some machine/items/gadget having only hardware​

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Answer 1
Yeh it’s becoz they work with hardware that’s why

Related Questions

Write an application that inputs a five digit integer (The number must be entered only as ONE input) and separates the number into its individual digits using MOD, and prints the digits separated from one another. Your code will do INPUT VALIDATION and warn the user to enter the correct number of digits and let the user run your code as many times as they want (LOOP). Submit two different versions: Using the Scanner class (file name: ScanP2)

Answers

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

public static void main(String[] args) {

 int n, num;

 Scanner input = new Scanner(System.in);

 System.out.print("Number of inputs: ");

 n = input.nextInt();

 LinkedList<Integer> myList = new LinkedList<Integer>();

 for(int i = 0; i<n;i++){

     System.out.print("Input Integer: ");

     num = input.nextInt();

     while (num > 0) {

     myList.push( num % 10 );

     num/=10;

     }

     while (!myList.isEmpty()) {

         System.out.print(myList.pop()+" ");

     }

     System.out.println();

     myList.clear();

 }

}

}

Explanation:

This declares the number of inputs (n) and each input (num) as integer

 int n, num;

 Scanner input = new Scanner(System.in);

Prompt for number of inputs

 System.out.print("Number of inputs: ");   n = input.nextInt();

The program uses linkedlist to store individual digits. This declares the linkedlist

 LinkedList<Integer> myList = new LinkedList<Integer>();

This iterates through n

 for(int i = 0; i<n;i++){

Prompt for input

     System.out.print("Input Integer: ");

This gets input for each iteration

     num = input.nextInt();

This while loop is repeated until the digits are completely split

     while (num > 0) {

This adds each digit to the linked list

     myList.push( num % 10 );

This gets the other digits

     num/=10;

     }

The inner while loop ends here

This iterates through the linked list

     while (!myList.isEmpty()) {

This pops out every element of thelist

         System.out.print(myList.pop()+" ");

     }

Print a new line

     System.out.println();

This clears the stack

     myList.clear();

 }

Used for monitoring web activity by users to make sure that sensitive information won't leave the building.

A, Web server
B, FTP server
C, POP server
D, Proxy server ​

Answers

Answer: PROXY

Explanation:

The basic objective of the web server is to store, process and deliver web pages to the users.

FTP server is to allow users to upload and download files. An FTP server is a computer that has a file transfer protocol (FTP) address and is dedicated to receiving an FTP connection. FTP is a protocol used to transfer files via the internet between a server (sender) and a client (receiver)

pop provides access via an Internet Protocol (IP) network for a user client application to a mailbox (maildrop) maintained on a mail server

proxy server is a system that isolates internal clients from the servers by downloading and storing files on behalf of the clients. it intercepts requests for web-based or other resources that come from

What is computer code?
A. Java Script
B. XML
C. HTML
D. Any programming language

Answers

Answer:

D

Explanation:

how to make an app according to peoples will

Answers

Answer:

Follow these steps to create your own app:

1)Choose your app name.

2)Select a color scheme.

3)Customize your app design.

4)Choose the right test device.

5)Install the app on your device.

6)Add the features you want (Key Section)

7)Test, test, and test before the launch.

8)Publish your app.

Explanation:

(!!_!!)

What does the abbreviation BBC stands for?

Answers

Answer:

British Broadcasting Corporation Microcomputer System

Explanation:

The British Broadcasting Corporation Microcomputer System, or BBC Micro, is a series of microcomputers and associated peripherals designed and built by the Acorn Computer company in the 1980s for the BBC Computer Literacy Project.

Answer:

British Broadcasting Corporation

Explanation:

This is a UK company which provides television and radio news in over 40 languages. This is the computer related meaning, there are other meanings to the abbreviation but they seem irrelevant in this case.

Hope this information was of any help to you. (:

Write a program that will: 1. Call a function to input temperatures for consecutive days in an array. The temperatures are to be integer numbers. 2. The user will input the number of temperatures. There will be no more than 10 temperatures. 3. Call a function to sort the array by ascending order. You can use any sorting algorithm you wish as long as you can explain it. 4. Call a function that will return the average of the temperatures. The average should be displayed to two decimal places.

