The formula for centripetal acceleration, a, is given by this formula, where v is the velocity of the object and r is the object’s distance from the center of the circular path:

A= V2/R

Solve the formula for r.

Answers

Answer 1

Answer:r=v^2/A

Step-by-step explanation: To solve for r means you have to isolate r on one side and put all the other terms on the other. To get r out from under the fraction, multiply both sides by r. This leaves:

A*r=v^2     so to isolate r, divide by A and get:

r=v^2/A.


Related Questions

Warren drives his car 330 miles and has an average of a certain speed. If the average speed had been 3 mph more. he could have traveled 352 miles in the same length
of time. What was his average speed?
Keypad

Answers

Answer:

45 miles per hour

Step-by-step explanation:

d=distance in miles

r=rate miles/hr

t = time in hours

t = 352/(r+3)

330/r = 352/(r+3)

352r = 330r + 990

22r = 990

r = 45

Which of the following demonstrates how the 20 is calculated using the
combination pattern?
1
1
1
1
2
1
1
3
3
1
1
6
4
1
1
5
10
10
5
1
1 6
15
20
15
6
1

Answers

Answer:

2

Step-by-step explanation:

What transformation to the linear parent function, f(x) = x, gives the function
g(x) = x + 7?
O
A. Shift 7 units down.
B. Vertically stretch by a factor of 7.
C. Shift 7 units right.
D. Shift 7 units left.

Helping my home girls for the future

Answers

Hello! I’m sorry that this is not the answer, but do you know what to do when someone is having a panic attack

Determine whether the following fractions terminate in their decimal form. Show all work and explain your reasoning. YOU CAN NOT USE A CALCULATOR. Try not using long division.

Answers

Answer:

8/22: this fraction will NOT terminate

189/270: this fraction WILL terminate

Step-by-step explanation:

I saw in the question that it says to solve the question by demonstrating the method discussed in class. I don't know what's the method you were taught, but I'll explain how I solved it.

When a fraction is in its simplest form, write out the prime factors of the denominator. If the denominator has 2s and/or 5s, the fraction WILL terminate in their decimal form.

8/22 in its simplest form is 4/11:

The only prime factors of the denominator, 11, are 1 and 11. There are no 2s and/or 5s present, so this fraction will NOT terminate.

189/270 in its simplest form is 7/10.

The prime factors of 10 are 2 and 5, meaning that this fraction WILL terminate.

Hope it helps (●'◡'●)

What is the factored form of 125a^6-64?

Answers

Answer:

(5 a^2 - 4) (25 a^4 + 20 a^2 + 16)

Step-by-step explanation:

Since both terms are perfect cubes, factor using the difference of cubes formula,  

a^3  −  b^ 3 = (a − b) (a^2 + a b + b^2) where a = 5a^2   and  b = 4 .

Question 8
Points 3
Identify the functions whose lines are parallel.
0 3x + 2y = 45 and 8x + 4y = 135
x + y = 25 and 2x + y = 15
O 2x + 2y = 50 and 4x + 2y = 90
O 2x + 2y = 4 and 4x + 4y = 16

Answers

Answer:

2x + 2y = 4 and 4x + 4y = 16

Step-by-step explanation:

For two lines to be parallel, they must have the same slope.

To determine the correct answer to the question, we shall determine the slope of each equation in the given options to see which have the same slope. This can be obtained as follow:

1st option:

3x + 2y = 45 and 8x + 4y = 135

We shall rearrange the above equations to look like y = mx + c

NOTE: m is the slope.

3x + 2y = 45

rearrange

2y = –3x + 45

Divide both side by 2

y = –3x/2 + 45/2

Slope (m) = –3/2

8x + 4y = 135

Rearrange

4y = –8x + 135

Divide both side by 4

y = –8x/4 + 135/4

Slope (m) = –8/4 = –2

The two equation has different slopes. Thus, they are not parallel.

2nd option:

x + y = 25 and 2x + y = 15

x + y = 25

Rearrange

y = –x + 25

Slope (m) = –1

2x + y = 15

Rearrange

y = –2x + 15

Slope (m) = –2

The two equations has different slopes. Thus, they are not parallel.

3rd option:

2x + 2y = 50 and 4x + 2y = 90

2x + 2y = 50

Rearrange

2y = –2x + 50

Divide both side by 2

y = –2x/2 + 50/2

Slope (m) = –2/2 = –1

4x + 2y = 90

Rearrange

2y = –4x + 90

Divide both side by 2

y = –4x/2 + 90/2

Slope (m) = –4/2 = –2

The two equations has different slopes. Thus, they are not parallel.

