Answer:
22/7 × [tex]10^{2}[/tex]
Explanation:
The area of a circle can be found out using π[tex]r^{2}[/tex]. Since r is the radius so if they multiply, they will give you an area of a square then multiply by 22/7 since it is a circle.
The surface area of the Tambourine at the given diameter of 10 inches is determined as 78.54 square inches.
Area of the TambourineA Tambourine has circular shape, and the area of the Tambourine can be determined by applying formula for area of a circle as shown below;
A = πr²
where;
r is the radius of the circleRadius of the Tambouriner = ¹/₂D
r = ¹/₂ x 10 in
r = 5 in
A = π(5)²
A = 25π in²
A = 78.54 in²
Thus, the surface area of the Tambourine at the given diameter of 10 inches is determined as 78.54 square inches.
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state the purpose of Watson and crick DNA structure experiment
Answer:
In Watson and Crick's model, the two strands of the DNA double helix are held together by hydrogen bonds between nitrogenous bases on opposite strands. Each pair of bases lies flat, forming a "rung" on the ladder of the DNA molecule.
Explanation:
hope it helps ya
Which commercial technology commonly uses plasmas?
a radio
a race car
a television
a microwave oven
Answer:
A television is commercial technology commonly uses plasmas.2KClO3 (s)⇄2KCl (s)+ 3O2 (aq) equilibrium constant
Answer: The equilibrium constant for the given chemical reaction is [tex][O_2]^3[/tex]
Explanation:
The equilibrium constant is defined as the ratio of the concentration of the products to the concentration of reactants each raised to the power of their stoichiometric coefficients.
The concentration of all the solids and liquids are considered to be 1 in the expression of equilibrium constant
For the given chemical equation:
[tex]2KClO_3(s)\rightleftharpoons 2KCl(s)+3O_2(aq)[/tex]
The expression of equilibrium constant follows:
[tex]K_{eq}=[O_2]^3[/tex]
Hence, the equilibrium constant for the given chemical reaction is [tex][O_2]^3[/tex]
An aqueous sucrose (C12H22O11) solution must be created for an experiment. If 100.00 mL of 0.200 M solution is needed, what amount of sucrose (in grams) must be weighed out
Answer:
6.85 g
Explanation:
Step 1: Given data
Molar concentration of the solution: 0.200 M (0.200 mol/L)Volume of the solution: 100.00 mL (0.10000 L)Step 2: Calculate the moles of sucrose (solute) required
Molarity is equal to the moles of solute divided by the liters of solution.
M = moles of solute / liters of solution
moles of solute = M × liters of solution
moles of solute = 0.200 mol/L × 0.10000 L = 0.0200 mol
Step 3: Calculate the mass corresponding to 0.0200 moles of sucrose
The molar mass of sucrose is 342.3 g/mol.
0.0200 mol × 342.3 g/mol = 6.85 g
The amount of sucrose (in grams) must be weighed out for the given reaction is 6.846g.
How we calculate mass from moles?Mass of any substance will be calculated by using the moles as:
n = W/M, where
W = required mass
M = molar mass
Given that, molarity of sucrose = 0.2 M
Volume of solution = 100mL = 0.1 L
Relation between moles and molarity is represented as:
M = n/V
On putting values on the above equation we get,
n = (0.2)(0.1) = 0.02 moles
We know that molar mass of sucrose (C₁₂H₂₂O₁₁) = 342.3 g/mole
Now we calculate the required mass by putting values on the first equation as:
W = (0.02)(342.3) = 6.846g
Hence, the required mass of sucrose is 6.846g.
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If a solid line represents a covalent bond and a dotted line represents intermolecular attraction, which of the choices shows a hydrogen bond?
1. H−H
2. H4C⋯H−F
3. H3N⋯H−O−H
4. H2O⋯H−CH3
Answer:
3
Explanation:
Hydrogen bonding occurs between molecules in which hydrogen is bonded to a highly electronegative atom such as nitrogen, oxygen, chlorine, etc.
In option 3, the two compounds are H3N and H2O. In both molecules, hydrogen is directly attached to highly electro negative atoms(nitrogen and oxygen respectively). Hence, it is only in option 3 that we observe hydrogen bonding.
Its Acutally A Because if you use the type he used its not even the question
Explination
Im RIght
How many moles of aluminum oxide are produced according to the reaction below given that you start with 40.0 grams of Al and 19.0 grams of O2?
Reaction: 4Al + 3O2 --> 2Al2O3
A. 0.185
B. 0.741
C. 5.00
D. 0.396
From the stoichiometry of the reaction, 0.74 moles of aluminium oxide is produced.
