Answer:
The p-value of the test is 0.2.
Step-by-step explanation:
Using the alternative hypothesis that µ ≠ 531, Amy found a t-test statistic of 1.311.
Alternative hypothesis means that e have a two-tailed hypothesis test.
Sample 30 citizens. Amy found a t-test statistic of 1.311.What is the p-value of the test statistic?
Thus, we have a two-tailed test with 30 - 1 = 29 degrees of freedom and t = 1.311. So, using a t-distribution calculator, the p-value of the test is 0.2.
1. Estimate the area of the irregular shape. Explain your method and show your work.
2. The coordinates of the vertices of △LMN are L (-2, 4), M (3, -1), and N (0, -4). Determine whether △LMN is a right triangle and support your decision. Show all work.
3. The coordinates of the vertices of quadrilateral PQRS are P (-6, 2), Q (-1, 4), R (2, 2), and S (-3, 0). Alexandra states that quadrilateral PQRS is a parallelogram. Prove or disprove Alexandra’s statement. Show all work.
Answer:
Step-by-step explanation:
1. Do not see a figure, and unsafe to download and execute .docx.
2. Vectors LM<5,-5>, NM<3,3>, NL<2,-8>
Since LM.NM = 15-15 = 0, LM and NM are orthogonal, hence the given points form a right triangle.
3. A parallelogram has opposite sides parallel.
Slope PQ = (4-2) / (-1 - -6) = 2/5
Slope RS = (2-0) / (2- -3) = 2/5
Therefore PQ || RS
Slope PS = (2-0)/(-6- -3) = -2/3
Slope QR = (4-2)/(-1 -2) = -2/3
Therefore PS | QR
Since opposite sides are parallel, PQRS is a parallelogram
Answer:
Step-by-step explanation:
1. There are 31 complete are almost complete squares.
Top line is about 3.5 squares
Right side is about 1.8
Bottom about 3.5 and left side about 1.2.
Total approximately 41 square units.
2. If it is a right triangle then 2 sides will be perpendicular.
Slope of LM = (-1-4)/(3 +2 = -1
Slope of MN = (-4+1)/ -3 = -3/-3 = 1.
So as the product of the slope = -1 * 1 = -1 the angles between LM and MN is a right angle and LMN is a right triangle.
A particle sits on a smooth surface and is acted upon by a time dependent horizontal force, giving it an
acceleration of a = 2t
2 + 4t where t is in seconds. Given that it is initially at rest and experiences no resistance
to motion, find:
a) The velocity of the particle at time t.
b) The distance travelled by the particle if acted on by the force for 8s
(a) By the fundamental theorem of calculus,
v(t) = v(0) + ∫₀ᵗ a(u) du
The particle starts at rest, so v(0) = 0. Computing the integral gives
v(t) = [2/3 u ³ + 2u ²]₀ᵗ = 2/3 t ³ + 2t ²
(b) Use the FTC again, but this time you want the distance, which means you need to integrate the speed of the particle, i.e. the absolute value of v(t). Fortunately, for t ≥ 0, we have v(t) ≥ 0 and |v(t) | = v(t), so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of
∫₀⁸ v(u) du = ∫₀⁸ (2/3 u ³ + 2u ²) du = [1/6 u ⁴ + 2/3 u ³]₀⁸ = 1024
What is the first step to solve the equation 12z - 21 = 92?
12z - 21 = 92
12z - 21 + 21 = 92 + 21
12z = 113
z = 113/12
Data are drawn from a bell-shaped distribution with a mean of 25 and a standard deviation of 4. There are 1,000 observations in the data set.
a. Approximately what percentage of the observations are less than 33?
b. Approximately how many observations are less than 33?
Answer:
a. 97.72% of the observations are less than 33
b. Approximately 977 observations are less than 33.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 25 and a standard deviation of 4.
This means that [tex]\mu = 25, \sigma = 4[/tex]
a. Approximately what percentage of the observations are less than 33?