Answers

Answer:

Following are the program to the given question:

#include<iostream>//defining header file  

using namespace std;

float temperatures()//defining a method temperatures

{

int a[10],i,j,n,min,max,sum=0,temp;//defining integer variable

float avg;//defining floating point variable

cout<<"Please input the number of temperatures to be read: ";//print message

cin>>n;//input integer value

if(i>10)//use if to check array length greater than 10

return -1;//return integer value -1

for(j=0;j<n;j++)//defining loop to input value

{

cout<<"Input temperature: "<<endl;//print message

cin>>a[j];//holding value in loop

}

for(i=0;i<n-1;i++)//defining loop to compare array value

{

for(j=i+1;j<n-1;j++)//defining loop to compare array value

{

if(a[i]>a[j])//use if to compare array values

{

   //swapping

temp=a[j];//holding array value in temp

a[j]=a[i];//holding value in first index of array  

a[i]=temp;//holding temp value

}

}

}

max=min=a[0];//holding max value  

for (i = 0; i < n; i++)//defining loop to compare array value

{

if (a[i] > max)//use if to compare max array value

{

max = a[i];//holding max array value

}

else if (a[i] < min)//use else if to compare min array value

{

min = a[i];//holding min array value

}

}

for(i=0;i<n;i++)//use loop to add array value

sum=sum+a[i];//adding array value

avg=(float) sum/n;//calculating avg of the array

std::cout.setf(std::ios::fixed);//using namespace

std::cout.precision(2);//using precision method

cout<<"The average temperature is: "<<avg<<endl;//print avg value with message

cout<<"The highest temperature is: "<<max<<endl;//print max value with message

cout<<"The lowest temperature is: "<<min<<endl;//print min value with message

return avg;//return avg value

}

int main()//defining main method

{

float k;//defining float variable

k=temperatures();//calling method  

}

Output:

Please find the attached file.

Explanation:

In this code, a method "temperatures" is declared that defines the integer and float variable in which "n, array" is used to store the array value and inside the method min and max variable is declared that use the conditional statement to store its value.

Outside the main method, a floating-point variable "k" is declared that calls the method and stores its value.  

Frames control what displays on the Stage, while keyframes help to set up

Answers

Answer: A keyframe is a location on a timeline which marks the beginning or end of a transition. So for example, you have a movie and it transitions to another scene, keyframes tell it when and where to start the transition then when and where to stop the transition.

What is a geam in the ggplot2 system?
a) a plotting object like point, line, or other shape
b) a method for making conditioning plots
c) a method for mapping data to attributes like color and size
d) a statistical transformation

Answers

Answer:

a) a plotting object like point, line, or other shape

Explanation:

A geom in the ggplot2 system is "a plotting object like point, line, or other shape."

A Geom is used in formulating different layouts, shapes, or forms of a ggplot2 such as bar charts, scatterplots, and line diagrams.

For example some different types of Geom can be represented as geom_bar(), geom_point(), geom_line() etc.

You are the IT administrator for a small corporate network. The employee in Office 1 needs your assistance managing files and folders. Your task is to use the command prompt to complete the following:

a. Create the D:​\​utilities​\​recover directory. Use the md or mkdir command to create (make) a directory.
b. Delete the D:​\​software​\​arch98 directory and all of its files.
c. Use the rd command to delete (remove) a directory.
d. Use the /s switch to remove the directory and all of its contents at once.

Answers

Answer:

(a) mkdir /d D:\utilities\recover    

     or

    mkdir D:\utilities\recover    

(b) rd  /s  D:​\software​\arch98

Explanation:

(a) To make a new directory we use the md or mkdir command followed by the name of the directory as follows;

mkdir [name_of_directory]

The name of the directory could also be a relative or absolute path depending on the request.

In the task, the specified directory uses an absolute path given as D:​\​utilities​\​recover. This path is in a drive D. Therefore, if you are in another drive different than D, to run this command, it is a great idea to do that with the /d switch.

In summary:

i. if in drive D, to make a directory D:\utilities\recover, type the following command;

mkdir  D:\utilities\recover    

ii. if otherwise in a different drive, type the following command.

mkdir /d D:\utilities\recover

(b) To delete a directory, we use the rd or rmdir command. If the directory has contents that also need to be deleted, we use the switch /s alongside the rd or rmdir.

