The first 32 amino acids from the N terminus of the protein bovine angiogenin were determined by edman degradation. (a) The cleavage sites for the trypsin-catalyzed hydrolysis are, AQDDYRYIHFLTQHYDAKPKGRNDEYCFNMMK.
(b) The following cleavage sites take place during hydrolysis that is catalyzed by chymotrypsin: AQDDYRYIHFLTQHYCFNMMK. Site-selective breakdown of extremely non-reactive peptide bonds also functions as a therapeutically helpful modulator of protein structure and function, providing essential information on the protein sequence. Regulated and selective cleavage is a challenging task and requires chemical reagents to be able to recognize or bind to one or more specific amino acid residues in the peptide chain. On the basis of this concept, we developed a technique that selectively changes the serine residue in a peptide chain using a chemical reagent, causing the peptide backbone to break at the N-terminus of the serine residue. After cleavage, modified residues can be transformed back into their original form. This method may cleave a wide variety of substrates and does so specifically for certain bioactive peptides with post-translational modifications (like N-acetylation and -methylation) and mutations (like D- and -amino acids), which are known to contribute to age-related diseases.
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1. Chromium, Cr, has 24 electrons. Write out the entire electron configuration for chromium using spdf notation.2. How many unpaired electrons would you expect for chromium in [Cr(H2O)6] 3+? Is this a paramagnetic or diamagnetic material?3. Cobalt, Co, has 27 electrons. Write out the entire electron configuration for cobalt using spdf notation.4. How many unpaired electrons would you expect for manganese in KMnO4? Is this a paramagnetic or diamagnetic material?5. This same experiment is performed on the international space station. What is the primary issue with performing this experiment in the absence of gravity? Design an experiment to compensate for this. As always, you do have duct tape.
The electronic configuration is also used to explain the orbitals of an atom and it helps to determine the physical and chemical properties of the elements. Here the electronic configuration of chromium is 1s²2s²2p⁶3s²3p⁶4s¹3d⁵.
What is electronic configuration?The distribution of electrons in the atomic orbitals is given by the electronic configuration. It is a standard notation in which all the electrons holding atomic subshells are arranged in a sequence. Each element has a unique electronic configuration.
The electronic configuration of an element can be written in two ways, in standard notation, and in condensed form. In the case of elements with larger atomic numbers, the electronic configuration becomes lengthy in standard notation. So in such cases condensed form is generally used.
In condensed form, Cr: [Ar] 3d⁵4s¹
There are six unpaired electrons in [Cr(H₂O)₆]³⁺ and it is a paramagnetic complex.
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Write the overall balanced cell reaction for the following voltaic cell Fe(s) | Fe2+ (aq) || Ag + (aq) | Ag(s) (Ctrl).
the overall balanced cell reaction for the following voltaic cell
Hg2Cl2(s) + Cu(s) ® 2Hg(l) + Cu2+(aq) + 2Cl-(aq)
The cell reaction, also known as the total reaction, is the reaction that occurs within the cell as a whole and is expressed under the assumption that the right electrode is the cathode and that the spontaneous reaction is the one in which reduction takes place in the right-hand compartment.Galvanic, also known as Voltaic, and electrolytic cells are the two varieties of electrochemical cells. While electrolytic cells utilize non-spontaneous reactions and therefore need an external electron source, such as a DC battery or an AC power source, galvanic cells get their energy from spontaneous redox reactions.
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The Solubility Of Fe (OH)2 In Water At 25 °C Is Measured To Be 5.2x 10-4 Fe(OH)2 Use This Information To Calculate K Round Your Answer To 2 Significant Digits.
The Solubility Of Fe(OH)₂ In Water At 25 °C Is Measured To Be 5.2x 10⁻⁴ Fe(OH)₂ Ksp value is 5.6 × 10⁻¹⁰.
The chemical reaction is given as follows :
Fe(OH)₂ ⇄ Fe²⁺ + 2OH⁻
Ksp expression for the given reaction is given as follows :
Ksp = [Fe²⁺] [OH⁻]²
the solubilty S = 5.2x 10⁻⁴
so , the Ksp = S × (2S)²
= 4S³
Ksp = 4 ×S³
= 4 × ( 5.2x 10⁻⁴ )³
= 4 × 140.6 × 10⁻¹²
= 5.6 × 10⁻¹⁰
The solubility product value for Fe(OH)₂ that is Ksp value is 5.6 × 10⁻¹⁰.
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Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to
graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine A
Hrxn for
C(diamond)
C(graphite)
with equations from the following list:
(1) C(diamond) + O₂(g) → CO₂(g)
(2) 2 CO₂(g) → 2 CO(g) + O₂(g)
(3) C(graphite) + O₂(g) → CO₂(g)
(4) 2 CO(g) → C(graphite) + CO₂(g)
AHoverall
KJ
AH = -395.4 kJ
AH= 566.0 kJ
AH=-393.5 kJ
AH = -172.5 kJ
The ΔH of the reaction for the formation of graphite from diamond is equal to -1.9 KJ/mol.
What is the heat of the formation of the reaction?The heat of formation can be described as the amount of heat absorbed or evolved when 1 mole of a substance is formed from its constituent elements, each substance being in its normal physical state.
We have to rearrange the provided equations in a way in which all molecules of O₂ and CO₂ can be eliminated:
2C (diamond) + 2O₂ (g) → 2CO₂ (g) ΔH₁= 2 × (-395.4 KJ)
2 CO₂ (g) → 2 CO(g) + O₂(g) ΔH₂ = 566.0 KJ
CO₂(g) → C (graphite) + O₂(g) ΔH₃= - 1 × (-393.5 KJ)
2CO (g) → C (graphite) + CO₂(g) ΔH₄= -172.5 KJ
When we eliminate the molecules that appear both in reactants and products, the total chemical reaction is the following:
2C (diamond) → 2C (graphite)
ΔH (total) = ΔH₁ + ΔH₂ + ΔH₃ + ΔH₄
ΔH (total) = 2 × (-395.4 KJ) + 566.0 KJ + (-1 × (-393.5 KJ)) - 172.5 KJ
ΔH (total) = 347.2 KJ
This is for 2 mol of C (diamond) which is converted into 2 mol of C (graphite). To find ΔH for the reaction of 1 mol C (diamond) to 1 mol (graphite) we have to divide it into 2:
ΔH = - 3.8/2 = -1.9 KJ/mol
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Metals and nonmetals display different properties. Sort each of the below properties listed below into one of the two categories, metal or nonmetal. Malleable Form cations in Poor conductors Shiny solilds at Gases at room temperature Good conduc of electricity Form anions in room ionic compounds ionic compounds of heat Categories Metals
Metals : Malleable, Form cations in ionic compounds, shiny solids at room temperature and good conduct of electricity.
Non Metals : Gases at room temperature , forms anions in ionic compounds, poor conductors of heat.
Metals are all elements besides hydrogen that undergo chemical reactions and lose electrons to produce positive ions. Metals are electropositive elements as a result. They have a brilliant shine, are tough, can resonate sound, and are great heat and electricity conductors. Except for mercury, all metals are solids under normal circumstances.
Non-metals are elements that frequently gain electrons during chemical processes to generate anions. These substances are electronegative ones. They lack luster, are fragile, and are poor heat- and electricity-conductors (except graphite). Non-metals come in solid, liquid, or gaseous forms.
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how do oxygen molecules interact differently with the systems and cells when you have asthma?
Answer:
In individuals with asthma, the airways (bronchial tubes) that carry air in and out of the lungs become narrowed, swollen, and inflamed due to an overactive immune response. This can lead to difficulty breathing, wheezing, coughing, and other symptoms.
During an asthma attack, the muscles around the airways may become tight and the lining of the airways may produce excessive mucus, further narrowing the airways and making it difficult for oxygen to reach the cells in the body. This can lead to low oxygen levels in the blood and cause symptoms such as shortness of breath and chest tightness.
In addition to these physical changes in the airways, individuals with asthma may also have an overactive immune response to certain triggers, such as allergens or irritants, which can further worsen inflammation and airway narrowing.
Treatment for asthma typically involves using medications to control inflammation and relax the muscles around the airways, as well as avoiding triggers that can worsen symptoms. By properly managing their asthma, individuals with the condition can often lead normal, active lives.
Explanation:
The tubes that carry air into and out of the lungs become irritated and constricted in people with asthma. This can make it difficult for air to enter and exit the lungs, which can cause symptoms including coughing, wheezing, and breathing problems.
Being less able to enter the lungs and reach the body's cells is one-way oxygen molecules can interact differently with the systems and cells in people with asthma. It is more difficult for oxygen to enter the lungs when the airways are constricted, which can result in a reduction in the amount of oxygen reaching the body's cells. This may cause symptoms including trouble breathing and difficulty engaging in physical activity.
In people with asthma, oxygen molecules can also affect the cells and systems in different ways by inducing an immunological reaction. When allergens or pollutants are breathed by asthmatic patients, their immune systems may be overly sensitive to them and may respond inappropriately. This may result in the release of inflammatory substances, which may further constrict the airways and hinder the absorption of oxygen by the lungs.
Inflammation and immune system overactivity can generally disrupt how oxygen molecules interact with the body's processes and cells in people with asthma, which can cause breathing problems and other symptoms.
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Determine the structure of C6H10, which upon oxidation gives acetic and isobutyric acid
Answer:CH
3
CH
2
CH
2
C≡C−CH
3
Explanation:
a chemistry graduate student is given of a chloroacetic acid solution. chloroacetic acid is a weak acid with . what mass of should the student dissolve in the solution to turn it into a buffer with ph ? you may assume that the volume of the solution doesn't change when the is dissolved in it. be sure your answer has a unit symbol, and round it to significant digits.
Choloracetic acid, 12 g. The colorless solution of the white crystalline substance known as chloroacetic acid.
Up to 80% of the solution can be acidic. By inhalation, ingestion, and skin contact, it is poisonous. It corrodes flesh and metals.
The equilibrium of the buffer is
CH2ClCO2 + H+ HCH2ClCO2
PKA = Log Ka
Ka: [CH2ClCO2] = 1,3 x 103. "H+" / "HCH2ClCO2"
Using the Henderson-Hasselbalch formula:
pH equals pka plus log10 [A]/[HA].
2,89 + log10 [A] / [HA] = 3,01
1,318 = [A⁻] / [HA]
Since chloroacetic acid (HA) has a molar concentration of 0,20M
[A⁻] = 0,26 mol/L
There are 500 mL plus 0.5 L.
Chloroacetic acid is equal to 0,26 mol/L x 0,5 l, or 0,13 moles. By weight:
Choloracetic acid is equal to 0,13 mol (94,5g / 1mol) = 12 g.
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use the reaction equilibria below to find the k value for the dissociation of the ammonium cation to ammonia and h .
K = [NH3][H+] / [NH4+], The concentrations of the products are not given, the K value cannot be calculated.
What is reaction equilibrium?
Reaction equilibrium is a state of chemical equilibrium in which a chemical reaction and its reverse reaction occur at equal rates. This means that the concentrations of all reactants and products remain constant over time. Equilibrium is reached when the forward and reverse reaction rates are equal and the concentrations of reactants and products are not changing.
NH4+ ⇌ NH3 + H+
The reaction equilibrium constant (K) is equal to the product of the concentrations of the products (NH3 and H+) divided by the concentration of the reactant (NH4+).
K = [NH3][H+] / [NH4+]
Since the concentrations of the products are not given, the K value cannot be calculated.
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In a gas chromatogram, the retention time of compounds A and B are 1.25 min and 1.45 min, respectively. If both of these compounds have similar structures, which of the compounds has a higher boiling point?
In a gas chromatogram, the retention time of compounds A and B are 1.25 min and 1.45 min, respectively. If both of these compounds have similar structures, Compound A has a higher boiling point.
Gas chromatogram is a widely used technique in analytical chemistry for the separation and investigation of compounds that may evaporate without disintegrating (GC). The purity of a substance can be assessed by GC, as can the components of a mixture. Preparative chromatography can make use of GC to separate pure compounds from a mixture. Other names for gas chromatography include vapor-phase chromatography (VPC) and gas-liquid partition chromatography (GLPC). These alternative names and the accompanying acronyms are frequently used in scientific literature. Gas chromatography is a technique for separating compounds in mixtures by injecting a gaseous or liquid sample into a mobile phase, which is usually referred to as the carrier gas, and passing the gas through a stationary phase. The mobile phase is often composed of an inert gas or an unreactive gas, such as helium, argon, nitrogen, or hydrogen. The stationary phase is a minuscule layer of viscous liquid on a surface of solid particles on an inert solid support in a piece of glass or metal tubing known as a column.
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Which of the following statements is a correct interpretation of the data regarding how the order of the reaction can be determined?
a. The reaction must be first order because there is only one reactant species
b. The reaction is first order if the plot of ln[H2O2] vs time is a straight line
c. The reaction is first order if the plot of 1/[H2O2] vs time is a straight line
d. The reaction is second order because 2 is the coefficient of H2O2 in the chemical equation
Answer: B
The reaction is first order if the plot of ln[H₂O₂] vs time is a straight line. Therefore, option B is correct.
What is the order of the reaction?The order of reaction can be described as the relationship between the rate of a reaction and the concentration of the species that participated in it. In order to get the reaction order, the rate expression of the reaction must be obtained.
The rates of reactions depend on the concentration of only one reactant can be considered as the first order of the reaction. In these reactions, there can be multiple reactants present, but only one reactant can be of first-order concentration.
An example of a first-order reaction can be : [tex]2H_2O_2 \longrightarrow 2H_2O + O_2[/tex]
The plot between the ln[H₂O₂] vs time will be a straight line.
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Combustion of 31.68 g of a compound containing only carbon, hydrogen, and oxygen produces 36.67 g CO2 and 15.01 gH2O. What is the empirical formula of the compound?
Combustion of 31.68 g of a compound containing only carbon, hydrogen, and oxygen produces 36.67 g CO₂ and 15.01 g H₂O. the empirical formula of the compound is CH₂O.
given that :
mass of CO₂ = 36.67 g
mass of H₂O = 15.01 g
total mass of compound = 31.68 g
moles of CO₂ = 36.67 / 44
= 0.833 mol
moles of C = 0.833 mol
moles of H₂O = 15.01 / 18
= 0.833 mol
moles of H = 2(0.833)
= 1.667 mol
mass of carbon = 0.833 × 12
= 10 g
mass of hydrogen = 1.667 × 1
= 1.667 g
mass of oxygen = 31.68 - ( 10 + 1.67 )
= 20 g
moles of Oxygen = 20 / 16
= 1.25 mol
dividing by the smallest one :
C = 0.833 / 0.833 = 1
H = 2
O = 1
The empirical formula is CH₂O.
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which of the following statements, i-iv, is/are true about the galvanic cell below? cu (s) | cu2 (aq) || ag (aq) | ag (s) given the following information:
There are constantly spontaneous oxidation-reduction events in galvanic cells. "H (2)" has a stronger propensity to liberate electrons in electrochemical cells.
H (2) is thus released at the anode, and Cu is deposited at the cathode. Here, Cu serves as the cathode and Ag as the anode. Similar to oxidation, when electrons are released from an electrode they produce aqueous ions in the solution, which reduces the mass of the electrode. A galvanic cell or voltaic cell is an electrochemical device that transforms the chemical energy of spontaneous redox reactions into electrical energy. electrical cell A voltaic cell is an electrochemical device that produces electricity through chemical processes.
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a molecule with 5 single bonds (and any number of lone pairs) could have which type of molecular geometry? i. trigonal bipyramidal ii. seesaw iii. t-shaped iv. square pyramidal
Which type of arrangement of atoms could a molecule with five covalent bond (and any percentage of lone pairs) have? Trigonal bipyramidal, square pyramidal
A cell is the smallest unit of a material that retains its composition and properties. It is made up of 2 or more atoms that are joined together by covalent bond. Chemistry is built on molecules. The element sign and a suffix indicating the number of ions are used to identify molecules. A molecule is the smallest unit of any material that is composed of one or more elements and is capable of existing independently while maintaining all of the substance's physical and chemical properties. Further atom division occurs within molecules. For instance, the symbols for the oxygen atom and molecule are O and O2, respectively.
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water is a polar molecule because: in the o-h bonds of water, the oxygen is more electronegative. the electrons in the o-h bond spend more time close to the oxygen. it has asymmetrically arranged polar bonds. water molecules have permanent electric dipole moments. the hydrogens have a partial positive charge, and the oxygen has a partial negative charge.