4th option:

2x + 2y = 4 and 4x + 4y = 16

2x + 2y = 4

Rearrange

2y = –2x + 4

Divide both side by 2

y = –2x/2 + 4/2

Slope (m) = –2/2 = –1

4x + 4y = 16

Rearrange

4y = –4x + 16

Divide both side by 4

y = –4x/4 + 16/4

Slope (m) = –4/4 = –1

The two equations have the same slopes. Thus, they are parallel.

Write the quadratic equation in standard form:
3x2 – 3x = 11

Answers

Answer:

[tex]3x^{2} -3x-11 = 0[/tex]

Step-by-step explanation:

The chance of winning the race of the horse A is 1/15 and that of horse B is 1/6. What is
the probability that the race will be won by A or B.

Answers

Answer:

7/30

Step-by-step explanation:

P = 1/15 + 1/6 = (2+5)/30 = 7/30

Help please
The cost, c(x), for parking in a hospital lot is given by c(x) = 5x + 3.00, where x is the number of hours. What does the slope mean in this situation?

Answers

Answer:

The slope is the cost per hour.

$5 per hour

The weight of a newborn is 7.5 pounds. The baby gained one-half pound a month constantly for its first year.
a) Find the linear function that models the baby’s weight, W, as a function of the age of the baby, in
months, t.

b) Find a reasonable domain and range for the function W.

c) If the function W is graphed, find and interpret the x- and y-intercepts.

d) If the function W is graphed, find and interpret the slope of the function.

e) When did the baby weight 10.4 pounds?

f) What is the output when the input is 6.2? Interpret your answer.

Answers

Answer is D if the function W is graphed find and interpret the slope of the function

If the profits in your consulting business increase by 8​% one year and decrease by 2% the following​ year, your profits are up by ​6% over two years.

Answers

Answer:

not true....

assume $100 start.

in year 1 you are at $108 (up 8%)

in year 2  $108(.98) ... that is 2% down = 105.84...

thus your profit is up only 5.84% over the two years

Step-by-step explanation:

Suppose that 70% of all voters prefer Candidate A. If 4 people are chosen at random for a poll, what is the probability that exactly 1 of them favor Candidate A?

Answers

Answer:

0.0756

Step-by-step explanation:

p(success), p = 70% = 0.7

Nunber of trials, n = 4

q = 1 - p = 1 - 0. 7 = 0.3

x = 1

The question meets the requirements of a binomial probability distribution :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 1) = 4C1 * 0.7^1 * 0.3^(4-1)

P(x = 1) = 4C1 * 0.7 * 0.3^3

P(x = 1) = 4 * 0.7 * 0.027

P(x = 1) = 0.0756

Help please asap!!! Thank you!

Answers

Answer:

Here's your answer.

Step-by-step explanation:

Just multiply in

Please explain :)

Expand 5x(x+2)

Thanks :)

Answers

Answer:

[tex] {5 x }^{2} +10x[/tex]

Step-by-step explanation:

[tex]5x(x+2)[/tex]

[tex]5x \times x+5x \times 2[/tex]

[tex]5(x \times x)+5x \times 2[/tex]

[tex]5 {x}^{2} +5x \times 2[/tex]

[tex]5 {x}^{2} + 10x[/tex]

Hope it is helpful....

We have just performed a one-way ANOVA on a given set of data and rejected the null hypothesis for the ANOVA F test. Assume that we are able to perform a randomized block design ANOVA on the same data. For the randomized block design ANOVA, the null hypothesis for equal treatments will ________ be rejected.

Answers

Answer:

The answer is "sometimes".

Step-by-step explanation:

A one-way ANOVA was merely performed on one collected data and the null hypothesis was rejected after an ANOVA F test. Assume we could randomize ANOVA block design with the same information. This null hypothesis for full equality is sometimes rejected for the randomized complete block design ANOVA. Therefore we understand the use of randomized ANOVA block if the null hypothesis is denied of a one-way ANOVA but the rejection of a null RBD ANOVA hypothesis isn't conditional mostly on denial of the yet another ANOVA null.


