supply drop design proposal

Schedules of reinforcement farm workers are paid x amount of dollars for every basket of fruit that they pick is based on the concept of fixed ratio.

A strengthening timetable, during which an answer or reaction is only strengthened after yet another given reaction can be determined, could be determined as a fixed ratio schedule. The particular topic gives a variety of questionnaires/solutions and therefore is subsequently rewarded by the educator or coach.

The man is under a fixed interval schedule of reinforcement, while the woman is under a fixed ratio schedule of reinforcement. Fixed interval reinforcement is a type of reinforcement that gives reward only after a specific period of time has passed. A fixed ratio reinforcement is a type of reinforcement that is based on production rate.

The other type is variable ratio. Variable Ratio schedule of reinforcement will give a person rewards after he/she fulfil a specific amount of works.

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The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same. Option D

We know that it is possible for an object to be able to bump into another object when this occurs, we would have to apply the law of the conservation of linear momentum. Recall that from the law of the conservation of linear momentum, momentum before collision is equal to the momentum after collision.

We would also have to consider the fact that the weight of the truck is much lager than the weight of the car. The forces that the two vehicles would exert on each other can not be the same. It is clear that the truck is going to exert more force than the car.

With that said, we must have in mind that the total momentum of the system does not change because we are going to approximate the system to function as a closed system.

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Between 400 nm and 700 nm of the electromagnetic spectrum, vegetation has the strongest response.

The electromagnetic spectrum travels in waves and spans an extensive spectrum from very long radio waves to very brief gamma rays. The human eye can simplest come across only a small portion of this spectrum called visible light.

In order from maximum to lowest power, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible mild, infrared radiation, and radio waves.

In a tumbler, the purple mild travels the fastest, and the violet light travels the slowest of all seven hues. Velocity and wavelength are without delay proportional.

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The value of R so that the response is critically damped using the equation is 25.0Ω.

Farads is the unit of measure for capacitance, which is the amount of electrical charge stored for a given voltage. Farads can be used to measure the amount of energy stored in a capacitor, which is made up of two conductive plates separated by an insulating material. The higher the capacitance, the more energy can be stored in a given capacitor. Farads are named after Michael Faraday, the British scientist who discovered the relationship between electricity and magnetism.

The resonant frequency of an RLC circuit is given by the equation:
ω_r=1/sqrt(LC)
where ω_r is the resonant frequency in rad/s, L is the inductance in Henries, and C is the capacitance in Farads.
Given the resonant frequency of 5000 rad/s and the inductance of 10 mH, we can calculate the capacitance as follows:
C=1/(ω_r^2*L)
C=1/(5000^2*0.01)
C=4.00μF
We can find the value of R so that the response is critically damped using the equation:
R=2*sqrt(L/C)
R=2*sqrt(0.01/4.00)
R=25.0Ω

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Main Answer:

The distance of L is [tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]

Explanation:

if the block will slide a distance 'L' then syoped;

The initial velocity given to the block is V m/s

So, Total K.E given will goes to gain in potential energy and work done by friction .

K.E=1/2mv^2

P.E at hight (Lsin[tex]\alpha[/tex]) will be = mgh

And work done by the Friction Force is given as = w.r = force*displacement= - uNL= -uMgGcos[tex]\alpha[/tex]L

so,

KE+WD by friction = gain in P.E

[tex]1/2mv^{2} +(-uMgGcos\alpha L)=MgLsin\alpha \\1/2V^{2} =glsin\alpha +uglcso\alpha \\v^{2} /2= Gl(sin\alpha +ucos\alpha )[/tex]

Hence by solving we get :

[tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]=L

So the distance = L

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The unit of G is found out to be m³/kg * s².

The force of gravitational attraction is represented by the equation.

F = (G m₁ m₂)/r²

where,

F is the magnitude of the gravitational attraction on either body

m₁ and m₂ are the masses of the bodies,

r is the distance between them

G is the gravitational constant

We need to find the unit of G,

G = (F * r²)/(m₁ m₂)

Let us place the units for the above formula,

G = (N * m²)/kg²

N = kg m/s²

G = (kg * m * m²)/ kg² * s²

G = m³/kg * s²

Thus, the correct option is m³/kg * s².

The question is incomplete. The complete question is 'Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equation.

