Speeding is one of the most prevalent factors contributing to traffic crashes.
A. TRUE
B. FALSE

Answer:

a) An ARRAY ( 3 )

B) relatively INSENSITIVE ( 7 )

c) a HYBRID ( 4 )

Explanation:

They both used an array based implementation in the standard form and are both relatively insensitive to the order of the data. The main similarity is that each one creates an environment in which a hybrid strategy works more efficiently.

Quadratic selection sort is the sorting system that sorts out the smallest value in an entire list and arrange the list in such a way that the smallest value comes first.

The penalties for ignoring the requirements for protecting classified information when using social networking services are the same when using other media and methods of dissemination.

The penalties are the same because it does not matter what the medium used, the effect is that classified information and confidential details have been left unguarded and exposed.

When in hold of such information, it is not okay to leave it unguarded or exposed. A person who is found guilty of disclosure of classified materials would face sanctions such as:

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Answer:

Check your router connections then restart your router.

Explanation:

When the internet connection is not displaying properly then the first step is to check the router. The network icon on the internet displays the availability of internet. Adjust the router and see if the router is working properly. If not restart the router so that it adjusts its settings to default. The connection will be available on the computer and internet will start working normally.

Answer:

Top to down approach

Explanation:

Answer:

D

Explanation:

The value of i is incremented by one then assigned to d

Answer:

a)

Account account = new Account();

b)

Account account = new Account(firstName, age);

c)

account.Age = newAge;

d)

int count = Account.Count;

Explanation:

a)

new is the keyword which is used to create an object.

Account is the class name.

account is the name of an object of class Account.

account object is created to access the class Account.

Account() is the constructor of Account class. This is the default constructor and it has no parameters. Constructor has the same name as class. When a account object is created, constructor Account will be invoked.

b)

Account is the class name.

account is the name of an object of class Account.

Account() is the constructor of Account class. This is the parameterized constructor and it has two parameters i.e. firstName and age. Constructor has the same name as class. When a account object is created, constructor Account will be invoked.

c)

account.Age = newAge;

Here account is the object name. The Age property to access and update the private field of the Account class is set to the variable named newAge.

d)

This int count = Account.Count; statement gets the value of a public static field named Count that’s defined in the Account class, and stores the value in a new int variable named count.

Answer:

H cannot update it because it is probably protected.

If you cannot click in the table of contents, it is probably because it is protected. To disable this protection, choose Tools > Options > OpenOffice.org Writer > Formatting Aids, and then select Enable in the Cursor in protected areas section. If you wish to edit the table of contents without enabling the cursor, you can access it from the Navigator.

Explanation:

. To update a table of contents when changes are made to the document:

Right-click anywhere in the TOC.

From the pop-up menu, choose Update Index/Table. Writer updates the table of contents to reflect the changes in the document.

You can also update the index from the Navigator by right-clicking on Indexes > Table of Contents1 and choosing Index > Update from the pop-up menu.

Answer:

Following are the code to this question:

userVal = input()#defining a variable userVal for input the value

x= 0#defining variable x that holds a value 0

for j in userVal:#defining for loop to count input value in number

   if not(j in " .,"):#defining if block that checks there is no spaces,periods,and commas in the value

       x += 1#increment the value of x by 1

print(x)#Print x variable value

Output:

Hello, My name is Alex.

17

Explanation:

In the above-given code, a variable "userVal" is defined that uses the input method for input the value from the user end, in the next line, an integer  variable "x" is defined, hold value, that is 0, in this variable, we count all values.

Answer:

Explanation:#include <iostream>

#include<string>

using namespace std;

int main()

{

  string str;

cout<<"Enter String \n";

getline(cin,str);/* getLine() function get the complete lines, however, if you are getting string without this function, you may lose date after space*/

  //cin>>str;

  int count = 0;// count the number of characeter

  for (int i = 1; i <= str.size(); i++)//go through one by one character

  {

   if ((str[i]!=32)&&(str[i]!=44)&&(str[i]!=46))//do not count  period, comma or space

{

          ++ count;//count the number of character

      }

  }

  cout << "Number of characters are  = "; //display

cout << count;// total number of character in string.

  return 0;

}

}

Hope this is correct

HAVE A GOOD DAY!

Answer:

The sternum or breastbone is a long flat bone located in the central part of the chest.