Show process!!!!!!!
Thank you

Answers

Answer:  45 degrees

======================================================

Work Shown:

We can apply the law of cosines

a^2 = b^2+c^2-2*b*c*cos(A)

(sqrt(5))^2 = (sqrt(2))^2+(3)^2-2*(sqrt(2))*(3)*cos(A)

5 = 2+9-6*(sqrt(2))*cos(A)

5 = 11-6*(sqrt(2))*cos(A)

11-6*(sqrt(2))*cos(A) = 5

-6*(sqrt(2))*cos(A) = 5-11

-6*(sqrt(2))*cos(A) = -6

(sqrt(2))*cos(A) = -6/(-6)

(sqrt(2))*cos(A) = 1

cos(A) = 1/(sqrt(2))

cos(A) = sqrt(2)/2

A = 45 degrees

Use the unit circle for the last step.

Interestingly, this triangle has only one angle that is a whole number. The other two angles are approximate decimal values.

-11 + 4(3+1) + 3(5-9) + 7(6-8) + 25

Answers

Answer:

4

Step-by-step explanation:

-11 + 4(3+1) + 3(5-9) + 7(6-8) + 25

-11+4*4+3*-4+7*-2+25

-11+16+-12+-14+25

4

A large container holds 4 gallons of chocolate milk that has to be poured into bottles. Each bottle holds 2 pints.
If the ratio of gallons to pints is 1: 8,
bottles are required to hold the 4 gallons of milk.

Answers

Answer:

64 Bottles

Step-by-step explanation:

that is the procedure above

6. Aerial photography is to be taken of a tract of land that is 8 x 8 mi2. Flying height will be 4000 ft above average terrain, and the camera has focal length of 6 inches. If the focal plane opening is 9 x 9 in., and minimum side overlap is 30%, how many flight lines will be needed to cover the tract for the given data

Answers

Answer:

the number of flight lines needed is approximately 72

Step-by-step explanation:

Given the data in the question;

Aerial photography is to be taken of a tract of land that is 8 x 8 mi²

L × B = 8 x 8 mi²

Flying height H = 4000 ft = ( 4000 × 12 )inches = 48000 in

focal length f = 6 in

[tex]l[/tex] × b = 9 × 9 in²

side overlap = 30% = 0.3

meaning remaining side overlap = 100% - 30% = 70% = 0.7

{ not end to end overlap }

we take 100% { remaining overlap }

[tex]l[/tex]' = 9 × 100% = 9 in

b' = 9 × 70% = 6.3 in

Now the scale will be;

Scale = f/H

we substitute

Scale = 6 in /  48000 in = 1 / 8000

so our scale is; 1 : 8000

⇒ 1 in = 8000 in

⇒ 1 in = (8000 / 63360)mi

⇒ 1 in = 0.126 mi

so since

L × B = 8 x 8 mi²

[tex]l[/tex]' = ( 9 × 0.126 mi ) = 1.134 mi

b' = ( 6.3 × 0.126 mi ) = 0.7938 mi

Now we get the flight lines;

N = ( L × B ) / ( [tex]l[/tex]' × b' )

we substitute

N = ( 8 mi × 8 mi ) / ( 1.134 mi × 0.7938 mi )

N = 64 / 0.9001692

N = 71.0977 ≈ 72

Therefore, the number of flight lines needed is approximately 72

Which are correct representations of the inequality -3(2x - 5) <5(2 - x)? Select two options.
Ox45)
0 - 6x - 5 < 10 - x
0 -6x + 15 < 10 - 5
E

-
3
5
2
-1
0
1
2
3

Answers

Answer:

45.9

Step-by-step explanation:

So for this problem I got 0.00023833 however it is not accepting my answer. If I rounded 4 decimal places it would be 0.000. How would I go about this problem? Can someone please help?

Answers

Answer:

0.0002

Step-by-step explanation:

4 decimal places means tenths, hundredths, thousandths, and ten thousandths places. If we count 4 decimal places, we come to 0.0002. The number next to it, 3, rounds down, so the answer should be 0.0002.

what's the value of the function f(x)= 2x+5 if x=3

Answers

Answer:

f(x) = 2(3) + 5

= 6 + 5 = 11

y = 11

x = 3

hope it helps.

Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.

M H To determine the number of deer in a game preserve, a conservationist catches 412 deer, tags them and lets them loose. Later, 316 deer are caught, 158 of them are tagged. How many deer are in the preserve?​

Answers

Answer:

There are 824 deer in the preserve.

