the area of kitchen is 149m^2 how many tiles each of area 0.2m^2 are needed to flooring the kitchen what will be the total coast at the rate of rs 250 per tiles..​

Answer:

hello,

answer C

Step-by-step explanation:

area of the rectangle=2b*b=2b²

area of the half cercle= [tex]\\\dfrac{\pi*(\frac{c}{2})^2}{2} =\dfrac{\pi*c^2}{8} \\[/tex]

Area in blue= 2b²-πc²/8

Answer:

i think

third option is correct.

cosY = 8 / 17, cotY = 8 / 15, secY = 17 / 8 is the required trigonometric functions of the same angle. Option C is correct

These are the equation that contains trigonometric operators such as sin, cos.. etc.. In algebraic operations.

Here,
cosY = 8 / 17, cotY = 8 / 15, secY = 17 / 8
Is the trigonometric function of the same angle,
cosY = 1 / SecY
8 / 17 = 1 / secY
secY = 17 / 8
Now,
P = √[17² - 8²]
P = 15
CotY = 8 / 15

Thus, trigonometric functions in option C are of the same angle.

Learn more about trigonometry equations here:

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Answer:

37.5%

Step-by-step explanation:

150/450 = .375 = 37.5%

The percentage is 150 grams out of 400 grams will be 37.5%.

The quantity of anything is stated as though it were a fraction of a hundred. A quarter of 100 can be used to express the ratio. Per 100 is what the term percent signifies. The symbol '%' is used to symbolize it.

The percentage is given as,

Percentage (P) = [Initial value - Final value] / Initial value x 100

It is given that the difference between the initial and final value is 15 grams and the initial value is 400 grams.

Then the percentage is 150 grams out of 400 grams will be

P = (150 / 400) x 100

P = 0.375 x 100

P = 37.5%

Thus, the percentage is 150 grams out of 400 grams will be 37.5%.

More about the percentage link is given below.

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Answer:

29/14

Step-by-step explanation:

Start by working out the LCM of these (or any common denominator). A common denominator for 4 and 7 is 28 cuz 4 x 7 = 28.

3/4 = 21/28

4/7 = 16/28

3/4 = 21/28

(21+16+21)/28 = 58/28 which can simplify to 29/14

hi

Golden rule : you can only add or substract fraction if and only if they have the same denominator.

so two solutions :

you see that one denominator is a multiple of the second. so you multiply all the fraction by this multiple.

ex : 1/3 + 5/6

here I can easely convert 1/3 into a fraction with 6 as 6 is 3x2.

so : 1x2 = 2 and 3x2 = 6

1/3 is 2/6

so. 1/3 +5/6 = 2/6 +5/6

fraction have same denominator, I add numerators : 2/6 +5/6 =7/6

if it not that evident, you multiply fraction A up and down by denominator of fraction B.

and you multiply up and down fraction B by denomonator of fraction A

let' s see with your exemle :

3/4 +4/7+3/4 = ?

first I add fraction with same denominator :

3/4+3/4+4/7 = 6/4 +4/7

fraction A is 6/4.

I multiply up and down by denominator fractiok B which is " 7"

so. 6/4 = 6x7/4×7 = 42/28

let's apply method to fraction B whixh is 4/7 . let' multiply up and down by denominator of fraction A which is " 4"

so : 4/7 = 4x4 /7x4 = 16/28

now we have :

6/4 +4/7 = 42/28 +16/28

both my fractions have same denominator "28" so I add numerator :

42/28 +16/28 = 58/28

Now must wonder if 58/28 can be simplify. Good trick is to decompose numbers, and in prime number is the best way to do

58 = 2x29

28 = 7x2x2

so 58/28= (2×29)/ (7x2x2)

when there is same number up and down I can cross it out .

so here one "2" up and down can be rule out

so 58/28 = 2x29 /7×2×2 = 29/7x2 =29/14

I can not symplify more, so calculus is over.

in short :

3/4+4/7+3/4 = 6/4+4/7

= 42/28 +16/28

=58/28

= 29/14

Answer:

A, it's the only one with a number greater then 1

Answer:

(-4, -1)

Step-by-step explanation:

The solution to the system of equations on a graph is the point in which they intersect. Therefore, the solution is (-4, -1).

Answer:

[tex]A' = (-2,2)[/tex]

[tex]B' = (2,2)[/tex]

[tex]C' = (2,-2)[/tex]

Step-by-step explanation:

Given

[tex]A = (-6,6)[/tex]

[tex]B = (6,6)[/tex]

[tex]C = (6,-6)[/tex]

[tex]k = \frac{1}{3}[/tex]

Required

The new coordinates

To do this, we simply multiply the coordinates of [tex]\triangle ABC[/tex] by the factor of dilation.

i.e.:

[tex]A' = A * k[/tex]

[tex]B' = B * k[/tex]

[tex]C' = C * k[/tex]

So, we have:

[tex]A' = (-6,6) * \frac{1}{3}[/tex]

[tex]A' = (-2,2)[/tex]

[tex]B' = (6,6) * \frac{1}{3}[/tex]

[tex]B' = (2,2)[/tex]

[tex]C' = (6,-6) * \frac{1}{3}[/tex]

[tex]C' = (2,-2)[/tex]

The depth of the mirror of the cross-section of a searchlight would be 8.33 cm if the light bub has a vertex at 3 cm and the mirror is 20 centimeters across at the origin.