The sternum or breastbone is a long flat bone located in the central part of the chest.

In the middle of the chest, there is a long, flat bone known as the sternum or breastbone. It forms the front of the rib cage and is joined to the ribs by cartilage, assisting in the protection of the heart, lungs, and major blood arteries from harm. It is one of the longest and largest flat bones in the body, somewhat resembling a necktie. The manubrium, body, and xiphoid process are its three regions.

Therefore, the sternum or breastbone is a long flat bone located in the central part of the chest.

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Answer:

Find the explanation below.

Explanation:

Asymmetric encryption is a system of communication in technology between two parties where keys which are variable values coined by an algorithm are used to encrypt and decrypt the messages between the sender and receiver. The two types of keys used in this process are the public and private keys. The public keys can be used by anyone to encrypt messages which are then sent to the receiver who decrypts the message using his private keys. The private keys on the other hand are only shared by the person who first set up the key. In sending messages this way, the receiver's public key is gotten from a public directory, and the message encrypted by the sender. The receiver can then decrypt the message using his private keys. But if the message is encrypted using a private key, it is decrypted by the receiver with a public key.

The one-way nature of this style of communication ensures data integrity and confidentiality since users are not required to disclose their keys and only the two parties can access the message. The two end users also preserve the right to authenticate the keys. The transport layer security protocol makes use of asymmetric encryption.

Answer:

i think is "none of them"

Answer:

line graph

Explanation:

the change in weight is linear

Answer:

Line Graph

Explanation:

Linear Weight change

Answer:

D. all of the above

Explanation:

A Stored Procedure (sp) is an already compiled group of SQL requests that contains either one or more statements which are stored in the master database.

A Stored Procedure can be created by using the CREATE PROC statement.

They perform standard tasks, stored in the master database and can change with each new version of SQL, so option D is correct.

Answer:

Here is the JAVA code:

public class Main{

public static int solution(int[] A) { //method that takes non-empty array A consisting of 0s and 1s

           int N = A.length; // number of 0s and 1s in array A

           int r = 0; //result of adjacency

           for (int i = 0; i < N - 1; i++;   )   { // iterates through A

               if (A[i] == A[i + 1])  //if i-th element of A is equal to (i+1)th element

                   r = r + 1;   }     //add 1 to the count of r

           if (r == N-1)   //for test cases like {1,1}

           {return r-1; }

           int max = 0; //to store maximum possible adjacency

           for (int i = 0; i <N; i++)   { //iterates through array

               int c = 0;

               if (i > 0)    { //starts from 1 and  covering the last

                   if (A[i-1] != A[i]) //checks if i-1 element of A is not equal to ith element of A

                       c = c + 1;    //adds 1 to counter variable

                   else

                      c = c - 1;   } //decrements c by 1

               if (i < N - 1)     {//starting with 0

                   if (A[i] != A[i + 1])  //checks if ith element of A is not equal to i+1th element of A

                       c = c + 1; //adds 1 to counter variable

                   else

                       c = c - 1;   }      //decrements c by 1        

               max = Math.max(max,c);   }  //finds the maximum of max and c

           return r + max;         } //returns result + maximum result

        public static void main(String[] args) {

   int[] A = {1, 1, 0, 1, 0, 0}; //sample array to test the method

   System.out.println(solution(A));} } //calls the method passing array to it

Explanation:

The program works as follows:

A[] = {1, 1, 0, 1, 0, 0}

N = A.length

N = 6

The A has the following elements:

A[0] =  1

A[1] = 1

A[2] = 0

A[3] = 1

A[4] = 0

A[5] = 0

Program iterates through array A using for loop. Loop variable i is initialized to 0

if condition if (A[i] == A[i + 1]) checks

if (A[0] == A[0 + 1])

A[0] =  1

A[0 + 1] = A[1] = 1

They both are 1 so they are equal

r = r + 1;  

Since the above if condition is true so 1 is added to the value of r Hence

r = 1

At each iteration of the loop the if condition checks whether the adjacent elements of A are equal. If true then r is incremented to 1 otherwise not.