Step-by-step explanation:

Since to determine the number of deer in a game preserve, a conservationist catches 412 deer, tags them and lets them loose, and later, 316 deer are caught, 158 of them are tagged, to determine how many deer are in the preserve you must perform the following calculation:

316 = 100

158 = X

158 x 100/316 = X

50 = X

50 = 412

100 = X

824 = X

Therefore, there are 824 deer in the preserve.

Factor 2x^2+15x+25. Rewrite the trinomial with the x-term expanded,using the two factors. Then, group the first two and last two terms together and find the GCF of each.

Answers

Answer:

[tex][x + 5][2x+ 5][/tex]

Step-by-step explanation:

Given

[tex]2x^2 + 15x + 25[/tex]

Required

Factorize

Expand the x term

[tex]2x^2 + 5x + 10x+ 25[/tex]

Group into 2

[tex][2x^2 + 5x] + [10x+ 25][/tex]

Take the GCF of each group

[tex]x[2x + 5] + 5[2x+ 5][/tex]

Factor out 2x + 5

[tex][x + 5][2x+ 5][/tex]

Identify the quantities that are equivalent to 250 meters.

Ratio Conversion Table
kilometer (km) : meter (m) 1 : 1,000
meter (m) : centimeter (cm) 1 : 100
centimeter (cm) : millimeter (mm) 1 : 10

Answers

Answer:

1. Convert all measurements to meters:

2.5km * 1,000 = 2,500m;.250km * 1,000 = 250m; 2,500cm / 100 = 25m

25,000cm / 100 = 250m; 250mm / 1,000 =.25m

2.) Compare the converted measurements. Therefore, the quantities that are equivalent to 250m are:

.250km; 25,000cm

Step-by-step explanation:

Which of the following indicates that Triangle ABC and Triangle DEF are similar?

Answers

Answer:

D

Step-by-step explanation:

The symbol ~ means similarity (same shapes, not same size)

your answer is going to be D!!

Respond to each of the four questions.

Describe the steps to graphing a linear equation. Be sure to provide an example to illustrate your description.
Describe the steps to graphing a quadratic equation. Be sure to provide an example to illustrate your description.
Describe how to solve a linear equation. Be sure to provide an example to illustrate your description.
Describe how to solve a quadratic equation. Be sure to provide an example to illustrate your description.

Answers

Answer:hello

Step-by-step explanation:

1+1

Suppose the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 11 million dollars. If incomes for the industry are distributed normally, what is the probability that a randomly selected firm will earn less than 114 million dollars

Answers

Answer:

95.73%

Step-by-step explanation:

Given data:

mean μ= 95

standard deviation, σ = 11

to calculate, the probability that a randomly selected firm will earn less than 114 million dollars;

Use normal distribution formula

[tex]P(X<114)=P(Z<\frac{X-\mu}{\sigma} )[/tex]

Substitute the required values in the above equation;

[tex]P(X<114)=P(Z<\frac{114-95}{11} )\\P(X<114)=P(Z<1.7272)\\P(X<114)=0.9573[/tex]

Therefore, the probability that a randomly selected firm will earn less than 114 million dollars = 95.73%

Find the missing term in the pattern.

Answers

Answer:

20

Step-by-step explanation:

6 + 2 = 8

8 + 3 = 11

11 + 4 =15

15 + 5 =20

Answer:

20

Step-by-step explanation:

the pattern is increase the number by one more than the increase before. so 6,8=2 greater

8-11=3 greater. 11-15=4 greater. so, 15+5=20 (with this answer being 5 greater continuing the pattern.)

What is the average rate of increase in enrollment
per
decade between 1950 and 2000?

Answers

Given:

The graph that represents the enrollment for college R between 1950 and 2000.

To find:

The average rate of increase in enrollment per decade between 1950 and 2000?

Solution:

The average rate of change of function f(x) over the interval [a,b] is:

[tex]m=\dfrac{f(b)-f(a)}{b-a}[/tex]

So, the average rate of increase in enrollment per year between 1950 and 2000 is:

[tex]m=\dfrac{f(2000)-f(1950)}{2000-1950}[/tex]

[tex]m=\dfrac{7-4}{50}[/tex]

[tex]m=\dfrac{3}{50}[/tex]

[tex]m=0.06[/tex]

It is given average rate of increase in enrollment per year between 1950 and 2000 is 0.06.

We need to find the average rate of increase in enrollment per decade between 1950 and 2000, So, multiply the average rate of increase in enrollment per year by 10.

[tex]0.06\times 10=0.6[/tex]

Therefore, the average rate of increase in enrollment per decade between 1950 and 2000 is 0.6.

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