The distance of planet Mercury from the Sun is approximately 5.8. 107 kilometers, and the distance of planet Venus from the Sun is 1.1. 10 kilometers. About how many more kilometers is the
distance of Venus from the Sun than the distance of Mercury from the Sun?
​

Answer:

33

Step-by-step explanation:

For every 5 squares, two are red and three are green.  So 3/5 of the squares are green.

3/5x55=33

[tex]t=\sqrt{\dfrac{ab-s}{r+ak}}\\\\t^2=\dfrac{ab-s}{r+ak}\\\\rt^2+akt^2=ab-s\\\\akt^2-ab=-rt^2-s\\\\a(kt^2-b)=-(rt^2+s)\\\\a=-\dfrac{rt^2+s}{kt^2-b}\\\\a=-\dfrac{rt^2+s}{-(b-kt^2)}\\\\a=\dfrac{rt^2+s}{b-kt^2}[/tex]

Answer:

2' 3"

Step-by-step explanation:

Here 4' 1" − 1' 10" is certainly possible, but to carry out this operation we must borrow 1', or 12", from 4' 1":

4' 1" becomes 3' 13", and so the original problem becomes

3' 13" - 1' 10"

which in turn becomes 2' 3"

Answer:

20 meters

Step-by-step explanation:

The track is circular so it means that after Patrick raced the entire track he is back at the starting point. In other words, every 440 meters he is back to the beginning.

So we would have that, if he races round the track twice, he would run 440(2) = 880 meters and he would be back at the starting point.

The problem asks us how far is he from the starting point at the 900 meter mark. If at 880 meters he is at the starting point, then at 900 meters he would be [tex]900-880=20[/tex] meters from the starting point.

Answer:

24

Step-by-step explanation:

Answer

24!

Step-by-step explanation:

Person above me is correct :)

Answer:

Confidence interval for the population mean is between 15 homes and 19 homes

Step-by-step explanation:

Given that:

Sample (n) = 17 homes, mean (μ) = 19 homes, standard deviation (σ)= 4 people and confidence (C) = 98% = 0.98

α = 1 - C = 1 - 0.98 = 0.02

α/2 = 0.02/2 = 0.01.

The z score of 0.01 (α/2) corresponds to the z score of 0.49 (0.5 - 0.01) which from the normal distribution table is 2.33

The margin of error (E) is:

[tex]E=z_{0.01}*\frac{\sigma}{\sqrt{n} } =2.33*\frac{4}{\sqrt{19} }=2[/tex]

The confidence interval = μ ± E = 17 ± 2 = (15, 19)

Confidence interval for the population mean is between 15 homes and 19 homes

7/12

Step-by-step explanation:

let x=0.583333..

multiply by powers of 10 to get repeated 3's only on the rights for two different multiples of x

1000x= 583.33

100x=58.33

50x= 525/900

=25x21/25x36

=21/36

=7/12

Greetings from Brasil...

According to the properties of the radiation:

X^(a/b) = [tex]\sqrt[b]{X^a}[/tex]

So

X^(2/3) = [tex]\sqrt[3]{X^2}[/tex]

And

Y^(-3/4) = 1/Y^(3/4)

so 1/Y^(-3/4) = Y^(3/4) = [tex]\sqrt[4]{Y^3}[/tex]

Then we get

[tex]\sqrt[2]{X^3} .\sqrt[4]{Y^3}[/tex]

Answer:

7.006*10⁻³ = 0.007006

Step-by-step explanation:

7.006*10⁻³ = 0.007006

Answer:

Step-by-step explanation:

A matrix is a set of numbers organized in rows and columns to represent the variables in a situation, and the determinant is used to find the inverse of a matrix which helps you solve for different variable values.

Answer: A matrix or matrices is a rectangular grid of numbers or symbols that is represented in a row and column format. A determinant is a component of a square matrix and it cannot be found in any other type of matrix. ... A determinant is a number that is associated with a square matrix.

Step-by-step explanation:

Answer:

5z

Step-by-step explanation:

As product = multiplication =>

5 x z --> 5(z)

[tex]\text{Find the product of 5 and z}\\\\\text{The key term in this questions is product, and in math it translates to}\\\text{the answer when multiplled}\\\\\text{In this case, you would multiply them together to get your "product"}\\\\\text{Solve:}\\\\5\cdot z\\\\\boxed{5z}[/tex]

Answer: C) similar, SAS similarity, triangle LQR

==============================================

Explanation:

The vertical angles KLJ and QLR are congruent. This forms the "A" in "SAS". The angles in question are between the marked sides.

