The following data represent the weights in pounds of a sample of 25 police officers:

164, 148, 137, 157, 173, 156, 177, 172, 169, 165, 145, 168, 163, 162, 174, 152, 156, 168, 154, 151, 174, 146, 134, 140, and 171.

Required:
a. Determine the location and value of the lower quartile of the weights
b. Determine the location and value of the upper quartile of the weights.
c. Find the interquartile range of the weights.

Answers

Answer 1

Given:

The data values are:

164, 148, 137, 157, 173, 156, 177, 172, 169, 165, 145, 168, 163, 162, 174, 152, 156, 168, 154, 151, 174, 146, 134, 140, and 171.

To find;

a. Lower quartile.

b. Upper quartile.

c. Interquartile range.

Solution:

We have,

164, 148, 137, 157, 173, 156, 177, 172, 169, 165, 145, 168, 163, 162, 174, 152, 156, 168, 154, 151, 174, 146, 134, 140, 171.

Arrange the data values in ascending order.

134, 137, 140, 145, 146, 148, 151, 152, 154, 156, 156, 157, 162, 163, 164, 165, 168, 168, 169, 171, 172, 173, 174, 174, 177.

Divide the data values in two equal parts.

(134, 137, 140, 145, 146, 148, 151, 152, 154, 156, 156, 157), 162, (163, 164, 165, 168, 168, 169, 171, 172, 173, 174, 174, 177)

Divide each parentheses in two equal parts.

(134, 137, 140, 145, 146, 148), (151, 152, 154, 156, 156, 157), 162, (163, 164, 165, 168, 168, 169), (171, 172, 173, 174, 174, 177)

a. Location of lower quartile is:

[tex]Q_1=\dfrac{1}{4}(n+1)\text{th term}[/tex]

[tex]Q_1=\dfrac{1}{4}(25+1)\text{th term}[/tex]

[tex]Q_1=\dfrac{26}{4}\text{th term}[/tex]

[tex]Q_1=6.5\text{th term}[/tex]

The lower quartile of the weights is:

[tex]Q_1=\dfrac{148+151}{2}[/tex]

[tex]Q_1=\dfrac{299}{2}[/tex]

[tex]Q_1=149.5[/tex]

Therefore, the location of the lower quartile of the weights is between 6th term and the 7th term. The value of the lower quartile is 149.5.

b. Location of upper quartile is:

[tex]Q_3=\dfrac{3}{4}(n+1)\text{th term}[/tex]

[tex]Q_3=\dfrac{3}{4}(25+1)\text{th term}[/tex]

[tex]Q_3=\dfrac{3\cdot 26}{4}\text{th term}[/tex]

[tex]Q_3=19.5\text{th term}[/tex]

The upper quartile of the weights is:

[tex]Q_3=\dfrac{169+171}{2}[/tex]

[tex]Q_3=\dfrac{340}{2}[/tex]

[tex]Q_3=170[/tex]

Therefore, the location of the upper quartile of the weights is between 19th term and the 20th term. The value of the upper quartile is 170.

c. The interquartile range of the given data set is:

[tex]IQR=Q_3-Q_1[/tex]

[tex]IQR=170-149.5[/tex]

[tex]IQR=20.5[/tex]

Therefore, the interquartile range of the weights is 20.5.


Related Questions

The perimeter of a parallelogram must be no less than 40 feet. The length of the rectangle is 6 feet. What are the possible measurements of the width? Write an inequality to represent this problem. Use w to represent the width of the parallelogram. [Hint: The formula for finding the perimeter of a parallelogram is P = 2 l + 2 w . What is the smallest possible measurement of the width? Justify your answer by showing all your work.