The equation of the reaction is;
4Al + 3O2 --> 2Al2O3
Number of moles of Al = 40.0/27 g/mol = 1.48 moles
Number of moles of O2 = 19.0 g/32 g/mol = 0.59 moles
Now;
4 mols of Al reacts with 3 moles of O2
1.48 moles of Al reacts with 1.48 moles × 3 moles/4 mols
= 1.11 moles
We can see that O2 is the reactant in excess.
Hence;
4 moles of Al produces 2 moles of aluminium oxide
1.48 moles of Al produces 1.48 moles × 2 moles/4 moles = 0.74 moles of aluminium oxide
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To what Celsius temperature does 750. mL of gas originally at −12°C need to be heated to bring the volume to 2.10 L?
will mark brainliest
Which characteristics are most likely found in mammals living in a tundra ecosystem
Answer:
Tundra and desert ecosystem are different especially when talking about their climate. Tundra is situated in northern latitude and is very cold having a negative 34 degrees and has a permafrost while desert is often situated closer to equator and thus have hot climate yet they have a similar characteristic when it comes to vegetation or the plants as both experience a water scarcity thus plants are already adapted to live in water-barren environment.
Explanation:
How is a bacterium cell different from a human cell?
Answer:
Human cells are eukaryotic which means they are more complicated, bacteria cells are prokaryotic which means they are simpler
Explanation:
Hope this helps
Alkenes undergo an addition reaction with borane in tetrahydrofuran (THF). For the reaction below: Write a mechanism for the reaction using curved arrows to show electron reorganization. b. write a mechanism
Answer:
See explanation and image attached
Explanation:
Alkenes react with borane (BH3) as shown in the image attached. Borane is a good electrophile since it is an electron deficient compound.
It can attack the electron rich pi bond. The attack of borane on the pi bond occurs as shown and leads to an addition reaction. Hydrogen and BH2^- are added across the double bond as shown.
The product of this reaction is shown in the image attached.
A molecule of composition is replicated in a solution containing unlabeled (not radioactive) GTP, CTP, and TTP plus adenine nucleoside triphosphate with all its phosphorus atoms in the form of the radioactive isotope 32P. Will both daughter molecules be radioactive
Answer:
Please find the complete question in the attached file.
Explanation:
It would only be radioactive if the DNA molecule that employed the poly-T rand as templates. Its other molecule of the daughter would not have been radioactive as it did not need dATP for its replication. While each strand of the second molecule includes t, simultaneous reproduction dATP from both daughter molecules is needed so that each of those is radioactive.
Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical equation for it. Be sure your chemical equation is balanced and has physical state symbols. situation chemical reaction
The question is incomplete, the complete question is;
Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical equation for it. Be sure your chemical equation is balanced and has physical state symbols. situation chemical reaction? chemical equation A strip of solid lead metal is put into a beaker of 0.043M Fe(NO3)2 solution. yes no A strip of solid iron metal is put into a beaker of 0.044M Pb(NO3)2 solution.
Answer:
No
Yes
Explanation:
A single replacement reaction occurs when a metal that is higher in the electrochemical series is placed in a solution of the salt of a metal which is lower than it in the electrochemical series.
For instance, when a strip of solid iron metal is put into a beaker of 0.044M Pb(NO3)2 solution, a reaction occurs as follows;
Fe(s) + Pb(NO3)2(aq) ---------> Fe(NO3)2(aq) + Pb(s)
However, when a strip of solid lead metal is put into a beaker of 0.043M Fe(NO3)2 solution no reaction occurs because lead is lower than iron in the electrochemical series hence it can not displace iron from an aqueous solution of its salt.
In the clinical laboratory, testing to identify specific porphyrins is performed using Group of answer choices Fluorometric emission scanning Chemical derivatization and spectrophotometry Liquid chromatography with fluorescent detection Thin layer chromatography
Answer:
Fluorometric emission scanning.
Explanation:
Fluorometric emission scanning is used to detect the presence of porphyrins. There are various types of porphyrins and they can be tested in a lab with either, urine or blood sample testing.
is it a physical or chemical change when a candle is lit
Calculate the mass of hydrogen formed when 26.98 g of aluminum reacts with excess hydrochloric acid according to the following balanced chemical equation: 2 Al + 6 HCl → 2 AlCl3 + 3 H2
Answer: The mass of hydrogen formed when 26.98 g of aluminum reacts with excess hydrochloric acid according to the given balanced equation is 3.03 g.
Explanation:
The given balanced reaction equation is as follows.
