The ____ contains app buttons that allow you to quickly run the File Explorer or Microsoft Edge apps.

Answer:

Following are the solution to the given question:

import java.util.Scanner;//import package

public class AscendingAndDescending//defining a class AscendingAndDescending  

{

   public static void main(String[] args) //main method

   {

       int n1,n2,n3,min,max,m;

       Scanner in = new Scanner(System.in);//creating Scanner class object

       System.out.print("Enter an integer: ");//print message

       n1 = in.nextInt();//input value

       System.out.print("And another: ");//print message

       n2 = in.nextInt();//input value

       System.out.print("And just one more: ");//print message

       n3 = in.nextInt();//input value

       min = n1; //use min variable that holds value

       max = n1; //use mix variable that holds value

       if (n2 > max) max = n2;//use if to compare value and hols value in max variable

       if (n3 > max) max = n3;//use if to compare value and hols value in max variable

       if (n2 < min) min = n2;//use if to compare value and hols value in min variable

       if (n3 < min) min = n3;//use if to compare value and hols value in min variable

       m = (n1 + n2 + n3) - (min + max);//defining m variable that arrange value

       System.out.println("Ascending: " + min + " " + m + " " + max);//print Ascending order value

       System.out.println("Descending: " + max + " " + m + " " + min);//print Descending order value

   }

}

Output:

Enter an integer: 8

And another: 9

And just one more: 7

Ascending: 7 8 9

Descending: 9 8 7

Explanation:

In this program inside the main method three integer variable "n1,n2, and n3" is declared that inputs value from the user end and also defines three variable "min, max, and m" that uses the conditional statement that checks inputs value and assigns value according to the ascending and descending order and prints its values.

Answer:

10

Explanation:

An enqueue operation is a function that adds an element(value) to a queue array. A dequeue operations removes an element from a queue array. Queue arrays follow a first-in-first-out approach, so elements that are first stored in the queue are removed/accessed first(enqueue operations add elements at the rear of the queue array).

The following operations leave 10 elements in the queue of array size 12 after its done:

10 enqueue operations= adds 10 elements

5 dequeue operations= removes 5 elements( 5 elements left in queue)

6 enqueue operations= adds 6 elements(11 elements in queue)

10 dequeue operations= removes 10 elements(1 element left in queue)

8 enqueue operations= adds 8 elements(9 elements in queue)

2 dequeue operations= removes 2 elements(7 elements left in queue)

3 enqueue operations= adds 3 elements(10 elements in queue)

Therefore there are 10 elements in the queue after enqueue and dequeue operations.

Solution :

ENTITY 1               CARDINALITY RATIO                                     ENTITY 2

1. Student                        1 to many                                     Social security card

                      A student may have more than one          

                     social security card (legally with the

                      same unique social security number),

                     and every social security number belongs

                   to a unique.

2. Student                   Many to Many                                    Teacher

                    Generally students are taught by many

                    teachers and a teacher teaches many students.

3.ClassRoom               Many to Many                                   Wall

                      Do not forget that the wall is usually

                      shared by adjacent rooms.

4. Country                 1 to 1                                             Current President

                       Assuming a normal country under normal

                       circumstances having one president at a

                      time.

5. Course               Many to Many                               TextBook

                        A course may have many textbooks and

                       text book may be prescribed for different

                      courses.

6. Item                             Many to Many                           Order

                        Assuming the same item can appear

                         in different orders.

7. Student                       Many to Many                          Class

                        One student may take several classes.

                        Every class usually has several students.

8. Class                                 Many to 1                             Instructor

                       Assuming that every class has a unique

                        instructor. In case instructors were allowed

                        to team teach, this will be many-many.

9. Instructor                  1 to 1                                             Office

                       Assuming every instructor has only one

                      office and it is not shared. In case of offices

                     shared by 2 instructors, the relationship

                    will be 2-1. Conversely, if any instructor has a joint

                    appointment and offices in both departments,

                    then the relationship will be 1-2. In a very general

                  case, it may be many-many.

