For what value of k does the equation (2k+1)x^2+2x=10x-6 have two real and equal roots?
Answer:
[tex]\displaystyle k = \frac{5}{6}[/tex]
Step-by-step explanation:
We are given the equation:
[tex]\displaystyle (2k+1)x^2 + 2x = 10x - 6[/tex]
And we want to find the value of k such that the equation has two real and equivalent roots.
Since the equation is a quadartic, we can find its discriminant (symbolized by Δ). Recall that:
If Δ < 0, we have no real roots (two complex roots). If Δ > 0, we have two real roots. And if Δ = 0, we have one real root, or two equivalent ones.First, rewrite our equation:
[tex](2k+1)x^2 -8x + 6 =0[/tex]
The discriminant is given by:
[tex]\displaystyle \Delta = b^2 -4ac[/tex]
In this case, b = -8, a = (2k + 1), and c = 6.
Therefore, the discriminant is given by:
[tex]\displaystyle \Delta = (-8)^2 - 4(2k+1)(6)[/tex]
For it to have two equal roots, the discriminant must be zero. Hence:
[tex]\displaystyle 0 = (-8)^2 - 4(2k+1)(6)[/tex]
Solve for k:
[tex]\displaystyle \begin{aligned} \displaystyle 0 &= (-8)^2 - 4(2k+1)(6) \\ 0 &= 64 - 48k - 24 \\ 0 &= 40 - 48k \\ -40 &= -48k \\ \\ k &= \frac{5}{6} \end{aligned}[/tex]
Hence, the value of k is 5/6.
Graph the line that has a slope of -7/4 and includes the point (0,10).
Answer:
y=-7/4x +10
Step-by-step explanation:
that the graph, you can plug the equation in desmos,
hope it helps! :)
What is the volume of a cylinder, in cubic centimeters, with a height of 8 centimeters
and a base diameter of 16 centimeters? Round to the nearest tenths place
Answer:
1608.5 cm³
Step-by-step explanation:
Use the cylinder volume formula, V = [tex]\pi[/tex]r²h
If the diameter is 16 cm, then the radius is 8 cm.
Plug in the radius and height into the formula, and solve:
V = [tex]\pi[/tex]r²h
V = [tex]\pi[/tex](8)²(8)
V = [tex]\pi[/tex](64)(8)
V = 1608.5
So, to the nearest tenth, the volume of the cylinder is 1608.5 cm³
order the following radicals from the least to greatest without using a calculator. show your reasoning
[tex]2 \sqrt{6} [/tex]
[tex]5 \sqrt{10} [/tex]
[tex]4 \sqrt{2} [/tex]
[tex]3 \sqrt{3} [/tex]
Answer:
2*sqrt6 = 2*apprx2 = 4
5*sqrt10 = 5*3.1 = 15.5
4*sqrt2 = 4*1.4 = 6.4
3*sqrt3 = 3*1.7 = 5.1
4, 5.1, 6.4, 15.5 or... 2sqrt6, 3sqrt3, 4sqrt2, 5sqrt10
Type the equation for the graph
below.
Answer:
Step-by-step explanation:
This is a "regular" sin graph that's "taller" than the original. The amplitude is 3; other than that, its period is the same and it has not shifted to the right or left, so the equation, judging from the graph, is
[tex]y=3sin(x)[/tex]
The midpoint of a segment is ( 6, -6) and one endpoint is (13,-1). Find the coordinates of the other endpoint
f(x)=square root 2x and g(x)=square root 50x find (f/g)(x)
Answer:
1/5
Step-by-step explanation:
(f/g)(x) = f(x)/g(x) = sqrt(2x)/sqrt(50x) = 1/5
express y=2x²+9x+4 in the form a(x+b)²+c . where a ,b,c are constant
Answer:
2(x+9)^2 + 4
Step-by-step explanation:
.............
helppppppppppppppp me
Answer:
42
Step-by-step explanation:
5²+3(2)+5+6
25+6+5+6
31+11
42
Hope it helps
Can u help solve this
Answer:
- 5/3
Step-by-step explanation:
We can use the slope formula
m = ( y2-y1)/(x2-x1)
= ( -1 -9)/(4 - -2)
= (-1-9)/(4+2)
= -10/6
- 5/3
Answer:
[tex]slope = \frac{y2 - y1}{x2 - x1} \\ = \frac{ - 1 - 9}{4 - - 2} \\ \frac{ - 10}{6} \\ = - \frac{5}{3} \\ thank \: you[/tex]
Please help me please and thank you
Answer:
3x² + 2x - 9 = 0
Step-by-step explanation:
Standard form of a quadratic: ax² + bx + c
Move all terms to one side of the equation:
[tex]3x^2-9=-2x\\3x^2-9+2x=-2x+2x\\3x^2+2x-9=0[/tex]
i have 17 coins. N of them are nickels and the rest are dimes. write an expression in two different ways for the amount of money that i have. (Hint: one is the other simplified)
Answer:
Step-by-step explanation:
Total amount in cents (unsimplified): 5N +17(10-N)
Simplified: 170-5N
The Volume of a sphare is 28/3 times the surface area calculate The surface area and the Volume of the sphere, correct to the nearest whole number.
