The height of the plant is given by the equation h = 0.5d + 4. Rewrite this as a function rule where f(x) is the height, in centimeters, and x is the time, in days. Use the rule to complete the table, and then use the drawing tools to create the graph representing this relationship.

Answer:

It means that above 0 degrees Celsius the water does not freeze, whereas 0 degrees are freezing teperatures of water.

Step-by-step explanation:

Water freezes at 0 degrees Celsius, but the freezing temperature can be lowered  by adding salt to the water. A student discovered that adding half a cup of salt to  a gallon of water lowers its freezing temperature by 7 degrees Celsius. What is  the freezing temperature of the gallon of salt water?

0° - 7° = -7°

Answer:

Subtraction property

Step-by-step explanation:

Answer:

Subtraction

Step-by-step explanation:I took the test

Answer: 1, 2, 4, 8, 16, and 32.

Step-by-step explanation:

Factors are what we can multiply to get the number.

Factors of 32:

1 x 32=32

2 x 16=32

4 x 8=32

Therefore, the factors of 32 are 1, 2, 4, 8, 16, and 32.

Answer:

0.09

Step-by-step explanation:

Let x = ages of mother

x  :  22   17    27    20    23     19      24    18    19    24

N = 10

Mean = ∑x/N = 218/10 = 21.8

Difference in mean = 21.8 - 20 = 1.8

If significance level = 5% or 0.05

∴ Rejection region = 1.8 X 0.05 = 0.09

Answer:

Left angle = 60°

Top angle = 120°

Right angle = 60°

Step-by-step explanation:

Use what you know about angle relationships to set up equations you can solve for each variable.

The top top angle, for example, added to one of the other angles must equal 180° because they are supplementary.

You have two variables, so you need at least two equations (I made three but only used two).

The work is in my attachment, comment of you have questions.

Answer:

28

Step-by-step explanation:

We need to find the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex]

We know that,

[tex]\Sigma n^2=\dfrac{n(n+1)(2n+1)}{6}[/tex]

Here, n = 3

So,

[tex]\Sigma n^2=\dfrac{3(3+1)(2(3)+1)}{6}\\\\\Sigma n^2=14[/tex]

So,

[tex]\Sigma_{x=0}^3\ 2x^2=2\times 14\\\\=28[/tex]

So, the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex] is 28. Hence, the correct option is (d).

Answer:

Policeman A = 56 tickets

Step-by-step explanation:

Policemen A + B = 70

If Policeman B hands out x no of tickets...

Then Policeman A hands out 4x no of tickets

meaning...

x + 4x = 70

5x = 70

x = 70/5

x = 14

Therefore Policeman A hands out..

4x = 4 × 14 = 56 tickets

Answer:

71°

Step-by-step explanation:

The sum of two interior angles in a triangle is equal to an exterior angle

m<x + m<y = m<z

4n - 18 + n + 9 = 151 - 5n

5n - 9 = 151 - 5n add like terms

10n = 160

n = 16

Since m<z = 151 - 5n we replace n with 16 and 151 - 5×16 = 71

Answer:

A. 71

Step-by-step explanation:

x + y = z

4n - 18 + n + 9 = 151 - 5n

5n - 9 = 151 - 5n

10n = 160

n = 16

Z = 151 - 5(16) = 71

Answer:

3 =x

Step-by-step explanation:

(segment piece) x (segment piece) =   (segment piece) x (segment piece)

3x(x+1) = 4x*x

Divide each side by x

3(x+1) = 4x

Distribute

3x+3 = 4x

Subtract 3x from each side

3x-3x +3 = 4x-3x

3 =x

Answer:

70

Step-by-step explanation:

If the team continues with same pace, they expected wins as per previous ratio:

Expected wins 70 out of 78 games

George should be 150 mm taller than Martha.

Since George's height is 1.75 meters and Martha's height is 160 centimeters.

So here we convert the meters to mm

So,

[tex]= 1.75\times 100\\\[/tex]

= 1750 mm

Now 160 cm to mm

So,

[tex]= 160\times 10[/tex]

= 1,600 mm

So, the difference should be

= 1,750 - 1,600

= 150 mm

Therefore, George should be 150 mm taller than Martha.