10. E-bay Auction item             1-Many                           E-bay bid

                        1 item has many bids and a bid is unique

                        to an item.

Answer:

Answer:

A triangle on the Clock input.

Answer:

caca

Explanation:

Answer:

A class may be a structured diagram that describes the structure of the system.  

It consists of sophistication name, attributes, methods, and responsibilities.  

A mailbox and an email message have certain attributes like, compose, reply, draft, inbox, etc.

Software architecture affects:

Performance, Robustness, Distributability, Maintainability.  

Explanation:

See attachment for the Model object classes which may be utilized in the system implementation to represent a mailbox and an email message.

Advantages:

Large-scale reuse Software architecture is vital because it affects the performance, robustness, distributability, and maintainability of a system.

Individual components implement the functional system requirements, but the dominant influence on the non-functional system characteristics is that the system's architecture.

Three advantages of System architecture:

• Stakeholder communication: The architecture may be a high-level presentation of the system which will be used as attention for discussion by a variety of various stakeholders.

• System analysis: making the system architecture explicit at an early stage within the system development requires some analysis.

• Large-scale reuse:

An architectural model may be a compact, manageable description of how a system is organized and the way the components interoperate.

The system architecture is usually an equivalent for systems with similar requirements then can support large-scale software reuse..

Answer:

data is the raw fact about its process

Explanation:

input = process= output

data is the raw fact which gonna keeps in files and folders. as we know that data is a information keep in our device that we use .

Answer:

Data and process modelling involves three main tools: data flow diagrams, a data dictionary, and process descriptions. Describe data and process tools. Diagrams showing how data is processed, transformed, and stored in an information system. It does not show program logic or processing steps.

Answer:

All of these.

PLZ MARK ME BRAINLIEST.

Answer:

A.

thanks later baby HAHAHAHAHAA

Answer:

line of code :

newString=myString+myString.charAt(0)+myString.charAt(myString.length()-1);

Explanation:

In Java, the + is used for concatenation

method

charAt() will return the character from the given index from string

myString.charAt(0) will return E

myString.charAt(myString.length()-1)

Answer:

15

Inside the type declaration, you specify the maximum length the entry can be. For branch, it would be 15.

I can't seem to type the full "vc(15)" phrase because brainly won't let me.

Answer:

Explanation:

The following code is written in Python. It is a function that takes two string parameters and compares the lengths of both strings. If the string in variable s1 is greater then the function returns True, otherwise the function returns False. A test case has been provided and the output can be seen in the attached image below.

def compareStrings(s1, s2):

   if len(s1) > len(s2):

       return True

   else:

       return False

print(compareStrings("Brainly", "Competition"))

Answer:-

CODE:

#include <iostream>

#include<cmath>

using namespace std;

float calcBaseArea(float a);

float calcSideArea(float s,float l);

void prntSprfArea(float base_area,float side_area);

int main()

{

float h;

float a;

float base_area

float side_area;

cout<<"Enter the side length of the base of the square pyramid in feet : ";

cin>>a;

cout<<"Enter the height of the square pyramid in feet : ";

cin>>h;

base_area=calcBaseArea(a);

side_area=calcSideArea(a,h);

cout<<"Base surface area of the square pyramid is "<<base_area<<" square feet. "<<endl;

cout<<"Side area of the square pyramid is "<<side_area<<" square feet."<<endl;

prntSprfArea(base_area,side_area);

return 0;

}

float calcBaseArea(float a)

{

return pow(a,2);

}

float calcSideArea(float s,float l)

{

float area=(s*l)/2;

return 4*area;

}

void prntSprfArea(float base_area,float side_area)

{

cout<<"Total surface area of the pyramid is "<<base_area+side_area<<" square feet.";

OUTPUT:

Answer:

Kindly find the code snippet in the explanation written in kotlin language

Explanation:

fun main(args: Array<String>) {

   var num:Int

   println("Enter a num")

    num= Integer.valueOf(readLine())

   for(i in num downTo 1){

       if(i==num){

           print("Ready!")

           print(" ")

       }

       print(i)

       print(" ")

       if(i==1){

           print(" ")

           print("Go!")