Given:
Volume of a sphere is [tex]\dfrac{28}{3}[/tex] times the surface area.
To find:
The surface area and the volume of the sphere.
Solution:
Volume of a sphere:
[tex]V=\dfrac{4}{3}\pi r^3[/tex] ...(i)
Surface area of a sphere:
[tex]A=4\pi r^2[/tex] ...(ii)
Where, r is the radius of the sphere.
Volume of a sphere is [tex]\dfrac{28}{3}[/tex] times the surface area.
[tex]V=\dfrac{28}{3}\times A[/tex]
[tex]\dfrac{4}{3}\pi r^3=\dfrac{28}{3}\times 4\pi r^2[/tex]
Multiply both sides by 3.
[tex]4\pi r^3=112\pi r^2[/tex]
[tex]\dfrac{\pi r^3}{\pi r^2}=\dfrac{112}{4}[/tex]
[tex]r=28[/tex]
Using (i), the volume of the sphere is:
[tex]V=\dfrac{4}{3}\times \dfrac{22}{7}\times (28)^3[/tex]
[tex]V\approx 91989[/tex]
Using (ii), the surface area of the sphere is:
[tex]A=4\times \dfrac{22}{7}\times (28)^2[/tex]
[tex]A=9856[/tex]
Therefore, the surface area of the sphere is 9856 sq. units and the volume of the sphere is 91989 cubic units.
What is the function rule that represents the sentence y is 7 less than the product of 6 and x?
Answer:
y = 6x-7
Step-by-step explanation:
product of 6 and x
6x
7 less than the product of 6 and x
6x-7
y = 6x-7
Answer this question, if anyone just posts an answer that is not relevant to this question will be reported.
Answer:
A is the correct answer
Step-by-step explanation:
I have looked at your bar graph.
What about B?
B is wrong because the first bar doesn't reach 5.8 billion
And C & D are wrong for the same reason. I hope this helps you:)
Note:
My answer WAS relevant to your question.
Answer:
tysm have a great day! Go rose!
Step-by-step explanation:
Select the expression that represents the following statement: find the sum of 6 and 14 and divide by 4.
a (6 + 14) ÷ 4
b 14 ÷ 4 + 6
c 4 x 4 – 6
d 14 x 6 ÷ 4
Answer:
A
Step-by-step explanation:
Find the measure of the indicated angle to the nearest degree
Which of the following is equal to ….
Answer:
B option is your answer
Step-by-step explanation:
please mark as brainliest
Answer:
B. 4th root of 7
Step-by-step explanation:
denominator is the root. numerator is the exponent
What is the slope of the line shown below?
(6,6)
m
O A. -2
B. 2
-5
6
O c. 7 /
IN
(1,-4)
5
1
O D.
D. -
2
Answer:
B
Step-by-step explanation:
answer is slope =2
use formula y2-y1 over x2-x1
two points of graph is (6,6) and (1,-4)
since 6 and -4 are both y, we take 6-(-4) over 6-1
we get 2
ask for further explanation if you need!!❤
The distance from Clinton to Greenville is 124 miles. To find the speed of a car, use the expression d divided t, where d represents the distance and t represents time. Find the speed of a car that travels from Clinton to Greenville in 2 hours
Step-by-step explanation:
time = 2 hours
distance travelled(d) = 124 miles
so
speed = d/t
= 124/2
= 62 miles per hour
Therefore, the speed of car is 62 miles per hour.
Isobel is pulling water up from an old-fashioned well. She lifts the bucket of water at a rate of 4 ft/s, and after 1 s, the bucket is 1 ft below the top of the well. Select the equation in point-slope form for the line that represents the height of the bucket relative to the top of the well.
A. y + 1 = 4x – 1
B. y – 1 = 4x + 1
C. y – 1 = 4(x + 1)
D. y + 1 = 4(x – 1)
Plane R and Plane U intersect at which of the following?
Answer:
do you have any images with the questions?
