Answer:
a) In the interval ( 55,9 ; 456,7 ) we will find 99,7 % of all values
b) In the interval ( 122,7 ; 389,9 ) we find 95,4 % of all values
Step-by-step explanation:
For a Normal distribution N (μ ; σ ) the Empirical rule establishes that the intervals:
( μ ± σ ) contains 68,3 % of all values
( μ ± 2σ ) contains 95,4 % of all values
( μ ± 3σ ) contains 99,7 % of all values
If N ( 256,3 ; 66,8 )
σ = 66,8 ⇒ 3*σ = 3 * 66,8 = 200,4
Then: 256,3 - 200,4 = 55,9
And 256,3 + 200,4 = 456,7
a) In the interval ( 55,9 ; 456,7 ) we will find 99,7 % of all values
b) 2*σ = 2 * 66,8 = 133,6
Then 256,3 - 133,6 = 122,7
And 256,3 + 133,6 = 389,90
Then in the interval ( 122,7 ; 389,9 ) we find 95,4 % of all values
Ellen is making jewelry sets that contain a bracelet and a pair of earrings. Each bracelet uses 3 times as many beads as one earring. Each bracelet uses 3 as times as many beads as one earring . Ellen uses 13 beads for each earring. How many beads does Ellen need to make one jewelry set?
It's given that the Bracelet uses 3 times the number of beads that's used in making a single earring.
It's also given that one single earing has 13 beads. So a single bracelet would have (3×13) beads .... and that's equal to 39.
Making a single set of jewellery needs a pair of earrings and a Bracelet.
So total number of required beads will be =
39 + 13 + 13 = 65Please help me guys :)
Question:
In exercises 1 through 4, find the one-sided limits lim x->2(left) f(x) and limx-> 2(right) from the given graph of f and determine whether lim x->2 f(x) exists.
Step-by-step explanation:
For a left-hand limit, we start at the left side and move right, and see where the function goes as we get close to the x value.
For a right-hand limit, we start at the right side and move left, and see where the function goes as we get close to the x value.
If the two limits are equal, then the limit exists. Otherwise, it doesn't.
1. As we approach x = 2 from the left, f(x) approaches -2.
lim(x→2⁻) f(x) = -2
As we approach x = 2 from the right, f(x) approaches 1.
lim(x→2⁺) f(x) = 1
The limits are not the same, so the limit does not exist.
lim(x→2) f(x) = DNE
2. As we approach x = 2 from the left, f(x) approaches 4.
lim(x→2⁻) f(x) = 4
As we approach x = 2 from the right, f(x) approaches 2.
lim(x→2⁺) f(x) = 2
The limits are not the same, so the limit does not exist.
lim(x→2) f(x) = DNE
3. As we approach x = 2 from the left, f(x) approaches 2.
lim(x→2⁻) f(x) = 2
As we approach x = 2 from the right, f(x) approaches 2.
lim(x→2⁺) f(x) = 2
The limits are equal, so the limit exists.
lim(x→2) f(x) = 2
4. As we approach x = 2 from the left, f(x) approaches 2.
lim(x→2⁻) f(x) = 2
As we approach x = 2 from the right, f(x) approaches infinity.
lim(x→2⁺) f(x) = ∞
The limits are not the same, so the limit does not exist.
lim(x→2) f(x) = DNE
Given a population with a mean of µ = 100 and a variance of σ2 = 1600, the central limit theorem applies when the sample size is n ≥ 25. A random sample of size n = 50 is obtained. • What are the mean and variance of the sampling distribution for the sample means? • What is the probability that ¯X > 110?
Answer:
The probability that the sample mean is more than 110 is 0.0384.
Step-by-step explanation:
According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the sampling distribution of the sample mean will be approximately normally distributed.
Then, the mean of the sampling distribution of sample mean is given by:
[tex]\mu_{\bar x}=\mu[/tex]
And the variance of the sampling distribution of sample mean is given by:
[tex]\sigma^{2}_{\bar x}=\frac{\sigma^{2}}{n}[/tex]
The information provided is:
[tex]n=50\\\\\mu=100\\\\\sigma^{2}=1600[/tex]
Since n = 50 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample mean by the normal distribution.
