the distance between any two bodies is 10 M and the gravitational force between them is 3.2×10-⁹m. if the mass of one object is 40 kg, calculate the mass of another body. (And:119.9 kg)​

Answers

Answer 1

Answer:

0.8 x 10^-9 kg

Explanation:

Given,

Distance ( R ) = 10 m

Force ( F ) = 3.2 x 10^-9 N

Mass ( m1 ) = 40 kg

To find : Mass ( m2 ) = ?

Formula : -

F = m1.m2 / R^2

m2 = FR^2 / m1

= 3.2 x 10^-9 x 10 / 40

= 3.2 x 10^-9 / 4

= ( 3.2 / 4 ) x 10^-9

m2 = 0.8 x 10^-9 kg


Related Questions

HELP ASAP
A. 1.09 A
B. 1.20 A
C.0.910 A
D. 0.830 A

Answers

Answer:

The answer should be: 1.20 A

Explanation:

Is a nanoliter greater then one liter?

Answers

No, a nanoliter is one billionth of one liter

You are trying to hold your 550 g physics books with your hand against a vertical wall. Using a force sensor you know that the force you are applying is 10.0 N. Below the book on the floor you have placed a motion sensor. The position time graph for the book is given. Find the coefficient of kinetic friction.

Answers

The book's position is changing linearly with time, so its velocity is constant. This means that the net force acting on the book in the direction parallel to the surface is

F = 10.0 N - n = 0

where n is the magnitude of the normal force on the book due to the wall, and the net force perpedicular to the surface is

F = f - (0.550 kg) g = 0

where f is the mag. of kinetic friction, and f = µn where µ is the coefficient of kinetic friction.

Then

n = 10.0 N

• f = (0.550 kg) g = 5.39 N

• 5.39 N = µ (10.0 N)

==>   µ = 0.539

Answer:

Above answer

Explanation:

The book's position is changing linearly with time, so its velocity is constant. This means that the net force acting on the book in the direction parallel to the surface is

∑ F = 10.0 N - n = 0

where n is the magnitude of the normal force on the book due to the wall, and the net force perpedicular to the surface is

∑ F = f - (0.550 kg) g = 0

where f is the mag. of kinetic friction, and f = µn where µ is the coefficient of kinetic friction.

Then

• n = 10.0 N

• f = (0.550 kg) g = 5.39 N

• 5.39 N = µ (10.0 N)

==>   µ = 0.539

A 25.0 kg probe fell freely with acceleration of 2.00 m/s^2 just before it landed on a distant planet. What is the weight of the space probe on that planet

Answers

Answer:

The weight of the probe is 50 Newtons

Explanation:

Newtons second law states that F = ma

Given the mass of 25kg, and the acceleration of 2m/s^2, we can substitute both values into the equation to find the weight force.

[tex]F = ma[/tex]

[tex]F = 25 * 2[/tex]

[tex]F = 50N[/tex]

The weight of the probe is 50 Newtons

Why is a flower not a good blackbody radiator?

Answers

Answer:

A flower emits only visible light

A flower reflects much of the light that hits it

which is part of the convection cycle in earths atmosphere?

a. hot, denser air rises
b. cold, denser air rises
c. hot, less-dense air rises
d. cold, less-dense air falls

Answers

I believe it’s C. hot, less-dense air rises

I hope this helps !!!!!!!!

Kevin used a pulley to lift a piano to the third floor of his apartment. His input work was 12,000 J and the output work was 10,000 J. What was the mechanical efficiency of the pulley?

A . 50%
B. 83.3%
C . 120%
D. 16.7%

Answers

Answer:

B

Explanation:

Eff = output work/input work ×100

Hence, Eff = 10000/12000 × 100

Eff = 83.3%

A pendulum of mass 18 kg is released from rest at some height, as shown by
point A in the image below. At the bottom of its arc at point B, it is traveling at
a speed of 17 m/s. What is the approximate amount of energy that has been
lost due to friction and air resistance? (Recall that a=98 m/s2

Answers

By the work-energy theorem, the total work done on the mass as it swings is

W = ∆K = 1/2 (18 kg) (17 m/s)² = 153 J

No work is done by the tension in the string, since it's directed perpendicular to the mass at every point in the arc. Similarly, the component of the mass's weight mg pointing perpendicular to the arc also performs no work.

If we ignore friction/drag for the moment, the only remaining force is the parallel component of weight, which performs mgh = (176.4 N) h of work, where h is the vertical distance between points A and B.

Now, if w is the amount of work done by friction/air resistance, then

(176.4 N) h - w = 153 J

If you know the starting height h, then you can solve for w.

Light of wavelength 530.00 nm is incident normally on a diffraction grating, and the first‑order maximum is observed to be 33.0∘ from the normal. How many slits per millimeter are marked on the grating?