Step-by-step explanation:
4. 19 feet to inches
SIN TRIG PLEASE HELP 50 POINTS
If sin y° = s/8 and tan y° = s/t what is the value of sec y°
a. sec y° = 8s
b. sec y° = 8t
c. sec y° = 8/t
d. sec y° = t/8
Answer:
C
Step-by-step explanation:
We are given that:
[tex]\displaystyle \sin y^\circ = \frac{s}{8}\text{ and } \tan y^\circ = \frac{s}{t}[/tex]
And we want to find the value of:
[tex]\displaystyle \sec y^\circ[/tex]
Recall that tan(θ) = sin(θ) / cos(θ). Since sec(θ) = 1 / cos(θ), tan(θ) = sin(θ)sec(θ). Substitute:
[tex]\displaystyle \sin y^\circ \sec y^\circ = \frac{s}{t}[/tex]
Substitute:
[tex]\displaystyle \frac{s}{8}\sec y^\circ =\frac{s}{t}[/tex]
Solve for secant:
[tex]\displaystyle \sec y^\circ = \frac{8}{t}[/tex]
Hence, our answer is C.
Answer:
c. sec y° = 8/t
Step-by-step explanation:
I took the test
x+y=4 and 2x+3y=2 then find x and y
Answer:
x=10, y=-6
Step-by-step explanation:
1) express x from the first equation x+y=4 x=4-y
2) It is the system of equations, so both equations are simultaneous.
you can replace x to 4-y in the second one
2 *(4-y) +3y=2
8-2y+3y= 2
y=-6
x= 4-y=4-(-6)=10
The answer is x=10, y=-6
given the circle, find the arc measure
ILL GIVE POINTS!! PLS HELP !!!
Which set of polar coordinates describes the same location as the
rectangular coordinates (1. - 1)?
A. (sqrt2,315°)
B. (-1,135°) C. (sqrt2,225°)
D. (1,45°)
Answer:
The polar coordinates appear in the form (r, θ), where r is the the radius from the center and θ is the angle. To get the radius, do the following.
[tex]r = \sqrt{x^2 + y^2} = \sqrt{1^2 + (-1)^2} = \sqrt{2}\\[/tex]
You can get the angle visually by drawing a point (1, -1) on a graph and seeing that it is 45 degrees from the top right quadrant (you can tell its 45 because both x and y have the same magnitude). Since there are 360 degrees, 360 - 45 = 315.
If you would like to find it mathematically, this is the way to do it
[tex]\theta = atan(y/x) = -45[/tex]
Notice that -45 degrees is just 360 - 45 = 315
Your answer would be
[tex](\sqrt{2}, 315)[/tex]
Write the integer represented by H. List its opposite and absolute value.
Answer:
The integer represented by H is -2
Its opposite is 2 and the absolute value is also 2
Answer:The integer represented by H is -2
Step-by-step explanation:
_(9)=(2(1-2(2)^(9)))/(1-2(2))
PLEASE HELP ME OUT.
Answer:
the answer = um ok
Step-by-step explanation:
Hello again! This is another Calculus question to be explained.
The prompt reads that "If f(x) is a twice-differentiable function such that f(2) = 2 and [tex]\frac{dy}{dx}[/tex] = [tex]6\sqrt{x^2 + 3y^2}[/tex], then what is the value of [tex]\frac{d^2y}{dx^2}[/tex] at x = 2?"
My initial calculation lead to 12, but then I guessed 219 as the answer and it was correct. Would any kind soul please explain why the answer would be 219? Thank you so much!
Answer:
See explanation.
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightAlgebra I
Functions
Function NotationExponential Property [Rewrite]: [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]Exponential Property [Root Rewrite]: [tex]\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}[/tex]Calculus
Differentiation
DerivativesDerivative NotationDerivative Property [Multiplied Constant]: [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]
Derivative Property [Addition/Subtraction]: [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Step-by-step explanation:
We are given the following and are trying to find the second derivative at x = 2:
[tex]\displaystyle f(2) = 2[/tex]
[tex]\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}[/tex]
We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:
[tex]\displaystyle \frac{dy}{dx} = 6(x^2 + 3y^2)^\big{\frac{1}{2}}[/tex]
When we differentiate this, we must follow the Chain Rule: [tex]\displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big][/tex]
Use the Basic Power Rule:
[tex]\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} (2x + 6yy')[/tex]
We know that y' is the notation for the 1st derivative. Substitute in the 1st derivative equation:
[tex]\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 6y(6\sqrt{x^2 + 3y^2}) \big][/tex]
Simplifying it, we have:
[tex]\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 36y\sqrt{x^2 + 3y^2} \big][/tex]
We can rewrite the 2nd derivative using exponential rules:
[tex]\displaystyle \frac{d^2y}{dx^2} = \frac{3\big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]}{\sqrt{x^2 + 3y^2}}[/tex]
To evaluate the 2nd derivative at x = 2, simply substitute in x = 2 and the value f(2) = 2 into it:
[tex]\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = \frac{3\big[ 2(2) + 36(2)\sqrt{2^2 + 3(2)^2} \big]}{\sqrt{2^2 + 3(2)^2}}[/tex]
When we evaluate this using order of operations, we should obtain our answer:
[tex]\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = 219[/tex]
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation