The graph shows the solution to a system of equations. What is that solution?
A) (-2,-2)
B) (2,2)
C) (2,-2)
OD) 1-22)

Answer: wheres the photo ?

Step-by-step explanation:

Answer:

-3-4=-7

-3+(-4)

hope this helps

have a good day :)

Step-by-step explanation:

Answer:- Hey Buddy! Hope this helps:-

12.5%= 125/10 and when simplified becomes 25/2

pls mark brainliest

Answer:

[tex]\displaystyle -x^3+10x^2-48x+64[/tex]

Step-by-step explanation:

We want to find the minimum-degree polynomial with real coefficients and zeros at:

[tex]x= 4+4i\text{ and } x = 2[/tex]

As well as a y-intercept of 64.

By the Complex Root Theorem, if a + bi is a root, then a - bi is also a root.

So, a third root will be 4 - 4i.

The factored form of a polynomial is given by:

[tex]P(x)=a(x-p)(x-q)...[/tex]

Where a is the leading coefficient and p and q are the zeros. More factors can be added if necessary.

Substitute:

[tex]P(x)=a(x-(2))(x-(4+4i))(x-(4-4i))[/tex]

Since we want the minimum degree, we won't need to add any exponents.

Expand the second and third factors:

[tex]\displaystyle \begin{aligned} (x-(4+4i))(x-(4-4i))&=(x-4-4i)(x-4+4i) \\ &= x(x-4-4i)-4(x-4-4i)+4i(x-4-4i)\\ &=x^2-4x-4ix-4x+16+16i+4ix-16i-16i^2\\ &= x^2-8x+32\end{aligned}[/tex]

Hence:

[tex]P(x)=a(x-2)(x^2-8x+32)[/tex]

Lastly, we need to determine a. Since the y-intercept is y = 64, this means that when x = 0, y = 64. Thus:

[tex]64=a(0-2)(0^2-8(0)+32)[/tex]

Solve for a:

[tex]-64a=64\Rightarrow a=-1[/tex]

Our factored polynomial is:

[tex]P(x)=-(x-2)(x^2-8x+32)[/tex]

Finally, expand:

[tex]\displaystyle \begin{aligned} P(x) &=-(x^2(x-2)-8x(x-2)+32(x-2)) \\&=-(x^3-2x^2-8x^2+16x+32x-64)\\&=-(x^3-10x^2+48x-64)\\&= -x^3+10x^2-48x+64\end{aligned}[/tex]

Answer:

(f+g)(2)  = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

[tex]f(x) = 2x + 3[/tex]

[tex]g(x) = x - 1[/tex]

(f+g)(2)

[tex](f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2[/tex]

At [tex]x = 2[/tex]

[tex](f+g)(2) = 3(2) - 2 = 6 - 2 = 4[/tex]

Then

(f+g)(2)  = 4

(f-g)(4)

[tex](f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4[/tex]

At x = 4

[tex](f-g)(4) = 4 + 4 = 8[/tex]

Then

(f-g)(4) = 8

(f ÷g)(2)

[tex](f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}[/tex]

At x = 2

[tex](f \div g)(2) = \frac{7}{1} = 7[/tex]

Then

(f ÷g)(2) = 7

(f x g)(1)

[tex](f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3[/tex]

Then

[tex](f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0[/tex]

So

(f x g)(1) = 0

The new age of the teacher is 25

Answer:

The age of the new teacher is 35

Answer:

x=9

Step-by-step explanation:

Answer:

the answer is 10

Step-by-step explanation:

Answer:

94

Step-by-step explanation:

We know that a straight line adds up to 180 degrees, and angle QPS, summed up by angles QPR and RPS, equals that.

Therefore,

angle QPS = QPR + RPS

180 = QPR + RPS

180 = 7x-4+9x-40

180 = 16x-44

224= 16x

x = 222/16 = 14

QPR  = 7x-4 = 94

Answer:

Step-by-step explanation:

Answer: 90

Step-by-step explanation:

c = 2πr

r = 15

d = 30

30π = 90

Answer:

C≈90

Step-by-step explanation:

remember circumference formula

[tex] \displaystyle C = 2\pi r[/tex]

given that,r=15 thus substitute:

[tex] \displaystyle C = 2\pi .15[/tex]

simplify mutilation:

[tex] \displaystyle C = 30\pi [/tex]

substitute the given value of π:

[tex] \displaystyle C = 30.3[/tex]

simplify multiplication:

[tex] \displaystyle C = 90[/tex]

and we are done!

