M1 = 17.45 M
M2 = 0.83 M
V2 = 250 ml
M1. V1= M2. V2
V1 = (M2. V2)/M1 = (0.83× 250)/ 17.45= 11.89 ml
What is the density of the football
Answer:
Mass of the ball is . 42 kg. The density of air is 1.2 kg/m3.
Explanation:
how many s electrons are there in potassium?
Answer: 19
Explanation:
In order to write the Potassium electron configuration we first need to know the number of electrons for the K atom (there are 19 electrons). When we write the configuration we'll put all 19 electrons in orbitals around the nucleus of the Potassium atom.
Ammonia burns in the presence of a copper catalyst to form nitrogen gas. 4 NH3(g) + 3 O2(g) → 2 N2(g) + 6 H2O(g) ΔΗ = -1267 kJ What is the enthalpy change to burn 38.4 g of ammonia?
Answer:
-713 kJ
Explanation:
Step 1: Write the balaned thermochemical equation
4 NH₃(g) + 3 O₂(g) → 2 N₂(g) + 6 H₂O(g) ΔΗ = -1267 kJ
Step 2: Calculate the moles corresponding to 38.4 g of NH₃
The molar mass of NH₃ is 17.03 g/mol.
38.4 g × 1 mol/17.03 g = 2.25 mol
Step 3: Calculate the enthalpy change to burn 2.25 mol of ammonia
According to the thermochemical equation, 1267 kJ are released per 4 moles of ammonia that react.
2.25 mol × (-1267 kJ/4 mol) = -713 kJ
What word means the same as Chordata?
A. non-vertebrate
B. vertebrate
What is the pH of a solution whose hydronium ion [H20+] (or proton [H+1)
concentration is 7.6' 10-5 M?
Answer:
[tex]pH = - log(7.6 \times {10}^{ - 5} ) \\ pH = 4.12[/tex]
Given the Vapour Density of a hydrocarbon is 150, what is it's molecular formula.
Classify each of the following as a Strong acid (sa) or a Weak acid (wa) and indicate how each should be written in aqueous solution.
1. hydrobromic acid
2. hydrochloric acid
3. carbonic acid
Write a net ionic equation for the reaction that occurs when aqueous solutions of hydrochloric acid and barium hydroxide are combined.
Answer:
A. 1. Strong acid (sa): Hydrobromic acid: HBr (aq)
2. Strong acid (sa); Hydrochloric acid: HCl (aq)
3. Weak acid (wa); Carbonic acid: H₂CO₃ (aq)
B. H+ (aq) + OH- (aq) ----> H₂O (l)
Explanation:
Strong acids are which ionize completely in aqueous solution into hydrogen ions and the corresponding anion. Examples of strong acids include hydrobromic acid, hydrochloric acid, tetraoxosulfate (vi) acid.
The ionization of hdyrobromic and hydrochloric acids in aqueous solution is given below:
1. Hydrobromic acid: HBr (aq) ----> H+ (aq) + Br- (aq)
Hydrobromic acid in aqueous solution ionizes completely into hydrogen ions and bromide ions
2. Hydrochloric acid: HCl (aq) ----> H+ (aq) + Cl- (aq)
Hydrochloric acid in aqueous solution ionizes completely into hydrogen ions and chloride ions
Weak acids are acids which ionizes only partially in aqueous solutions to hydrogen ions and the corresponding anions. Examples of weak acids are carbonic acid and ethanoic acid. The ionization of carbonic acid in aqueous solution is shown below:
3. Carbonic acid: H₂CO₃ (aq) ⇄ 2 H+ (aq) + CO₃²- (aq)
Carbonic acid ionizes partially only to give hydrogen ions and trioxocarbonate (iv) ions. The unionized acid exists in equilibrium with the ions produced by the partial ionization of the acid.
Part B:
The reaction between hydrochloric acid and barium hydroxide is a neutralization reaction producing barium chloride salt and water.
The net ionic equation of the neutralization reaction is given below :
H+ (aq) + OH- (aq) ----> H₂O (l)
how many grams of p2o3 can be produced from 95l o2 at STP
Explanation:
Balanced Equation
P
2
O
3
+
3H
2
O
→
2H
3
PO
3
First use the balanced equation to determine the mole ratio between
H
3
PO
3
and
P
2
O
3
. This ratio will be used to determine the moles
P
2
O
3
required to produce
10.2
moles
H
3
PO
3
.
