Someone help me asap

Answer:

Step-by-step explanation:

Y equals mx plus b

Answer:

hope it helps.

Answer:

For this exercise we need to solve the next equation:

3 +6x = 2x + 27

We can start substracting 3 at both sides:

3 + 6x - 2 = 2x + 27 - 3

6x = 2x + 25

And then, we can substract 2x::

6x - 2x = 2x + 24 - 2x

4x = 25

Then, we divide by 4:

4x/4 = 24/4

x = 24/4 = 6

Now, we can see if we have done it correctly:

3 + 6*6 = 39

2 * 6 + 27 = 39

And we have seen our result is correct

Answer:

[tex]y = |x+2|+1[/tex]

Step-by-step explanation:

Answer:

Let that rational number to be subtracted be x.Given,-5/​6 - x = 4/9= - x = 4/9+5/6= - x = 23/18x = - 23/18.

Step-by-step explanation:

Answer:

It might be negative, I'm not sure, but I feel postive about that answer.

Step-by-step explanation:

Answer:

Step-by-step explanation:

The discriminant is zero because the graph of the parabola is on the x axis.

Answer:

1/√2

Step-by-step explanation:

The value of sin 45 is 1/√2

Answer:

1 / sqrt(3)

Step-by-step explanation:

tan(o) = sin(o) / cos(o)

sin(o) is the vertical distance from the x-axis. and that is in this basic circle the y-coordinate of the point.

cos(o) is the horizontal distance from the y-axis. that is the x-coordinate of the point.

so,

tan(o) = (1/2) / (sqrt(3)/2) = (2×1) / (2×sqrt(3)) = 1/sqrt(3)

Answer:

Step-by-step explanation:

as angles of two triangles are equal, so they are similar.

x/17 =35/14=40/16

x/17=35/14

x=35/14×17=85/2=42.5

perimeter of ΔJKL=40+35+42.5=117.5

Answer: The question is not complete. the figure is attached below.

The polygon is a rectangle.

Step-by-step explanation:

Line 1 goes through (-2, 3)

hence the slope of line 1 = -3/2

Line 2 goes through (0, 3) (2, 0)

hence the slope of line 2 = -3/2

Line 3 goes through (0, 1) (-3, 1)

hence the slope of line 3 = 2/3

Line 4 goes through (3, 0) (0, -2)

Hence the slope of line 4 = 2/3

therefore -3/2 * 2/3 = -1

Line1 + Line3      Line1 + Line4       Line2 + Line3        Line2+Line4

because, the distance between Line1 and Line2 is not equal to that Line3 and Line4.

The polygon is a rectangle polygon.

Answer:

6, -5 and 6. Assume the leading coefficient of f(x) is 1. Write the equation of the cubic polynomial in standard form.

Answer:

94

Step-by-step explanation:

(264+3*6)/3 = e

PEMDAS, so multiplication first.

3*6 = 18

= (264 + 18)/3

= 282/3

= 94

Answer:

1/ x = 22.5°

2/ x = 60°

Step-by-step explanation:

1/ We have: 3x + 2x + 3x = 180°

=> 8x = 180° => x = 22.5°

2/ We have: x + x + x = 3x = 180°

=> x = 60°

Answer:

1) x = 22.5

2) x = 60

Step-by-step explanation:

→ Add the angles together

1) 3x + 2x + 3x = 8x

2) x + x + x = 3x

→ Make it equal to 180

1) 8x = 180

2) 3x = 180

→ Divide both sides by 8 and 3

1) x = 22.5

2) x = 60

=================================================

Explanation:

Consider something like 2b+6 factoring to 2(b+3). When we distribute that outer 2 back inside the parenthesis, we're multiplying that 2 by everything inside. Factoring goes in reverse of this and we divide each term of 2b+6 by the GCF 2.

The same thing applies to this current problem as well.

Divide each term by the -1.8 we want to factor out.

The results -2b and 5 will go inside the parenthesis. That's how we end up with -1.8(-2b+5)

You can use distribution to verify this

-1.8(-2b+5)

-1.8*(-2b) - 1.8*(5)

3.6b - 9

Answer:[tex]-0.802; \ 1.517[/tex]

Step-by-step explanation:

Given

[tex]3^x=x^4[/tex]

Here, two functions are given that is [tex]y=3^x[/tex] and [tex]y=x^4[/tex]

Check for the intersection of the graph of two curves

From the graph, they cut at two different points  i.e. [tex]x=-0.802\ \text{and}\ x=1.517[/tex]

Rest two roots are negative.

Answer:

you should make the picture more clear, i cant see the answer choices

Answer:

use pythogoream theorem that is,

Step-by-step explanation:

c*2=a*2+b*2

so in order to find a*2;

a*2=c*2-b*2

Answer:

-4°C

Step-by-step explanation:

At the beginning of the chemistry experiment the temperature of the liquid was -5°C and it dropped 9°C so you do:

-5°C - 9°C = -14°C

The answer is -14°C for the first part of the question because when you are subtracting a positive number from a negative number you have to add the two numbers together but your answer will always be a negative number.

Then you add 25°C to -14°C:

-14°C + 25°C = 11

Because when adding a negative number to a positive number that is bigger than the negative number you have to subtract but your answer will always be a positive number, however if the positive number is smaller than the negative number your answer will be a negative number.

Then you subtract 11°C from 15°C:

11°C - 15°C = -4°C

Because when you subtract a number that is bigger than the first number you get a negative number.

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Its area includes all Sahara's locations in North Africa, South Arabia, Iran's and Iraq's larger parts, North-Western India, California throughout the United States, South Africa but most of Australia.

Half-arid temperatures include places like the Utah, Montana, and Gulf Coastal regions of sagebrush. Also, it comprises regions in Iceland, Russia, Scandinavia, Greenland, and Northeast India. Semi-arid thankless than tube called per year of rain and up to 20 inches per year at much more than arid deserts.

Regions from of the latitude of 25° to 35° usually develop desert, because air sinks and is heated under pressures in this area. The world's dry and semi-arid desert regions are between 20°C and 35°C north latitude and between 20°C and 35°C South latitude.

Answer:

6 I think

Step-by-step explanation:

Answer:

C. Line

Is the correct answer

Answer:

Falso.

Step-by-step explanation:

Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]

[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.

(c) El exponente es un negativo par.

Si [tex]n[/tex] es par, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' = c'[/tex], la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]

[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

9514 1404 393

Answer:

  (x, y) = (-2 12/17, -51)

Step-by-step explanation:

Here is the answer to ...

  [tex]4x+\dfrac{9}{y}+11=0\\\\\dfrac{6}{y}-3x=8[/tex]

If you mean something else, then parentheses are needed.

__

Let z = 1/y. Then the equations in general form are ...

  [tex]4x+9z+11=0\\3x-6z+8=0[/tex]

The solution (cross multiplication method) is ...

  x = (9·8 -(-6)·11)/(4(-6)-3·9) = 138/-51 = -2 12/17

  z = (11·3 -8·4)/-51 = -1/51

  y = 1/z = -51

The solution is (x, y) = (-2 12/17, -51).