The proportion is the p-value of Z when X = 33. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{33 - 25}{4}[/tex]
[tex]Z = 2[/tex]
[tex]Z = 2[/tex] has a p-value of 0.9772
0.9772*100% = 97.72%
97.72% of the observations are less than 33.
b. Approximately how many observations are less than 33?
Out of 1000:
0.9772*1000 = 977.2
Approximately 977 observations are less than 33.
2,45,250 students appeared for an entrance examination. If 94,750 students did not get admission, find how many students got admission.
can i please get the answer
Answer:
2.45.250- 94.750
= 92. 2975. this is the learners who got the admission
Answer:
1,50,500 students
Step-by-step explanation:
Hope this helps... vote as brainliest
Calculate the mean,median and mode.(3 points each)
1. 1,2,3,4,5
2. 2,3,4,5,6,6
3. 6,7,5,4,5,6,2,5
Answer:
1. The first set of number is
1,2,3,4,5
Mean= 1+2+3+4+5/5
= 15/5
= 3
Median= 3
Mode= N/A
The next set of numbers is
2,3,4,5,6,6
Mean= 2+3+4+5+6+6/6
= 26/6
= 4.3
Median=4+5/2
= 9/2
= 4.5
Mode= 6
The next set of number is
6,7,5,4,5,6,2,5
Mean= 2+4+5+5+5+6+6+7/8
= 40/8
= 5
Median= 5+5/2
= 10/2
= 5
Mode= 5
Triangle ABC will be translated right 3 units and down 5 units to create triangle A'B'C'. What are the coordinates of B'?
Answer:
B'(4, 0)
Step-by-step explanation:
B (1, 5)
it translated right 3 units => x'=x+3
down 5 units => y'= y-5
Dertemine a área total at
To simplify 1/4(8)^2(12), Rémy wrote 2^2•12=48. Find and correct Remy’s error.
Answer:
work out 8^2 and then ×1/4
[tex] \frac{1}{4} (8)^{2} = 16 \: not \: 8[/tex]
therefore
[tex] \frac{1}{4} ({8})^{2} (12) = 192[/tex]
How many vertices does a triangular prism have?
4 5 6 9
Answer:
6
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
Vertices are the vertex points. there are 4 vertices at the bottom and 2 vertices at the top which makes 6.
Hope this helps
Solve for A
a=22/7•13/4^2
Answer:
A= ~2.55
Step-by-step explanation:
Using Pemdos, or gemdos, you can find you do the exponent first
4^2 = 16
then to everything else in left to right order since they're all multiplication or division
22/7 = ~3.14 * 13 = ~40.86/16 = ~2.55
(I'm using "~" to mean about/rounded to)
Translate the following sentence into an algebraic inequality: Three times a number, v, added to eight is greater than or equal to twenty-two. Question 7 options: A) 3v + 8 > 22 B) 3v + 8 ≥ 22 C) 3v + 8 ≤ 22 D) 3v + 8 < 22
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]3v + 8 \geq 22[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Breaking down the phrase...}}\\\\\text{Three times a number, v, added to eight is greater than or equal to twenty-two. }\\------------------\\\rightarrow \text{"Three times a number, v..."} - 3v \text{ This expresses the product of '3' and 'v'.}\\\\\rightarrow \text{"added to eight..."} - + 8 \text{ The product gets added to eight.}\\\\--------------\\\text{The First Part Is:}}\\\\3v + 8\\---------------\\\rightarrow \text{is greater than or equal to twenty-two. } - \geq 22[/tex]
[tex]\text{The value of '3v + 8' is greater than or equal to 22.}\\---------------\\\text{\underline{Putting it together, we would have:}}\\\\\boxed{3v + 8 \geq 22}}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Alexis pls answer this question you are sooooooooooooo good at math. (Nobody else answer this, only Alexis)
Answer:
5/8
Step-by-step explanation: Keep, Change and Flip so you do 1/2 times 5/4
Answer:
5/8
Step-by-step explanation:
To divide by a fraction. multiply by the reciprocal of that fraction.