The mean variance of the sampling distribution for the sample mean are:
[tex]\mu_{\bar x}=\mu=100\\\\\sigma^{2}_{\bar x}=\frac{\sigma^{2}}{n}=\frac{1600}{50}=32[/tex]
That is, [tex]\bar X\sim N(100, 32)[/tex].
Compute the probability that the sample mean is more than 110 as follows:
[tex]P(\bar X>110)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{110-100}{\sqrt{32}})[/tex]
[tex]=P(Z>1.77)\\=1-P(Z<1.77)\\=1-0.96164\\=0.03836\\\approx 0.0384[/tex]
*Use a z-table.
Thus, the probability that the sample mean is more than 110 is 0.0384.
Please answer! I am struggling with this question! Please show ALL work! <3 (the answer choices are provided on a separate image)
Answer:
The radius is 18 inches
Step-by-step explanation:
The circumference of a circle is given by
C = 2 * pi *r
36 pi = 2 * pi *r
Divide each side by pi
36 = 2r
Divide each side by 2
18 =r
Answer:
The answer is option CStep-by-step explanation:
Circumference of a circle = 2πr
where
r is the radius of the circle
From the question
Circumference = 36π inches
To find the radius substitute the value of the circumference into the above formula and solve for the radius
That's
[tex]36\pi = 2\pi r[/tex]Divide both sides by 2π
We have
[tex] \frac{36\pi}{2\pi} = \frac{2\pi \: r}{2\pi} [/tex]We have the final answer as
r = 18 inchesHope this helps you
The hypotenuse of a right triangle is 5 inches long. One of the legs is 1 inch longer than the other. What is the length (in inches) of the longer leg?
Answer: 4 inches
Step-by-step explanation:
1. We gonna find the the length of the right triangle legs using Phitagor theorem.
c²=a²+b² (1) , where c is triangle's hypotenuse
a and b are the triangle's legs.
Let the leg a =x, so leg b=x+1 inches
Now we can write the equation using (1)
25=x²+(x+1)²
25=x²+x²+2*x+1
2*x²+2*x-24=0 ( divide by 2 both sides of the equation)
x²+x-12=0
Find the discriminant D=1+12*4=49
√D=7
x1= (-1+7)/2=3 x2=(-1-7)/2=-4 - x2=-4 not possible so length of the leg can not be negative.
So the shorter leg a=x= 3 inches
The longer leg b=x+1=4 inches
Find the domain and the range of the relation.
Find the domain of the relation. Select the correct choice below and fill in the answer box to
complete your choice.
O A. The domain is _
(Type your answer in interval notation.)
B. The domain is {_}
(Type an integer or a fraction. Use a comma to separate answers as needed.)
Find the range of the relation. Select the correct choice below and fill in the answer box to
complete your choice.
O A. The range is _
(Type an integer or a fraction. Use a comma to separate answers as needed.)
OB. The range is {_}
Answer:
1) the domain is all real numbers
2) the range is
[tex]y \geqslant 3[/tex]
Consider the line =−−7x4y−6.
What is the slope of a line parallel to this line?
What is the slope of a line perpendicular to this line?
Answer:
4/7
Step-by-step explanation:
Original equation, in general form: -7x - 4y - 6
Rearrange to get: 4y = -7x - 6
Divide both sides by 4 to get: y = -7/4(x) - 1.5
To find the slope of a line perpendicular to another line, take the original gradient, and find the negative inverse
So for here,
Original gradient: -7/4
Negative: 7/4
Negative Inverse: 4/7 (which is our gradient)
Done!
The following sample contains the scores of 6 students selected at random in Mathematics and English. Use the scores in English as the dependent variable Y.
Mathematics score (X) 70 92 80 74 65 83
English score 74 84 63 87 78 90
Σx =464 Σy=476 Σx^2= 36354 Σy^2=38254 Σxy= 36926
Find the sample coefficient of determination and interpret.
a. 0.0575 and prediction accuracy is 5.75%
b. 0.2397 and prediction accuracy is 23.97%
c. 0.0575 and prediction accuracy is 94.25%
d. 0.2397 and prediction accuracy is 76.03%
Answer:
d the answer is d
Step-by-step explanation:
it is 235 miles from tulsa to dallas. it is 390 miles from dallas to houston. a) what is the total distance of a trip from tulsa to dallas to houston? b) what is the total distance from houston to dallas to tulsa? c) explain how you can tell whether the distances described in parts (a) and (b) are equal by using reasoning.
Answer:
a- tulsa to dallas to houston is 235+390 which is 625 miles
b - houston to dallas to tulsa is 390+235 miles which is 625 miles
c - by using reasoning both are same because they are just rewritten differently but the equation is same
please give me brainliest
hope it helps buddy
una compañía sabe que si produce "x" unidades mensuales su utilidad "u" se podría calcular con la expresión:
u(x)=-0.04x^2+44x-4000
donde "u" se expresa en dólares. Determine la razón del cambio promedio de la utilidad cuando el nivel de producción cambia de 600 a 620 unidades mensuales. Recuerde que la pendiente de la recta secante a la gráfica de la función representa a la razón de cambio promedio.
porfavor alguien que me explique el procedimiento :(
Answer:
Δf(u) /Δx = 92,8 ( razón de cambio promedio)
Step-by-step explanation:
La expresión de la utilidad de la empresa u(x) en función de la cantidad de unidades producidas "x" es:
u(x) = 0,04*x² + 44*x -4000
Entonces la razón de cambio promedio en un intervalo (a ; b) en este caso ( 620 ; 600 ) viene dada por la expresión:
Δf(x)/ Δx = [ f(b) - f(a) ]/( b - a )
en donde f(b) y f(a) se obtienen por sustitución de los valores a y b es decir 600 y 620 respectivamente en la función f(x) = u(x) entonces
Δf(u) /Δx = [ u(b) - u(a) ]/( b -a ) (1)
u(b) = 0,04*(620)² + 44*(620) - 4000
u(b) = 15376 + 27280 -4000
u(b) = 2656 unidades
u(a) = 0,04* (600)² + 44* 600 - 4000
u(a) = 14400 + 26400 - 4000
u(a) = 800
Sustituyendo esos valores en la ecuación 1
Δf(u) /Δx = 2656 - 800 / 620 - 600
Δf(u) /Δx = 92,8
Apply the distributive property to factor out the greatest common factor. 40f+30 =
Answer:
10(4f+3)
Step-by-step explanation:
boo
The product of a number and 3 is equal to 15 minutes twice the number, find the number.
Answer:
The answer is 3Step-by-step explanation:
Let the number to be found be x
The product of a number and 3 is written as
3 × x = 3x15 minus twice the number is written as
15 - 2xNow equate the two statements
That's
3x = 15 - 2x
Group like terms
3x + 2x = 15
5x = 15
Divide both sides by 5
the final answer is
x = 3Hope this helps you
The length of a rectangle is twice its width. If the perimeter of the rectangle is 30m, find its area.
Answer:
If the perimeter of the rectangle is 30cm , find its area. W=5 FOR THE WIDTH. 5*10=50 FOR THE AREA.
Step-by-step explanation:
The area of the Rectangle is 50 sq.m
What is the formula of Area of Rectangle?The area of rectangle for a rectangle of length L and width W is given by
A = L* W
It is measured in square units.
Let the length of the rectangle be L
The width of the rectangle is W
The length of a rectangle is twice its width
L = 2W
Perimeter of the Rectangle is 2( Length + Width)
30 = 2 (L +W)
15 = L + W
15 = 2W +W
15 = 3W
W = 5m
L = 10m
The area of the rectangle is Length * Width
Area = 10 *5
Area = 50 sq.m
To know more about Area of Rectangle
brainly.com/question/20693059
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10 easy points!!!! What is the x-intercept of the line?