F= Gm1 m2 /r^2

where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, r is the distance between them, and G is the gravitational constant. In Sl units, the units of force are kg m/s^2, the units of mass are kg, and the units of distance are m. For this equation to have consistent units, the units of G must be which of the following?

a. kg^3/ms^2

b. kgs^2/m^3

c. m^3/kgs^2

d. m/kgs^2

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I think it is "energy cannot be destroyed but it can change forms".

To get the work, you have to integrate the force as a function of [tex]$x$[/tex] from zero displacement to Xo

[tex](Integral of) $\mathrm{k} \mathrm{x}^{\wedge} 2 \mathrm{dx}$ from 0 to $\mathrm{Xo}_{\mathrm{o}}=(1 / 3) \mathrm{k}\left(\mathrm{Xo}^{\wedge}\right)^{\wedge} 3$[/tex]

The work done by stretching the spring to the given distance is [tex]W=\frac{k x_0}{3}[/tex]

The given parameters:

- Applied force on the spring [tex]$=F$[/tex]

- Extension of the spring [tex]$=x_0$[/tex]

The work done by stretching the spring to the given distance is calculated as follows;

[tex]W=\frac{k x_0}{3}[/tex]

[tex]$$\begin{aligned}& W=\int_{x_a}^{x_b} F d x \\& W=\int_{x_a}^{x_b} k x^2 d x \\& W=k \int_{x_a}^{x_b} x^2 d x \\& W=k\left[\frac{x^3}{3}\right] \\& W=k\left[\frac{x_b-x_a}{3}\right] \\& W=k\left[\frac{x_0-0}{3}\right] \\& W=\frac{k x_0}{3}\end{aligned}[/tex]

Thus, the work done by stretching the spring to the given distance is

[tex]W=\frac{k x_0}{3}[/tex]

measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.

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The experimental procedures that will allow the students to determine both of these relationships is option E:

The formula  F = IL x B calculates the magnetic force acting through a magnetic field on a current-carrying wire. The magnetic field acts on a wire when a current is conducted through it in a direction that is perpendicular to both the magnetic force.

By increasing the amount of current flowing through the wire, the magnetic field's strength can be enhanced. As you get further from the wire, the strength gets weaker. If the amount of current flowing through it stays constant, its length and thickness have no bearing.

Therefore, the length of the wire in the magnetic field has an impact on the magnetic force's strength as well. The force acting on a wire increases with wire length in a magnetic field.

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The force of gravity acting on the 23 Kg object in the diagram is 225.4 N

The force of gravity is defined as follow:

Force of gravity (F) = mass (m) × acceleration due to gravity (g)

Using the above formula, we can easily obtain the force gravity acting on the 23 Kg object. This is shown below:

Force of gravity (F) = mass (m) × acceleration due to gravity (g)

Force of gravity = 23 Kg × 9.8 m/s²

Force of gravity = 225.4 N

Thus, from the calculation made above, we can conclude that the gravitaional force is 225.4 N

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The coefficient of static friction between feet and ground is 0.2522.

Static friction is defined as when there is no motion between the two surfaces, the force that one surface applies to another. The friction that exists between two or more objects when they are not moving relative to one another is referred to as static friction.

The coefficient of static friction between his feet and the ground, denoted by the symbol s, determines how to express the frictional force as

fs =μsFN1

The μs can be calculated as

μs = a / √L² - a² x d / L

μs = 0.945 / √(1.95)² - (0.945)² x 0.89 / 1.95

μs = 0.945 / √2.91225 x 0.89 / 1.95

μs = 0.2522

Thus, the coefficient of static friction between feet and ground is 0.2522.

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Step 1: Calculate the ratio of the final and beginning temperatures using the ideal gas law solved for temperature.

Step 2: Calculate the ratio after eliminating any constant values.

Step 3:Solve for the final temperature after substituting the beginning temperature into the ratio.

PV= nRT

However, for this method to work properly, the temperature must be stated in Kelvin. This is true because Kelvin's zero point is absolute zero. Theoretically, molecules are entirely immobile at 0 Kelvin.

T = PV/nR

The ideal gas law equivalency is used to compute the final temperature in the next two issues.

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Important Formula:

[tex]s=\dfrac{d}{t}[/tex]

__________________________________________________________

[tex]d=85m[/tex] (measured in meters)

[tex]t=13s[/tex] (measured in seconds)

[tex]s=?[/tex] (measured in meters per second; m/s)

__________________________________________________________

[tex]s=\dfrac{d}{t}[/tex]

[tex]s=\dfrac{85}{13}[/tex]

__________________________________________________________

[tex]\fbox{6.54 m/s},\fbox{Option C}[/tex]

The correct option is that C. The induced current will be clockwise until the bottom of the loop reaches the wire and will be counterclockwise when the bottom of the loop goes below this point. This is because the induced current is proportional to the rate of change of the magnetic field flux, which increases when the bottom of the loop is above the wire and decreases when the bottom of the loop is below the wire.

