Carol wants to tile her utility room. Each tile is 1 square foot. She draws the shape of her room on a grid. Each square unit on the grid represents 1 square foot. How many tiles will she need?
Answer:
1
Step-by-step explanation:
that's a very vague question
A rectangular garden has length and width as given by the expressions below.
Length: 4 - 7(3x + 4y)
Width: 3x(-2y)
Write a simplified expression for the perimeter of the rectangle.
y
ху
Answer:
8 - 42x - 56y - 12xy
Step-by-step explanation:
Length = 4 - 7(3x + 4y)
= 4 - 21x - 28y
Width = 3x(-2y)
= -6xy
Perimeter of the rectangle = 2(length + width)
= 2{(4 - 21x - 28y) + ( -6xy)}
= 2(4 - 21x - 28y - 6xy)
= 8 - 42x - 56y - 12xy
Perimeter of the rectangle = 8 - 42x - 56y - 12xy
20 men take 10 days to complete a piece of work. find the time taken by 8 men to complete the same piece of work
en un salón para eventos (con 4 patas) y banquillos (con 3 patas). si hay x sillas y y banquillos,¿cuántas patas podrías contar en total?
ayuda porfa es para ahora
In parallelogram HJKL if m∡KLH=125∘find m∡LHJ.
Answer:
∠ LHJ = 55°
Step-by-step explanation:
Consecutive angles in a parallelogram are supplementary, sum to 180° , so
∠ LHJ + ∠ KLH = 180° , that is
∠ LHJ + 125° = 180° ( subtract 125° from both sides )
∠ LHJ = 55°
2. Round off the following numbers to two decimal places:
b) 4,5873
c) 32,095
a) 56,3456
d) 13,997
Answer:
I think you mean significant figures
Step-by-step explanation:
460003200056000014000For what values of b will F(x) = logo x be a decreasing function?
A. b>0
B. 0
C. b< 0
D. O >b>-1
[tex]f(x) = \log_b(x)[/tex] is a decreasing function when [tex]0 < b < 1[/tex]
This is because we can use the change of base formula to say
[tex]\log_b(x) = \frac{\log(x)}{\log(b)}[/tex]
If b is between 0 and 1, not including either endpoint, notice how the log(b) term is negative.
For example, if b = 0.5, then log(b) = log(0.5) = -0.301 approximately. I'm using log base 10 to get log(0.5) = -0.301
So for b = 0.5, we have,
[tex]\log_{0.5}(x) = \frac{\log(x)}{\log(0.5)} \approx \frac{\log(x)}{-0.301} \approx -3.322\log(x)[/tex]
The log(x) part on its own is always increasing. The negative coefficient out front flips it to always decreasing.
By applying the behavior rules we notice that the expression [tex]F(x) = \log_{b} x[/tex]decreasing function if the base of the logarithm is 0 < b < 1. (Correct choice: D) #SPJ5
How to define the behavior of a logarithmLogarithms are trascendent functions whose form is defined by the following expression:
[tex]\log _{b} x[/tex] such that [tex]x = b^{a}[/tex], where b > 0.
Where b is the base of the power.
Whose rules are described below:
The logarithm is an increasing function if its base is less than 1.The logarithm is a decreasing function if its base is greater than 1.By applying the behavior rules we notice that the expression [tex]F(x) = \log_{b} x[/tex] is a decreasing function if the base of the logarithm is 0 < b < 1. (Correct choice: D)
RemarkThe statement is poorly formatted and reports several mistakes. Correct form is shown below:
For what values of b will [tex]F(x) = \log_{b} x[/tex] be a decreasing function?
A. b > 0
B. 0
C. b < 0
D. 0 < b < 1
To learn more on logarithms, we kindly invite to check this: https://brainly.com/question/20785664 #SPJ5
**PLEASE HELP**The frequency table below represents the 30 best battling averages for a semi pro baseball league. Which ranges of battling averages were least common among the players
The lower the frequency the least common the average.
There are two frequencies that are 1, which would be the least common.
The answer is C. 0.320-0.329 and 0.360 -0.369
Answer:
option C
Step-by-step explanation:
option c is contains the two batting averages which have a frequency of 1, this means that they both only occurred once which is the least amount of times any of the batting averages has occurred.
A cube of sides 10cm was cut across to obtain a prism. Calculate the surface area of the prism and the volume of the prism
[tex] \frac{1}{2} bh \times h[/tex]
Answer:
Part A
The volume of the triangular prism is 500 cm³
Part B
The total surface area of the prism is approximately 441.42 cm²
Step-by-step explanation:
The given details are;
The dimensions of the side length of the cube, s = 10 cm
The shape the cube was cut across to obtain = A prism
Part A
Whereby the prism obtained is a triangular prism, we have;
The cube can be cut in half to form a triangular prism
The volume of each triangular prism obtained = (1/2) × The volume of the cube
∴ The volume of the triangular prism = (1/2) × (10 cm)³ = 500 cm³
Part B
The height of the prism, h = 10 cm × sin(45°) = 5·√2 cm = (1/2) × The base width of the prism
The triangular cross sectional area of the prism, A₁ = 5·√2 × 5·√2 = 50
The square cross sectional area, A₂ = 10 × 10 = 100
The cross sectional area of the base, A₃ = 10·√2 × 10 = 100·√2
The total surface area of the prism, A = 2·A₁ + 2·A₂ + A₃
∴ A = 2×50 + 2×100 + 100·√2 = 300 + 100·√2 ≈ 441.42
The total surface area of the prism, A ≈ 441.42 cm²
If f(x)=2(x)2 +5w/(x+2)
(2) =
F(2)=
Answer:
16+5w/4
Step-by-step explanation:
The area of a wall that needs to be papered is 84sqft. The wallpaper that needs to be papered is 18in wide and 33ft long. Rolls of solid color wallpaper will be used, so patterns do not have to match up.
Answer:
The answer is below
Step-by-step explanation:
The area of the wall is 84 ft².
The width of the wallpaper is 18 in.
1 ft. = 12 in
Hence; 18 in = 18 in * 1 ft. per 12 in = 1.5 ft
The length of the wallpaper is 33 ft.
Therefore, the area of the wallpaper = length * width = 1.5 ft. * 33 ft. = 49.5 ft². This means that each roll of wallpaper has an area of 49.5 ft²
Therefore, the minimum amount of rolls of wallpaper needed = area of wall / area of wallpaper
Amount of wallpaper = 84 ft² / 49.5 ft² = 1.7 rolls
Trigonometry help me
Answer:
[tex]\theta = \frac{\pi}{6}[/tex]
Step-by-step explanation:
[tex]tan^ 2 \theta - ( \sqrt 3 + \frac{1}{\sqrt3}}) tan \theta + 1 = 0\\\\tan \theta - ( \sqrt 3 + \frac{1}{\sqrt3}}) +\frac{1}{ tan \theta } = 0\\\\[/tex] [tex][ \ divide \ by \ tan \theta \ on \ both \ sides \ ][/tex]
[tex]tan\theta + \frac{1}{ tan \theta }- ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\\frac{tan^2 \theta + 1}{ tan \theta } - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\\frac{sec ^2 \theta}{ \frac{sin \theta }{cos \theta}} - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0[/tex] [tex][ \tan ^ 2\theta + 1 = sec ^2 \theta \ , \ tan \theta = \frac{sin \theta }{cos \theta } \ ][/tex]
[tex]\frac{sec^2 \theta }{sin \theta \times sec \theta } - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\[/tex] [tex][\ \frac{sin \theta }{cos \theta } = sin \theta \times sec \theta \ ][/tex]
[tex]\frac{sec \theta }{sin \theta } - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\[/tex]
[tex]sec \theta \ cosec \theta - ( \sqrt 3 + \frac{1}{\sqrt3}}) = 0\\\\[/tex] [tex][ \ \frac{1}{sin \theta } = cosec \theta \ , \ \frac{ sec \theta }{sin \theta } = sec \theta cosec \theta \ ][/tex]
[tex]sec \theta \ cosec \theta - \sqrt 3 - \frac{1}{\sqrt3}} = 0\\\\\frac{\sqrt 3\ sec \theta \ cosec \theta - 3 - 1}{\sqrt3} = 0\\\\\sqrt 3 sec \theta cosec \theta - 4 = 0\\\\[/tex]
[tex]\sqrt3 \frac{1}{cos \theta } \frac{1}{sin \theta } - 4 = 0\\\\\frac{\sqrt3 - 4sin \theta cos \theta} { sin \theta cos \theta } = 0[/tex]
[tex]\sqrt 3 - 2sin 2\theta = 0[/tex] [tex][ \ sin 2 \theta = 2 sin \theta cos \theta \ ][/tex]
[tex]2sin 2 \theta = \sqrt3\\\\sin 2 \theta = \frac{\sqrt3 }{2} \\\\2 \theta = sin^{-1} (\frac{\sqrt3}{2})\\\\2 \theta = 60^{ \circ} = \frac{ \pi}{3}\\\\\theta = \frac{\pi} {6}[/tex]
The scores from Dr. Wilhelm's students science fair project are shown below .
Dr wilhelm made a histogram for the data.
answer choices :
50
65
70
71
plsss help I appreciate it thank you so much
Answer:
See Explanation
Step-by-step explanation:
You posted an incomplete question with little and unclear details.
I will answer this question with a more complete version (see attachment)
Given that:
[tex]Scores: 100\ 95\ 88\ 62\ 76\ 90\ 100\ 58\ 72\ 60\ 85\ 90\ 70\ 72\ 54\ 100\ 60\ 80\ 75\ 51[/tex]
Required
The fraction that passed the test
Rearrange the score in ascending order:
[tex]Scores: 51\ 54\ 58\ 60\ 60\ 62\ 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]
The total number of students is:
[tex]n =20[/tex]
Extract the students that passed (scored 70 and above)
[tex]Passed: 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]
Their numbers are:
[tex]Passed: 14[/tex]
So, the fraction of those that passed is:
[tex]Fraction = \frac{Passed}{n}[/tex]
[tex]Fraction = \frac{14}{20}[/tex]
Reduce fraction
[tex]Fraction = \frac{7}{10}[/tex]
Think of 5 positive integers that have a mode of 4, a median of 6, a mean of 7 and a range of 10.
Answer:
6 6 6 6 11
Step-by-step explanation:
The median is the middle number
the mode is the number of items, usually the number that are the same.
the mean is the average
the range is the number between the smallest and the largest.
So the information you have makes 4 of the 5 numbers the same.
The middle number is 6. This is an interesting fact because it means that 4 of the five numbers are 6
x 6 6 6 6 or 6 6 6 6 x is what you know so far.
The range is a bit of a devil. And so is the mean. We need the mean to be related to 5*7 = 35. So the sum of the five numbers equals 35. The range would have to be 5, I think. (35 - 4*6) = 11
The difference between 11 and 6 = 5
So 11 works for everything but the range.
If the range must be ten, then x = 16 but then the mean = 8 and 7 is incorrect
So I can get 3 out of 4, but not them all.
Which of the pairs of functions and their inverses will always have a domain and range of all real numbers?
Answer:
A pair of linear functions
Step-by-step explanation:
Given
See comment for options
Required
Which has real numbers as its range and domain
The answer to this is, the linear functions
Take for instance
[tex]f(x) = mx + b[/tex]
The above function is real for all values of x
The inverse is calculated as thus:
[tex]f(x) = mx + b[/tex]
Replace f(x) with y
[tex]y = mx + b[/tex]
Swap y and x
[tex]x = my + b[/tex]
Make y the subject
[tex]my = x - b[/tex]
Divide by m
[tex]y = \frac{x - b}{m}[/tex]
Replace y with the inverse function
[tex]f^{-1}(x) = \frac{x - b}{m}[/tex]
The above function (i.e. the inverse function) is real for all values of x
This is not true for other options
Please help I’ll give brainliest
Answer:
v = 27,000 mm³
Step-by-step explanation:
v = s³
v = 30³
v = 27,000 mm³
Completing the Square
Guided Practice
Solve the equation by completing the square. If necessary, round to the nearest hundredth.
2x2 - 10x - 20 = 8
A. 91/4, — 71/4
B. 7
C.7, -2
Charlie withdraws cash from an ATM that is not his own bank’s 3 times a month. He pays $1.50 per transaction. If this pattern is consistent across a year, what will his yearly cost be?
Answer:
If I understand this right, the answer is $48.00
Step-by-step explanation:
If they pay $1.50 three times a month just times $1.50 by 12 because there are 12 days in a month, then you get 16, then you times 16 by 3 and you get 48.
(I hope this is right lol)
Answer:
$54.00
Step-by-step explanation:
3 transactions × $1.50 per transaction = $4.50 per month
$4.50 × 12 months in a year = $54.00
Analyze the diagram below and complete the statement that follows.
The perimeter of the square is
A. 42
B. 60
C. 110.25
D. 112.5
Answer:
A: 42
Step-by-step explanation: 10.5x4=42
Answer:
your answer is A 42
Step-by-step explanation:
make me brainliest
minus 15 over minus 4
Answer:
3.75
Step-by-step explanation:
What is the perimeter of this rectangle?
Think about the vertical line test and answer the following question. Would a vertical line be a relation, a function, both a relation and a function, or neither a relation nor a function?
A.
both a relation and a function
B.
neither a relation nor a function
C.
function only
D.
relation only
Answer:
relation only
Step-by-step explanation:
The vertical line will be relation only.
What is a function?Function is a type of relation, or rule, that maps one input to specific single output.
In mathematics, a function is an expression, rule, or law that describes the relationship between one variable (the independent variable) and another variable.
In mathematics and the physical sciences, functions are indispensable for formulating physical relationships.
Noted that Linear function is a function whose graph is a straight line
We can conclude that vertical line would be relation only.
Learn more about function here:
https://brainly.com/question/2253924
#SPJ3
Find the sum difference 104 - (-92)
Answer:
12
Step-by-step explanation:
Question 7
1. Calculate and write your answer as a mixed number
1 4/5 + 2 2/3 - 16/15
Answer:
3 7/15
Step-by-step explanation:
1 4/5 + 2 2/3 - 16/15
9/5 + 8/3 - 16/15
27/15 + 40/15 - 16/15
52/15 = 3 7/15
Answer:
3 2/5
Step-by-step explanation:
STEP 1: Convert all fractions into improper fractions
9/5 + 8/3 - 16/15
Step 2: pass denominators
(9x3 + 8x5 - 16) / 15
=51/15
Step it into proper mixed number
3 2/5
De las ventas obtenidas en el mes de enero , el dueño de " La chiquita " tiene la obligación de entregar el 16 % de IVA . Si en un mes se vendieron en la tienda $80,000 ¿ Cuánto tendrá que reportar de IVA al gobierno ?
Answer:
The amount paid as VAT is $ 12800.
Step-by-step explanation:
Sales = $ 80,000
VAT = 16 %
The amount of VAT paid to the government is
= 16 % of $ 80,000
= 0.16 x $ 80,000
= $ 12800
The amount paid as VAT is $ 12800.
Find the area of the figure
Will
Give
Brainlist
Answer: 52x+4
Step-by-step explanation: Do 16(2x-1)+4(5x+5) and get 52x+4.
What is 2.3(x – 2) = 15
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\mathsf{2.3(x - 2) = 15}[/tex]
[tex]\mathsf{2.3(x) + 2.3(-2) = 15}[/tex]
[tex]\mathsf{2.3x - 4.6 = 15}[/tex]
[tex]\large\textsf{ADD 4.6 to BOTH SIDES}[/tex]
[tex]\mathsf{2.3x - 4.6 + 4.6 = 15 + 4.6}[/tex]
[tex]\large\textsf{CANCEL out: -4.6 + 4.6 because it gives the number 0}[/tex]
[tex]\large\textsf{KEEP: 15 + 4.6 because that helps solve find the x-value}[/tex]
[tex]\mathsf{15 + 4.6 = \boxed{\bf 19.6}}[/tex]
[tex]\large\textsf{NEW EQUATION: 2.3x = 19.6}[/tex]
[tex]\large\textsf{DIVIDE 2.3 to BOTH SIDES}[/tex]
[tex]\mathsf{\dfrac{2.3x}{2.3}=\dfrac{19.6}{2.3}}[/tex]
[tex]\large\textsf{CANCEL out: }\mathsf{\dfrac{2.3}{2.3}}\large\textsf{ because that gives you 1}[/tex]
[tex]\large\textsf{KEEP: }\mathsf{\dfrac{19.6}{2.3}}\large\textsf{ because that gives you the value of x}[/tex]
[tex]\mathsf{\dfrac{19.6}{2.3}= \boxed{\bf x}}[/tex]
[tex]\mathsf{\boxed{\bf x}=\dfrac{19.6}{2.3}}[/tex]
[tex]\boxed{\bf {x = 8.521739}}[/tex]
[tex]\boxed{\boxed{\large\textsf{Answer: \huge \bf x = 8.521739}}}\huge\checkmark[/tex]
[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:) }[/tex]
i need help like asap!!!!
