The following data represent the number of housing starts predicted for the 2nd quarter (April through June) of 2014 for a random sample of 40 economists.

984 1260 1009 992 975 993 1025 1164 1060
992 1100 942 1050 1047 1000 938 1035 1030
964 970 1061 1067 1100 1095 976 1012 1038
929 920 996 990 1095 1178 1017 980 1125
964 888 946 1004

Required:
a. Draw a histogram of the data.
b. Construct a 95 % confidence interval for the population mean forecast of the number of housing starts in the second quarter of 2014.
c. Construct a 90% confidence interval for the population mean forecast of the number of housing starts in the second quarter of 2014

Answers

Answer 1

Answer:

Kindly check attached picture ;

(999.494 ; 1046.056) ;

(1003.235 ; 1042.315)

Step-by-step explanation:

Given the data:

888, 920, 929, 938, 942, 946, 964, 964, 970, 975, 976, 980, 984, 990, 992, 992, 993, 996, 1000, 1004, 1009, 1012, 1017, 1025, 1030, 1035, 1038, 1047, 1050, 1060, 1061, 1067, 1095, 1095, 1100, 1100, 1125, 1164, 1178, 1260

Using calculator to obtain the mean and standard deviation :

Mean, x = 1022.775

Standard deviation, s = 75.124

Sample size, n = 40

Zcritical at 95% = 1.96

Zcritical at 90% = 1.645

Using the relation :

x ± E

E = error margin = Zcritical * s / sqrt(n)

At 95% ;

Error margin = 1.96 * 75.124/ sqrt(40) = 23.281

At 90% ;

Error margin = 1.645 * 75.124/ sqrt(40) = 19.540

Confidence interval at 95%:

(1022.775 - 23.281) ;(1022.775 + 23.281)

(999.494 ; 1046.056)

Confidence interval at 90%:

(1022.775 - 19.540) ;(1022.775 + 19.540)

(1003.235 ; 1042.315)

The Following Data Represent The Number Of Housing Starts Predicted For The 2nd Quarter (April Through

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Step-by-step explanation:

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9514 1404 393

Answer:

  (b)  Output 6, Input 8

Step-by-step explanation:

One of the things you can look at is the ratio of output to input. Here, it is constant, which makes things a lot easier

  output/input = 12/2 = 30/5 = 66/11 = 6

Then for input 1, output is 1×6 = 6.

For unknown input, we have ...

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__

The two blanks are ...

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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

Step-by-step explanation:

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El desplazamiento (en metros) de una partícula que se mueve
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Answer:

c

Step-by-step explanation:

hize la misma pregunta que vos

The average velocities for the given time intervals are,

(i) -8 m/s,

(ii) -12 m/s,

(iii) 4 m/s, and

(iv) 4 m/s. The instantaneous velocity at t = 4 is -8 m/s. The attached graph of s as a function of t is a straight line with slope -8, showing the secant and tangent lines.

a) To find the average velocity in each time interval,

calculate the change in displacement (Δs) divided by the change in time (Δt) within each interval.

s = 12 - 8t + 18

i) [3, 4]:

Δs = s(4) - s(3) = (12 - 8(4) + 18) - (12 - 8(3) + 18) = -8

Δt = 4 - 3 = 1

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iii) [4, 5]:

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Δt = 5 - 4 = 1

Average velocity = Δs / Δt = 4 / 1 = 4 m/s

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Attached graph.

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Secant lines:

Draw a straight line connecting the points (3, 10) and (4, 2) for the interval [3, 4].

Draw a straight line connecting the points (3.5, 4) and (4, 2) for the interval [3.5, 4].

Draw a straight line connecting the points (4, 2) and (5, 6) for the interval [4, 5].

Draw a straight line connecting the points (4, 2) and (4.5, 4) for the interval [4, 4.5].

Tangent line:

At t = 4, draw a straight line with a slope of -8 and passing through the point (4, 2).

The attached graph will show the secant lines with different slopes as the average velocities in each interval and the tangent line with a slope of -8 as the instantaneous velocity at t = 4.

learn more about average velocity here

brainly.com/question/32663715

#SPJ2

The above question is incomplete , the complete question is:

The displacement (in meters) of a moving particle

in a straight line is given by s = 12 – 8t + 18, where t is

measured in seconds.

a) Find the average velocity in each time interval:

i) [3, 4] ii) [3.5, 4]

iii) [4, 5] iv) [4, 4.5]

b) Find the instantaneous velocity when t = 4.

c) Plot s as a function of t and draw the secant lines whose slopes are the average velocity in part (a) and the tangent line whose slope is the

instantaneous velocity in part (b).

POSSIBLE POINTS: 15
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Step-by-step explanation:

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