According to Faraday's law, the magnetic flux change rate in a circuit equals the magnitude of the induced EMF in the circuit. Additionally inversely correlated with the rate of change of magnetic flux in the circuit is hens induced current.

Lenz's law states that an induced current will flow in the opposite direction of the cause that is causing it. When the bottom of the loop is below this point, the induced current is counterclockwise until the bottom of the loop reaches the wire. This is because the magnetic field flux changes more quickly when the bottom of the loop is above the wire because the induced current is proportional to this

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A particle moves under the influence of a conservative force, The maximum x-coordinate of the particle at x = -3 m is 7 m.

Given that,

Potential energy of the particle u(x) = 5x² - 20x + 2

We know the relation between force and potential energy as,

F = -du/dx = -d/dx (5x² - 20x + 2) = -(10 x - 20 ) = 20 - 10 x at mean position x = 2.

At x = -3, amplitude is given by x = 2 - (-3) = 5

The maximum x co-ordinate is given as x = 5 + 2 = 7 m

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If wire loop is being pulled to the right with a constant velocity of 3 meters per second , then the potential difference induced between points X and Y is 3V .

it is given that a 5Ω resistor is connected between points X and Y ;

the magnetic field (B) = 0.5 ;

length of wire (l) [tex]=[/tex] 2 ;

velocity of the wire loop (v) = 3 m/s ;

the potential difference will be induced because charge separation on the vertical hand wire of wire loop.

Points X and Y are the same as the top and bottom of left wire.

The EMF(potential difference) induced in wire is given by

EMF = B*l*v

substituting the values ,

we get  

= (0.5)(2)(3) = 3V

Therefore , the induced potential difference between points X and Y is 3V .

The given question is incomplete , the complete question is

A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines. The loop is being pulled to the right with a constant velocity of 3 meters per second. Make all determinations for the time that the left end of the loop is still in the field, and points X and Y are not in the field.

Determine the potential difference induced between points X and Y.

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Answer:

Here, h1=4.00m,h92)=3.00m,Delta t =0.01 s.Letv1 be the velocity of the ball (actind downwards) just before striking the floor an dv20 be the velocity of the ball (acting upwaeds) ust after striking the floor. Then, change in velocity of the ball in time Δtv2−(−v1)v2+v1

:. acceleration, a=v2+v1Δt ..(i)

When body falls from height h1,

then u=o,v1,a=gandS=h1

As, v21=u2+2aS,

:. v_(1) ^(2) =0 + g h_(10 or v12–√gh1

Taking motion of the ball after striking the floor, then u=v2,v=0,a=−g,S=h2

As, v2=u22as,∴v21=0+2gh1orv_(1) =sqrt 32 g h_(1)Tak∈gmotionoftheballa>erstrik∈gthe⌊,⌋thenu=v_(2), v=0, a=- g, S=h_(2)As,v2=u2+2aS,wehave0 = v_(2)^(2) +2 (-g) h_92) otr v2=2–√gh2

Putting values in (i) we get,

a=2–√gh2+2–√gh1Δt)

a=2–√×9.8×3+2–√×9.8×40.01

= 1652m/s2.

Explanation:

The centripetal force needed to keep the fly from sleeping will be zero point 0.00176 Newton in magnitude.

The mass of the fly is 2 gram and it is selling itself on a phonograph turntable.

The fly is at a distance of 4 cm away from the center of the phonograph turntable and when the turntable is turned on and retreats with 45 Revolution per minute the centripetal force that would be working on the fly will be given by,

F = Mw²R

Where,

M is mass of the fly,

w is the angular speed of the fly and,

R is the radius of the turnable.

Putting all the values,

F = 0.002×(4.7)²×0.04

F = 0.00176N.

So, a centripetal force of magnitude 0.00176 Newton will be required in order to keep the fly from slipping.

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Complete question- A fly of mass 2.00 g is sunning itself on a phonograph turntable at a location that is 4.00 cm from the center. When the turntable is turned on and rotates at 45.0 rev/min, calculate the centripetal force needed to keep the fly from slipping?

If an object producing sound is moving away from us, the wavelength of the sound heard is longer than the actual wavelength. The conclusion is from the concept of Doppler effect.

The Doppler's effect is a phenomenon when the source of a wave and an observer move relative to each other, the frequency heard is not the same with the actual frequency.

The equation of the Doppler effect is

f₀ = [(v ± v₀)/(v ± vs)] × fs

Where

Note:

When an object producing sound is moving away from us, the frequency of the sound we heard changed.

Let's say we are at rest, it means v₀ = 0. The sound source is moving away makes vs (+).

With the Doppler's effect, we get

f₀ = [(v+0) / (v+vs)] × fs

f₀/fs = v/(v+vs)

v < v+vs

f₀ < fs

The frequency of sound we heard is lower that the actual frequency.

The wavelength is inversely proportional to the frequency. It is described in the equation:

λ = c/f

It means that the lower the frequency, the longer the wavelength.

Hence, the phenomenon which the wavelength of the sound we heard is longer than the actual wavelength when the sound source is moving away from us is called the Doppler's effect.

Here is the group of answer choices:

(a) Band width

(b) Doppler's effect

(c) Sound refraction

(d) Vibrations

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Answer:

18447 J

Explanation:

To calculate the internal energy of steam at a given temperature, we need to know the specific heat capacity of steam and the enthalpy of vaporization. The specific heat capacity of steam at a constant pressure is approximately 2.08 J/g*K, and the enthalpy of vaporization (latent heat) at 100°C is 2257 kJ/kg.

We can use the following equation to calculate the internal energy of steam at a given temperature:

U = m * Cp * (T - T_b) + m * L

Where U is the internal energy, m is the mass of the steam, Cp is the specific heat capacity of steam, T is the temperature of the steam, Tb is the boiling temperature of the steam, and L is the enthalpy of vaporization.

Since we are given the amount of steam in moles (1.2 moles) and the temperature (177°C), we can convert the moles of steam to mass using the molar mass of water (18 g/mol). The boiling temperature of water at standard atmospheric pressure is 100°C, so we can use this value for Tb.

First, we need to convert the temperature from degrees Celsius to kelvins:

T = 177°C + 273 = 450 K

Then, we can calculate the mass of the steam:

m = 1.2 moles * 18 g/mol = 21.6 g

Substituting these values into the equation for internal energy, we get:

U = 21.6 g * 2.08 J/g*K * (450 K - 273 K) + 21.6 g * 2257 kJ/kg

Solving for the internal energy, we get:

U = 18,447 J

Therefore, the internal energy of 1.2 moles of steam at 177°C is approximately 18,447 J.

D) The Sun's evolution from youngest to the oldest stage is protostar, main-sequence, red giant, a white dwarf.

A protostar is the very beginning stage of a star's life. It is a cloud of gas and dust that starts to collapse due to its own gravitational pull. As it collapses, the gas and dust heat up, and eventually, nuclear fusion begins, creating a star.

The main-sequence stage is the longest and most stable period of a star's life. During this stage, the star is converting hydrogen into helium in its core, producing energy and light. This stage can last for billions of years.

Once a star has used up its hydrogen fuel, it enters the red giant phase. This is when the star expands, becoming much larger and much brighter. The star is now converting helium into other elements in its core, such as carbon and oxygen.

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The distance travelled by the car after the brake was applied is 125 m.

The distance travelled by the car is calculated by applying the following kinematic equation as shown below.

Mathematically, the distance travelled by the car at the given average speed is calculated as;

s = [ ( v + u ) / 2 ] t

where;

The distance travelled by the car is calculated as;

s = [ ( 0 + 25 m/s ) / 2 ] ( 10 s )

s = 125 m

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Where the exercise here is to name the disorder, note that:

It should be mentioned that medication (such as antidepressants or benzodiazepines) and/or counseling may be used to treat a panic disorder such as cognitive-behavioral therapy.

A suitable course of treatment for dissociative disorders may involve counseling (such as cognitive-behavioral therapy, trauma-focused therapy, or psychodynamic therapy) and/or medication.

The focus of psychodynamic therapy is on unconscious processes as they show in the client's current behavior. Client self-awareness and knowledge of the effect of the past on present behavior are the aims of psychodynamic therapy.

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The path taken by a light beam after passing through a mirror's focus is where it hits the mirror and reflects back in exactly the same direction as it went in.

Specular reflection is the name for this. A smooth surface allows light to bounce back at the same angle that it was incident. Rays of light that are reflected off of a smooth surface go in that same direction.