Answers

Answer:

1028 slits/mm

Explanation:

We are given that

Wavelength of light, [tex]\lambda=530nm=530\times 10^{-9} m[/tex]

1nm=[tex]10^{-9} m[/tex]

[tex]\theta=33^{\circ}[/tex]

n=1

We have to find the number of slits per mm are marked on the grating.

We know that

[tex]dsin\theta=n\lambda[/tex]

Using the formula

[tex]dsin33^{\circ}=1\times 530\times 10^{-9}[/tex]

[tex]d=\frac{530\times 10^{-9}}{sin33^{\circ}}[/tex]

[tex]d=9.731\times 10^{-7} m[/tex]

1m=[tex]10^{3}mm[/tex]

[tex]d=9.731\times 10^{-7}\times 10^3[/tex]mm

[tex]d=0.0009731mm[/tex]

Number of slits=[tex]\frac{1}{d}[/tex]

Number of slits=[tex]\frac{1}{0.0009731}[/tex]/mm

Number of slits=1028/mm

Hence, 1028 slits/mm are marked on the grating.

Answer:

1027.6 lines per mm.

Explanation:

wavelength = 530 nm

order, m= 1

Angle = 33 degree

Let the slits per mm is 1/d.

So,

[tex]m \lambda = d sin A\\\\1\times 530\times 10^{-6} = d sin 33\\\\\frac{1}{d} = 1027.6 lines per mm[/tex]

the direction of applied force has to be_____ to the distance in order to say work is done

Answers

Answer:

Explanation:

The direction of the applied force has to be parallel to the distance an object moved in order to say that work has been done.

what is the source of energy​

Answers

Fossil Fuels is the largest source for energy

Hope this is what you were asking :)

A stone is thrown vertically upwards with an initial velocity of 20m/sec. Find the maximum height ot reaches and the time taken by it to reach the height. (g=10m/s2)

plz short numerical ASAP​

Answers

Answer:

The height reached is 20m, The time taken to reach 20m is 2 seconds

Explanation:

Observing the equations of motion we can see that the following equation will be most helpful for this question.

[tex]v^{2} = u^{2} + 2as[/tex]

We are given initial velocity, u

We know that the stone will stop at its maximum height, so final velocity, v

Acceleration, a

And we are looking for the displacement (height reached), s

Substitute the values we are given into the equation

[tex]0^{2} = 20^{2} + 2(10)s[/tex]

Rearrange for s

[tex]0^{2} -20^{2} =20s[/tex]

[tex]-400=20s[/tex]

[tex]\frac{-400}{20} =s[/tex]

s = -20 (The negative is just showing direction, it can be ignored for now)

The height reached is 20m

Use a different equation to find the time taken

[tex]s = vt - \frac{1}{2} at^{2}[/tex]

Substitute in the values we have

[tex]-20=(0)t - \frac{1}{2} (10)t^{2}[/tex]

Rearrange for t

[tex]-20 =0 -5 t^{2}[/tex]

[tex]\frac{-20}{-5} =t^{2}[/tex]

[tex]4 = t^{2}[/tex]

t = 2s

The time taken to reach 20m is 2 seconds

Convertir 25 km/h a m/s

Answers

Answer:

6.9 m/s

Explanation:

1000m = 1km

3600s = 1hr

25000m/3600s

6.9m/s

what do you mean by supplementary quantities and its unit?​

Answers

~Solution :-Supplementary Quantities are geometrical quantities of circle and sphere. Supplementary are the units not still classified either as base or derived.

$ \large\boxed{ \sf \red{More ~Info :}}$

The units of supplementary quantities are dimensionless units.

[tex] \\ [/tex]

An electron experiences a downward force of 12.8×10-19 N while traveling in a magnetic field of 8×10-5 T west, what is the magnitude of the velocity?

Answers

Answer:

[tex]v=10^5\ m/s[/tex]

Explanation:

Given that,

Magnetic force acting on an electron, [tex]F=12.8\times 10^{-19}\ N[/tex]

The magnitude of the magnetic field,[tex]B=8\times 10^{-5}\ T[/tex]

We need to find the magnitude of the velocity. We know that the magnetic force is given by :

[tex]F=qvB[/tex]

Where

v is the velocity

So,

[tex]v=\dfrac{F}{qB}\\\\v=\dfrac{12.8\times 10^{-19}}{1.6\times 10^{-19}\times 8\times 10^{-5}}\\\\v=10^5\ m/s[/tex]

So, the magnitude of velocity is[tex]10^5\ m/s[/tex].

Which wave has the smallest amplitude?

Answers

Answer:

C. C

Explanation:

A wave can be defined as a disturbance in a medium that progressively transports energy from a source location to another location without the transportation of matter.

In Science, there are two (2) types of wave and these include;

I. Electromagnetic waves: it doesn't require a medium for its propagation and as such can travel through an empty space or vacuum. An example of an electromagnetic wave is light.