Answer:
Step-by-step explanation:
As x increases from -74 to -54 (a 'run' of 20), y decreases from 18 to 12 (a 'rise' of -6. Thus, the slope of this line is m = rise/run = -6/20 = -13/10.
From y = mx + b we get 12 = (-13/10)(12) + b, or (after dividing all terms by 12)
1 = -13/10 + b/12, or
60 = -3(6) + 5b, or
42 = - 5b, or b = -42/5
The line is y = (-13/10)x - 42/5.
At the x-intercept, y = 0. Setting y = 0, we get:
(13/10)X = -42/5, or 13x = -84.
Thus, x = -84/13 = -6.46
and so the x-intercept of the line is (-6.46, 0)
Eliminate the parameter for the following set of parametric equations: x= t + 6 y= 3t – 1
Answer:
Solution : Option A
Step-by-step explanation:
What we want to do here is eliminate the parameter t. In order to do that, we can isolate t in our first equation x = t + 6 ----- ( 1 ) and then plug that value for t in the second equation y = 3t - 1. Our solution will be an equation that is not present with t.
( 1 ) x = t + 6, t = x - 6
( 2 ) y = 3( x - 6 ) - 1 ( Distribute the " 3 " in 3( x - 6 ) )
y = 3x - 18 - 1 ( Combine like terms )
y = 3x - 19
As you can see our result will be option a, y = 3x - 19.
Tierra's THR zone is 135-185 bpm (beats per minute). What might Tierra's heart rate be to
indicate that she was working too hard?
A. 145 bpm
B. 195 bpm
C. 175 bpm
D. 130 bpm
The correct answer is B. 195 bpm
Explanation:
In health and related areas, THR or Target Heart Rate zone refers to the range of heart rate an individual should have including the maximum heart rate. In the case of Tierra, her THR zone indicates her maximum heart rate should be 185 beats per minute.
In this context, a heart rate above this number shows Tierra is working too hard or that his heart is doing too much effort, which is dangerous for her health. Thus, the heart rate that shows she is doing too hard is 195 bmp as this is the only one that is above the ideal rate.
f(x)=3x2+10x-25 g(x)=9x2-25 Find (f/g)(x).
Answer:
[tex](f/g)(x) = \frac{x + 5}{3x + 5} [/tex]
Step-by-step explanation:
f(x) = 3x² + 10x - 25
g(x) = 9x² - 25
To find (f/g)(x) divide f(x) by g(x)
That's
[tex](f/g)(x) = \frac{3 {x}^{2} + 10x - 25 }{9 {x}^{2} - 25 } [/tex]
Factorize both the numerator and the denominator
For the numerator
3x² + 10x - 25
3x² + 15x - 5x - 25
3x ( x + 5) - 5( x + 5)
(3x - 5 ) ( x + 5)
For the denominator
9x² - 25
(3x)² - 5²
Using the formula
a² - b² = ( a + b)(a - b)
(3x)² - 5² = (3x + 5)(3x - 5)
So we have
[tex](f/g)(x) = \frac{(3x - 5)(x + 5)}{(3x + 5)(3x - 5)} [/tex]
Simplify
We have the final answer as
[tex](f/g)(x) = \frac{x + 5}{3x + 5} [/tex]
Hope this helps you
The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.966 grams and a standard deviation of 0.315 grams. Find the probability of randomly selecting a cigarette with 0.305 grams of nicotine or less.