Learn more about height here: https://brainly.com/question/15810288

Answer:

2.7 in²

Step-by-step explanation:

Given:

∆BAC ~ ∆EDF

Area of BAC = 6 in²

EF = 2 in

BC = 3 in

Required:

Area of ∆EDF

SOLUTION:

Let x = area of ∆EDF

[tex] \frac{6 in^2}{x} = (\frac{3 in}{2 in})^2 [/tex] (theorem of area of similar triangles)

[tex] \frac{6 in^2}{x} = (\frac{3 in}{2 in})^2 [/tex]

[tex] \frac{6}{x} = \frac{9}{4} [/tex]

Cross multiply:

[tex] 6*4 = 9*x [/tex]

[tex] 24 = 9x [/tex]

Divide both sides by 9

[tex] \frac{24}{9} = x [/tex]

[tex] 2.67 = x [/tex]

Area of ∆EDF = 2.7 in²

Answer:

(a) 50%

(b) 47.5%

(c) 2.5%

Step-by-step explanation:

According to the honest coin principle, if the random variable X denotes the number of heads in n tosses of an honest coin (n ≥ 30), then X has an approximately normal distribution with mean, [tex]\mu=\frac{n}{2}[/tex] and standard deviation, [tex]\sigma=\frac{\sqrt{n}}{2}[/tex].

Here the number of tosses is, n = 2500.

Since n is too large, i.e. n = 2500 > 30, the random variable X follows a normal distribution.

The mean and standard deviation are:

[tex]\mu=\frac{n}{2}=\frac{2500}{2}=1250\\\\\sigma=\frac{\sqrt{n}}{2}=\frac{\sqrt{2500}}{2}=25[/tex]

(a)

To not lose any money the even rolls has to be 1250 or more.

Since, μ = 1250 it implies that the 50th percentile is also 1250.

Thus, the probability that by the end of the evening you will not have lost any money is 50%.

(b)

If the number of "even rolls" is 1250, it implies that the percentile of 1250 is 50th.

Then for number of "even rolls" as 1300,

1300 = 1250 + 2 × 25

        = μ + 2σ

Then P (μ + 2σ) for a normally distributed data is 0.975.

⇒ 1300 is at the 97.5th percentile.

Then the area between 1250 and 1300 is:

Area = 97.5% - 50%

        = 47.5%

Thus, the probability that the number of "even rolls" will fall between 1250 and 1300 is 47.5%.

(c)

To win $100 or more the number of even rolls has to at least 1300.

From part (b) we now 1300 is the 97.5th percentile.

Then the probability that you will win $100 or more is:

P (Win $100 or more) = 100% - 97.5%

                                   = 2.5%.

Thus, the probability that you will win $100 or more is 2.5%.

Answer:

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0: p1= p2 there is no difference in population proportions of households that decorate their houses with lights for the holidays

against Ha : p1≠ p2  (claim)  ( two sided)

The significance level is set at ∝= 0.05

The critical value for two tailed test at alpha=0.05 is ± 1.96

or Z∝= 0.05/2= ± 1.96

The test statistic is

Z = p1-p2/√pq(1/n1 +1/n2)

p1= proportions of households  decorating in city 1  = 45/60=0.75

p2= proportions of households  decorating in city 2 = 40/50= 0.8

p = the common proportion on the assumption that the two proportion are same.

p =   [tex]\frac{n_1p_1 +n_2p_2}{n_1+n_2}[/tex]

Calculating

p =60 (0.75) + 50 (0.8) / 110

p=  45+ 40/110= 85/110 = 0.772

so  q = 1-p= 1- 0.772= 0.227

Putting the values in the test statistic and calculating

z= 0.75- 0.8/ √0.772*0.227( 1/60 + 1/50)

z= -0.05/√ 0.175244 ( 110/300)

z= -0.05/0.25348

z= -0.197

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

Answer:

[tex]18\sqrt2[/tex]

Step-by-step explanation:

To simplify:

[tex]2 \sqrt{18}+ 3 \sqrt2+ \sqrt{162 }[/tex]

First of all, let us write 18 and 162 as product of prime factors:

[tex]18 = 2 \times \underline{3 \times 3}\\162 = 2 \times \underline{3 \times 3} \times \underline{3 \times 3}[/tex]

The pairs are underlined as above.

While taking roots, only one of the numbers from the pairs will be chosen.

Now, taking square roots.

[tex]\sqrt{18} =3 \sqrt2[/tex]

[tex]162 = 3 \times 3 \times \sqrt 2 = 9 \sqrt2[/tex]

So, the given expression becomes:

[tex]2 \sqrt{18}+ 3 \sqrt2+ \sqrt{162 } = 2 \times 3\sqrt2 + 3\sqrt2 +9\sqrt2\\\Rightarrow 6\sqrt2 + 3\sqrt2 +9\sqrt2\\\Rightarrow \sqrt2(6+3+9)\\\Rightarrow \bold{18\sqrt2}[/tex]

So, the answer is:

[tex]18\sqrt2[/tex] or 18 StartRoot 2 EndRoot

Answer:

its B. 18 sqrt(2)

Step-by-step explanation:

just took test

Answer:

3 pennies, 9 nickels, and 6 dimes

Step-by-step explanation:

We have three conditions:

(1)         p +        n +        d = 18

(2) 0.01p + 0.05n + 0.10d = 1.08

(3)                                   d = 2p

Multiply (2) by 100 and rearrange (3) to get a standard array.

