Suppose that, out of a group of 100 UF students, 90 are from Florida. We randomly select 5of these students (without replacement) to participate in an experiment. LetXdenote thenumber of students selected who are from Florida.

Required:
a. Find E[X].
b. Find P(X > 4).
c. Now suppose that we instead select 20 of these students. Let Y denote the number of selected students who are from Florida. Find P(Y < 5).

Answer:

60m^2 is the answer im pretty sure

Step-by-step explanation:

yeah man thats it

He used 620 gallons of gas

Answer:

m<F = 95°

Step-by-step explanation:

We'll begin by calculating the value of x. This can be obtained as follow:

m<C = 50

m<A = (10x – 5)

m<B = m<G = (2x + 15)

m<C + m<A + m<B = 180 (Sum of angles in a triangle)

50 + (10x – 5) + (2x + 15) = 180

50 + 10x – 5 + 2x + 15 = 180

50 – 5 + 15 + 10x + 2x = 180

60 + 12x = 180

Collect like terms

12x = 180 – 60

12x = 120

Divide both side by 12

x = 120 / 12

x = 10

Finally, we shall determine the value of m<F. This can be obtained as follow:

m<F = m<A

But

m<A = 10x – 5

x = 10

Therefore,

m<F = 10x – 5

m<F = 10(10) – 5

m<F = 100 – 5

m<F = 95°

9514 1404 393

Answer:

  x = 142

Step-by-step explanation:

You want to find x such that ...

  [tex]\sqrt{x+2} -15=-3\qquad\text{given}\\\\\sqrt{x+2} =12\qquad\text{add 15}\\\\x+2=144\qquad\text{square both sides}\\\\\boxed{x=142}\qquad\text{subtract 2 to get x by itself}[/tex]

Answer:

a

Step-by-step explanation:

Completing the square gives

[tex]x^2-2x-2=(x-1)^2-3[/tex]

and comparing to [tex]y=x^2[/tex], the graph of [tex]y=x^2-2x-2[/tex] would be a horizontal shift to the right by 1 unit, and a vertical shift down by 3 units.

Hope this help!!!

Have a nice day!!!

Answer:

ED = 31

DT = 20

Step-by-step explanation:

m< ESD = 90-52=38°

the distance ED = 40×tan 38° = 31.25 = 31

ET = 40 x tan (90-38) = 40×tan 52°

= 51.19= 51

the distance DT = 51-31 = 20

Answer:

Evans would have $852.8

Step-by-step explanation:

Given

[tex]PV = \$800[/tex]

[tex]r = 3.25\%[/tex]

[tex]t = 2[/tex]

[tex]n = 1[/tex] --- annually'

Required

The future value

This is calculated using:

[tex]FV = PV*(1 + \frac{r}{n})^{nt[/tex]

So, we have:

[tex]FV = 800 * (1 + 3.25\%/1)^{2*1}[/tex]

[tex]FV = 800 * (1 + 3.25\%)^{2}[/tex]

[tex]FV = 800 * (1 + 0.0325)^{2}[/tex]

[tex]FV = 800 * (1 .0325)^2[/tex]

[tex]FV = 852.845[/tex]

[tex]FV = 852.8[/tex]

FV =

9514 1404 393

Answer:

  160 cm³

Step-by-step explanation:

The ratio of the linear dimensions is the square root of the ratio of areas:

  scale factor B/A= √(64/144) = 8/12 = 2/3

The ratio of volumes is the cube of the scale factor:

  (volume B)/(volume A) = (2/3)³ = 8/27

Then the volume of pyramid B is ...

  volume B = (volume A) × (volume B)/(volume A)

  = (540 cm³) × (8/27) = 160 cm³ . . . . volume of pyramid B

_____

Equivalently, the ratio of volumes is the 3/2 power of the ratio of areas.

 Vb = Va(64/144)^(3/2) = (540 cm³)(4/9)^(3/2) = (540)(8/27) cm³ = 160 cm³

Answer:

[tex]P(x < 4) = \frac{9}{50}[/tex]

Step-by-step explanation:

Given

[tex]n(S) = 50[/tex]

See attachment for distribution

Required

[tex]P(x < 4)[/tex]

This is calculated as:

[tex]P(x < 4) = \frac{n(1) + n(2) + n(3)}{n(S)}[/tex]

Using the data on the frequency distribution table, we have:

[tex]P(x < 4) = \frac{4 + 2 + 3}{50}[/tex]

[tex]P(x < 4) = \frac{9}{50}[/tex]

Answer:

well,

it's more than (20ft)²

bc 20*20 =400

21² = 21 * 21 = 441

getting closer...

22² = 22 * 22 = 484

[tex] \sqrt{484} = {22}^{2} [/tex]

yet, we arrived, short trip tough, pls leave the bus in an orderly manner

Answer: the required sample size =1658944

Step-by-step explanation:

When the prior population proportion for the study is unknown , then the formula for sample size is [tex]Sample \ size = 0.25(\dfrac{z^*}{Margin\ of \ error})^2[/tex]

z-value for 99% confidence = 2.576

[tex]Sample \ size = 0.25(\dfrac{2.576}{0.001})^2\\\\=0.25(2576)^2\\\\=1658944[/tex]

Hence, the required sample size =1658944

Answer:

Period: [tex]\pi[/tex]

Phase shift: n

Step-by-step explanation:

Tangent function:

Has the following format:

[tex]f(x) = \tan{ax - n}[/tex]

In which the period is [tex]\frac{\pi}{x}[/tex] and the phase shift is n.