Answer:
The probability is [tex]P(X \le 0.305 ) = 0.01795[/tex]
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 0.966 \ grams[/tex]
The standard deviation is [tex]\sigma = 0.315 \ grams[/tex]
Given that the amounts of nicotine in a certain brand of cigarette are normally distributed
Then the probability of randomly selecting a cigarette with 0.305 grams of nicotine or less is mathematically represented as
[tex]P(X \le 0.305 ) = 1 - P(X > 0.305) = 1 - P(\frac{X - \mu }{\sigma } > \frac{0.305 - \mu }{\sigma } )[/tex]
Generally
[tex]\frac{X - \mu }{\sigma } = Z (The \ standardized \ value \ of X )[/tex]
So
[tex]P(X \le 0.305 ) = 1 - P(X > 0.305) = 1 - P(Z > \frac{0.305 - 0.966 }{0.315} )[/tex]
[tex]P(X \le 0.305 ) = 1 - P(X > 0.305) = 1 - P(Z >-2.0984 )[/tex]
From the z-table(reference calculator dot net ) value of [tex]P(Z >-2.0984 ) =0.98205[/tex]
So
[tex]P(X \le 0.305 ) = 1 - P(X > 0.305) = 1 - 0.98205[/tex]
=> [tex]P(X \le 0.305 ) = 1 - P(X > 0.305) = 0.01795[/tex]
=> [tex]P(X \le 0.305 ) = 0.01795[/tex]
What is 5% added to $194?
Answer:
203.7
Step-by-step explanation:
5% of 194 added to 194 =
= 5% * 194 + 194
= 0.05 * 194 + 194
= 9.7 + 194
= 203.7
I require someone to answer this question for me ASAP please?
Answer:
x has to be less than 3
Step-by-step explanation:
Answer:
x < 3
I hope this helps!
The parallelogram to be a square,x=?
Answer:
7°
Step-by-step explanation:
for this paralellogram to be a square, the sides should be perpendicular.
Woch means that 4x+17° = 45°
● 4x +17° = 45°
Substract 17 from both sides.
● 4x +17°-17° = 45°-17°
● 4x = 28°
Divide both sides by 4
● 4x/4 = 28°/ 4
● x = 7°
What is the probability that a randomly selected individual on this campus weighs more than 166 pounds? (express in decimal form and round final answer to 4 decimal places)
Answer:
hello attached is the missing part of your question and the answer of the question asked
answer : 0.2951
Step-by-step explanation:
Given data:
number of persons allowed in the elevator = 15
weight limit of elevator = 2500 pounds
average weight of individuals = 152 pounds
standard deviation = 26 pounds
probability that an individual selected weighs more than 166 pounds
std = 26 , number of persons(x) = 15, average weight of individuals(u) = 152 pounds
p( x > 166 ) = p( x-u / std, 166 - u/ std )
= p ( z > [tex]\frac{166-152}{26}[/tex] )
= 1 - p( z < 0.5385 )
p( x > 166 ) = 1 - 0.70488 = 0.2951
Question 3: The gasoline gauge on a van initially read ⅛ full. When 15 gallons of gasoline were added to the tank, the gauge then read ¾ full. How many more gallons would be needed to fill the tank?
Answer:
hi
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
3/4=6/8
6/8-1/8=5/8
So 5/8 of the tank is 15 gallons. This means each 1/8 of a tank is 3 gallons.
The van is currently 6/8 full. We need to add another 2/8 to completely fill the tank.
2x3=6
You’ll need 6 more gallons to fill the tank.
Raul tried to evaluate an expression step by step.
Answer:
(B) Step 2
Step-by-step explanation:
In step 2, Raul should have had one of these results:
8 -7 . . . . according to the order of operations
or
3 -2 . . . . properly adding 5 -7
Raul's step 2 is not either of these (or 5-4), so is incorrect.
Answer:
step 2 i did it on khan yall
Step-by-step explanation:
Average of 44.64, 43.45, 42.79, 42.28
Answer:
43.29Step-by-step explanation:
[tex]44.64+ 43.45+42.79+42.28\\\\= \frac{44.64+ 43.45+42.79+42.28}{4} \\\\\\= \frac{173.16}{4} \\\\= 43.29\\[/tex]
3(x–6)=18 help plese
Answer:
x = 12
Step-by-step explanation:
3(x–6)=18
x-6 = 18:3
x-6 = 6
x = 6+6
x = 12
Answer:
x=12
Step-by-step explanation:
BRAINLEST Find the sum of the first 6 terms of the infinite series: 1 - 2 + 4 - 8+...