1/2 * 5/4
Multiply the fractions across.
so 1*5=5, then do 2*4= 8
5/8
33. A labourer is engaged for 20 days on the condition that he will receive 120 for each day he
works and will be fined 10 for each day he is absent. If he receives 1880 in all, for how
many days did he remain absent?
thind of his nronerty to his son one-fourth to his daughter and
Answer:
false
Step-by-step explanation:
What is the area of the triangle formed from (0,-3), (0,4), and (4,-3)?
O A. 14 square units
O B. 6 square units
O c. 48 square units
O D. 24 square units
Find the volume of a sphere with a diameter of 4 inches. Use 3.14 for π
.
Round your answer to the nearest hundredth.
The volume of the sphere is cubic inches.
Answer:
33.51 cubic inches
Step-by-step explanation:
Formula for volume of a sphere is V= 4 /3 · π · r3
We know the diameter is 4, and the radius is half the diameter, so the radius is 2.
V = 4 /3 · π · [tex]2^{3}[/tex]
≈ 33. 51032
Rounded to the nearest hundreth is 33.51.
If a star is 5,699,999,999,999,999 meters from earth, how long does it take light to travel from earth to the star?
Answer
19.013.153,42629466 giây
Step-by-step explanati
van toc ánh sán =299.792.458 m/s
s= v*t
t=s/v
t= 5.699.999.999.999.999/299.792.458= 19.013.153,42629466 giây
Pls help this is urgent!!!
Answer:
1/2
Step-by-step explanation:
numbers taken = 1 to 40
multiples of 2 are = {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40}
so there are 20 favourable outcomes.
probability = 20/40
=1/2
for multiples of 3
multiples = {3,6,9,12,15,18,21,24,27,30,33,36,39}
there are 13 favourable outcomes
probability = 13/40
since there is no 13/40 the answer should be the probability of multiples of 2 i.e 1/2
Given F ( x ) = -2/3 x - 4 What is the zero of this function?
Answer:
-4
Step-by-step explanation:
f(0)=(-2/3)(0) - 4
= - 4
1. The arithmetic mean of roots of the quadratic equation x^2- 10x+16=0 is
Answer:
5
Step-by-step explanation:
x^2 - 10x + 16 = 0
factor
(x - 2)(x - 8) = 0
roots
x = {2, 8}
mean of roots
a = (2 + 8) /2
a = 5
i need to know how to solve this
Answer:
C
Step-by-step explanation:
I think you have to call a = 14/32 and b = 7/4
3a = 3 * 14/32 = 42/32
b = 1 3/4 = (4 + 3)/4 = 7/4
42/32 // 7/4 Invert and multiply
42/32 * 4/7 Cancel 4 into 32 and 7 into 42
6/8 = 3/4
I make the answer C
Answer:
So the square seems to multiply the first number by three and then divide it by the second number.
So,
14/32 * 3
=
42/32
Simplify
21/16
And now for division, we flip the diveding fraction and multiply.
21/16 * 4/7
Which is after some fraction simplifing:
3/4
Help is appreciated
Answer:
m = 6
n = 2√3
Step-by-step explanation:
Reference angle = 30°
Hypotenuse = 4√3
Opposite = n
Adjacent = m
✔️To find m, apply CAH:
Cos θ = Adj/Hypo
Substitute
Cos 30° = m/4√3
4√3 × Cos 30° = m
4√3 × √3/2 = m (cos 30 = √3/2)
(4*3)/2 = m
6 = m
m = 6
✔️To find n, apply SOH:
Sin θ = Opp/Hypo
Substitute
Sin 30° = n/4√3
4√3 × Sin 30° = n
4√3 × ½ = n (Sin 30 = ½)
2√3 = n
n = 2√3
find the surface area of the composite figure
Answer:
276 cm^2
Step-by-step explanation:
Separate figure into triangular and rectangular prisms.