So after all the iterations value of r = 2

if (r == N-1) evaluates to false because r=2 and N-1 = 5

So program moves to the statement:

for (int i = 0; i <N; i++)

This loop iterates through the array A

if (i > 0) condition checks if value of i is greater than 0. This evaluates to false and program control moves to statement:

if (i < N - 1) which makes if(0<5) This evaluates to true and program control moves to statement

if (A[i] != A[i + 1])  which means:

if (A[0] != A[0 + 1]) -> if (A[0] != A[1])

We know that

A[0] =  1

A[1] = 1

So this evaluates to false and else part is executed:

value of c is decremented to 1. So c=-1

max = Math.max(max,c) statement returns the max of max and c

max = 0

c = -1

So max = 0

value of i is incremented to 1 so i = 1

At next step:

if (i < N - 1) which makes if(1<5) This evaluates to true and program control moves to statement

if (A[i] != A[i + 1]) which means:

if (A[1] != A[1 + 1]) -> if (A[1] != A[2])

A[1] = 1

A[2] = 0

So the statement evaluates to true and following statement is executed

c = c + 1; The value of c is incremented to 1. So

c = -1 + 1

Hence

Hence c= 0, max = 0 and i = 2

next step:

if (i < N - 1) which makes if(2<5) This evaluates to true and program control moves to statement

if (A[i] != A[i + 1]) which means:

if (A[2] != A[2 + 1]) -> if (A[2] != A[3])

A[2] = 0

A[3] = 1

So the statement evaluates to true and following statement is executed

c = c + 1; The value of c is incremented to 1. So

c = 0 + 1

c = 1

Hence

The statement max = Math.max(max,c) returns the max of max and c

max = 0

c = 1

So max = 1

Hence  c= 1, max = 1 and i = 3

next step:

if (i < N - 1) which makes if(3<5) This evaluates to true and program control moves to statement

if (A[i] != A[i + 1]) which means:

if (A[3] != A[3 + 1]) -> if (A[3] != A[4])

A[3] = 1

A[4] = 0

So the statement evaluates to true and following statement is executed

c = c + 1; The value of c is incremented to 1. So

c = 1 + 1

c = 2

Hence

The statement max = Math.max(max,c) returns the max of max and c

max = 1

c = 2

So max = 2

Hence c= 2, max = 2 i = 4

next step:

if (i < N - 1) which makes if(4<5) This evaluates to true and program control moves to statement

if (A[i] != A[i + 1])  which means:

if (A[4] != A[4+ 1]) -> if (A[4] != A[5])

A[4] = 0

A[5] = 0

So this evaluates to false and else part is executed:

value of c is decremented to 1. So c=1

max = Math.max(max,c) statement returns the max of max and c

max = 2

c = 1

So max = 2

value of i is incremented to 1 so i = 5

next step:

if (i < N - 1) which makes if(5<5) This evaluates to false

if (i > 0) evaluates to true so following statement executes:

if (A[i-1] != A[i])

if (A[5-1] != A[5])

if (A[4] != A[5])

A[4] = 0

A[5] = 0

This statement evaluates to false so else part executes and value of c is decremented to 1

Hence

max = 2

c = 0

So max = 2

value of i is incremented to 1 so i = 6

The loop breaks because i <N evaluates to false.

Program control moves to the statement:

return r + max;

r = 2

max = 2

r + max = 2+2 = 4

So the output of the above program is:

4

Answer:

the answer is 300 feet in the daytime

Answer:

Here is the Python and C++ program.

Python program:

gallons_paint=0.0  #declare and initialize gallons_paint  

wall_area = float(input())  #prompts user to enter wall area

gallons_paint = wall_area / 350  #formula to compute gallons of paint needed to cover the given square feet of walls

print(gallons_paint) #display the result

C++ program:

#include <iostream> //to use input output functions

using namespace std; //to identify objects like cin cout

int main(){ //start of main() function body

   float wall_area,gallons_paint=0; //declare variables

   cin>>wall_area; //reads input wall area from user

   gallons_paint=wall_area/350; //formula to compute gallons of paint needed to cover the given square feet of walls

   cout<<gallons_paint;} //print the result

Explanation:

The program prompts the user to enter the area of wall and stores the input value in wall_area

Suppose the user enters 250 as wall area

The the formula gallons_paint=wall_area/350; works as follows:

gallons_paint = wall_area/350;

                         = 250/350

                         = 0.71428

gallons_paint  = 0.71428

So the output is:

0.71428

The screenshot of the program along with its output is attached.