Answers

Answer: [tex]14\ ft[/tex]

Step-by-step explanation:

Given

Length of rectangle is [tex]6\ ft[/tex]

Perimeter must be greater than 40 ft

Suppose l and w be the length and width of the rectangle

[tex]\Rightarrow \text{Perimeter P=}2(l+w)\\\Rightarrow P\geq 40\\\Rightarrow 2(l+w)\geq40\\\Rightarrow l+w\geq20\\\Rightarrow w\geq20-6\\\Rightarrow w\geq14\ ft[/tex]

So, the smallest width can be [tex]14\ ft[/tex]

1/6 of ______ equals 9

What is the blank?

Answers

Answer:

54

Step-by-step explanation:

1/6 × y = 9

y ÷ 6 = 9

y ÷ 6 × 6 = 9 × 6

y = 54

16. Using divisibility tests, check whether the number 240720 is divisible by
2, 3, 4, 5, 6, 8, 9, 10 and 11. (Give reason)

Answers

2: it is, because last digit is even
3: it is, because the sum of the digit, 2+4+7+2=15, is divisible by 3
4. it is, because the last 2 digits, 20, is divisible by 4
5. it is, because last digit is 0
6. it is, because it is divisible by 2 and 3
8. it is, because the last 3 digits, 720, is divisible by 8
9. It is not, because the sum of the digits, which is 15, is not divisible by 9
10. It is, because the last digit is 0
11. It is not, because the difference of alternating digits, which is 2+0+2-4-7-0, is not divisible by 11

At the beginning of a population study, a city had 320,000 people. Each year since, the population has grown by 2.1%. Lett be the number of years since start of the study. Let y be the city's population. Write an exponential function showing the relationship between y and t. ​

Answers

Answer:

y = 320,000(2.1)^t

Step-by-step explanation:

uhm, im not very good at explaining, but everytime the year increases, the population will exponentially increase, that's why 't' is an exponent

Answer:

[tex]y=320000(1.021)^t[/tex]

Step-by-step explanation:

To increase something by x% mulitply it by (1+x)

in other words, to increase sometihng by 2.1% mulitply it by

(1+.021) or 1.021

because we are mulitplying 320000 by 1.021 each year we can write the equation as

y=320000(1.021)^t

100° - y А (x+2) units Match the values based on parallelogram ABCD, shown in the figure. length of BC value of y mZDAB value of I 56 4 44 2​

Answers

Answer:

BC = 4 units

Value fo y = 44

∠DAB = 56°

Value of x = 2

Step-by-step explanation:

100 - y = 12 + y  (opposite angles of parallelogram are equal)

2y = 88

y = 44

Similarly,

6-x = x+2   (opposite sides of parallelogram are equal)

2x = 4

x = 2

Differentiate the function. y = (2x - 5)^2 (5 - x)?​

Answers

Answer:

[tex]\displaystyle y' = -(2x - 5)(6x - 25)[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Distributive Property

Algebra I

Terms/CoefficientsFactoring

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                                    [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Chain Rule]:                                                                                       [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

y = (2x - 5)²(5 - x)

Step 2: Differentiate

Derivative Rule [Product Rule]:                                                                        [tex]\displaystyle y' = \frac{d}{dx}[(2x - 5)^2](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Chain Rule [Basic Power Rule]:                                                                        [tex]\displaystyle y' = [2(2x - 5)^{2 - 1} \cdot \frac{d}{dx}[2x]](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Simplify:                                                                                                             [tex]\displaystyle y' = [2(2x - 5) \cdot \frac{d}{dx}[2x]](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Basic Power Rule:                                                                                             [tex]\displaystyle y' = [2(2x - 5) \cdot 1 \cdot 2x^{1 - 1}](5 - x) + (2x - 5)^2(1 \cdot -x^{1 - 1})][/tex]Simplify:                                                                                                             [tex]\displaystyle y' = [2(2x - 5) \cdot 2](5 - x) + (2x - 5)^2(-1)[/tex]Multiply:                                                                                                             [tex]\displaystyle y' = 4(2x - 5)(5 - x) - (2x - 5)^2[/tex]Factor:                                                                                                               [tex]\displaystyle y' = (2x - 5)[4(5 - x) - (2x - 5)][/tex][Distributive Property] Distribute 4:                                                                 [tex]\displaystyle y' = (2x - 5)[20 - 4x - (2x - 5)][/tex][Distributive Property] Distribute negative:                                                    [tex]\displaystyle y' = (2x - 5)[20 - 4x - 2x + 5][/tex][Subtraction] Combine like terms (x):                                                              [tex]\displaystyle y' = (2x - 5)[20 - 6x + 5][/tex][Addition] Combine like terms:                                                                        [tex]\displaystyle y' = (2x - 5)(25 - 6x)[/tex]Factor:                                                                                                               [tex]\displaystyle y' = -(2x - 5)(6x - 25)[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

WILL MARK YOU IF YOU ANSWER SO PLEASE HELP

Answers

Answer:

x= 83

first take vertical opposite angle then take corresponding angles then you're done

Answer:

x value is 83 degree

because they both are alternate exterior angle

Sketch the region enclosed by the given curves and calculate its area.
y=4-x^2 ,y=0

The answer is 32/3. But how do I get to that answer?

Answers

Answer:

Step-by-step explanation:

1.) we need to find the bounds of integration which is just the points of intersection

here is it (-2,0) and (2,0)

which means we will integrate from -2 to 2

next, we take the upper equation and subtract that from the lower one

kind of confusing but it would look like (sketch it out if you're not sure)

(4-x²)-0= 4-x²

then we can integrate

[tex]\int\limits^2_{-2} {4-x^2} \, dx =4x-\frac{x^3}{3}|_{-2}^{2}=(4*(2)-\frac{2^3}{3})-(4(-2)-\frac{-2^3}{3})=5.333333-(-5.3333333)= 10.666666667=\frac{32}{3}[/tex]

Solve for y.
r/3-2/y=s/5

Answers

Answer:

y = 2 / (r/3 - s/5)

Step-by-step explanation:

r/3 - 2/y = s/5

add 2/y to both sides

r/3 = s/5 + 2/y

Subtract s/5 from both sides

r/3 - s/5 = 2/y

multiply both sides by y

y(r/3 - s/5) = 2

Divide both sides by r/3 - s/5

y = 2 / (r/3 - s/5)

A trinomial is a perfect square when two terms are
a. Positive
b.negative
c. Neither positve
d. Either negative

Answers

Answer:

a trinomial is a perfect square trinomial if it can be factorized into a binomial multiplies to itself. In a perfect square trinomial, two of your terms will be perfect squares.

The manufacturer claims the mean bursting pressure for a certain type and size of PVC irrigation pipe to be at least 350 psi. A sample of 10 such pipes were experimentally determined to have the following bursting pressures: 401 359 383 427 414 415 389 463 394 428 State the null and alternative hypotheses:

Answers

Answer:

H0 : μ ≥ 350

H1 : μ < 350

Step-by-step explanation:

It is claimed that the mean is atleast 350 psi ;

10 such pipes were experimentally sampled ;

Here, the null hypothesis is the claim ; this means that the alternative hypothesis will be the opposite of the claim.

The hypothesis

H0 : μ ≥ 350

H1 : μ < 350

brainliest answer po yung tama
nk tym for nega NEED HELP PK TALAG​

Answers

A

A

B

C

A

D

B

C

May choices po yan saamen

Step-by-step explanation:

Love you

Solve for T: 10t-4x=3S Explanation plz

Answers

T=3s/10+2x/5 hope this helped <3

Simplify the expression

Answers

Answer:

6

Step-by-step explanation:

3 sqrt(20) / sqrt(5)

We know that sqrt(a) /sqrt(b) = sqrt(a/b)

3 sqrt(20/5)

3 sqrt(4)

3 *2

6

what the person above me said

Joseph borrows $10000 from his sister Katie at an annual interest rate of 10%. If the
interest is compounded twice a year, how much does he owe after 12 months? Give your answer in dollars.

