxed{\text{Solving for 'n'...}} \\\\\rightarrow n - 5 + 5 = 14 + 5\\\\\rightarrow \boxed{n = 19}[/tex]

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

There are 5 more girls than boys in a class. The girls are 60 percent
a. How many pupils are in the class?​

Answers

Answer:

25.

Step-by-step explanation:

Let the number of pupils be x, then:

there are 0.6x girls and 0.4x boys.

From the given information:

0.6x - 0.4x = 5

0.2x = 5

x = 5/0.2

= 50/2

= 25.

What’s the answers ?

Answers

hope this helps! feel free to clarify if unsure

What the additional information fill in the blanks

Answers

Answer:

QXV=WXV

Step-by-step explanation:

Please I need help who want to earn 13 points ..

Answers

Answer:

Triangle ISK

Step-by-step explanation:

Answer:

Triangle ISK

Step-by-step explanation:

if the angles and sides of one triangle are equal to the corresponding sides and angles of the other triangle, they are congruent.

∠Q = ∠I

∠R = ∠S

∠S = ∠K

What is tanA?
Triangle A B C. Angle C is 90 degrees. Hypotenuse A B is 17, adjacent A C is 8, opposite B C is 15.
a.
StartFraction 15 Over 17 EndFraction
c.
StartFraction 8 Over 15 EndFraction
b.
StartFraction 8 Over 17 EndFraction
d.
StartFraction 15 Over 8 EndFraction

Answers

Answer:

D. [tex] \frac{15}{8} [/tex]

Step-by-step explanation:

Recall: SOH CAH TOA

Thus,

Tan A = Opposite/Adjacent

Reference angle (θ) = A

Length of side Opposite to <A = 15

Length of Adjacent side = 8

Plug in the known values

[tex] Tan(A) = \frac{15}{8} [/tex]

Log5 =0,699 find log 0,5

Answers

Answer:

-0.301

Step-by-step explanation:

Correct Question :-

If log 2 = 0.301 , find log 0.5

Solution :-

We are here given that the value of log 5 is 0.699 . Here the base of log is 10 .

[tex]\rm\implies log_{10}2= 0.301 [/tex]

And we are supposed to find out the value of log 0.5 . We can write it as ,

[tex]\rm\implies log_{10}(0.5) = log _{10}\bigg( \dfrac{5}{10}\bigg)[/tex]

Simplify ,

[tex]\rm\implies log _{10}\bigg( \dfrac{1}{2}\bigg)[/tex]

This can be written as ,

[tex]\rm\implies log_{10} ( 2^{-1})[/tex]

Use property of log ,

[tex]\rm\implies -1 \times log_{10}2 [/tex]

Put the value of log 2 ,

[tex]\rm\implies -1 \times 0.301 =\boxed{\blue{-0.301}} [/tex]

Hence the value of log (0.5) is -0.301 .

*Note -

Here here there was no use of log 5 in the calculation .

In a survey of adults aged 57 through 85​ years, it was found that 86.6​% of them used at least one prescription medication. Complete parts​ (a) through​ (c) below.

a. How many of the 3149 subjects used at least one prescription​ medication?

​(Round to the nearest integer as​ needed.)

b. Construct a​ 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication.


​(Round to one decimal place as​ needed.)

Answers

Answer:

a) 272 used at least one prescription​ medication.

b) The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

Step-by-step explanation:

Question a:

86.6% out of 3149, so:

0.866*3149 = 2727.

272 used at least one prescription​ medication.

Question b:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 3149, \pi = 0.866[/tex]

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 - 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.856[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 + 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.876[/tex]

For the percentage:

0.856*100% = 85.6%

0.876*100% = 87.6%.

The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

The number of subjects in the study who used at least one prescription medication is 2727 approx. The needed 90% confidence interval is:  [0.8560, 0.8758] or in percentage as: 85.6% to 87.58%

How to construct confidence interval for population proportion based on the sample proportion?

Suppose that we have:

n = sample size[tex]\hat{p}[/tex] = sample proportion[tex]\alpha[/tex] = level of significance = 1 - confidence interval  = 100 - confidence interval in percentage

Then, we get:

[tex]CI = \hat{p} \pm Z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]

where [tex]Z_{\alpha/2}[/tex] is the critical value of Z at specified level of significance and is obtainable from its critical value table(available online or in some books)

For this case, we have:

n = 3149confidence interval is of 90%[tex]\alpha[/tex] = level of significance  = 100 - 90% = 10% = 0..10[tex]\hat{p}[/tex] = sample proportion = ratio of 86.6% of n to n (at the least)

Part (a):

The number of subjects used at least one prescription​ medication is:

[tex]\dfrac{3149}{100} \times 86.6 \approx 2727[/tex]

Thus, the sample proportion we get is:

[tex]\hat{p} = \dfrac{2727}{3149} \approx 0.8659[/tex]

For level of significance 0.10, we get: [tex]Z_{\alpha/2} = 1.645[/tex]

Thus, the confidence interval needed is:

[tex]CI = \hat{p} \pm Z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\CI \approx 0.8659\pm 1.645 \times \sqrt{\dfrac{0.8659(1-0.8659)}{3149}}\\\\\\CI \approx 0.8659 \pm 0.0099[/tex]

Thus, CI is [0.8659 - 0.0099, 0.8659 + 0.0099] = [0.8560, 0.8758]

Thus, the number of subjects in the study who used at least one prescription medication is 2727 approx. The needed 90% confidence interval is:  [0.8560, 0.8758] or in percentage as: 85.6% to 87.58%

Learn more about population proportion here:

https://brainly.com/question/7204089

What is the measure of ∠
A. 60°

B. 6°

C. 42°

D. 49°

Answers

If it’s solving for x it’s 6 but the angle is 49

1) 18,27 – 9,756 =
2) 6 – 2,407 =
3) 18 – 5,432 =
4) 10 – 7,602 =
5) 13,013 – 12,5 =
6) 972,5 – 247,451 =
7) 83,12 – 90,2 + 12,3 =
8) 46,75 – 60,13 + 32,50 =
9) 254,0187 – 29,34682 =
10)1.015,568 – 123,712 =
no entiendo me ayudan

Answers

Answer:

1) -7929

2) -2401

3)-5414

4) -7592

5) 12888

6)-237726

7) 7287

8)-4588

9)-394495

10) 891856

A boardwalk game of chance costs 2 dollars to play. You have a 20% chance of winning 1 dollar, a 25% chance of winning back your entire 2 dollars, and a 35% chance to win 5 dollars. What is the expected value of playing the game if you lose your bet 20% of the time?

Answers

Answer:

For a give event with outcomes:

{x₁, x₂, ..., xₙ}

Each with probabilities:

{p₁, p₂, ..., pₙ}

The expected value is:

Ev = x₁*p₁ + ... + xₙ*pₙ

Here we have the outcomes and probabilities:

win $1, with a probability 20%/100% = 0.2

win $2, with a probability 25%/100% = 0.25

win $5, with a probability of 35%/100% = 0.35

do not win, with a probability of 20%/100% = 0.2

Then the expected value of the game is:

Ev = $1*0.2 + $2*0.25 + $5*0.35 + $0*0.2 = $2.45

And if we know that the game costs $2, then the expected value is:

Ev = $2.45 - $2 = $0.45

The expected value is  $0.45

if -2 is a zero the polynomial 3x^2+2x+k, find the value of k​

Answers

Answer:

value of K =16

I hope it's helps you

Find the circumference and area of a circle with a diameter of 12 cm. (Use the approximation of 3.14 for )

Answers

here u go look at the image for the answer and i hope this helps !!!!

Find the size of the angles marked by letters in the following diagram.​

Answers

a=132°

b=20°

Answer:

Solution given:

a=132°[exterior angle of a cyclic quadrilateral is equal to the opposite interior angle]

again

In ∆ BCO is similar to ∆ BOE

so

b=20°[corresponding angle of similar triangle are equal]

Anyone good at Ks3 math?

Answers

Answer:

210 Km

Step-by-step explanation:

Distance travelled is calculated as

distance = speed × time ( time is in hours )

              = 90 × 2 [tex]\frac{1}{3}[/tex]

             = 90 × [tex]\frac{7}{3}[/tex]

            = 30 × 7

            = 210 Km

A motorist travels 90 miles at a rate of 20 miles per hour. If he returns the same distance at a rate of 40 miles per hour, what is the average speed for the entire trip, in miles per hour?

Answers

Answer:

The answer is x = 1800

Step-by-step explanation:

Hope this helps :)

Have a nice day.

Tìm x,y thỏa mãn: x^2-2xy+3y-5x+7=0

Answers

I think there's an error with this question. Mind to check it back and tell me the detail?

Find the volume of the composite solid.
10 cm
12 cm
32 cm
10 cm

Answers

Your is answer would be choice C which is : 32 cm

Answer:

Your is answer would be choice C which is : 32 cm

Step-by-step explanation:

height increase (m)
Temperature drop (°C)=
200


If the temperature at a height of 500 m is 23°C, what will it be when you climb to 1300 m
How far would you need to climb to experience a temperature drop of 5°C?

Answers

Complete question is;

In mountaineering, in general, the higher you go, the colder it gets. This formula shows how the heights and temperatures are related.

Temperature drop (°C) = height increase(m)/200

A) If the temperature at a height of 500 m is 23°C, what will it be when you climb to 1300 m

B) How far would you need to climb to experience a temperature drop of 5°C

Answer:

A) 19°C

B) 1500 m

Step-by-step explanation:

A) We are told that the temperature is at a height of 500 m is 23°C, now we want to find the temperature when height increases to 1300 m.