Answer:

1,736 chocolate cover peanuts

Step-by-step explanation:

do 28×62 hope this helps

Answer:

1736 chocolate-covered peanuts

Step-by-step explanation:

[tex]\frac{1}{62} :\frac{28}{y}[/tex]

1 · y = 62 · 28

y = 1736

Answer:

[tex]x\approx 5.48[/tex]

Step-by-step explanation:

Draw a line from the center of the circle O to the end of either side of the line marked as 4. This line represents two things:

In this case, both are important. Since [tex]x[/tex] is also a radius of the circle, the line must be equal to [tex]x[/tex], since all radii of a circle are equal. To find the length of this line, use the Pythagorean Theorem:

[tex]a^2+b^2=c^2[/tex], where [tex]c[/tex] is the hypotenuse of the triangle and [tex]a[/tex] and [tex]b[/tex] are the two legs of the triangle.

Since we're solving for the hypotenuse and the two legs are 5.1 and 2, we have:

[tex]5.1^2+2^2=c^2,\\26.01+4=c^2,\\c^2=30.01,\\c=5.47813836992\approx \boxed{5.48}[/tex] (round as necessary).

Answer:

4.5 hours

Step-by-step explanation:

8t + 10(7-t) = 61

8t +70-10t=61

-2t = 61-70

-2t= -9

t = -9/-2

t = 4.5

Answer:

The distance between A(-8, 4) and B(4, -1) is 13 units.

Step-by-step explanation:

To find the distance between any two points, we can use the distance formula given by:

[tex]\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]

We have the two points A(-8, 4) and B(4, -1). Let A(-8, 4) be (x₁, y₁) and let B(4, -1) be (x₂, y₂). Substitute:

[tex]d=\sqrt{(4-(-8))^2+(-1-4)^2}[/tex]

Evaluate:

[tex]d=\sqrt{(12)^2+(-5)^2}[/tex]

So:

[tex]d=\sqrt{144+25}=\sqrt{169}=13\text{ units}[/tex]

The distance between A(-8, 4) and B(4, -1) is 13 units.

___________________________________

[tex]\quad\quad\quad\quad\tt{A.) x\tiny{1}\small{=-8}, y\tiny{1}\small{=4}}[/tex]

[tex]\quad\quad\quad\quad\tt{B.) x\tiny{2}\small{=4}, y\tiny{2}\small{=-1}}[/tex]

[tex]\quad\quad\quad\quad\tt{d = \sqrt{(x \tiny{2} \small{ - x \tiny{1} \small {)}^{2} + (y \tiny{2} \small{ - y \tiny{1} \small{)}^{2} } }}} [/tex]

[tex]\quad\quad\quad\quad\tt{d = \sqrt{(4 - \small{ (- 8}{))}^{2} + ( \small{- 1)}\small{ - {4)}}^{2} }}[/tex]

[tex]\quad\quad\quad\quad\tt{d = \sqrt{ ( {12)}^{2} + {( -5)}^{2} }}[/tex]

[tex]\quad\quad\quad\quad\tt{d = \sqrt{ {144} + {25}}}[/tex]

[tex]\quad\quad\quad\quad\tt{d = \sqrt{ 169}}[/tex]

[tex]\quad\quad\quad\quad\tt{d = 13}[/tex]

[tex]\quad\quad\quad\quad\boxed{\boxed{\tt{\color{magenta}d = 13}}}[/tex]

___________________________________

#CarryOnLearning

✍︎ C.Rose❀

9514 1404 393

Answer:

  x = 25

Step-by-step explanation:

The parallel lines divide the triangle sides proportionally.

  x/40 = 15/24

  x = 40(15/24) . . . . multiply by 40

  x = 25

Answer:

Comics6366

05/20/2020

Mathematics

Middle School

answered

a dog searching for a bone walks 3.5 m southeast, then 8.2 m at an angle 30 degrees north of east. Find the magnitude of the dog's resultant vector

1

SEE ANSWER

Comics6366 is waiting for your help.

Add your answer and earn points.