KL = 18 is twice that of QL = 9, or put another way, KL/QL = 18/9 = 2. The ratio of the sides is 2. Also, JL/RL = 16/8 = 2 is the same ratio. Because both pairs of sides have the same ratio, the sides are in proportion. This helps form the two "S" letters of "SAS".

The original triangle has LKJ mentioned at the top. Note the order as its important. We start with L and move to K, so LK is the first segment mentioned. LK = 18 pairs up with LQ = 9, meaning that LQ must be the first segment mentioned of the answer triangle. Therefore LQR is the correct letter sequence if we start with point L. Writing QLR is not correct because Q is the first letter here but Q does not pair up with L.

Answer:

(a) (f o g)(x) =  x^2 - 15x + 54

(b) (g o f)(x) = x^2 + 3x - 9

(c) (f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x

(d) (g o g)(x) = x - 18

Step-by-step explanation:

f(x) = x^2 + 3x

g(x) = x - 9

(a)

(f o g)(x) = f(g(x)) = (g(x))^2 + 3(g(x)) = (x - 9)^2 + 3(x - 9)

(f o g)(x) = x^2 - 18x + 81 + 3x - 27

(f o g)(x) = x^2 - 15x + 54

(b)

(g o f)(x) = g(f(x)) = f(x) - 9 = x^2 + 3x - 9

(c)

(f o f)(x) = f(f(x)) = (x^2 + 3x)^2 + 3(x^2 + 3x)

(f o f)(x) = x^4 + 6x^3 + 9x^2 + 3x^2 + 9x

(f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x

(d)

(g o g)(x) = g(g(x)) = x - 9 - 9 = x - 18

Step-by-step explanation:

why did u add the 5 in the question?.

Answer:

always b is equal to 9 is rhdx forum post in is ek of

Answer:

6.7 cm

Step-by-step explanation:

A+B+C=180°

55°+B+82°=180°

B=43°

Using the formulae

(Sin A)/a = (Sin B)/b

(Sin 55)/8 = (Sin 43)/b

b = [8(Sin 43)]/(Sin 55)

b= 6.7 cm

probability = favourable outcomes/total outcomes

you need 1 banana, out of 4 and there are total of 6 items so probability will be 4/6

when you take out 1 banana, there are 3 banana left and total of 5 items

so probability of this action will be 3/5

now, next action is taking out another banana.

this is NOT an independent event.

so by we will multiply the probabilities of these events according to rule of products.

so the answer is [tex] \frac{4\cdot3}{6\cdot5}=\frac25[/tex]

or 2×100/5=40%

Answer:

7/2 pi

or approximately 10.99557429

Step-by-step explanation:

2 pi sqrt( a/b)

let a = 49 and b = 16

2 pi sqrt( 49/16)

We know that sqrt( a/b) = sqrt(a) /sqrt(b)

2 pi sqrt(49) / sqrt(16)

2pi ( 7) / (16)

2 pi ( 7/4)

7/2 pi

This is the exact answer

We can make an approximation for pi

Using the pi button on the calculator

10.99557429

Answer:

{(1, 2), (3, 2), (5, 7)}

Step-by-step explanation:

A function has a one to one correspondence

Each x can go to only 1 y value

{(1, 2), (3, 2), (5, 7)} function

{(3, 5), (-1, 7), (3, 9)} 3 goes to more than 1 y value

{(1, 2), (1, 4), (1, 6)} 1 goes to more than 1 y value

Answer:

[tex]\huge \boxed{ \{(1, 2), (3, 2), (5, 7)\} }[/tex]

Step-by-step explanation:

[tex]\sf A \ function \ is \ a \ relation \ if \ each \ x \ value \ is \ for \ each \ y \ value.[/tex]

[tex]\{(1, 2), (3, 2), (5, 7)\} \ \sf represents \ a \ function.[/tex]

[tex]\{(3, 5), (-1, 7), (3, 9)\} \ \sf does \ not \ represent \ a \ function.[/tex]

[tex]\{(1, 2), (1, 4), (1, 6)\} \ \sf does \ not \ represent \ a \ function.[/tex]

Answer:

see details below

Step-by-step explanation:

a) week 1 :  #10" / (#10"+#12") = 509 / 736 =  69% (to nearest percent)

b) week 2 :  #10" / (#10"+#12") = 766 / 1076 = 383/538 = 71% (to nearest percent)

A).69% for week 1

B)71% for week 2

Answer:

Amadi is 86m far from Becky

Amadi is on the bearing of 78° .