A cross-section is perpendicular to the axis of the symmetry goes through the vertex of the parabola. The cross-sectional shape of the mirrored section of most searchlights or spotlights is parabolic.

Given:

a = 3

y = [tex]\frac{20}{2}[/tex] cm = 10 cm

Solution:

from the equation [tex]y^{2} = 4ax[/tex]

[tex]y^{2} = 4*3*x\\ y^{2} = 12x[/tex]

putting x, 10 cm in the equation

[tex]x=\frac{10^{2} }{12} \\\\x= \frac{100}{12} \\\\x= 8.33 cm[/tex]

thus, the depth of the mirror would be - 8.33 cm

Learn more about other problems of the parabola:

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Answer:

It is 3/2, I got it right on my exam.

Step-by-step explanation:

Dilation is a transformation that allows you to resize an object. The dilation factor of the given point is 3/2.

Dilation is a transformation that allows you to resize an object. Dilation is a technique for making items bigger or smaller. This transformation yields a picture that is identical to the original shape. However, there is a size discrepancy in the form.

Given the dilation of the k around the origin as K = (2,4) → (3,6), therefore, the point k is dilated 1 unit to the right and 2 units upwards.

Let the dilation factor be represented by a, then,

2 × a = 3

a = 3/2

Similarly for the y-axis,

4 × a = 6

a = 6/4 = 3/2

Hence, the dilation factor of the given point is 3/2.

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Answer:

b) 6

Step-by-step explanation:

x - 4 = 2

x = 2 + 4

x = 6

Answer:

-13 1/2 < -6/8

Step-by-step explanation:

*Any negative in either the numerator or denominator will make the entire fraction negative.

1/2  = .5

-13 1/2 = -13.5

-6/8 = -3/4

-3/4 = -0.75

-6/8 = -0.75

-13 1/2 = -13.5

Which means:

-13 1/2 < -6/8

Hope this helped.

Answer:

[tex] < [/tex]

Step-by-step explanation:

[tex] \frac{6}{8} [/tex]

Is close to 0 (to positive) you can use a time line to determine which is a correct answer

Answer:

[tex]area \: of \: a \: squre = {a}^{2} \\ {a}^{2} = 176 \\ a = 13.26m \\ perimeter = 4a = 4 \times 13.26 = 53.04m^2 \\ thank \: you[/tex]

Answer:

Concept:

Here, we need to know how to find the area and perimeter of the square.

Area (square) = s²

Perimeter (square) = 4s

Solve:

Given information

Area = 1764 m²

Given formula

A = s²

Substitute values into the formula

1764 = s²

Square root both sides

√s² = √1764

[tex]\boxed{s=42m}[/tex]

--------------------------------------------------------------------------------------------------------

Given information

s = 42 m

Given formula

P = 4s

Substitute values into the formula

P = 4 (42)

Simplify by multiplication

[tex]\boxed{P=168m}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

x = - 1, x = - 0.5

Step-by-step explanation:

Given

2x(x + 1.5) = - 1 ← distribute parenthesis on left side

2x² + 3x = - 1 ( add 1 to both sides )

2x² + 3x + 1 = 0 ← in standard form

(2x + 1)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = - 0.5

Answer:

hope it helps

Step-by-step explanation:

Answer:

Step-by-step explanation:

S is the midpoint of QR.

⇒ RS = QS    

QR ⊥ PS

⇒ ∠RSP = ∠QSP = 90°

In ΔPSR & ΔPSQ,

Statement                     Reason

RS ≅ QS                       S is midpoint of QR

∠RSP ≅ ∠QSP              QR ⊥ PS

PS ≅ PS                         Reflexive property

ΔPSR ≅ ΔPSQ               Side Angle Side - S A S Congruent

PR≅  PQ                        CPCTC

Hi.

Let's call X number of visits.

so members pay for a year : membership 24 and reduce entrance at 3 dollars.

so you member pay : 3X+24

a non member pay entrance fee of 6 for each visit.

so 6X

Question : for how many visit would a membership will be more intresting than standar entrance ?

3X+24 = 6X

3X-6X = -24

-3X=-24

X= -24/-3

X =24/3

X= 8

Under 8 visit a year, it's cheaper non being a member.

at 8 entrance cost is the same for members and non member. After it better to choose membership as

9 entrances for member is : 3x9 +24 = 27+24= 51

non member : 9x6 = 54

And so on for each supplementary visits.