In this question:

[tex]f(x) = -4\tan{(x-n)}[/tex]

[tex]a = 1[/tex], and thus, the period is [tex]\pi[/tex], with a phase shift of n.

Answer:

x=-10

Step-by-step explanation:

2(x+3)=x-4

2*x+2*3=x-4

2x+6=x-4

2x-x=-4-6

x=-10

Answer:

[tex]x = - 10[/tex]

Step-by-step explanation:

Let's solve:

[tex]2(x+3)=x−4[/tex]

Step 1: Simplify both sides of the equation.

[tex]2(x+3)=x−4 \\ (2)(x)+(2)(3)=x+−4(Distribute) \\ 2x+6=x+−4 \\ 2x+6=x−4[/tex]

Step 2: Subtract x from both sides.

[tex]2x+6−x=x−4−x \\ x+6=−4[/tex]

Step 3: Subtract 6 from both sides.

[tex]x+6−6=−4−6 \\ x=−10[/tex]

Answer:

-5 is the answer

Step-by-step explanation:

Answer:

-5 corresponds to the coldest temperature here.

Step-by-step explanation:

-5 is to the left of -1 on a number line and is therefore smaller than -1.

9514 1404 393

Answer:

  30 grams

Step-by-step explanation:

The time 120 seconds is 4 times the half-life of 30 seconds. That means (1/2)^4 = 1/16 of the original amount will remain. That is (480 g)(1/16) = 30 g.

  30 g of the radioactive rhodium will be left

Answer:

w ≈ 21.053 inches

l ≈ 28.353 inches

Step-by-step explanation:

Answer:

C. [tex]\frac{}{AB}[/tex]

Step-by-step explanation:

You can solve this in two ways, firstly by eliminating all the wrong answers, and secondly by just knowing that the horizontal line in [tex]_[/tex][tex]\frac{}{AB}[/tex] means that we are talking about a line.

This is how we solve this question by using the eliminating process.

(A. ∠C) is not the right answer because the ∠ sign lets us know that this answer represents an angle, not a line

(B. B) is not the right answer because it represent a point, not a line (in math we use a singular capital letter to represent points)

(D. ΔABC) is not the right answer because the Δ sign lets us know that the answer represents a triangle, not a line.

Therefore, the only option left is C. [tex]\frac{}{AB}[/tex]

Answer:

The amount of money one may spend in a month may be greater than that of ones monthly payment especially when the payment is at a lower rate.

Answer:

1 / 1365

Step-by-step explanation:

Given that :

Number of employees to choose from = 15

Number of employees to be chosen = 4

Probability of choosing You, Kyle, Carol and Adam

Recall ;

P(A) = number of required outcome / Total possible outcomes

Number of required outcome = 4C4

Total possible outcomes = 15C4

nCr = n! ÷ (n-r)!r!

Using calculator to save computation time :

15C4 = 1365

4C4 = 1

P(choosing you, Kyle, Carol and Adam) :

1 / 1365

Answer:

T = k * (A/W)

Step-by-step explanation:

Answer:

[tex]2x^2y\sqrt[3]{7xy^2}[/tex]

Step-by-step explanation:

Given

[tex]\sqrt[3]{56x^7y^5}[/tex]

Required

Solve

Expand

[tex]\sqrt[3]{8*7*x^6*x*y^3*y^2}[/tex]

Rewrite as:

[tex]\sqrt[3]{8*x^6*y^3*7*x*y^2}[/tex]

Split

[tex]\sqrt[3]{8*x^6*y^3} *\sqrt[3]{7*x*y^2}[/tex]

Express 8 as 2^3

[tex]\sqrt[3]{2^3*x^6*y^3} *\sqrt[3]{7*x*y^2}[/tex]

Apply law of indices

[tex]2^{(3/3)}*x^{(6/3)}*y^{(3/3)} *\sqrt[3]{7*x*y^2}[/tex]

[tex]2*x^2*y *\sqrt[3]{7*x*y^2}[/tex]

[tex]2x^2y *\sqrt[3]{7xy^2}[/tex]

[tex]2x^2y\sqrt[3]{7xy^2}[/tex]

Answer:

$5900

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Simple Interest Rate Formula: A = P(1 + rt)

Step-by-step explanation:

Step 1: Define

Identify variables

P = 5000

r = 3% = 0.03

t = 6

Step 2: Find Interest

Answer:

?????????????????????????

Answer:

The relationship between the above two triangles is SAS and they are congruent

Answer:

.101501615

.84982392

.901244701

Step-by-step explanation:

For this question use a binomial distribtuion

a.

12C3*.44³*(1-.44)⁹= .101501615

b.

to find at least 4 find the probability of less than 4 and take its compliment

12C0*(1-.44)¹²+12C1*.44*(1-.44)¹¹+12C2*.44²*(1-.44)¹⁰+12C3*.44³*(1-.44)⁹= .15017608

1-.15017608=.84982392

c.

To find less than eight's probability find the proability of at least 8 and take its compliment

12C8*.44⁸(1-.44)⁴+12C9*.44⁹(1-.44)³+12C10*.44¹⁰(1-.44)²+12C11*.44¹¹*(1-.44)+12C12*.44¹²= .098755299

1-.098755299= .901244701