Answer:
to do this lets first solve this so
5*5*5*5=625
5^-3=0.008
0.008^2=0.000064
0.000064*625=0.4
so all equations that are equal to 0.4 are right which is C
if cos A= 9\13 find csc A
Answer:
13[tex]\sqrt{22}[/tex] / 44
Step-by-step explanation:
cos A = 9/13
here adjacent = 9 and hypotenuse = 13 opposite = ?
using pythagoras theorem to find opposite
a^2 + b^2 = c^2
9^2 + b^2 = 13^2
81 + b^2 = 169
b^2 = 169 - 81
b^2 = 88
b = [tex]\sqrt{88}[/tex]
b = [tex]2\sqrt{22}[/tex]
therefore opposite = [tex]2\sqrt{22}[/tex]
cosec A = hypotenuse/opposite
= 13/[tex]2\sqrt{22}[/tex]
rationalizing the denominator
=13/ [tex]2\sqrt{22}[/tex] * [tex]2\sqrt{22}[/tex] / [tex]2\sqrt{22}[/tex]
=13 *[tex]2\sqrt{22}[/tex] /( [tex]2\sqrt{22}[/tex] )^2
=26 [tex]\sqrt{22}[/tex] / 4*22
=26 [tex]\sqrt{22}[/tex] / 88
=13[tex]\sqrt{22}[/tex] / 44
Answer:
[tex]cosec A = \frac{13}{\sqrt{88}}[/tex]
OR
[tex]cosec A = \frac{13 \sqrt{22}}{44}[/tex]
Step-by-step explanation:
Formulas used:
[tex]cos^2 A = 1 - sin^2 A\\\\cosec A = \frac{1}{sin A}[/tex]
Given :
[tex]cos A = \frac{9}{13}[/tex]
Find cosec A
[tex]sin ^2 A = 1 - cos^2 A[/tex]
[tex]= 1 - (\frac{9}{13})^2\\\\= 1 - \frac{81}{169}\\\\=\frac{169 - 81}{169}\\\\=\frac{88}{169}[/tex]
[tex]sin A = \sqrt{\frac{88}{169}} = \frac{\sqrt{88}}{13}[/tex]
Therefore,
[tex]cosec A = \frac{1}{sin A} = \frac{1}{ \frac{\sqrt{88}}{13}} = \frac{13}{ \sqrt{88}}[/tex]
OR In a simplified form :
[tex]cosec A = \frac{13}{\sqrt{88}} \times \frac{\sqrt{88}}{\sqrt{88}} = \frac {13 \times \sqrt{4 \times 22}}{88} = \frac{13 \times 2 \sqrt{22}} {88} = \frac{13 \sqrt{22}}{44}[/tex]
Keller performed the work below to express the polynomial in factored form:
r(x) = x4 – 8x2 – 9
r(x) = (x2 + 1)(x2 – 9)
(x) = (x + 1)(x – 1)(x + 3)(x – 3)
Explain the error he made and complete the factorization correctly.
Answer:
He made the following mistake, he assumed that polynomial [tex](x^{2}+1) = (x^{2}-1)[/tex], having for granted that [tex]x^{2}+1[/tex] has two real roots, instead of two complex roots.
Step-by-step explanation:
He made the following mistake, he assumed that polynomial [tex](x^{2}+1) = (x^{2}-1)[/tex], having for granted that [tex]x^{2}+1[/tex] has two real roots, instead of two complex roots. The true factorized form of the fourth grade polynomial is:
[tex]r(x) = (x^{2}+1)\cdot (x^{2}-9)[/tex]
[tex]r(x) = (x- i)\cdot (x+i)\cdot (x+3)\cdot (x-3)[/tex]