OutsideSong

Answer:

Step 1: Firstly, we draw both of the axes.

Step 2: We then draw a vector of length 3.5 m (theoretical) along the (-x) axis.

Step 3: Next, we draw a vector of length 8.2 m from the endpoint towards to top, at an angle of 60° from that point (N.B: 90-30, since it is required to make a 30°∠ with the current vertical; eventually the triangle being formed will be 90° minus the 30°.) Most importantly, the 8.2 m vector should be drawn in such a way so that it is higher than the starting point of the 3.5 m vector. )

Step 4: Lastly, we draw a 15 m vector from the endpoint of the 8.2 m vector, running above the original vector, and to the left. This one should be drawn on the left side, and must be situated far enough.

∴ Triangle 1 () is of angles 30°, 60° and 90°;

On solving for the vertical side (the slope similar to the 3.5 vector), we get

(8.2/2) m = 4.1 m

Next, we solve for the opposite side via 4.1 × √3= 7.1 m

Moving on to Triangle 2 (),

top side = (15 - 7.1) m = 7.9 m

similarly, right side = (4.1 - 3.5) m = 0.6 m

∴ last side = resultant displacement:

⇒ + (0.6)² = 7.9 m

and, direction of displacement = arcTan(y/x)

= arcTan(0.6/7.9)

= 4.3° north of west

Answer:

y = -x + 8

Step-by-step explanation:

First, plug in the slope.

y = mx + b

y = -1x + b

y = -x + b

Then, plug in the point.

7 = -(1) + b

7 = -1 + b

8 = b

Answer:

Area of the given sector = 130.9 cm²

Step-by-step explanation:

Area of a sector is given by the formula,

Area of the sector = [tex]\frac{\theta}{2\pi }\times (\pi r^{2})[/tex]

Area of the sector of the circle given in the picture = [tex]\frac{\frac{5\pi }{6} }{2\pi }[\pi (10)^{2}][/tex]

                                                                               = [tex]\frac{5}{12}(100\pi )[/tex]

                                                                               = 130.8996

                                                                               ≈ 130.9 cm²

Answer: Hello your question is poorly written attached below is the complete question

answer : 101.8

Step-by-step explanation:

Given data :

Standard deviation ( б ) = 14

55% have IQ scores > 100

45% have IQ scores < 100

Determine the mean IQ score for the region

P ( X > x ) =

P ( Z ≥ ( 100 - μ ) / 14 ) = 0.55    also

P ( Z ≤ ( 100 - μ ) / 14 ) = 0.45

using standard normal calculator

100 - μ  / 14  = Z₀.₄₅ = - 0.126

resolving the relation above

100 - μ  / 14  = - 0.126

μ = 100 - 14 ( -0.126 )

   = 101.764 ≈ 101.8

Answer:

56.52 cm³

Step-by-step explanation:

[tex]\boxed{volume \: of \: cone = \frac{1}{3} \pi {r}^{2}h }[/tex]

Diameter= 2 ×radius

Radius

= 6 ÷2

= 3cm

Height, h= 6cm

Volume of the cone

[tex] = \frac{1}{3} (3.14)( {3}^{2} )(6)[/tex]

= 56.52 cm³

Answer:

A. Acute

B. 80 degrees

Step-by-step explanation:

Answer:

The amount of interest he paid at the end of the loan is $ 311.85.

Step-by-step explanation:

Given that Juan borrowed $ 1500 from a credit union for 7 years and was charged simple interest at a rate of 2.97%, to determine what is the amount of interest he paid at the end of the loan, the following calculation must be performed:

(1500 x 0.0297) x 7 = X

44.55 x 7 = X

311.85 = X

Therefore, the amount of interest he paid at the end of the loan is $ 311.85.

Answer:

x=3

Step-by-step explanation:

Answer:

This identity holds as long as [tex]\displaystyle \theta \ne k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex].

For the proof, make use of the fact that:

[tex]\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}[/tex] (definition of tangents,) and

[tex]\cos(\theta) = \sqrt{1 - \sin^{2}(\theta)}[/tex] (Pythagorean identity,) which is equivalent to [tex]1 - \cos^{2}(\theta) = \sin^{2}(\theta)[/tex].