Step-by-step explanation:

From the information given ,

let I represent Ikyume

A represent Amadi  and B represent Becky

From the information in the diagrammatic expression shown below:

Using cosine rule;

i² = a² + b² - 2ab cos (I)

i² = 42² + 62² - 2(42×62) cos (110°)

i² =  1764 + 3844 - 5208 (- 0.342)

i² =  1764 + 3844 -  ( - 1781.136)

i² = 1764 + 3844 + 1781.136

i² = 7389.136

i = [tex]\mathtt{\sqrt{7389.136}}[/tex]

i = 85.96

i [tex]\simeq[/tex] 86 m

Amadi is 86m far from Becky

From  point I , 12° = 12° at point A (alternate  angles)

In that quadrant = 90 - 12° = 78°

Therefore, Amadi is on the bearing of 78° .

Part (a)

BC = opposite side (furthest leg from the reference angle)

AB = adjacent side (closest leg from the reference angle)

AC = hypotenuse (always opposite the 90 degree angle)

=============================================

Part (b)

i. False. Angle B is 90 degrees as shown by the square angle marker.

ii. False. Side AB is opposite angle C. Note how "C" is part of "BC", so that means we cannot have BC be opposite C.

iii. True. Leg AB is the closer leg to angle A. We have "A" in "AB" to see this without having to draw the diagram. Refer to part (a) above.

iv. False. The longest side of any right triangle is always the hypotenuse. The longest side of any triangle is always opposite the largest angle.

==============================================

Part (c)

cos(theta) = adjacent/hypotenuse = AB/AC

tan(theta) = opposite/adjacent = BC/AB

Refer back to part (a) to determine the opposite,adjacent and hypotenuse side lengths.

==============================================

Part (d)

The reference angle has changed, so the opposite and adjacent sides swap. The hypotenuse remains the same regardless of what reference angle you pick.

sin(C) = opposite/hypotenuse = AB/AC

cos(C) = adjacent/hypotenuse = BC/AC

tan(C) = opposite/adjacent = AB/BC

Note the tangent ratio is the reciprocal of what we found back in part (c).

Answer & Step-by-step explanation:

(a)

The hypotenuse is on line CA (the hypotenuse is always opposite the 90° angle (marked by a little square))

The adjacent is on the line BA (adjacent is next to the given angle, but NOT the hypotenuse)

The opposite is on the line CB (this is opposite the given angle)

(b)

i.   false (b is a right angle)

ii.  false (the side opposite C is BA)

iii. true

iv. false (the side opposite B is the hypotenuse, and the hypotenuse is always the longest side in a triangle)

(c)

cosine ratio: [tex]cos=\frac{adjacent}{hypotenuse}[/tex]

tangent ratio: [tex]tan=\frac{opposite}{adjacent}[/tex]

The cosine and tangent ratios of the given angle:

[tex]cos0=\frac{AB}{CA} \\\\tan0=\frac{CB}{AB}[/tex]

(d)

Remember SOH-CAH-TOA:

Sine=Opposite/Hypotenuse

Cosine=Adjacent/Hypotenuse

Tangent=Opposite/Adjacent

Using the angle C, plug in the appropriate sides:

[tex]sinC=\frac{BA}{CA}\\\\ cosC=\frac{CB}{CA}\\\\ tanC=\frac{BA}{CB}[/tex]

:Done

Answer:

-i

Step-by-step explanation:

(-i)^0 = 1

(-i)^1 = -i

(-i)^2 = -1

(-i)^3 = -i

(-i)^4 = 1

(-i)^5 = -i

etc.

From this pattern, you see that when the exponent is a multiple of 4, you get 1. When the exponent is a multiple of 4 plus 1, you get -i, etc.

213 = 4 * 53 + 1

213 is 1 more than a multiple of 4.

(-i)^213 = (-i)^1 = -i

Answer:

d. -4

Step-by-step explanation:

Let's plug in g

8 - |2(-3.5) - 5|

8 - |-7-5|

8 - |-12|

The absolute value is always positive of any number,

8 - 12

= -4

Answer:

D. -4

Step-by-step explanation:

We are given this expression:

[tex]8-|2g-5|[/tex]

and asked to evaluate when g= -3.5 Therefore, we must substitute -3.5 in for g.