[tex]2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}[/tex]
Here, the mole ration of Al and hydrogen produced is 2 : 3
As mass of aluminum is given as 26.98 g. So, moles of aluminum (molar mass = 26.98 g/mol) is as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{26.98 g}{26.98 g/mol}\\= 1 mol[/tex]
So, when 1 mole of Al reacted then 1.5 moles of hydrogen is produced as per the given mole ratio.
Therefore, mass of hydrogen formed is calculated as follows.
[tex]mass = moles \times molar mass\\= 1.5 mol \times 2.02 g/mol\\= 3.03 g[/tex]
Thus, we can conclude that the mass of hydrogen formed when 26.98 g of aluminum reacts with excess hydrochloric acid according to the given balanced equation is 3.03 g.
As a result of the particles in a gas being in constant motion, gas has a _______.
variable volume
variable Pressure
variable Shape
variable mass
Answer:
i think it's variable pressure
if not soo advance sorry :)
What is the
of a 750 milliliters solution containing 54.0 grams of KBr?
Answer:
0.605 M
Explanation:
What is the molarity of a 750 milliliters solution containing 54.0 grams of KBr?
Step 1: Given data
Mass of KBr (solute): 54.0 gVolume of solution: 750 mL (0.750 L)Step 2: Calculate the moles corresponding to 54.0 g of KBr
The molar mass of KBr is 119.00 g/mol.
54.0 g × 1 mol/119.00 g = 0.454 mol
Step 3: Calculate the molarity of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.454 mol / 0.750 L = 0.605 M
12 + NaF --> Nal + F2 What is the coefficient of Nal when this equation is
balanced? *
Answer:
Explanation:
NaL
Difluorine - F2
Molar Mass Bond Polarity F₂ Fluorine Gas Fluorine
Products
Sodium Fluoride - NaF
Molar Mass Bond Polarity Oxidation State Floridine Sodium Monofluoride Naf
L2
Identify the compound with the lowest dipole moment. Identify the compound with the lowest dipole moment. CH3CH2CH3 CH3OCH3 CH3CHO CH3OH CH3CN
Answer:
CH3CH2CH3
Explanation:
Dipole moment is the measure of the polarity of a chemical bond. It is the extent of charge separation in a molecule.
Dipole moment is the product of the magnitude of charge and the distance separating the charges from each other.
The molecule having the lowest dipole moment among the options is the molecule that has the least polarity. The least polar molecule among the options is CH3CH2CH3, it has no polar bonds in its structure.
We have that for the Question "Identify the compound with the lowest dipole moment. Identify the compound with the lowest dipole moment. CH3CH2CH3 CH3OCH3 CH3CHO CH3OH CH3CN "
it can be said that
[tex]CH_3CH_2CH_3 have the lowest dipole moment[/tex]From the question we are given
CH3CH2CH3
CH3OCH3
CH3CHO
CH3OH
CH3CN
Generally alkanes have the lowest dipole moment, they have C-H bond which are non polar.
Therefore,
[tex]CH_3CH_2CH_3[/tex] have the lowest dipole moment
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What is the definition of outer layer? *
Answer:
1 being or located on the outside; external
2 further from the middle or central part
Explanation:
A bottle containing a reagent was weighed to show a mass of 25.3658 g. Some material was carefully transferred to a reaction flask, and the bottle reweighed to show a mass of 22.1287 g. What mass of the material was transferred to the flask
Answer:
3.2371 g
Explanation:
Step 1: Given data
Initial mass of the bottle and the reagent: 25.3658 gFinal mass of the bottle and the reagent: 22.1287 gStep 2: Calculate the mass of the material was transferred to the flask
Since the bottle is unaltered, the mass of the material transferred to the flask is equal to the difference between the initial mass of the system and the final mass of the system.
m = 25.3658 g - 22.1287 g = 3.2371 g
describe what it would be like to be an atom
Explanation:
An atom consists of two regions. The first is the tiny atomic nucleus, which is in the center of the atom and contains positively charged particles called protons and neutral, uncharged, particles called neutrons. ... Most atoms contain all three of these types of subatomic particles—protons, electrons, and neutrons.
What is the wavelength of light that has a frequency of 3.7 x 1014 Hz? Show all work!!!
Answer:
Explanation:
Speed of light = Frequency * Wavelength
Speed of light is 3*10^8 m/s
Wavelength = Speed / Frequency = 3*10^8 / 3.7*10^14
= 8.11*10^(-7) m
= 811 nanometer
The wavelength of light will be
What is wavelength?The wavelength of such a periodic wave would be the interval in which the shape of the wave repeats.