       }

   }

}

This function too can also work

fun numTo(num:Int){

   if (num>0) for(i in num downTo 1) print("$i ")

   println("Go!")

Answer: Availability

Explanation:

Answer:

All flags are On ( c, z , N  )

Explanation:

Given data:

4-bit operation

Assuming 2's complement representation

Determine status flags that are on after performing 1010+0110

    1   1

    1  0   1  0

    0  1   1  0

  1  0 0 0 0

we will carry bit = 1 over

hence C = 1

given that: carry in = carry out there will be zero ( 0 ) overflow

hence V = 0

also Z = 1      

But the most significant bit is  N = 1

Answer:

The program in Java is as follows:

import java.util.*;

public class Main {

public static void removeDuplicate(ArrayList<Integer> list){

 ArrayList<Integer> newList = new ArrayList<Integer>();

 for (int num : list) {

  if (!newList.contains(num)) {

   newList.add(num);  }  }

 for (int num : newList) {

     System.out.print(num+" ");  } }

public static void main(String args[]){

 Scanner input = new Scanner(System.in);

 ArrayList<Integer> list = new ArrayList<Integer>();

 System.out.print("Enter ten integers: ");

 for(int i = 0; i<10;i++){

     list.add(input.nextInt());  }

 System.out.print("The distinct integers are: ");

 removeDuplicate(list);

}}

Explanation:

This defines the removeDuplicate function

public static void removeDuplicate(ArrayList<Integer> list){

This creates a new array list

 ArrayList<Integer> newList = new ArrayList<Integer>();

This iterates through the original list

 for (int num : list) {

This checks if the new list contains an item of the original list

  if (!newList.contains(num)) {

If no, the item is added to the new list

   newList.add(num);  }  }

This iterates through the new list

 for (int num : newList) {

This prints every element of the new list (At this point, the duplicates have been removed)

     System.out.print(num+" ");  } }

The main (i.e. test case begins here)

public static void main(String args[]){

 Scanner input = new Scanner(System.in);

This declares the array list

 ArrayList<Integer> list = new ArrayList<Integer>();

This prompts the user for ten integers

 System.out.print("Enter ten integers: ");

The following loop gets input for the array list

 for(int i = 0; i<10;i++){

     list.add(input.nextInt());  }

This prints the output header

 System.out.print("The distinct integers are: ");

This calls the function to remove the duplicates

 removeDuplicate(list);

}}

Answer:

Explanation:

The code provided worked for the most part, it had some gramatical errors in when printing out the information as well as repeated values. I fixed and reorganized the printed information so that it is well formatted. The only thing that was missing from the code was the input validation to make sure that no negative values were passed. I added this within the getMonths() method so that it repeats the question until the user inputs a valid value. The program was tested and the output can be seen in the attached image below.

import java.io.*;

import java.util.*;

class Rainfall

{

   Scanner in = new Scanner(System.in);

   private int month = 12;

   private double total = 0;

   private double average;

   private double standard_deviation;

   private double largest;

   private double smallest;

   private double months[];

   public Rainfall()

   {

       months = new double[12];

   }

   public void setMonths()

   {

       for(int n=1; n <= month; n++)

       {

           int answer = 0;

           while (true) {

               System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );

               answer = in.nextInt();

               if (answer > 0) {

                   months[n-1] = answer;

                   break;

               }

           }

       }

   }

   public void getTotal()

   {

       total = 0;

       for(int i = 0; i < 12; i++)

       {

           total = total + months[i];

       }

       System.out.println("The total rainfall for the year is " + total);

   }

   public void getAverage()

   {

       average = total/12;

       System.out.println("The average monthly rainfall is " + average);

   }

   public void getLargest()

   {

       double largest = 0;

       int largeind = 0;

       for(int i = 0; i < 12; i++)

       {

           if (months[i] > largest)