Step-by-step explanation:

Assume that [tex]\displaystyle \theta \ne k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex]. This requirement ensures that the [tex]\tan(\theta)[/tex] on the left-hand side takes a finite value. Doing so also ensures that the denominator [tex]\sqrt{1 - \sin^2(\theta)}[/tex] on the right-hand side is non-zero.

Make use of the fact that [tex]\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}[/tex] to rewrite the left-hand side:

[tex]\begin{aligned} & \tan(\theta) \cdot \sin(\theta) \\ =&\; \frac{\sin({\theta})}{\cos({\theta})} \cdot \sin(\theta) \\ =&\; \frac{\sin^{2}(\theta)}{\cos(\theta)}\end{aligned}[/tex].

Apply the Pythagorean identity [tex]\sin^{2}(\theta) = 1 - \cos^{2}(\theta)[/tex] and [tex]\cos(\theta) = \sqrt{1 - \sin^{2}(\theta)}[/tex] to rewrite this fraction:

[tex]\begin{aligned} & \frac{\sin^{2}(\theta)}{\cos(\theta)}\\ =\; &\frac{1 - \cos^{2}(\theta)}{\cos(\theta)}\\ =\; & \frac{1 - \cos^{2}(\theta)}{\sqrt{1 - \sin^{2}(\theta)}}\end{aligned}[/tex].

Hence, [tex]\displaystyle \tan(\theta) \cdot \sin(\theta) = \frac{1 - \cos^{2}(\theta)}{\sqrt{1 - \sin^{2}(\theta)}}[/tex].

Answer:

The probability that the mean number of holding penalties per game is of X or less is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean number of penalties per game, [tex]\sigma[/tex] is the standard deviation and n is the number of games that will be sampled.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have that:

The mean number of penalties per game is [tex]\mu[/tex] and the standard deviation is [tex]\sigma[/tex].

Sample of n games:

This means that [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

What is the probability that, for a sample of college games to be played next week, the mean number of holding penalties will be X penalties per game or less?

The probability that the mean number of holding penalties per game is of X or less is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean number of penalties per game, [tex]\sigma[/tex] is the standard deviation and n is the number of games that will be sampled.

Answer:

Hence when the radius is halved the area is divided by 4

2.5 inches^2

Step-by-step explanation:

Given data

Area= 10inches^2

We know that the expression for the area of  a circle is given as

Area= πr^2

10= 3.142*r^2

10/3.142= r^2

r^2= 3.18

Square both sides

r= √3.18

r= 1.78 inches

Now let us half the radius and find the area of the new circle

r/2= 1.78/2

r= 0.89

Area of the new circle is

Area= 3.142*0.89^2

Area= 3.142*0.7921

Area= 2.5 inches^2

Answer:

38

Step-by-step explanation:

Answer:

(a) The mean is 0

(b) The median is -30

(c) The mode is unimodal

Step-by-step explanation:

Given

[tex]Data: 15,-4,-10,8,14,-10,-2,-11[/tex]

Solving (a): The mean.

This is calculated using:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x =\frac{15-4-10+8+14-10-2-11}{8}[/tex]

[tex]\bar x =\frac{0}{8}[/tex]

[tex]\bar x =0[/tex]

Solving (b): The median

First, arrange the data

[tex]Sorted: -11,-10, -10, -4, -2,8,14,15[/tex]

There are 4 elements in the dataset. So, the median is the mean of the 4th and 5th item.

[tex]Median = \frac{-4-2}{2}[/tex]

[tex]Median = \frac{-6}{2}[/tex]

[tex]Median = -3[/tex]

Solving (c): The mode

The item that has occurs most is -10.

Hence, the mode is -10. The dataset is unimodal because it has only 1 mode (-10).

Answer:

to put the equation into standard for we must multiply the terms on the right side of the equation. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

Step-by-step explanation:

y

=

(

x

−

13

)

(

x

−

12

)

becomes:

y

=

(

x

×

x

)

−

(

x

×

12

)

−

(

13

×

x

)

+

(

13

×

12

)

y

=

x

2

−

12

x

−

13

x

+

156

We can now combine like terms:

y

=

x

2

+

(

−

12

−

13

)

x

+

156

y

=

x

2

+

(

−

25

)

x

+

156

y

=

x

2

−

25

x

+

156