Answers

Answer:

A  =  P  ( 1  + r / n)  ^( t * n)

where

A  =  the amt  owed

P  = amt borrowed

r  = the  interest  rate  as a decimal

n =  the  number of compoundings  per year

t  = the  number of years

A  =    10000  (  1  + .10  / 2)^(2 *1)    =   10000  ( 1.05)^2    =  $11025

Step-by-step explanation:

6
Which expression is equivalent

Answers

Answer:

I thimk it is B

Step-by-step explanation:

Determine the value of x for which r is parallel to s if m angle 1 = 60-2x and m angle 2=70-4x

Answers

Answer:  r = 5

Step-by-step explanation:

Gỉaỉ pt
2x^2×(2x^2+3)=2-x^2 ai giải giúp vs

Answers

2x²×(2x²+3)=2-x²

[tex]x = \frac{1}{2} , - \frac{1}{2} ,i \sqrt{2} , - i \sqrt{2} [/tex]

Find an equation for the line parallel to 3x-5y=2 with​ y-intercept (0,1/5). Write the answer in ​ slope-intercept form.

Answers

y= 3x/5 - 2/5 .i think

This is for my brother’s test
What are the measures of L1 and L2? Show your work or explain your answers.

Answers

Answer:

angle 2 is 75°

osjdiajsjoasnndosnsnd

please help me please help me please help me please help me please help me please help me please​

Answers

Answer:

Q3. 9

Q4. 6

Step-by-step explanation:

Evan wants to make an array of 32 miniature cars What are all the different ways Evan can place the cars? ​

Answers

Answer:

1 × 32,  2 × 16,  4 × 8,  8 × 4,  16 × 2,  32 × 1

Step-by-step explanation:

There are 6 different ways for Evan to create a array of 32 miniature cars.

What is the fundamental principle of multiplication?

Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

An array would constitute the shape of a parallelogram, in which you are essentially solving for s₁ and s₂.

Since there are 32 miniature cars in all, in which both sides, when multiplied, must result in said number:

32 x 1 = 32

2 x 16 = 32

4 x 8 = 32

8 x 4 = 32

16 x 2 = 32

1 x 32 = 32

Hence, There are 6 different ways for Evan to create a array of 32 miniature cars.

Learn more about multiplications;

https://brainly.com/question/14059007

#SPJ2

PLEASE HELP ME WILL MARK YOU JF YOU HELP ME PLEASE!!!

Answers

Answer:

2, 3, 4, 7, 8, 10 I hope

Answers

Congruent by AAS (shown in the example)Congruent by SASCongruent by SSSCongruent by ASANot enough info  (shown in the second example)Congruent by AASCongruent by SASCongruent by SSSCongruent by AASNot congruent

=================================================

Explanations:

As the example shows, we have two pairs of congruent angles and a pair of congruent sides. The side are not between the angles in question. So AAS is slightly different from ASA.We have two pairs of congruent sides, and a pair of congruent angles. The angles are between the sides. So we use SAS which is a valid congruence theorem. Recall that SSA is not a valid theorem, so the order matters.We have three pairs of congruent sides, so we go with SSS. The order doesn't matter here.Similar to problem 1, but now the sides are between the angles. So we go with ASA this time instead of AAS.We unfortunately don't have enough info to determine if the triangles are congruent or not. We need to know something about the side lengths to determine congruency.As the hint suggests, marking the vertical angles will produce the other pair of congruent angles. So that's why we go for AAS (the side is not between the angles).This is similar to problem 2, as both use SAS. Note the unmarked vertical angles which are congruent.This is similar to problem 3. We use SSS here because we have 3 pairs of congruent sides as indicated by the tickmarks.The unmarked vertical angles can get double arcs to show they are congruent. We have a pair of congruent sides that are not between the two pairs of congruent angles, so we go for AAS (problems 1 and 6 also use AAS).For the triangle on the left, the arc is between the tickmarked sides. The triangle on the right has the arc not between the tickmarked sides. So there's no way the triangles are the same. The arc needs to be between the marked sides for each triangle, if we wanted them to be congruent (using SAS).