(4)      p +   n +     d =   18

(5)      p + 5n + 10d = 108

(6)  -2p          +     d =    0

Subtract (4) from (5). This gives

(4)      p +   n +   d =  18

(7)            4n + 9d = 90

(6)  -2p          +   d =   0

Multiply (4) by 2 and add to (6). This gives

(4) p +   n +    d =  18

(7)        4n + 9d = 90

(8)        2n + 3d = 36

Double (8) and subtract from (7). This gives

(4)      p +   n +   d = 18

(7)            4n + 9d = 90

(9)                    3d = 18

Divide (9) by 3. This gives

(10) d = 6

Substitute (10) into (7). This gives

4n + 9(6) = 90

4n +   54 = 90

4n           = 36

(11) n       =    9

Substitute (10) and (11) into (4). This gives

p + 9 + 6 = 18

p +      15 = 18

p              =  3

Sasha has 3 pennies, 9 nickels, and 6 dimes.

Answer:  11 down and 9 right

Step-by-step explanation:

Slope IS rise over run where the top number of the fraction (numerator) determines the vertical distance --> positive is up, negative is down

and the bottom number of the fraction (denominator) determines the horizontal distance --> positive is right, negative is left.

Given slope = -11/9

the numerator is -11 so the "rise" is  DOWN 11 units

the denominator is 9 so the "run" is RIGHT 9 units

Complete Question

In a genetics experiment on​ peas, one sample of offspring contained 372 green peas and 35 yellow peas. Based on those​ results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was​ expected?

Answer:

The  probability is  [tex]P(g) = 0.9140[/tex]

No it is not close to the probability expected

Step-by-step explanation:

From the question we are told that

    The sample size is  [tex]n = 372 + 35= 407[/tex]

      The  number of  green peas is  [tex]n_g = 372[/tex]

    The  number of  yellow  peas is  [tex]n_y = 35[/tex]

The  probability of getting an offspring pea that is green is mathematically represented as

         [tex]P(g) = \frac{n_g}{n}[/tex]

substituting values

         [tex]P(g) = \frac{372}{ 407}[/tex]

         [tex]P(g) = 0.9140[/tex]

The  expected probability is  [tex]\frac{3}{4} = 0.75[/tex]

But what we got is  [tex]P(g) = 0.9140[/tex]

So we can say that the value obtained is not equal to the expected value

Answer:

Step-by-step explanation:

The comparison will be the same if you subtract the right side and compare to zero:

  a/b ?? c/d . . . . . . . using ?? for the unknown comparison symbol

  a/b - c/d ?? 0 . . . . subtract the fraction on the right

  (ad -bc)/bd ?? 0 . . . combine the two fractions

  ad - bc ?? 0 . . . . . . multiply by bd to make the job easier

__

5/6 and 2/5

  5(5) -6(2) = 25 -12 > 0   ⇒   5/6 > 2/5

4/10 and 7/8

  4(8) -10(7) = 48 - 70 < 0   ⇒   4/10 < 7/8

3/12 and 1/4

  3(4) -12(1) = 0   ⇒   3/12 = 1/4

_____

Of course, you can use your calculator (or your memory) to change each of these to a decimal equivalent. The comparison should be easy at that point.

  0.833 > 0.400

  0.400 < 0.875

  0.250 = 0.250

Answer:

Brainliest! Hope I helped!

Step-by-step explanation:

you know its greater than 1cm and less than 2cm,

1 and 7hundreths cm is = 1.07 cm

thats not right because you know it is greater than that for sure!

so the only answer left is 1.7 cm

You answer is 1.7 cm

another way...

read the ruler and see the answer

Answer:

1.7 cm.

Step-by-step explanation:

The midpoint of 1 - 2 is 5 so count the lines after 5 and you get .7 to add to one cm.

Hope this helps, have a good day :)

Answer:

f(x) = (x - 3)² - 5

Step-by-step explanation:

equate equation to 0

(x - 3)² = 0

take the square root on both sides

x - 3 = 0

add 3

x = 3

If x = 3 then you are moving to 3 units to the right.