SA of triangular prism (finding each area of a face and add them all up)
4 x 5 = 20 cm^2
13 x 4 = 52 cm^2
1/2 x 12 x 5 = 30 cm^2
1/2 x 12 x 5 = 30 cm^2
20 + 52 + 30 + 30 = 132 cm^2
SA of triangular prism is 132 cm^2
SA of rectangular prism (do the same thing):
12 x 4 = 48 cm^2
12 x 3 = 36 cm^2
12 x 3 = 36 cm^2
3 x 4 = 12 cm^2
3 x 4 = 12 cm^2
48 + 36 +36 + 12 + 12 = 144
Add the SA OF BOTH PRISMS:
144 + 132 = 276 cm^2
Determine the equation of the circle graphed below.
10
8
10
-10
-8
-6
2
-2
-4
-6
-8
-10
Answer:
Equation = (x - 6 )² + ( y + 3 )² = 9
Step-by-step explanation:
The circle passes through ( 6, 0) and ( 6 , -6)
They are the coordinates of the diameter.
Using this we can find the centre of the circle.
Find the centre of the circle.
Centre of the circle is the mid- point of (6, 0) and ( 6, -6)
[tex]Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})[/tex]
[tex]=(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)[/tex]
Find the radius of the circle.
[tex]Radius = \frac{Diameter }{2}[/tex]
Diameter is the distance between the points (6 , 0) and ( 6, - 6)
[tex]Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}[/tex]
[tex]=\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6[/tex]
Therefore,
[tex]Radius ,r = \frac{6}{2} = 3[/tex]
Standard equation of a circle:
[tex](x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.[/tex]
Therefore , equation of the circle ;
[tex](x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9[/tex]
i need help w this pls
Answer and Step-by-step explanation:
The answer is the second answer choice. y = 2x + 1
By looking at the graph, we see that there is a y-intercept at (0, 1), and it has a positive slope of 2.
#teamtrees #PAW (Plant and Water)
Suppose a researcher found an rs of .89 between amount of blood cholesterol and the severity of the heart attack. Based on an N of 6 and a two-tailed test, the researcher should conclude:_________.a. not significantb. significant at the .05 levelc. p > .05d. higher blood cholesterol causes more severe heart attacks
Answer:
d. higher blood cholesterol causes more severe heart attacks.
Step-by-step explanation:
Two tailed tests are a method for hypothesis testing when data is distributed on the two sides. P value is determined to identify whether the hypothesis is true or false. When rs is 0.89 between blood cholesterols and severity of heart attacks then these is significant relation between them.
Consider the random experiment of tossing 3 fair coins and observing how many of them come to rest with the heads side of the coin facing upwards. (Assume that each of the coins comes to rest with either its heads side or its tails side facing upwards (i.e., none of the coins comes to rest balanced on its edge).) Letting A denote the event that at least 1 of the coins comes to rest with its heads side upwards, B denote the event that none of the coins comes to rest with its heads side upwards, and S denote the sample space, which of the following statements does not include an abuse of notation?
a. S = 16
b. S = AUB
c. S - 4
d. S = 3
e. P(B) = φ
Answer:
b. S = AUB
Step-by-step explanation:
Since the coins are tossed 3 times and each coin has head, H and tail, T(2 sides), the sample space is S = 2 × 2 × 2 = 2³ = 8
All the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH,THT and TTT
Since S denote the sample space
S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}
Since A denote the event that at least 1 of the coins comes to rest with its heads side upwards, the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH and THT
So, A = {HTT, HHT, HHH, THH, TTH, HTH,THT}
Also B denote the event that none of the coins comes to rest with its heads side upwards, that is no heads. The possible outcome is TTT
So, B = {TTT}
Since S denote the sample space
S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}
So, A ∪ B = {HTT, HHT, HHH, THH, TTH, HTH,THT} ∪ {TTT} = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT} = S
So, S = A ∪ B
So, S = A ∪ B does not denote an abuse of notation.