Answer:
-21
Step-by-step explanation:
1-2+4-8+16-32
=-21
Answer:
The sum of the first 6 terms of the infinite series will be - 21.
Step-by-step explanation:
In this case, the infinite geometric series 1 - 2 + 4 - 8 + ... is represented by the following summation,
[tex]\sum _{{k=0}}^{{n}}(-2)^{k}[/tex]
Therefore if we continue this pattern, the first 6 terms will be 1 - 2 + 4 - 8 + 16 - 32. Adding these terms,
1 - 2 + 4 - 8 + 16 - 32
= - 1 + 4 - 8 + 16 - 32
= 3 - 8 + 16 - 32 = - 5 + 16 - 32
= 11 - 32 = Solution : - 21
A Prefeitura da Cidade Feliz doou um
terreno para a Comunidade Viver Bem
discutir projetos que deveriam ser
implantados no local. Após um planejamento
participativo, ficou acertado que 45% da área
total desse terreno serão destinados a uma
creche;
3%,
para banheiros públicos e 12%
para uma academia de ginástica comunitária.
A sobra da área, que é de 960m² será
utilizada para uma pequena praça com
parque de lazer. Qual é a área total ocupada
pela creche, banheiros públicos e academia
de ginástica comunitária?
Aqui temos a seguinte divisao de terreno:
creche + banheiros + academia = 45% + 3% + 12% = 60%
O que sobra: Fazendo a conta, 100 - 60 = 40, restará 40%
No enunciado informa que sobraram 960m².
Logo concluimos que 40% = 960m²
Sendo assim, regra de 3:
m² %
960 -------- 40
X -------- 60
40X = 960 . 60
X = 57600/40
X = 1440
Logo 1440m² é destinado para: creche, banheiros públicos e academia
de ginástica comunitária.
O terreno tem um total de 1440 + 960 = 2400m²
para cada espaço - novamente diversas regra de 3:
→ creche = 45%
m² %
2400 -------- 100
X -------- 45
X = 108000/100 = 1080
→ banheiros públicos = 3%
m² %
2400 -------- 100
X -------- 3
X = 7200/100 = 72
→ academia de ginástica comunitária = 12%
m² %
2400 -------- 100
X -------- 12
X = 28800/100 = 288
provando:
60% = 1440m² (visto acima)
creche - 1080
banheiros - 72
academia - 288
1080 + 72 + 288 = 1440 (60%)
How do u solve A/B + C/D = E
Find the mass and center of mass of the solid E with the given density rho. E is the cube 0 ≤ x ≤ a, 0 ≤ y ≤ a, 0 ≤ z ≤ a; rho(x, y, z) = 9x2 + 9y2 + 9z2.
Answer:
mass = 9a^5
center of mass = [tex]\frac{7a}{12}, \frac{7a}{12}, \frac{7a}{12}[/tex]
Step-by-step explanation:
Finding the mass of the solid E
given density function : p ( x,y,z ) = [tex]9x^2 + 9y^2 + 9z^2[/tex]
Mass = [tex]\int\limits^a_0 \int\limits^a_0 \int\limits^a_0 {9(x^2+y^2+z^2)} \, dx dydz[/tex] [tex]= \int\limits^a_0 \int\limits^a_0 {9(\frac{a^3}{3}+ay^2+az^2 )} \, dydz[/tex]
[tex]= \int\limits^a_0 {9(\frac{a^4}{3}+\frac{a^4}{3} +a^2z^2 )} \, dz[/tex] [tex]= \int\limits^a_0 {9(\frac{2a^4}{3}+a^2z^2 )} \, dz[/tex] [tex]= 9 ( \frac{2a^5}{3} + \frac{a^5}{3} )[/tex]
( taking limits as a and 0 )
hence Mass = 9 [tex](a^5)[/tex]
finding the center of mass
attached below is solution