           {

               largest = months[i];

               largeind = i;

           }

       }

       System.out.println("The largest amount of rainfall was " + largest +

               " inches in month " + (largeind + 1));

   }

   public void getSmallest()

   {

       double smallest = Double.MAX_VALUE;

       int smallind = 0;

       for(int n = 0; n < month; n++)

       {

           if (months[n] < smallest)

           {

               smallest = months[n];

               smallind = n;

           }

       }

       System.out.println("The smallest amount of rainfall was " + smallest +

               " inches in month " + (smallind + 1));

   }

   public static void main(String[] args)

   {

       Rainfall r = new Rainfall();

       r.setMonths();

       r.getTotal();

       r.getSmallest();

       r.getLargest();

       r.getAverage();

   }

}

Answer:

Explanation:

The code provided had many errors. I fixed the errors and changed the userAgeCheck function as requested. Checking the age of that the user has passed as an input and changing the variables as needed depending on the age. The background color that was changed was for the form field as the question was not very specific on which field needed to be changed. The piece of the code that was created can be seen in the attached image below.

var validColor = "LightGreen";

var invalidColor = "Orange";

var userAgeInput = document.getElementById("userAge");

var formWidget = document.getElementById("userForm");

var userAgeValid = false;

function userAgeCheck(event) {

   if ((userAgeInput >= 25) && (userAgeInput <= 35)) {

       document.getElementById("userForm").style.backgroundColor = validColor;

       userAgeValid = true;

   } else {

       document.getElementById("userForm").style.backgroundColor = invalidColor;

       userAgeValid = false;

   }

};

function formCheck(event) {};

if (!userAgeValid) {

   userAgeInput.addEventListener("input", userAgeCheck);

   formWidget.addEventListener('submit', formCheck);  

   event.preventDefault();

}

Answer:

Explanation:

#include <stdlib.h>

#include <stdio.h>

#include <string.h>

#define MAX 1024

int total = 0 ;

int n1, n2;

char s1, s2;

FILE fp;

int readf(FILE fp)

{

 if((fp=fopen("strings.txt", "r"))==NULL) {

   printf("ERROR: can’t open string.txt!\n");

   return 0;

 }

 s1=(char)malloc(sizeof(char)MAX);

 if(s1==NULL) {

   printf("ERROR: Out of memory!\n");

   return 1;

 }

 s2=(char)malloc(sizeof(char)MAX);

 if(s1==NULL) {

   printf("ERROR: Out of memory!\n");

   return 1;

 }

 /* read s1 s2 from the file */

 s1=fgets(s1, MAX, fp);

 s2=fgets(s2, MAX, fp);

 n1=strlen(s1); /* length of s1 */

 n2=strlen(s2)-1; /* length of s2 */

 if(s1==NULL || s2==NULL || n1<n2) /* when error exit */

   return 1;

}

int num_substring(void)

{

 int i, j, k;

 int count;

 for(i=0; i<=(n1-n2); i++) {

   count=0;

   for(j=i, k=0; k<n2; j++, k++){ /* search for the next string of size of n2 */

   if((s1+j)!=(s2+k)) {

     break;

   }

   else

     count++;

   if(count==n2)

     total++; /* find a substring in this step */

   }

 }

 return total;

}

int main(int argc, char argv[])

{

 int count;

 readf(fp);

 count=num_substring();

 printf("The number of substrings is: %d\n", count);

 return 1;

}

Answer:

E). User education and training.

Explanation:

In the context of network security, the most significant aspect of ensuring security from workstation cyberattacks would be 'education, as well as, training of the users.' If the employee users are educated well regarding the probable threats and attacks along with the necessary safety measures to be adopted and trained adequately to use the system appropriately so that the sensitive information cannot be leaked while working on the workstation and no networks could be compromised. Thus, option E is the correct answer.

Answer:

Hence the answer is top and peek.

Explanation:

In a stack, we insert and delete an item from the top of the stack. So we use variables top, peek to stay track of the position.