Answer:

a

Explanation:

because they need to protect the organization's information

Explanation:

Refactoring consists of improving the internal structure of an existing program's source code, while preserving its external behavior. 

Answer:

Following are the code to this question:

f1=input('Input first file name: ')#defining f1 variable that input file 1

f2=input('Input second file name: ')#defining f2 variable that input file 2

file1=open(f1,'r')#defining file1 variable that opens first files by using open method  

file2=open(f2,'r')#defining file1 variable that opens second files by using open method  

d1=file1.readlines()#defining d1 variable that use readlines method to read first file data

d2=file2.readlines()#defining d2 variable that use readlines method to read second file data

if d1==d2:#defining if block that check file data

   print('Yes')#when value is matched it will print message yes  

   exit# use exit keyword for exit from if block

for j in range(0,min(len(d1),len(d2))):#defining for loop that stores the length of the file  

   if (d1[j]!=d2[j]):#defining if block that check value is not matched

       print('No')#print the message "NO"

       print("mismatch values: ",d1[j]," ",d2[j])#print file values

Output:

please find the attached file.

Explanation:

code description:

Answer:

first = input("enter first file name: ")

second = input("enter second file name: ")

file_one = open(first, 'r')

file_two = open(second, 'r')

if file_one.read() == file_two.read():

  print("Both files are the same")

else:

  print("Different files")

file_one.close()

file_two.close()

Answer:

It depends on the model of the printer you want to install. Recent printers when connected to the computer install themselves searching for the drivers needed on the internet. Anyway, you can always google the word "driver" plus the model of your printer and it will surely appear the driver you need from the the company's website of the printer

The print driver that you will need to complete the installation of a printer on Windows 7 Professional x86 workstation is; 32 bit driver

In windows 7 Professional, an x86 name architecture simply denotes a 32 - bit CPU and operating system while x64 will refer to a 64-bit CPU and operating system.

Thus, since we want to install a printer on a Windows 7 Professional x86 workstation, it means we have to use a print driver that is 32 - bit.

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Answer:

because they inspecting or checking how there works good or not good there are under there work what a result cause they want a good and beautiful work

They're inspecting or checking how there works good or not good there are beneath there job what a result because they want a nice and beautiful work.

The discipline of project planning focuses on how to complete a project within a predetermined timeframe, often with predetermined stages and resources. According to one method of project planning, the first stage is to set definable goals. scheduling the deliverables definition.

A project plan is made in order to effectively provide a result for the internal or external client. Project deliverables include, for instance, software products, design documentation, and other assets listed in the project plan. Deliverables for projects are frequently asked for as software products.

A project plan is a group of official documents that describe the execution and control phases of the project. The strategy considers risk management, resource management, and communications in addition to scope, cost, and schedule baselines.

Thus, They're inspecting or checking how there works good or not good.

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Answer:

struct PatientData{

   int heightInches, weightPounds;

};

Explanation:

In order to declare the required struct in the question, you need to type the keyword struct, then the name of the struct - PatientData, opening curly brace, data members - int heightInches, weightPounds;, closing curly brace and a semicolon at the end.

Note that since the object - lunaLovegood, is declared in the main function, we do not need to declare it in the struct. However, if it was not declared in the main, then we would need to write lunaLovegood between the closing curly brace and the semicolon.

Answer:

d. Backdoor

Explanation:

A backdoor is a type of malware that overrides security checks and authentications to access a computer or embedded device.

When this is done, remote access is granted and databases and servers can be accessed and modified. Attackers can also give remote commands to the system.

What happened to Ann in the payroll department is probably a backdoor attack that affected her device.

Answer:

Wireless resources management is communication to address they faster response time.

Explanation:

Wireless communication that provide bandwidth, and transmission reliable, towards development.

This communication is discovered to the date and have consumed physical layer  of available wireless resources.

Wireless communication management all this critical topic  and the management techniques, and limited device battery power.

Communication as the address channel loss, and multi path .

Communication are the latest resources allocation and new or next generation and technologies.

Wireless communication theoretical concepts in a manner, and the necessary mathematical tools and fundamental tools.

Wireless communication device industries up to date of the topic,readers are benefit from a basic.