[tex]8-|2(-3.5)-5|[/tex]

First, multiply 2 and -3.5

2 * -3.5 = -7

[tex]8-|-7-5|[/tex]

Next, subtract 5 from -7.

-7-5= -12

[tex]8-|-12|[/tex]

Next, evaluate the absolute value of -12. The absolute value is how far away a number is from 0, and it is always positive. The absolute value of -12 is 12.

[tex]8-12[/tex]

Subtract 12 from 8.

[tex]-4[/tex]

The value of the expression is -4 and D is the correct answer.

Answer:

The terms 11, 9, 7, 5, 3, 1 have a common difference of -2 therefore, the correct option defining the relationship between the terms is

B) Common difference

Step-by-step explanation:

The common difference between a series of numbers is found by subtracting a number from the next number following and a common difference exists  when the difference between successive adjacent number pairs is the same

A sequence that has a common difference is an arithmetic sequence or arithmetic projection.

The given sequence, 11, 9, 7, 5, 3, 1, is an arithmetic sequence.

Answer:

Kindly check explanation

Step-by-step explanation:

Given the details :

Kofi is older than kweku

kofi's age = (5x-4) years

kweku's age = (2x+1) years

a. write down an expression, interns of x,for how much old is Kofi than kweku

Equate the ages of Kofi and kweku

(5x - 4) = (2x + 1)

5x - 4 = 2x + 1

5x - 2x = 1 + 4

3x = 5

3x - 5

B.) if Kofi is tens years older than kweku, find the value of x and the ages of Kofi and kweku

Then,

(5x-4) = (2x + 1) + 10

5x - 4 = 2x + 1 + 10

5x - 2x = 1 + 10 + 4

3x = 15

x = 5

Kofi's age : 5x - 4

5(5) - 4 = 25 - 4 = 21 years

Kweku's age : (2x + 1)

2(5) + 1 = 10 + 1 = 11 years

━━━━━━━☆☆━━━━━━━

▹ Answer

-1 - 1/2x

▹ Step-by-Step Explanation

3x ÷ x - 4 + x - 3 ÷ 2x

Divide and Rewrite:

3 * 1 - 4 + x - 3 ÷ 2 * x

Calculate:

3 - 4 + x - 3/2x

-1 + x - 3/2x

= -1 - 1/2x

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

Answer:

Step-by-step explanation:

[tex]\frac{3x}{x-4}+\frac{x-3}{2x}[/tex]

Make them into common denominators. To do so, multiply by the LCM of the denominators. The LCM of the denominators is (x-4)(2x). Thus, we multiply 2x to the first term and (x-4) to the second:

[tex](\frac{2x}{2x}) \frac{3x}{x-4}+(\frac{x-4}{x-4}) \frac{x-3}{2x}[/tex]

Simplify:

[tex]\frac{6x^2}{2x(x-4)}+\frac{x^2-7x+12}{2x(x-4)} \\=\frac{7x^2-7x+12}{2x(x-4)}[/tex]

And this cannot be simplified further (you can also distribute the denominator if preferred).

Answer:

  C)  y ≥ 3

Step-by-step explanation:

The answer choices suggest that you're interested in the range of the function. x^2 cannot be negative, so its value will be 0 or greater. Adding 3 to x^2 ensures that the value of f(x) will be 3 or greater.

  y ≥ 3 . . . . matches C

Answer:

[tex]\huge\boxed{d = 4 }[/tex]

Step-by-step explanation:

41 = 12d - 7

Adding 7 to both sides

41+7 = 12d

48 = 12 d

Dividing both sides by 12

4 = d

OR

d = 4

Answer:

[tex]\large \boxed{{d=4}}[/tex]

Step-by-step explanation:

[tex]41 =12d-7[/tex]

Add 7 on both sides.

[tex]41 +7=12d-7+7[/tex]

[tex]48=12d[/tex]

Divide both sides by 12.

[tex]\displaystyle \frac{48}{12} =\frac{12d}{12}[/tex]

[tex]4=d[/tex]

Answer:

5

Step-by-step explanation:

Answer:

5 (Follow PEMDAS left—>right)

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B)  = (A ∩ B) (Addition to zero identity property)

∴  A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅  ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.