The narrow beams of light that travel in straight lines along their courses as electromagnetic waves are known as rays. Though its path might be altered by reflection or refraction, light always moves in a straight line.

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Since light is faster in space, it takes less time for light to travel a distance of 1000m, a time difference of 0.977ns.

Light travels more slowly in a transparent medium than in the vacuum of empty space. The speed of light in any medium (air, water, glass) is determined by the refractive index of the medium. However, this exponent itself may be wavelength dependent (ie different colored rays travel at different speeds). In fact, this is why a prism splits white light into the colors of the rainbow.

The main reason that a light beam slows down in a medium has to do with the fact that the photons, or 'raw light beams', are excited by an electromagnetic field. When the field is in the ground state (vacuum), these excitations actually propagate at the vacuum speed of light. However, when there are positively charged atoms and negatively charged electrons, the electromagnetic field does not go to the ground state. There are many virtual photons. Yes, some of the photons of the passing light beam can be absorbed. After all, no material is completely transparent. But even those who aren't are moving in an environment so different from the vacuum that their paths will be different. It also depends on the structure that the molecule forms.

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Joan is going with speed 30 m/s. Hence, option (C) is correct.

Acceleration is the rate at which a velocity changes over time. It qualifies as a vector quantity because it possesses both direction and magnitude. Meter/second^2 (m/s^2) is the SI unit of acceleration.

Given that: initial speed of the car: u = 10 m/s.

Uniform acceleration of the car: a =  4 m/s^2.

Distance travelled: s = 100 meters.

Let, the final speed is = v

Using the formula v² = u² + 2as, we get:

v = √(10² + 2×4×100) m/s.

= 30 m/s.

Hence, final speed of the car is 30 m/s.

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Parallax, main-sequence fitting, cepheid variables, Tully-Fisher relation, and Hubble's law are the sequence lists methods for determining distance.

Parallax is the closest method for determining distance. This method uses the principle of triangulation to measure the distance of a nearby star relative to Earth. Main-sequence fitting is another method used to measure the distance of stars. This method compares the brightness of a star to other stars of known distance and luminosity to determine its distance.

Cepheid variables are stars whose brightness varies in a predictable way over time. This method uses the period of the star's brightness to determine its intrinsic luminosity, and then its distance. The Tully-Fisher relation is a method for measuring the distance of galaxies. This method uses the rotation speed of the galaxy and its brightness to calculate its distance.

Finally, Hubble's law is the most distant method for determining distance. This law states that the farther away a galaxy is, the faster it moves away from us. This allows us to calculate the distance of galaxies by measuring their rate of recession.

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The angular momentum of a system does not depend on the point about which it is taken, according to equation (iv). the particles  eventually move back together because of mutual gravitational attraction.

As depicted in the following diagram, assume that two particles are present at positions P and Q at some point in time.

Think about a point R that is y miles away from a point Q, or QR=y PR=dy.

LP=mv0+mvd=mvd is the system's angular momentum around point P.

I The system's angular momentum around point Q is given by LQ=mvd+mv0=mvd.....(ii)

System's angular momentum about point R is given by LR=mv(d, y)+mv(y, d)=mvd....(iii)

The result of comparing equations I (ii), and (iii) is L P = LQ = LR....... (iv)

The angular momentum of a system does not depend on the point about which it is taken, according to equation (iv).

All objects with mass are attracted to one another by the gravitational attraction, which has a magnitude that is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another.

Our feet remain firmly planted on the ground thanks to gravity, which also keeps the Moon in orbit around the Earth, the Earth in orbit around the Sun, the Sun in orbit around the galactic core of our Milky Way galaxy, and the Milky Way and Andromeda galaxies orbiting each other.

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The force exerted at the large piston will be double in magnitude in comparison with the force applied at the smaller piston.

We know, according to the pascal's law,

The pressure applied at any point in the incompressible fluid is equal in magnitude at each and every point.

So,

P = Force/Area

Where P is pressure,

If pressure is same, then we can write,

F₁/A₁ = F₂/A₂

Where,

F₁ is the force applied at the small piston,

A₁ is the area of the smaller piston,

F₂ is the force at the larger piston,

A₂ is the area of the larger piston,

It is also given that, area if the larger piston is two times the area of the smaller piston so,

A₂ = 2A₁

So, putting the values we get,

F₂/F₁ = 2

So, F₂ = 2F₁

It means that the force exerted by the larger piston will be double in magnitude.

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