Answer:

[tex]we \: know \: that \: commutative \: prop \\ = x + y = y + x \\ then \\ 4xy + 0 = 0 + 4xy \\ thank \: you[/tex]

Answer:

the answer is -299.808 well that's what I think it's

Answer:

-299.808

Step-by-step explanation:

= 10700/100 + 5192/100 - 412

= 107 + 5.192 - 412

= -299.808

Answer:

it will take 5days to reach a total of 180meters

Step-by-step explanation:

80m+20+20+20+20+20

=180meters

=5days

Answer:

2nd option

Step-by-step explanation:

Given f(x) then f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift left of a units

• If a < 0 then a shift right of a units

Here g(x) = (x - 6)²

The base graph has been shifted right 6 units

Answer:

8 hours 10 minutes

I hope this answers your question

Answer: paul has been away from home for 7 hours and 50 minutes.

Step-by-step explanation:

Answer:

The answer is 2.)

Step-by-step explanation:

Given initial velocity=135 ft/s

& cliff=76 foot

Given quadratic equation

⇒                      (let h=0 it is given)

⇒  

⇒  

⇒    t=8.96≈9 s (the other root is negative)

Hence, rocket will take 9 s to hit the ground after launched.

Answer:  Choice D

0 = 16t^2 + 135t + 76;  9 s

==============================================

Explanation:

The equation we start with is

[tex]h = -16t^2 + vt + c\\\\[/tex]

where v is the starting or initial velocity, and c is the starting height.

We're told that v = 135 and c = 76

We let h = 0 to indicate when the object hits the ground, aka the height is 0 ft.

That means the equation updates to [tex]0 = -16t^2 + 135t + 76\\\\[/tex]

Based on that alone, the answer is between A or D

-------------------

We'll use the quadratic formula to solve for t

We have

So,

[tex]t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\t = \frac{-135 \pm \sqrt{135^2 - 4(-16)(76)}}{2(-16)}\\\\t = \frac{-135 \pm \sqrt{23,089}}{-32}\\\\t \approx \frac{-135 \pm 151.9506}{-32}\\\\t \approx \frac{-135 + 151.9506}{-32} \ \text{ or } \ t \approx \frac{-135 - 151.9506}{-32}\\\\t \approx \frac{16.9506}{-32} \ \text{ or } \ t \approx \frac{-286.9506}{-32}\\\\t \approx -0.52971 \ \text{ or } \ t \approx 8.96721\\\\[/tex]

We ignore the negative t value because a negative time duration makes no sense.

The only practical solution here is roughly 8.96721 which rounds to 9.0 or simply 9 when we round to the nearest tenth (one decimal place).

In short, the object will hit the ground at the 9 second mark roughly. Or put another way: the object is in the air for about 9 seconds.

From this, we can see that the final answer is choice D.

Keep in mind that we aren't accounting for any wind resistance. Considering this variable greatly complicates the problem and requires much higher level mathematics. So we just assume that there is no wind at this moment.

Answer:

1.9

Step-by-step explanation:

You round when the numbers behind the decimal are 5 or greater. This being said, you need to round from the number furthest away from the decimal. In this case it would be 9. 9 is greater than 5 so we round 8 up to 9 and get rid of the number behind it. We are left with 1.9

Answer:

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

Step-by-step explanation:

There are mistakes in the statement, correct form is presented below:

[tex]5+\frac{\sqrt{3}}{7} + 2\sqrt{3} = a - b\cdot \sqrt{3}[/tex].

By direct comparison we have the following system of equations:

[tex]a = 5[/tex] (1)

[tex]\frac{\sqrt{3}}{7}+2\sqrt{3} = -b\cdot \sqrt{3}[/tex] (2)

In (2) we solve for [tex]b[/tex]:

[tex]\left(\frac{1}{7}+2 \right)\cdot \sqrt{3} = -b\cdot \sqrt{3}[/tex]

[tex]b = -\frac{15}{7}[/tex]

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

Refer the attached image for the answer

HOPE SO IT HELPS YOU

Answer:

she baked 3 times as many cranberry than blueberry muffins

Step-by-step explanation:

i think that because 9×3=27

the amount of the cranberry muffins are 9

Answer:

B. 4/5

Step-by-step explanation:

Sin = Opposite/Hypotenuse

Sin∠A = 8/10 = 4/5

Answer:

wyatt

Step-by-step explanation:

4:30 mins is 270 seconds

Answer:

c) 21

Step-by-step explanation:

[tex] \sqrt{169} + \sqrt{64} [/tex]

13+8

answer is 21

Answer:

The cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.

Step-by-step explanation:

Given that Sayad bought a watch and sold to Dakshes at 10% profit, and Dakshes again sold it to Sahayata for $ 6,050 at 10% profit, to find the cost price of Dakshes and the cost price of Sayad the following calculations must be performed:

6,050 / 1.1 = X

5,500 = X

5,500 / 1.1 = X

5,000 = X

Therefore, the cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.