---------------

Acronyms

SSS = side side side

SAS = side angle side

ASA = angle side angle

AAS = angle angle side

Help me pls I don’t know how to do this

Answers

Answer:

[tex]radius=6.68cm[/tex]

Step-by-step explanation:

Formula to find radius:

[tex]r=\frac{C}{2\pi }[/tex]

[tex]r=42/2\pi[/tex]

[tex]r=42/2(3.14)[/tex]

[tex]r=6.68cm[/tex]

hope this helps......

4. Steven drove from place A to place B at an average speed of 50 km/h. At the same
time, Joseph drove from place B to place A at an average speed of 60 km/h using
the same route. If the distance between A and B were 300 km, what is the distance
between Steven and Joseph after one and one half hours?

5.An owner jeep traveling at an average speed of 70 km/h left the town at 2:00 pm
If it arrived in another town at 6:00 p.m., how far are the two towns?

Answers

Answer:

1. 10 km

2.280 km

please mark my answer as brainliest answer.

the answer is surely correct

4. Steven and Joseph distance between them is 162.5km
5. Two towns are 280km away

what number must you add to complete the square? x^2+24x=50

Answers

Answer:

144

Step-by-step explanation:

Divide the b term which is 24 by 2

Gives you 12, then square it.

that's 144

formula for completing squares is [tex](b/2)^{2}[/tex]

Answer fast please and thanks!

Answers

Answer:

tan 30 = x / 15

General Formulas and Concepts:

Trigonometry

[Right Triangles Only] SOHCAHTOA[Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = 30°

Opposite Leg = x

Adjacent Leg = 15

Step 2: Solve for x

Substitute in variables [tangent]:                                                                     tan 30 = x / 15

Answer:

3rd one

Step-by-step explanation:

Recall that

Sin = opposite over hypotenuse

Cos = adjacent over hypotenuse

Tan = opposite over adjacent

For the angle with a measure of 30 degrees we are given it's adjacent side length and need to find it's opposite side length

When dealing with opposite and adjacent we use tangent

If tan = opposite over adjacent

Then tan30 = x / 15 and the correct answer choice is the third one

Rewrite the equation by completing the square.
x^2 + 7x + 12 = 0

Answers

Answer:

x^2 + 7x + 12 = 0

x^2 + 7x  = -12

(+3)(+4)=0

=−3

=−4

I also love r        o      blox

Hope This Helps!!!

Answer:

(x + [tex]\frac{7}{2}[/tex] )² - [tex]\frac{1}{4}[/tex] = 0

Step-by-step explanation:

Given

x² + 7x + 12 = 0

To complete the square

add/subtract ( half the coefficient of the x- term)² to x² + 7x

x² + 2([tex]\frac{7}{2}[/tex] )x + [tex]\frac{49}{4}[/tex] - [tex]\frac{49}{4}[/tex] + 12 = 0

(x + [tex]\frac{7}{2}[/tex] )² - [tex]\frac{49}{4}[/tex] + [tex]\frac{48}{4}[/tex] = 0 , that is

(x + [tex]\frac{7}{2}[/tex] )² - [tex]\frac{1}{4}[/tex] = 0

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Answers

mong moi do giup mguoi

A right rectangular container is 10 cm wide and 24 cm long and contains water to a depth of 7cm. A stone is placed in the water and the water rises 2.7 cm. Find the volume of the stone.

Answers

Answer:

The volume of the rock is 648 cm^3

Step-by-step explanation:

Likely the only dimension that is free to move is the depth of 7 cm.

Volume of the Rock = L * W * h1

L = 24

W = 10

h1 = 2.7

V = 24 * 10 * 2.7

V = 648 cm^3

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