The insertion operation is understood as push and deletion operation is understood as entering stack.

Hence the answer is top and peek.

Answer:

a. A workstation with a 3.9 GHz quad-core processor, 16 gigabytes of RAM, and a 24" monitor.

Explanation:

From the description, Jane needs to be able to multitask and run various programs at the same time in order to be efficient. Also since she wants to play the latest video games she will need high end hardware. Therefore, from the available options the best one would be a workstation with a 3.9 GHz quad-core processor, 16 gigabytes of RAM, and a 24" monitor. This has a very fast cpu with 4 cores to process various threads at the same time. It also has 16GB of memory to be able to multitask without problems and a 24" monitor. From the available options this is the best choice.

Answer:

The program is as follows:

[tex]mult\_table = [[1, 2, 3], [2, 4, 6], [3, 6, 9]][/tex]

count = 1

for row in mult_table:

   for item in row:

       if count < len(row):

           count+=1

           print(item,end="|")

       else:

           print(item)

   count = 1

Explanation:

This initializes the 2D list

[tex]mult\_table = [[1, 2, 3], [2, 4, 6], [3, 6, 9]][/tex]

This initializes the count of print-outs to 1

count = 1

This iterates through each rows

for row in mult_table:

This iterates through each element of the rows

   for item in row:

If the number of print-outs is less than the number of rows

       if count < len(row):

This prints the row element followed by |; then count is incremented by 1

           count+=1

           print(item,end="|")

If otherwise

       else:

This prints the row element only

           print(item)

This resets count to 1, after printing each row

   count = 1

To delete the whitespace, you have to print each element as:            print(item,end="|")

See that there is no space after "/"

Answer:

count = 1

for row in mult_table:

  for item in row:

      if count < len(row):

          count+=1

          print(item,end=" | ")

      else:

          print(item)

  count = 1

Explanation: Other answers didnt have the spacing correct

Answer:

Following are the responses to these questions:

Explanation:

It employs keywords to autonomously do work tasks. Users can type numbers directly into the formulas or use the following formulae, so any data the cells referenced provide would be used in the form.

For instance, this leadership involves accounting, and Excel is concerned with organizing and organizing numerical data. In this Equation, I can discover all its information in the data. This idea is simple me count the number many cells containing a number, and also the number of integers. It counts integers in any sorted number as well. As both financial analysts, it is helpful for the analysis of the data if we want to maintain the same number of neurons.

Answer:

LAB means laboratory

IEEE means institute of electrical and electronic engineer

Answer:

This can be done by a greedy solution. The algorithm does the following:  

Put song 1 on CD1.

For song 1, if there's space left on the present CD, then put the song on the present CD. If not, use a replacement CD.

If there are not any CDs left, output "no solution".

Explanation:  

The main thing is prove the correctness, do that by the "greedy stays ahead argument". For the primary song, the greedy solution is perfect trivially.  

Now, let the optimal solution match the greedy solution upto song i. Then, if the present CD has space and optimal solution puts song (i+1) on an equivalent CD, then the greedy and optimal match, hence greedy is not any worse than the optimal.Else, optimal puts song (i + 1) on subsequent CD. Consider an answer during which only song (i + 1) is moved to the present CD and zip else is modified. Clearly this is often another valid solution and no worse than the optimal, hence greedy is not any worse than the optimal solution during this case either. This proves the correctness of the algorithm. As for every song, there are constantly many operations to try to do, the complexity is O(n).

Answer:

see the code snippet below writing in Kotlin Language

Explanation:

fun main(args: Array<String>) {

   sumOfNumbers()

}

fun sumOfNumbers(): Int{

   var firstNum:Int

   var secondNum:Int

   println("Enter the value of first +ve Number")

   firstNum= Integer.valueOf(readLine())

   println("Enter the value of second +ve Number")

   secondNum= Integer.valueOf(readLine())

   var sum:Int= firstNum+secondNum

  println("The sum of $firstNum and $secondNum is $sum")

   return sum

}