II. Mechanical waves: it requires a medium for its propagation and as such can't travel through an empty space or vacuum. An example of a mechanical wave is sound.

A crest can be defined as the highest (vertically) point on a waveform.

On a related note, a trough is the lowest (vertically) on a waveform.

An amplitude can be defined as a waveform that's measured from the center line (its origin or equilibrium position) to the bottom of a trough or top of a crest. Thus, the vertical axis (y-axis) is the amplitude of a waveform i.e it's measured vertically.

In this scenario, waveform C which is represented by a blue curvy line has the smallest amplitude in comparison with the other waveforms because it has the minimum height when measured from the origin.

In contrast, waveform A represented by a purple line has the highest amplitude because it has the maximum height when measured from the origin.

Mathematically, the amplitude of a wave is given by the formula;

x = Asin(ωt + ϕ)

Where;

x is displacement of the wave measured in meters.A is the amplitude.ω is the angular frequency measured in rad/s.t is the time period measured in seconds.ϕ is the phase angle.

Answer:

The answer is indeed D as the comment above suggests.

Explanation:

Simply put, wave D's highest point is closer to the line than all of the other high points of A, B and C

An ice-skater with a mass of 80kg is holding a bowling ball with a mass of 8 kg. Suppose that the skater tosses the bowling ball forward with a speed of 6 m/s. What is the skater's reactive velocity? Show all work.

Answers

Answer:

0.6 m/s

Explanation:

The details of the masses and velocities are;

The mass of the ice skater, m₁ = 80 kg

The mass of the ball, m₂ = 8 kg

The speed with which the skater tosses the ball forward, v₂ = 6 m/s

Therefore;

According to the principle of conservation of linear momentum, we have;

m₁·v₁ = m₂·v₂

Where;

v₁ = The skater's reactive velocity

Therefore, we get;

80 kg × v₁ = 8 kg × 6 m/s

v₁ = 8 kg × 6 m/s/(80 kg) = 0.6 m/s

The skater's reactive velocity, v₁ = 0.6 m/s.

Which of the following is evidence for continental drift?

Answers

They based their idea of continental drift on several lines of evidence: fit of the continents, paleoclimate indicators, truncated geologic features, and fossils.

Which symbol and unit of measurement are used for electric current?
symbol. A, unit: 1
symbol: C, unit: A
symbol l; unit C
symbol: 1; unitA

Answers

Answer: Symbol is I and unit A

Explanation: A represents Amperes

HOPE THIS HELPS!!!!!!!!

A 20-N force acts on a 5-kg object at rest. How fast will
the object accelerate on a frictionless surface?
A. 15 m/s^2
B. 25 m/s^2
C. 4 m/s^2
D. 100 m/s^2

Answers

Answer:

C.

Explanation:

Force = Mass * Acceleration

So 20 = 5* Acceleration

4 = Acceleration

The acceleration of the object is 4 m/s².

To find the acceleration, the given values are:

Force = 20 N

Mass = 5 kg

Define acceleration.

Definition:

     As it was given as the values of  Force and mass, here acceleration definition depends on the Newton's second law of motion.

Using the second law of motion, the force will be equal to the product of the mass and the acceleration.

As formula,

                               F = ma Newton

Here, to find acceleration,

                              a =f/ m

Substituting the values,

                              = 20 / 5

                            a = 4m/s².

So, the acceleration was 4 m/s². The Option C is the correct answer.

Learn more about acceleration,

https://brainly.com/question/12550364

#SPJ6

un litro de un gas es calentado a presión constante desde 20°C hasta 60°C que volumen final ocupará dicho gas? ​

Answers

Answer:

Final volume, V2 = 3 Litres

Explanation:

Given the following data;

Initial volume, V1 = 1 litre

Initial temperature, T1 = 20°C

Final temperature, T2 = 60°C

To find the final volume, we would use Charles' law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

V1/T1 = V2/T2

Making V2 as the subject formula, we have;

V1T2 = V2T1

V2 = (V1T2)/T1

Substituting into the formula, we have;

V2 = (1 * 60)/20

V2 = 60/20

Final volume, V2 = 3 Litres

Which wave has the largest amplitude?
A.D
B.B
C.C
D.A

Answers

Answer:

D. A

General Formulas and Concepts:

Simple Harmonic Motion

Parts of a wave

PeriodAmplitudeWavelengthCrest/Trough

Explanation:

The amplitude is the distance from the horizon to either the crest or trough of a wave.

In layman's terms, it is how high the wave is.

The "highest" wave would be wave A.

∴ our answer is D.