The answer is b.
ano ang area ng isang maliit na parisukat
Answer:
Area of square = Side²
Step-by-step explanation:
The area of a 2-D region, form, or flattened lamina in the planes is the quantity that represents its extent. On the 2-D surface or 3-D object, surface is its counterpart. A shape's area can be calculated by comparing it to squares of a specific size.
Area of square = Side²
Is this right help me PLEASE
Answer:
Letter B, C and E are correct
Step-by-step explanation:
hope this helps
tell if you got it right
Answer:
Letter B, C and E are correct
Step-by-step explanation:
hope this helps
Dannette and Alphonso work for a computer repair company. They must include the time it takes to complete each repair in their repair log book. The dot plots show the number of hours each of their last 12 repairs took. Part a. Calculate the median, mean, IQR, and standard deviation of each data set. Part b. Which measure of central tendency and spread should you use to compare the two data sets? Explain your reasoning. Part c. Determine whether there are any outliers in either data set. Dannette's Repair Times х х X X X X Х Х + 9 + 1 0 Relations 2 3 4 8 10 12 5 6 7 Repair Time (hours) Geometry Alphonso's Repair Times Groups X Trigonometry X Х X X X х X х Statistics 7 X + 3 10 9 0 4 12 Series 8 1 2 5 7 Repair Time (hours) Greek
PLZ HELP
Answer:
(a):
Dannette Alphonso
[tex]\bar x_D = 4.33[/tex] [tex]\bar x_A = 5.17[/tex]
[tex]M_D = 2.5[/tex] [tex]M_A = 5[/tex]
[tex]\sigma_D = 3.350[/tex] [tex]\sigma_A = 1.951[/tex]
[tex]IQR_D = 7[/tex] [tex]IQR_A = 1.5[/tex]
(b):
Measure of center: Median
Measure of spread: Interquartile range
(c):
There are no outliers in Dannette's dataset
There are outliers in Alphonso's dataset
Step-by-step explanation:
Given
See attachment for the appropriate data presentation
Solving (a): Mean, Median, Standard deviation and IQR of each
From the attached plots, we have:
IQR_A = 1.5 ---- Dannette
[tex]A = \{3,4,4,4,4,5,5,5,5,6,6,11\}[/tex] ---- Alphonso
n = 12 --- number of dataset
Mean
The mean is calculated
[tex]\bar x = \frac{\sum x}{n}[/tex]
So, we have:
[tex]\bar x_D = \frac{1+1+1+1+2+2+3+7+8+8+9+9}{12}[/tex]
[tex]\bar x_D = \frac{52}{12}[/tex]
[tex]\bar x_D = 4.33[/tex] --- Dannette
[tex]\bar x_A = \frac{3+4+4+4+4+5+5+5+5+6+6+11}{12}[/tex]
[tex]\bar x_A = \frac{62}{12}[/tex]
[tex]\bar x_A = 5.17[/tex] --- Alphonso
Median
The median is calculated as:
[tex]M = \frac{n + 1}{2}th[/tex]
[tex]M = \frac{12 + 1}{2}th[/tex]
[tex]M = \frac{13}{2}th[/tex]
[tex]M = 6.5th[/tex]
This implies that the median is the mean of the 6th and the 7th item.