Water is a polar molecule because in the O-H bond of water, Oxygen is more electronegative due to which partial positive charge and partial negative charge is created on hydrogen and oxygen respectively, resulting in a dipole moment.
A dipole moment is created between two atoms having a suitable electronegativity (ability to pull electrons more towards itself) difference.
A difference in electronegativity between two atoms creates a partial positive charge and a partial negative charge on the atoms. The electrons are pulled towards the atom having partial negative charge. The resultant direction of the atoms in which they get pulled gives the dipole moment of the bond.
If the resultant dipole is zero then the bond is considered to be non-polar
water is an example of a polar molecule as in the bent structure of the molecule, with oxygen at the center, surrounded by two H atoms on both sides, the electrons of the two O-H bonds are pulled towards O, resulting in a dipole moment in the upward direction. Thus, making water a polar molecule.
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Suppose the galvanic cell sketched below is powered by the following reaction: Fe(s)+NiCl2(aq) → FeCl2(aq)+Ni(s) E2 S1 S2 Write a balanced equation for the half-reaction that happens at the cathode of this cell. Write a balanced equation for the half-reaction that happens at the anode of this cell. Of what substance is E1 made? of what substance is E2 made? What are the chemical species in solution S1? What are the chemical species in solution S2?
The chemical species in solution S2 Fe(s)+NiCl2(aq) → FeCl2(aq)+Ni(s)
Fe(s) ------> [tex]Fe^{2+}[/tex] + 2e (Oxidation)
[tex]Ni^{2+}[/tex] (aq) + 2e ------> Ni(s) (Reduction)
Galvanic Cell
Galvanic cells employ the electrical energy generated by the transport of electrons during a redox reaction to carry out practical electrical work. By separating the oxidation and reduction half-reactions and connecting them with a wire so that the electrons must pass through the wire, it is possible to gather the electron flow.
Write a balanced equation for the half-reaction that happens at the cathode of this cell = Ni (aq) + 2e ------> Ni(s)
Write a balanced equation for the half-reaction that happens at the anode of this cell = Fe(s) ------> [tex]Fe^{2+}[/tex] + 2e.
Of what substance is E1 made? = Fe
of what substance is E2 made? = Ni
What are the chemical species in solution S1? = [tex]Fe^{2+}[/tex]
What are the chemical species in solution S2? = [tex]Ni^{2+}[/tex]
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Consider the titration of 100.0 mL of 0.59 M H3A by 0.59 M KOH for the next three questions. The triprotic acid has Ka1 = 1.0 x 10-3, Ka2 = 1.0 x 10-6, and an unknown value for Ka3.1) Calculate the pH after 100.0 mL of KOH has been added.2) Calculate the pH after 150.0 mL of KOH has been added.3) The pH of the solution after 200.0 mL of KOH has been added is 8.00. Determine the value of Ka3 for this triprotic acid. Use scientific notation to enter this answer, e.g., 1.0 x 10-3 = 1.0E-3.
Acid concentration: 0.49 M KOH concentration is 0.49 MKa1=1.0 x 104 eq. rm
a remedy for Take the example of titrating 100 mL of 0.100 M HOCl with 0.100 M KOH at 25 °C. HOCl has a Ka of 3.5 10-8. Calculate the pH after 0.0 mL of KOH in Part 1.
Consider titrating 0.115 M RbOH in a 25.0 mL sample with 0.100 M HCl. Figure out each quantity. The initial pH and the amount of acid that must be added to achieve the equivalence point are also factors. c. the pH after adding 5.0 mL of acid. pH at the equivalency point (d). e. the pH following the addition of 5.0 mL of acid over the equivalency point.
Think about titrating 100 mL of 0.59 M H 3 a 1-3 a2-6 a3. 1) Determine the pH following
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How many compounds, of the ones listed below, have hydrogen bonding?CH3CH2CH2NH2 CH3CH2NHCH2CH3 (CH3CH2)2NCH2CH32130
Since CH3CH2CH2NH2 may form intermolecular hydrogen bonds, it has a higher boiling point than other compounds. The hydrogen atoms in (CH3)3N (C H 3) 3 N are joined to the carbon atoms.
Since carbon is not a particularly electronegative atom, it cannot donate hydrogen. There aren't any hydrogen atoms to accept, despite the fact that nitrogen is a strong hydrogen atoms. As a result, CH3CH2CH2CH3 is a nonpolar molecular complex in which induced dipole forces are the only intermolecular forces. When both the donor atom, D, and the acceptor atom, A, are among the highly electronegative elements O, N, or F, hydrogen bonding occurs, as shown by the symbol D-H—-A.
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zones in lakes and oceans are delineated by depth, distance from shore, or light penetration. different zones have different physical and chemical characteristics, such as temperature and salinity. label the diagrams of zonation in lakes and oceans. drag the labels to their correct targets on the diagrams below.
The diagrams of zonation in lakes and oceans with correct targets are :
a) fresh plant may be rooted here
b) littoral zone
c) limnetic zone
d) alternately dry and submerged
e) extends to edge of the continental shelf
f) generally low nutrient levels
g) light penetrates here
h) no photosynthesis occurs here
i) benthic zone
There are zones which divided the lakes. they are separated by the water from the top to bottom and the side to the side. that is named as : the littoral zone , the limnetic zone, the profundal zone , the benthic zone and the euphotic zone . the waters temperature will be affected the density. there are several zones in the ponds and the lakes. these are dived by the water column.
The limnology divides the lakes in the three types of zones ., that is the limnetic zone, the littoral zone and the benthic zone.
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It is not necessary for velocity measurements to be made in units of concentration per time (M.5-?, for example) in order to calculate Km because the Km is a concentration (the concentration when the velocity equals the velocity divided by two. Question 18 Enzyme A catalyzes the reaction S + P and has a KM of 50 MM and a Vmax of 100 nM.5-1. Enzyme B catalyzes the reaction S → and has a km of 5 mM and a Vmax of 120 nM s 1. When 100 M of S is added to a mixture containing equivalent amounts of enzymes A and B, after 1 minute will be more abundant because . Because is has a much for the two for the substrate than enzymes, the relative efficiency of the enzymes depends almost entirely on their values.
Velocity can be measured using whatever comfortable unit of transition per unit of time. KM is a substrate concentration by meaning (the concentration when vo = Vmax/2), so its valuation doesn't really represent how well the velocity is measured.
The metre per second (m/s) is the basic measure of velocity magnitude (also referred as speed). Alternatively, velocity magnitude could be given in centimetres per second (cm/s). The orientation of a velocity vector can be expressed in different ways, according to the number of variables involved. The Michaelis constant (KM) is defined as the quantity of substrate at which the reaction rate is half of its maximum (or in other words it defines the substrate concentration at which half of the active sites are occupied).
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The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row You will find it useful to keep in mind that NH3 is a weak base. acids ,口, 1.3 mol of HNO3 is added to 1.0 L of a 1.3 MNH, solution bases: other acids: bases: - 0.57 mol of KOH is added to 1.0 L of a solution that is 1.2 M in both NH3 and NH4CI. other:
a) NaFi is formed when 1 mol of NaOH is oriented to 1.0 L of a 0.5 M HF mixture.
b) To 1.0 L of a solution that is 0.8 M in both HF & KF-producing KF, 0.3 mol of KOH is added.
An acid generates the hydronium ions H3O+ in an aqueous solution, whereas a base creates the hydroxide ions OH. Water and salt are the byproducts of the neutralization process that occurs when an acid and a base interact.
A) 1 mol of NaOH is counted to 1.0 L of a 0.5 M HF resolution.
The reaction involved in this is:
NaOH + HF → NaF + H2O
acid: HF
base: NaOH
species that neither creates an acid and neither a base nor a salt NaF
b) To 1.0 L of a mixture that seems to be 0.8 M in both HF as well as KF, 0.3 mol of KOH is added.
The reaction involved in this is:
KOH + HF → KF + H2O
acid: HF
base: KOH
the mixture that could be neither an acid nor a base or salt delivered: KF
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The question is -
The preparations of two aqueous solutions are described below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself.
For each of the questions, write the chemical formulas of the species that will act as acids, the formulas of the species that will act as bases, and the formulas of the species that will act as neither acids nor bases. Note that HF is a weak acid.
A) 1 mol of NaOH is added to 1.0 L of a 0.5 M HF solution.
B) 0.3 mol of KOH is added to 1.0 L of a solution that is 0.8 M in both HF and KF.
The formation of sodium chloride from sodium and chlorine is an
example of a simple Redox reaction. This reaction is displayed
below.
2Na(s) + Cl2(g) → 2NaCl(s)
Explain (with reference to changes in oxidation states) why this
is a Redox reaction and again with reference to it, explain what
is meant by the terms ‘reducing agent’ and ‘oxidising agent’.
The sodium is oxidized while the chlorine atom is reduced from the equation.
What is a redox reaction?We know that a redox reaction is the kind of reaction that involves the change in the oxidation number of a substance. The oxidation number is the magnitude of the charge that a specie appears to have. In this case, we can see that the reaction that has been shown here has to do with a change in the oxidation number of the species that are involved in the reaction from left to right.
We can see that on the right hand side, the sodium and chlorine are both in an oxidation state of zero. If we move to the right hand side, the oxidation number of the sodium can be seen to haver increased to +1 while the oxidation n umber of the chlorine can be seen to have been decreased to - 1.
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i can not figure out this question to save my life
Specific heat capacity of a substance is the amount of heat required to raise the temperature by one degree Celsius of one gram of a substance. Therefore, the total enthalpy of the given reaction is -781.44KJ.
What is Enthalpy?Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances.
Mathematically,
q = n ×ΔH
where
q = amount of heat
n = no of moles
ΔH = enthalpy
n = w / M.M
w = given mass
M.M = molar mass
4CH[tex]_3[/tex]NH[tex]_2[/tex]+2H[tex]_2[/tex]O[tex]\rightarrow[/tex]3CH[tex]_4[/tex]+CO[tex]_2[/tex]+4NH[tex]_3[/tex] ΔH=-138.8KJ
number of moles of methyl amine=175/31.06
=5.63moles
enthalpy for reaction of one mole of methyl amine=-138.8KJ
enthalpy for reaction of 5.63 mole of methyl amine=-138.8KJ×5.63
=-781.44KJ
Therefore, the total enthalpy of the given reaction is -781.44KJ.
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given the reaction: 234 91 pa x 0 -1e when the equation is correctly balanced the nucleus represented by x is
The reaction is given : ²³⁴Pa₉₁ -----> X + ⁰e₋₁ , the equation is balanced and the nucleus represented by X is ²³⁴U₉₂.
The balanced reaction is given as :
²³⁴Pa₉₁ -----> X + ⁰e₋₁
This reaction is the balanced reaction and X is represented the nucleus and is given as : ²³⁴U₉₂.
The given reaction is the nuclear reaction. the nuclear reaction is the reaction in which the nuclides are produced by the collision between the two atoms nuclei. the nuclear reaction are of the two types the nuclear fission and the nuclear fusion reaction. the nuclear fission is the splitting of the large nuclei in to the smaller ones.
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this method of acquiring mw differs from sec and gives dosy nmr many advantages over sec. as stated before, molecules of specific sizes produce indi-vidual diffusion coefficients. due to low sample con-centration, the purity of polymer is not as essential compared to sec; thus, reducing preparation time. dosy also requires minimum amounts of solvent
A well-known NMR technique called diffusion ordered spectroscopy (DOSY) provides diffusion coefficients for specific resonances in NMR spectra.
The main applications of DOSY are the analysis of small molecule mixtures and the oligomeric state of biomolecules. The spreading Self-Diffusion (SD)-NMR and diffusion ordered spectroscopy are two common names for the NMR technology (DOSY). This is accomplished by fusing magnetic field gradients, which encode spatial information, with radio-frequency pulses, which are commonly employed in NMR spectroscopy. Magnetic field gradients are used by Diffusion Ordered Spectroscopy (DOSY) to examine diffusion processes in both solid and liquid materials. Liquid structure is discovered using NMR spectroscopy. It is also used to figure out how soluble chemical molecules are structured.
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What is the formula for cobalt (III) oxide?
Co3O2
Co2O3
Co3O
CoO3
Answer:Co2O3
Explanation:
look it up
Answer:
Co2O3
Explanation:
when you write any formula you apply the criss-cross method where you write the charges of each substance
Co3 and O2
applying the criss-cross method( you switch the charges number, in this case you switch the 2 and the 3) :-
Co2 and O3
so Co2O3
What mass of silver will be precipitated when 5.0g of copper are reacted with
excess of silver nitrate solution?
Cu(s) + 2AgNO3(aq) → Cu(NO3)₂(aq) + 2Ag(s)
As per the given balanced reaction, one mole or 63.5 g of Cu produces 2 moles or 215.6 g of silver metal. Hence, 5 g of copper produces16.9 g of Ag.
What is displacement reaction?A displacement reaction is a type of reaction, in which one element or group of the reactant is displaced by the attacking group or element. The reaction between copper and silver nitrate is an example of single displacement reaction.
Given the balanced equation of the reaction. One mole of Cu produces 2 moles of Ag.
atomic mass of Cu = 63.5 g/mol
atomic mass of Ag = 107.8 g/mol
mass 2 moles of Ag = 2 × 107.8 =215.6 g.
Hence, 63.5 g of Cu produces 215.6 g of Ag.
The mass of Ag produced by 5 g of Cu is calculated as follows:
mass of Ag = (5 × 215.6 g) /63.5 g = 16.9 g
Therefore, the mass of silver precipitated will be 16.9 g.
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Epinephrine is a hormone secreted into the bloodstream in times of danger and stress. It is 59% Carbon, 7.1% Hydrogen, 26.2% Oxygen and 7.7% Nitrogen by mass. Determine the empirical formula. The molar mass is 148 g/mol.
Based o the percentage masses of the elements, the empirical formula of epinephrine is C₉H₁₃O₃N.
What is the empirical formula of epinephrine?The empirical formula of epinephrine is calculated below as follow:
Mole ratio of the elements are determined:
Carbon = 59% / 12
Carbon = 0.049 moles
Hydrogen = 7.1% / 1
Hydrogen = 0.07 moles
Oxygen = 26.2% / 16
Oxygen = 0.016
Nitrogen = 7.7% / 14
Nitrogen = 0.0055
The simplest whole-number ratio will be:
C = 0.049/0.0055
C = 9
Hydrogen = 0.07/0.0055
H = 13
Oxygen = 0.016/0.0055
Oxygen = 3
Nitrogen = 0.0055/0.0055
Nitrogen = 1
The empirical formula = C₉H₁₃O₃N
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when circuit town electronics sets its televisions at three price levels of $699, $899, and $1,099, it is most likely using .
When circuit town electronics sets its televisions at three price levels of $699, $899, and $1,099, it is most likely using product line pricing.
Product line pricing involves the separation of goods and services into cost categories in order to create various perceived quality levels in the minds of consumers. You might also hear product line pricing referred to as price lining, but they refer to the same practice.Selling a product at or below cost to lure customers in and drive other sales is an example of product-line pricing. A restaurant, for example, might offer a low-priced entrée with the purchase of a drink and dessert that have higher profit margins.A product line refers to a particular good or service that a company makes and markets to customers. A food company may extend a product line by adding various similar or related products (e.g., adding mesquite BBQ flavor to its existing potato chips line), and create a more diversified product family.Using product line pricing allows companies to target customers with low-end, mid-range and high-end budgets. By offering two, three or more product tiers, a company can reach a much larger range of customers. This grants companies the potential to attain more sales and greater brand recognition.
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An organism with the genotype of AaXx can produce gametes containing _________ if the two genes are unlinked.
a. either Aa or Xx
b. either AX, Ax, aX, ax
c. AaXx
d. AX or ax
e. None of the above.
An organism with the genotype of AaXx can produce gametes containing either AX, Ax, aX, ax if the two genes are unlinked .
An organism's genotype is the complete set of its genetic material. [1] Genotype can also be used to refer to the alleles or variants that an individual has at a particular gene or locus. The number of alleles an individual can have for a particular gene depends on the number of copies of each chromosome (also called polyploidy) found in that species. Diploid species like humans have two complete sets of chromosomes. This means that each individual has her two alleles for a particular gene. If both alleles are the same, the genotype is said to be homozygous. If the alleles are different, the genotype is called heterozygous.
Genotypes contribute to the phenotype, observable traits and characteristics of an individual or organism. The extent to which genotype influences phenotype depends on the trait.
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