Calculation of wavelength of light
It is given that,
frequency = 3.7 x [tex]10^{14}[/tex] Hz
Speed of light = 3 × [tex]10^{8}[/tex] m/s
frequency × wavelength = speed of light.
wavelength = speed of light / frequency
wavelength = 3 × [tex]10^{8}[/tex] m/s / 3.7 x [tex]10^{14}[/tex] Hz
wavelength = 0.81 × [tex]10^{-7}[/tex] m
wavelength = 8.1 × [tex]10^{-7}[/tex]
Therefore, wavelength of light will be 8.1 × [tex]10^{-7}[/tex].
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A voltaic cell consists of a standard hydrogen electrode and a second half-cell in which a magnesium electrode is immersed in a 1.00 M solution of Mg2+ ions. Calculate Ecell given that the standard reduction potential for the magnesium half-reaction is -2.37 V.
Answer:
The correct answer is "+2.37 V".
Explanation:
Given that,
Concentration of [tex]Mg^{2+}[/tex]
= 1.00 M
[tex]E^0 \ Mg^{2+}/Mg[/tex],
= -2.37 V
[tex]E^0 \ \mu^+/H_2[/tex],
= 0.00V
When S.H.E as well as anode act as cathode, then
⇒ [tex]E^0 cell=E^cathode-E^0 anode[/tex]
By putting the values, we get
⇒ [tex]=0.00V-(-2.37 V)[/tex]
⇒ [tex]=+2.37 \ V[/tex]
Hydrogen iodide is not produced by the same method as for hydrogen chloride.why??
Answer:
Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...
Using an ionic chloride and Phosphoric acid
H3PO4 + NaCl ==> HCl + NaH2PO4
H3PO4 + NaI ==> HI + NaH2PO4
H2SO4 + NaCl ==> HCl + NaHSO4
This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.
The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.
2I-² === I2 + 2e-
Explanation:
When sugar is added to a sugar solution, the sugar dissolves. Which term
describes the original sugar solution?
A. Saturated
B. Unsaturated
C. Supersaturated
D. Pseudosaturated
SUBMIT
Answer:
the answer is b,.........
Answer:
Unsaturated
Explanation:
Salt water contains n sodium ions (NA ) per cubic meter and n chloride ions (Cl-) per cubic meter. A battery is connected to metal rods that dip into a narrow pipe full of salt water. The cross-sectional area of the pipe is A:
Answer: hello your question is incomplete below is the complete question
Salt water contains n sodium ions (Na+) per cubic meter and n chloride ions (Cl−) per cubic meter. A battery is connected to metal rods that dip into a narrow pipe full of salt water. The cross sectional area of the pipe is A. The magnitude of the drift velocity of the sodium ions is VNa and the magnitude of the drift velocity of the chloride ions is VCl.
What is the magnitude of the ammeter reading ?
answer :
| I | = neAVₙₐ + neAV (Cl-)
Explanation:
Given that there are N sodium ions
Determine the Magnitude of the ammeter reading
| I | = current due to sodium ions + current due to (Cl-) ions
= neAVₙₐ + neAV (Cl-)
Look at picture please
Answer:
Keep temperature constant and increase the pressure of the reaction. The rate of reaction increases.
Explanation:
First of all, the question is asking us to design an experiment to investigate the effect of pressure on the rate of reaction hence the pressure can not be held constant since it is the variable under investigation. This eliminates the first option.
Secondly, increasing the pressure of the reaction means that particles of the gas collide more frequently leading to a greater number of effective collisions and a consequent increase in the rate of reaction according to the collision theory.
Hence the answer above.
How many grams of Al2O3 is extracted from 250. g of FeO?
Answer:
[tex]m_{Al_2O_3}=118.27gAl_2O_3[/tex]
Explanation:
Hello there!
In this case, if we consider the following chemical reaction, whereby Al2O3 is produced from Al and FeO:
[tex]3FeO+2Al\rightarrow 3Fe+Al_2O_3[/tex]
Thus, since there is 3:1 mole ratio of FeO to Al2O3, it turns out feasible for us to use their molar masses, 71.844 g/mol and 101.96 g/mol respectively, to obtain the grams of the latter as follows:
[tex]m_{Al_2O_3}=250.gFeO*\frac{1molFeO}{71.844gFeO}*\frac{1molAl_2O_3}{3molFeO} *\frac{101.96gAl_2O_3}{1molAl_2O_3}\\\\m_{Al_2O_3}=118.27gAl_2O_3[/tex]
Regards!
If something is not an acid or a base what is it
Answer:
neutral one with ph equal to 7
