Suggest a possible mechanism for the acid catalyzed reaction of a typical ketohexose to give 5-hydroxymethylfurfural.

Answer:

18.84 g of silver.

Explanation:

We'll begin by calculating the number atoms present in 5.59 g of sulphur. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of sulphur contains 6.02×10²³ atoms.

1 mole of sulphur = 32 g

Thus,

32 g of sulphur contains 6.02×10²³ atoms.

Therefore, 5.59 g of sulphur will contain = (5.59 × 6.02×10²³) / 32 = 1.05×10²³ atoms.

From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.

Finally, we shall determine the mass of silver that contains 1.05×10²³ atoms.

This is illustrated below:

1 mole of silver = 6.02×10²³ atoms.

1 mole of silver = 108 g

108 g of silver contains 6.02×10²³ atoms.

Therefore, Xg of silver will contain 1.05×10²³ atoms i.e

Xg of silver = (108 × 1.05×10²³)/6.02×10²³

Xg of silver = 18.84 g

Thus, 18.84 g of silver contains the same number of atoms (i.e 1.05×10²³ atoms) as 5.59 g of sulfur

Answer:

P4O10

Explanation:

Answer:

is B

Explanation:

Answer:

p orbitals

Explanation:

Answer:

salt (NaCl)

Explanation:

Pure substance is defined as the substance that consist of a single type of material and does not contain contaminants. A pure substance has uniform composition throughout the process.

sodium chloride (NaCl) also known as table salt is a pure substance because it has a uniform and definite composition that is  1:1 ratio of sodium and chloride ions.

Hence, the correct answer is "salt (NaCl)".

Answer:

bottom right corner with arrows going up

Answer:

Explanation:

T

Answer:

for this one you would have to divide 19.9g by the kinetic energy 1.0 and you would get your answer.

Explanation:if you would give me brainiest that would help a lot :)

Answer:

hope this helps :)

Explanation:

Cl2 + NaBr = NaCl + Br2

NaCl + Br2 = NaBr + Cl2

Answer: The empirical formula is [tex]NaBO_2[/tex]

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given:

Mass of Na= 34.5 g

Mass of B= 16.4 g

Mass of O = 48.6 g

Step 1 : convert given masses into moles.

Moles of Na =[tex]\frac{\text{ given mass of Na}}{\text{ molar mass of Na}}= \frac{34.5g}{23g/mole}=1.5moles[/tex]

Moles of B =[tex]\frac{\text{ given mass of B}}{\text{ molar mass of B}}= \frac{16.4g}{11g/mole}=1.5moles[/tex]

Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{48.6g}{16g/mole}=3moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Na = [tex]\frac{1.5}{1.5}=1[/tex]

For B = [tex]\frac{1.5}{1.5}=1[/tex]

For O =[tex]\frac{3}{1.5}=2[/tex]

The ratio of Na: B: O= 1: 1: 2

Hence the empirical formula is [tex]NaBO_2[/tex]

Answer:

a.) 294.12 g/mol

Explanation:

1 equivalent of fatty acid reacts with 1 equivalent of NaOH.

As in the titration are required 0.0034 equivalents of NaOH, the equivalents of fatty acids = moles of fatty acids are:

0.0034 moles of fatty acids

Molar mass is defined as the ratio between mass of substance in a determined amount of moles. The mass of the fats was 1 gram, that means the molar mass is:

1g / 0.0034moles =

294.12g/mol

Right option is:

Answer:

carbon mono oxide CO

Explanation:

as both are in 1:1 ratio so CO is formed

Hi there! :)

[tex]\large\boxed{x = 2.49 L}[/tex]

Use the proportion for Charles' Law where:

[tex]\frac{v_{1}}{t_{1}}= \frac{v_{2}}{t_{2}}[/tex]

v1 = initial volume

t1 = initial temperature

v2 = final volume

v2 = final temperature

Substitute in the given values into the proportion:

v1 = 4.39 L

t1 = 44° C

t2 = 25°C

v2 = x L

Set up the proportion:

[tex]\frac{4.39}{44} = \frac{x}{25}[/tex]

Cross multiply:

[tex]25 * 4.39 = 44x\\\\109.75 = 44x\\\\x = 2.49 L[/tex]

Answer:

The new volume will be approximately 2.49 L.

Explanation:

We are given that a gas sample occupies 4.39 L at 44° C.

We are also given that we are going decrease the temperature to 25° C.

Charles' Law has a formula which shows the relationship between the volumes of a samples and the temperatures of the samples.

The proportion is shown as:

[tex]\displaystyle \bullet \ \ \ \frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex],

where V₁ and V₂ are the initial and final volume respectively and T₁ and T₂ are the initial and final temperature respectively.

This proportion can be used to determine what our unknown is. We need to know the final volume.

[tex]\displaystyle \frac{4.39 \ \text{L}}{44 \ \text{C}} = \frac{\text{x}}{25 \ \text{C}}\\\\\\\frac{4.39}{44} = \frac{x}{25}\\\\\\4.39 \times 25 = 44 \times x\\\\\\44x = 109.75\\\\\\\frac{44x}{44}=\frac{109.75}{44}\\\\\\x = 2.49432 \approx \boxed{2.49 \ \text{L}}[/tex]

Therefore, if we reduce the temperature to 25 °C, we will be reducing the volume of the substance to 2.49 L.

Answer:

After 3 half lives 10 g of radio active material left.

Explanation:

Given data:

Total amount of radio active material = 80 g

Amount left after 3 half lives = ?

Solution:

At time zero = 80 g

At first half life = 80 g/2 = 40 g

At 2nd half life = 40 g/2 = 20 g

At 3rd half life = 20 g/2 = 10 g

Thus, after 3 half lives 10 g of radio active material left.

Explanation:

I think it's the third one but I'm not sure

Answer:

The Answer for this is C

Answer:

D. Upper right

Explanation:

The position the student should look for such element is in the upper right corner before the noble gases.

Specifically, the group of halogens will react vigorously with lithium.

Answer:

D. Upper right

Explanation:

I had the exact same question

Answer:

i do k12 too!

Explanation:

lol

Answer:

Molecular Formula Ca(OH)2 or CaH2O2

Synonyms CALCIUM HYDROXIDE 1305-62-0 Slaked lime Hydrated lime Ca(OH)2

Molecular Weight 74.09 g/mol

Component Compounds CID 962 (Water) CID 5460341 (Calcium)

Explanation:

Explanation:

₇N = 1s² 2s² 2p³

Therefore,

Option C is correct ✔

Answer:

35.453 amu.

Explanation:

From the question given above, the following data were obtained:

Isotope A (Cl–35):

Abundance (A%) = 75.77%

Mass of A = 34.969 amu

Isotope B (Cl–37):

Abundance (B%) = 24.23%

Mass of B = 36.966 amu

AVERAGE atomic mass of Cl =?

The average atomic mass of Cl can be obtained as follow:

Average = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

Average = [(34.969 × 75.77)/100] + [(36.966 × 24.23)/100]

Average = 26.496 + 8.957

Average atomic mass of Cl = 35.453 amu.

The [H₃0⁺] of the solution : 1.778  x 10⁻¹² M

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.  

pH = - log [H⁺]  

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.  

A solution whose value is different by n has a difference in the concentration of H⁺ ion of 10ⁿ.  

pH of solution = 11.75

the [H₃0⁺] of the solution :

[tex]\tt pH=-log[H_3O^+]\\\\11.75=-log[H_3O^+]\\\\(H_3O^+]=10^{-11.75}=1.778\times 10^{-12}[/tex]

Answer:

1) magnesium chloride

2) b) The copper is getting oxidized from Cu+ to Cu2+ and turns blue.

Explanation:

The work published by David N. Frick, Sukalyani Banik, and Ryan S. Rypma in J Mol Biol. 2007 Jan 26; 365(4): 1017–1032 clearly shows that divalent metal ions of group 2 such as Mg^2+ play an important role in ATP hydrolysis. Addition of EDTA decreased the rate of hydrolysis of ATP (due to sequestration of the divalent ion of group 2) indicating an active participation of divalent ions in the process.

2) The copper I ion is colourless because it is a d^10 specie. However, when it is oxidized to Cu^2+, a blue colour appears in the solution.

Answer:

87.5 %

Explanation:

Step 1: Given data

Step 2: Calculate the percent yield

When working with chemical reactions, we can determine the efficience in obtaining a product measuring the percent yield. The theoretical yield is the maximum amount of product that we could obtain according to the stoichiometry, whereas the real yield is the amount of product that we actually obtain when we carry out the process. We can calculate the percent yield usign the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 105 kg / 120 kg × 100%

%yield = 87.5 %

Answer:

118 mL

Explanation:

We can easily calculate the final volume of the solution (V₂) by applying the following mathematical expression:

V₁ x C₁ = V₂ x C₂

⇒ V₂ = V₁ x C₁/C₂

Given:

V₁ = 10 mL

C₁ = 0.65 M

C₂ = 0.055 M

We replace the data in the mathematical expression to calculate V₂:

V₂ = V₁ x C₁/C₂ = 10 ml x (0.65 M)/ (0.055 M) = 118.18 mL ≅ 118 mL

Answer: In the case of water, we know that the O-H covalent bond is polar, due to the different electronegativities of hydrogen and oxygen. Since there are two O-H bonds in water, their bond dipoles will interact and may result in a molecular dipole which can be measured.

Explanation:

Answer:

Octahedral

Explanation:

The idea of hybridization is a valence bond concept introduced by Linus Pauling and soon became an important explanation for the structure of molecules even in coordination chemistry.

Hybridization involves the mixing of orbitals of appropriate energy to form a new set of orbitals that are more suitable for bonding with ligands.

When one s, two d and three p orbitals are hybridized in complex formation, octahedral complexes are formed.

thermal contact

When heat flows from one object or substance to another it is in contact with, the objects or substances are said to be in thermal contact. The state where objects in thermal contact with each other reach the same temperature, no heat flows between them.

Answer:

the  molar mass of the compound is  34.0 g /mol

Explanation:

The computation of the molar mass of the compound is as follows:

As we know that

PV = nRT

n = mass ÷ MW

PV = mRT ÷ MW

It can be rearrange as

MW = mRT ÷ (PV)

MW = (0.941)(0.082)(150 + 273) ÷ (1 × 0.96)

= 33.99g/mol

= 34.0 g /mol

Hence, the  molar mass of the compound is  34.0 g /mol