Answer:

Here are the methods:

a) count

def count(object, list):  

   counter = 0

   for i in list:

       if i == object:

           counter = counter + 1

   return counter

b) in : return True if the item is in the list

def include(object, list):  

   for i in list:

       if i == object:

           return True

   return False

c)  reverse

def reverse(list):

   first = 0            

   last = len(list)-1    

   while first<last:

       list[first] , list[last] = list[last] , list[first]

       first = first + 1

       last = last - 1

   return list

d) index: return -1 if the item is not in the list  

def index(object, list):

   for x in range(len(list)):

       if list[x] == object:

           return x

   return -1

e)  insert

def insert(object, index, list):

   return list[:index] + [object] + list[index:]

Explanation:

a)

The method count takes object and a list as parameters and returns the number of times that object appears in the list.

counter variable is used to count the number of times object appears in list.

Suppose

list = [1,1,2,1,3,4,4,5,6]

object = 1

The for loop i.e. for i in list iterates through each item in the list

if condition if i == object inside for loop checks if the item of list at i-th position is equal to the object.  So for the above example, this condition checks if 1 is present in the list. If this condition evaluates to true then the value of counter is incremented to 1 otherwise the loop keeps iterating through the list searching for the occurrence of object (1) in the list.

After the complete list is moved through, the return counter statement returns the number of times object (i.e. 1 in the example) occurred in the list ( i.e. [1,1,2,1,3,4,4,5,6]  ) As 1 appears thrice in the list so the output is 3.

b)  

The method include takes two parameters i.e. object and list as parameters and returns True if the object is present in the list otherwise returns False. Here i have not named the function as in because in is a reserved keyword in Python so i used include as method name.

For example if list = [1,2,3,4] and object = 3

for loop for i in list iterates through each item of the list and the if condition if i == object checks if the item at i-th position of the list is equal to the specified object. This means for the above example the loop iterates through each number in the list and checks if the number at i-th position in the list is equal to 3 (object). When this if condition evaluates to true, the method returns True as output otherwise returns False in output ( if 3 is not found in the list). As object 3 is present in the list so the output is True.

c) reverse method takes a list as parameter and returns the list in reverse order.

Suppose list = [1,2,3,4,5,6]

The function has two variables i.e. first that is the first item of the list and last which is the last item of the list. Value of first is initialized to 0 and value of last is initialized to len(list)-1 where len(list) = 6 and 6-1=5 so last=5 for the above example. These are basically used as index variables to point to the first and last items of list.

The while loop executes until the value of first exceeds that of last.

Inside the while loop the statement list[first] , list[last] = list[last] , list[first]  interchanges the values of elements of the list which are positioned at first and last. After each interchange the first is incremented to 1 and last is decremented to 1.

For example at first iteration:

first = 0

last = 5

list[0] , list[5] = list[5] , list[0]

This means in the list [1,2,3,4,5,6] The first element 1 is interchanged with last element 6. Then the value of first is incremented and first = 1, last = 4 to point at the elements 2 and 5 of the list and then exchanges them too.

This process goes on until while condition evaluates to false. When the loop breaks  statement return list returns the reversed list.

d) The method index takes object and list as parameters and returns the index of the object/item if it is found in the list otherwise returns -1

For example list = [1,2,4,5,6] and object = 3

for loop i.e.  for x in range(len(list)):  moves through each item of the list until the end of the list is reached. if statement  if list[x] == object:  checks if the x-th index of the list is equal to the object. If it is true returns the index position of the list where the object is found otherwise returns -1. For the above examples 3 is not in the list so the output is -1  

e) insert

The insert function takes as argument the object to be inserted, the index where the object is to be inserted and the list in which the object is to be inserted.

For example list = [0, 1, 2, 4, 5, 6] and object = 3 and index = 3

3 is to be inserted in list  [1,2,4,5] at index position 3 of the list. The statement:

return list[:index] + [object] + list[index:]

list[:index] is a sub list that contains items from start to the index position. For above example:

list[:index] = [0, 1, 2]

list[index:] is a sub list that contains items from index position to end of the list.

list[index:] = [4, 5, 6]

[object] = [3]

So above statement becomes:

[0, 1, 2] + [3] + [4, 5, 6]

So the output is:

[0, 1, 2, 3, 4, 5, 6]