So, we have:
[tex]M_D = \frac{2+3}{2}[/tex]
[tex]M_D = \frac{5}{2}[/tex]
[tex]M_D = 2.5[/tex] ---- Dannette
[tex]M_A = \frac{5+5}{2}[/tex]
[tex]M_A = \frac{10}{2}[/tex]
[tex]M_A = 5[/tex] ---- Alphonso
Standard Deviation
This is calculated as:
[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}[/tex]
So, we have:
[tex]\sigma_D = \sqrt{\frac{(1 - 4.33)^2 +.............+(9- 4.33)^2}{12}}[/tex]
[tex]\sigma_D = \sqrt{\frac{134.6668}{12}}[/tex]
[tex]\sigma_D = 3.350[/tex] ---- Dannette
[tex]\sigma_A = \sqrt{\frac{(3-5.17)^2+............+(11-5.17)^2}{12}}[/tex]
[tex]\sigma_A = \sqrt{\frac{45.6668}{12}}[/tex]
[tex]\sigma_A = 1.951[/tex] --- Alphonso
The Interquartile Range (IQR)
This is calculated as:
[tex]IQR =Q_3 - Q_1[/tex]
Where
[tex]Q_3 \to[/tex] Upper Quartile and [tex]Q_1 \to[/tex] Lower Quartile
[tex]Q_3[/tex] is calculated as:
[tex]Q_3 = \frac{3}{4}*({n + 1})th[/tex]
[tex]Q_3 = \frac{3}{4}*(12 + 1})th[/tex]
[tex]Q_3 = \frac{3}{4}*13th[/tex]
[tex]Q_3 = 9.75th[/tex]
This means that [tex]Q_3[/tex] is the mean of the 9th and 7th item. So, we have:
[tex]Q_3 = \frac{1}{2} * (8+8) = \frac{1}{2} * 16[/tex] [tex]Q_3 = \frac{1}{2} * (5+6) = \frac{1}{2} * 11[/tex]
[tex]Q_3 = 8[/tex] ---- Dannette [tex]Q_3 = 5.5[/tex] --- Alphonso
[tex]Q_1[/tex] is calculated as:
[tex]Q_1 = \frac{1}{4}*({n + 1})th[/tex]
[tex]Q_1 = \frac{1}{4}*({12 + 1})th[/tex]
[tex]Q_1 = \frac{1}{4}*13th[/tex]
[tex]Q_1 = 3.25th[/tex]
This means that [tex]Q_1[/tex] is the mean of the 3rd and 4th item. So, we have:
[tex]Q_1 = \frac{1}{2}(1+1) = \frac{1}{2} * 2[/tex] [tex]Q_1 = \frac{1}{2}(4+4) = \frac{1}{2} * 8[/tex]
[tex]Q_1 = 1[/tex] --- Dannette [tex]Q_1 = 4[/tex] ---- Alphonso
So, the IQR is:
[tex]IQR = Q_3 - Q_1[/tex]
[tex]IQR_D = 8 - 1[/tex] [tex]IQR_A = 5.5 - 4[/tex]
[tex]IQR_D = 7[/tex] --- Dannette [tex]IQR_A = 1.5[/tex] --- Alphonso
Solving (b): The measures to compare
Measure of center
By observation, we can see that there are outliers is the plot of Alphonso (because 11 is far from the other dataset) while there are no outliers in Dannette plot (as all data are close).
Since, the above is the case; we simply compare the median of both because it is not affected by outliers
Measure of spread
Compare the interquartile range of both, as it is arguably the best measure of spread, because it is also not affected by outliers.
Solving (c): Check for outlier
To check for outlier, we make use of the following formulas:
[tex]Lower =Q_1 - 1.5 * IQR[/tex]
[tex]Upper =Q_3 + 1.5 * IQR[/tex]
For Dannette:
[tex]Lower = 1 - 1.5 * 7 = -9.5[/tex]
[tex]Upper = 8 + 1.5 * 7 = 18.5[/tex]
Since, the dataset are all positive, we change the lower outlier to 0.
So, the valid data range are:
[tex]Valid = 0 \to 18.5[/tex]
From the question, the range of Dannette's dataset is: 1 to 9. Hence, there are no outliers in Dannette's dataset
For Alphonso:
[tex]Lower = 4 - 1.5 * 1.5 =1.75[/tex]
[tex]Upper = 5.5 + 1.5 * 1.5 =7.75[/tex]
So, the valid data range are:
[tex]Valid = 1.75\to 7.75[/tex]
From the question, the range of Alphonso's dataset is: 3 to 11. Hence, there are outliers in Alphonso's dataset