In the task given, the directory to be deleted is D:\software\arch98. This includes deleting all of its files too. To do this, type the following command;

rd /s D:\software\arch98

Convert each number into scientific notation.
1. 4,000,000,000
2. 0.000000027
3. 67,760,000
4. 90,500
5. 540,900
6. 0.00904
7. 0.032
8. 512,000,000

Answers

Answer:

4 * 10^9

2.7 * 10^-8

6.776 * 10^7

9.05*10^4

5.409*10^5

9.04 * 10^-3

3.2 * 10^-2

5.12 * 10^8

Explanation:

1. 4,000,000,000

4 * 1,000,000,000 = 4 * (10*10*10*10*10*10*10*10*10) = 4 * 10^9

2. 0.000000027

27 * 10^-9 = 2.7 * 10^-8

0.000000027 = 2.7 * 10^-8

3. 67,760,000 = 6776 * 10000

6776 * 10000 = 6776 * 10^4

6776 * 10^4 = 6.776 * 10^3 * 10^4 = 6.776 * 10^7

4. 90,500

905 * 100 = (9.05 * 100) * 100

(9.05*100) * 100 = 9.05 * 10^2 * 10^2 = 9.05*10^4

5. 540,900

5409 * 100 = (5.409 * 1000) * 100

(5.409*1000)*100 = 5.409*10^3 * 10^2

5.409*10^3 * 10^2 = 5.409*10^5

6.) 0.00904

0.00904 = 904 * 10^-5

904 * 10^-5 = 9.04 * 10^-3

7. 0.032

32 * 10^-3 = 3.2 * 10^-2

8. 512,000,000

512 * 1000000

512 * 10^6 = 5.12 * 10^2 * 10^6 = 5.12 * 10^8

Write an algorithm that accepts two numbers,
divide the first number by the second and display the
quotient

Answers

Let’s write the algorithm in the form of a pseudocode!

Pseudocode:Quotient_of_Two_Number
Declare: num1, num2, quotient
START
Display (Enter a number)
Read num1
Display (Enter a number)
Read num2
quotient = num1/num2
Print (“Quotient”)
STOP

_ is a term used for license like those issues by creative commons license as an alternative to copyright

Answers

, . , .

Explanation:

'

Explain why Thompson's Construction Algorithm is considered to be a proof by induction. Hint: consider what the inductive steps and base cases are. What does Thompson's Construction Algorithm prove

Answers

Answer:

We assume that the NFA for the expression S is theorem by using the expressions given below.

Cases as

NFA for empty-expression is ε NFA for symbol is a  NFA for union expression is a|b NFA for concatenation expression is ab NFA for Kleene star expression is a*

Thompson's Construction Algorithm proves that any expression can be expressions in the NFA's.

A capacitor of capacitance 102/π µF is connected across a 220 V, 50 Hz A.C. mains. Calculate the capacitive reactance, RMS value of current and write down the equations of voltage and current.

Answers

Answer:

The capacitive reactance will be "100Ω" and RMS value of current is "2.2 A". A further explanation is provided below.

Explanation:

Given:

[tex]C =\frac{10^2}{\pi}\times 10^{-6} \ F[/tex]

[tex]V_{RMS}=220 \ V[/tex]

[tex]f = 50 \ Hz[/tex]

Now,

The capacitive reactance will be:

⇒ [tex]X_c=\frac{1}{\omega C} =\frac{1}{2 \pi f C}[/tex]

                   [tex]=\frac{1}{2\times \pi\times 50\times \frac{10^{-4}}{\pi} }[/tex]

                   [tex]=100 \ \Omega[/tex]

RMS value of current will be:

⇒ [tex]I_{RMS}=\frac{V_{RMS}}{X_c}[/tex]

             [tex]=\frac{220}{100}[/tex]

             [tex]=2.2 \ A[/tex]

So that,

⇒ [tex]V_m=220\times \sqrt{2}[/tex]

         [tex]=311 \ V[/tex]

⇒ [tex]I_m=2.2\times \sqrt{2}[/tex]

         [tex]=3.1 \ A[/tex]

hence,

The equation will be:

⇒ [tex]\nu=311 sin31 \ 4t[/tex]

and,

⇒ [tex]i=3.1 sin(314t+\frac{\pi}{2} )[/tex]

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