Topic: AP Physics 1 Algebra-Based

Unit: SMH

Answer:

A (The wave)

Explanation:

Wave A

16 100 g of water at 25 °C is poured into an insulating cup. 50 g of ice at 0 °C is added to the water.
The water is stirred until the temperature of the water has fallen to 0°C.
18 g of ice remains unmelted.
The specific heat capacity of water is 4.2 J /g °C.
Which value does this experiment give for the specific latent heat of fusion of ice?

Answers

Answer:

Q = Q

mcT = ml

100 x 4.2 x 25 = (50-18) l

l = 328

*Hope it helps*

The specific latent heat of fusion of the melted ice is 328.13 J/kg.

Conservation of energy

The specific latent heat of fusion of the melted ice is determined by applying the principle of conservation of energy as shown below;

Heat lost by the water = Heat gained by the ice

McΔθ = mL

where;

c is specific heat capacity of waterL is pecific latent heat of fusion of icem is mass of melted ice = 50 g - 18 g = 32 g

(100)(4.2)(25) = (32)L

32L = 10500

L = 328.13 J/kg

Thus, the specific latent heat of fusion of the melted ice is 328.13 J/kg.

Learn more about heat capacity here: https://brainly.com/question/16559442

newtons second law lab report link

Answers

Answer:

ghittu iihg उह्स उउह्स उग्य्किव जिक्ह्ब

Cuánto demorará un cuerpo en alcanzar su máxima altura, sabiendo que fue lanzado, verticalmente hacia arriba, con una velocidad cuyo valor fue de 90 m/s?

Answers

Answer:

The maximum height reached is 413.27 m.

Explanation:

How long will it take for a body to reach its maximum height, knowing that it was thrown, vertically upwards, with a velocity whose value was 90 m / s?

initial velocity , u = 90 m/s

gravity, g = 9.8 m/s^2

Let the maximum height is h.

At maximum height the velocity v = 0

Use third equation of motion

[tex]v^2 = u^2 - 2 gh\\\\0 = 90\times 90 - 2 \times 9.8 \times h\\\\h = 413.27 m[/tex]

Pls help asap!!

A bucket contains hot water at 95°c. A man wants to bath with water at 40°c. What is the ratio of the mass of hot water to the mass of cold water that he needs.​

Answers

Answer:

55

Explanation:95-40=55

i hope i did the math right if i didnt please tell me


20 kg rodsis on the edge of a 80 m high de What is the rodes gracional potencial energy?

Answers

Answer:

Gpe = 15680 Joules

Explanation:

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Given the following data;

Mass = 20 kg

Height = 80 m

We know that acceleration due to gravity is equal to 9.8 m/s²

To find the gravitational potential energy;

Gpe = mgh

Gpe = 20 * 80 * 9.8

Gpe = 15680 Joules

An object is free falling near the surface of the earth. At a certain instant in time, it is falling downward at a rate 25.0 m/s. After 2.5 seconds, what are its acceleration and velocity?

Answers

Answers:

acceleration = 9.81 m/s^2velocity = 49.5 m/s

The values are approximate.

==========================================================

Explanation:

When near the surface of the earth, the acceleration of gravity is roughly 9.81 m/s^2. This means that after each second passes, the velocity increases by roughly 9.81 m/s.

After 2.5 seconds, the velocity increases by 2.5*9.81 = 24.525 m/s = 24.5 m/s

If it was already going 25.0 m/s, then it bumps up to 25.0+24.5 = 49.5 m/s which is also approximate.

The acceleration of gravity stays the same when the object is close to the surface of the earth, so it stays at roughly 9.81 m/s^2

Side note: I'm ignoring air resistance (aka air friction or drag) since that greatly complicates things, and we would need to know the shape and surface area of the object. The material type would also be relevant info as well.

What is the difference between heat capacity and specific heat capacity? I want the meaning please.

Answers

Answer:

The heat capacity of a body is defined as the heat required to raise it's temperature by me degree or one kelvin.while specific heat capacity of a substance is defined as the heat required to the temperature of a unit mass of it through one degree or one kelvin.

I hope it helps

A convex mirror of radius of curvature 1.6 m has an object placed at a distance of 1.0 m from it. Find the position of image and the magnification.​

Answers

Answer:

The image is formed at 0.44 m in front of the mirror

magnification (M) = 0.44

Explanation:

Applying, mirror formular

1/f = (1/u)+(1/v).................... Equation 1

Where f = Focal length of the convex mirror, u = object distance, v = image distance.

Using the real is positive convection,

From the question,

Given: f = -1.6/2 = -0.8 m( The focal length of a convex mirror is vitual), u = 1.0 m

Substitute these values into equation 1

-1/0.8 = (1/v)+(1/1)

Solve for v

1/v = 1.25+1

1/v = 2.25

v = 1/2.25

v = 0.44 m

Hence the image is formed at 0.44 m in front of the mirror

Magnification (M) = v/u

m = 0.44/1

m = 0.44

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