Thus, it means;

Height increase = 1300 - 500 = 800 m

Thus, from the formula;

Temperature drop (°C) = height increase(m)/200, we have;

Temperature drop (°C) = 800/200 = 4°C

Now,since Initial temperature was 23°C, thus temperature at this increased height ; 23°C - 4°C = 19°C

B) for a temperature drop of 5°C, we have;

5°C = height increase(m)/200

Height increase = 200 × 5

Height increase = 1000 m

Thus, you will need to climb; 500 + 1000 = 1500 m

Let t
4 and u = 6 + 2i. Find t * u

Answers

Answer:

24 + 8i

Step-by-step explanation:

t = 4

u = 6 + 2i

t x u

= 4 ( 6 + 2i )

= 24 + 8i

Answer:

24+8i

Step-by-step explanation:

i took the test

can someone please help ? i know one of the answers is c but couldn’t b and d also work ? when you figure them out you get x is less than 10 as well.

Answers

Answer:

b,c,d

Step-by-step explanation:

a ≤ 10  would have a closed circle at 10

b x+10 <15  x < 10  correct  open circle line going to left

c x < 10 correct  open circle line going to left

d 0 > x-10  10 > x    x < 10  correct  open circle line going to left

e  2 > x-11 13 > x   would have open circle at 13

The open circle tells us that the sign is only less than/greater than, not less than/greater than or equal to. That immediately rules out A.

Now, we can see that this is a less than inequality, because the arrow is pointing to the left, toward the negative numbers. And, the inequality covers every number that is less than 10.

A - Incorrect, less than or equal to

B - Correct, when solved = x < 10

C - Correct

D - Correct, when solved = x < 10

E - Incorrect, when solved = x < 13

Hope this helps!

18
20 men, 10 women and 10 children are in a competition.
The mean score for the women is 15.6.
The mean score for the children is 9.2.
Kevin says that the mean score for all 40 people is 11.2.
Work out the mean score for the men.

Answers

Answer:

20

Step-by-step explanation:

The mean score for the women = 15.6

Sum of score for the women = 15.6*10 = 156

The mean score for the children = 9.2

Sum of score for the children = 9.2 * 10 = 92

The mean score for all 40 people = 11.2

Sum of the score of 40 people = 11.2 *40 = 448

Sum of the score for 20 men = 448 - 92 - 156 = 200

Mean of the score for the men = 200÷ 20 =20

Nigel is making holiday cookies. His recipe calls for 1/2 pound of raisins. The recipe also calls for 1/4 pound of dates and 1/8 pound of dried apricots. How much dried fruit will be put into the cookies in all?

A: 1/8 pound
B: 3/8 pound
C: 5/8 pound
D: 7/8 pound

Answers

Answer:

D. 7/8 pound

Step-by-step explanation:

1/2+1/4+1/8=7/8

7/8 pound of dried fruit will be put into the cookies in all.

Other Questions
What is the theme of Cell phone Sides? What was the major goal of the political reforms enacted during the Progressive Era (1900-1920)?1.expanding citizen participation in government2.lowering the legal voting age3.discouraging the formation of new political parties4.providing public funding of campaigns IN C++A. Create an abstract base class called Currency with two integer attributes, both of which are non-public. The int attributes will represent whole part (or currency note value) and fractional part (or currency coin value) such that 100 fractional parts equals 1 whole part. B. Create one derived class - Money - with two additional non-public string attributes which will contain the name of the currency note (Dollar) and currency coin (Cent) respectively. DO NOT add these attributes to the base Currency class.C. In your base Currency class, add public class (C++ students are allowed to use friend methods as long as a corresponding class method is defined as well) methods for the following, where appropriate:Default Construction (i.e. no parameters passed)Construction based on parameters for all attributes - create logical objects only, i.e. no negative value objects allowedCopy Constructor and/or Assignment, as applicable to your programming language of choiceDestructor, as applicable to your programming language of choiceSetters and Getters for all attributesAdding two objects of the same currencySubtracting one object from another object of the same currency - the result should be logical, i.e. negative results are not allowedComparing two objects of the same currency for equality/inequalityComparing two objects of the same currency to identify which object is larger or smallerPrint method to print details of a currency objectAll of the above should be instance methods and not static.The add and subtract as specified should manipulate the object on which they are invoked. It is allowed to have overloaded methods that create ane return new objects.D. In your derived Money class, add new methods or override inherited methods as necessary, taking care that code should not be duplicated or duplication minimized. Think modular and reusable code.E. Remember -Do not define methods that take any decimal values as input in either the base or derived classes. Only the print method(s) in the classes should print anything to console.Throw String (or equivalent) exceptions from within the classes to ensure that invalid objects cannot be created.F. In your main:Declare a primitive array of 5 Currency references (for C++ programmers, array of 5 Currency pointers).Ask the user for 5 decimal numbers to be input - for each of the inputs you will create one Money object to be stored in the array.Once the array is filled, perform the following five operations:Print the contents of the array of objects created in long form, i.e. if the user entered "2.85" for the first value, it should be printed as "2 Dollar 85 Cent".Add the first Money object to the second and print the resulting value in long form as above.Subtract the first Money object from the third and print the resulting value in long form as above.Compare the first Money object to the fourth and print whether both objects are equal or not using long form for object values.Compare the first Money object to the fifth and print which object value is greater than the other object value in long form.All operations in the main should be performed on Currency objects demonstrating polymorphism. 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