- 5 means you are going downward 5 units.

Answer:

Following are the answer to this question:

Step-by-step explanation:

In the given statement, we don't agree with Ed’s conclusion, because it is not relevant simply since it is not statistically significant. The reduction of prostate cancer is the death risk, which is highly significant even if it decreases significantly. It can also be something statistically important without becoming important.

Answer: D. 8.25

Step-by-step explanation: A data set can be divided into 4 equal parts, called Quartile. A quartile divides the data into three points:

Interquartile Range (IQR) is a measure of variability based on data divided into quartiles or the measure of where the bulk of the values are.

To calculate interquartile range:

IQR = Q3 - Q1

The table shows Q1 = 27.825 and Q3 = 36.075, then

IQR = 36.075 - 27.825

IQR = 8.25

The value of interquartile range is 8.25.

Answer:

D. F(x) = ( (1/5)x)^2 - 4

Step-by-step explanation:

The standard transformation with a stretch and a shift is

F(x) = f(x/b) + k

The red curve has a vertex at (0,-4), and cuts the x-axis at (10,0)

That means that before the vertical shift (of k=-4), the vertex was at (0,0), and the curves passes through (10,4).

Substituting in the equation

F(10) = (10/b)^2 -4 = 0

solve for b

(10/b)^2-4 = 0

(10/b)= sqrt(4) = 2

b = 10/2 = 5

Therefore the transformation equation is

F(x) = (x/5)^2-4

The answer is

F(x) = ( (1/5)x)^2 - 4

Answer:

14/20 or .7 or 70%

Step-by-step explanation:

Total Number of cards: 20

Number of Red cards: 6

The leftover cards: 20 -6 = 14

The probability of not getting a red = 14/20

14/20 as a decimal = 14/20 = 70/100 = .7

14/20 as a percent = 14/20 = 70/100 = 70%

Answer:

  5/2

Step-by-step explanation:

Let u = sin(t). Then this is the integral ...

  [tex]\displaystyle\int_0^{\frac{\pi}{2}}{5u}\,du=\left.\dfrac{5u^2}{2}\right|_0^{\frac{\pi}{2}}=\dfrac{5}{2}(\sin(\frac{\pi}{2})^2-\sin(0)^2)=\dfrac{5}{2}(1-0)=\boxed{\dfrac{5}{2}}[/tex]

Answer:

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = Expected outcome of event/Total outcome.

If a video rental store keeps a list of their top 15 movie rentals each week, the total outcome is 15.

If the list for the week includes 6 action, 4 comedies, 3 dramas, and 2 mysteries and the store manager removes a copy of each of the 15 movies from the shelf, then randomly selects 3 of the 15 to show on the display monitors in the store, the probability that she selected 2 comedies and 1 action movie will be calculated as shown;

Probability of selecting 2 comedies  = 4/15*4/15 = 16/225 (Note that the expected outcome in this case is 4).

Probability of selecting 1 action movie = 6/15 = 2/5

Hence, the probability that she selected 2 comedies and 1 action movie will be equivalent to 16/225*2/5 = 32/1125

Note that the rented movies will have to be returned hence reason for the replacement.

Answer:

The author have to use his/her phone less than 20 hours in a month in order for Don’tTalkMuch's is a deal to be better than TalkLots's is.

Step-by-step explanation:

Call X is the number of hours that the author uses on monthly basis.

Total bill value if the author uses Don’tTalkMuch service is $80 + $1 X.

Total bill value if the author uses TalkLots service is $20 + $4X

The total fees between 2 providers equal as:

$80 + $1 X = $20 + $4X => 3X = $60 => X = 20

Hence: The author have to use his/her phone less than 20 hours in a month in order for Don’tTalkMuch's is a deal to be better than TalkLots's is.

Answer:

g(3) = -5

Step-by-step explanation:

g(3) is basically the value of g(x) when x = 3. Therefore, g(3) = -3 - 2 = -5.

Answer:

[tex] \boxed{\sf g(3) = -5} [/tex]

Given:

g(x) = -x - 2

To Find:

g(3) i.e. g(x) where x = 3

Step-by-step explanation:

[tex]\sf Evaluate \ -x - 2 \ where \ x = 3:[/tex]

[tex] \sf \implies - x - 2 = - 3 - 2[/tex]

[tex] \sf - 3 - 2 = - (3 + 2) : [/tex]

[tex] \sf \implies - (3 + 2)[/tex]

[tex] \sf 3 + 2 = 5 : [/tex]

[tex] \sf \implies - 5[/tex]