Mole Ratio Between
P
2
O
3
and
H
3
PO
3
from the balanced equation.
1
mol P
2
O
3
2
mol H
3
PO
3
and
2
mol H
3
PO
3
1
mol P
2
O
3
Multiply the moles
H
3
PO
3
by the molar mass that cancels
H
3
PO
3
and leaves
P
2
O
3
10.2
mol H
3
PO
3
×
1
mol P
2
O
3
2
mol H
3
PO
3
=
5.10 mol P
2
O
3
Now that the moles
P
2
O
3
required to produce
10.2 mol H
3
PO
3
are known, multiply the number of moles by its molar mass,
109.945 g/mol
. https://www.ncbi.nlm.nih.gov/pccompound?term=P2O3 This will give the mass in grams needed for
P
2
O
3
to produce
10.2 mol H
3
PO
3
.
5.10
mol P
2
O
3
×
109.945
g P
2
O
3
1
mol P
2
O
3
=
561 g P
2
O
3
rounded to three significant figures
The chemical formula for an emerald is Be3Al2(SiO3)6. An emerald can be described as
Answer:
Emerald is a compound made of Beryllium, Aluminium, Silicon and Oxygen with the formula, Be3Al2(SiO3)6
Explanation:
Answer:
A pure substance because its a compound
Explanation:
How many photons are produced in a laser pulse of 0.203 J at 553 nm?
Answer:
8.59
⋅
10
17
Explanation:
You can start by figuring out the energy of a single photon of wavelength
505 nm
=
505
⋅
10
−
9
m
.
To do that, use the equation
E
=
h
⋅
c
λ
Here
h
is Planck's constant, equal to
6.626
⋅
10
−
34
.
J s
c
is the speed of light in a vacuum, usually given as
3
⋅
10
8
.
m s
−
1
λ
is the wavelength of the photon, expressed in meters
Plug in your value to find--notice that the wavelength of the photon must be expressed in meters in order for it to work here.
E
=
6.626
⋅
10
−
34
J
s
⋅
3
⋅
10
8
m
s
−
1
505
⋅
10
−
9
m
E
=
3.936
⋅
10
−
19
J
So, you know that one photon of this wavelength has an energy of
3.936
⋅
10
−
19
J
and that your laser pulse produces a total of
0.338 J
of energy, so all that you need to do now is to find how many photons are needed to get the energy output given to you.
0.338
J
⋅
1 photon
3.936
⋅
10
−
19
J
=
8.59
⋅
10
17
photons
−−−−−−−−−−−−−−−−−
The answer is rounded to three sig figs.
What three parts of your eye work together to create a clear image?
Answer:
cornea,Jens and pupil
tma Po yan
Almost 99% of Earth's atmosphere is made up of two gases. What are the two gases and the percents of each?
A)
21% oxygen and 78% nitrogen
B)
21% water vapor and 78% oxygen
09
21% nitrogen and 78% oxygen
D)
21% carbon dioxide and 78% oxygen
A. Direction: Identify the word or phrase being described in the sentence. Write your
answers in your notebook.
1. It is an electronic measuring instrument that combines several
measurement functions in one unit.
2. In diodes, what do the silver stripe represents?
3. This is an Electronic/Electrical component that stores energy in
the form of Electric Charge.
4. This allows you to change the function between volts, ohms, and
amps, and to change the scale of the meter.
5. In testing capacitor, if the multimeter shows very low resistance,
it means that the capacitor is .
6. These are components used to resist the flow of electric current.
7. It is a system used to determine the value of a resistor without
using a multimeter.
8. What defective capacitor that shows very low Resistance?
9. A type of transformer that is used to increase the output voltage.
10. A type of transformer that is used to decrease the output voltage.
Answer:
1. Multimeter
2. Cathode
3. Capacitor
4. Selector switch
5. Short or Shorted
6. Resistors
7. Resistor color coding
8. Open Capacitor
9. Step-up transformer
10. Step-down transformer
Explanation:
The above-described elements are electronic components. Resistors for instance are designed to resist the flow of electric current. They are also standardized such that a deviation from the set resistance level will indicate a problem. The capacitor is another electrical component that stores energy as an electrical charge. Knowledge of these electrical components and the ways they are tested will make a person proficient in electrical electronics.
unsa ang karaan nga duwa saonang panaho
Answer:
Ang kasaysayan ng mga laro ay nagmula sa sinaunang nakaraan ng tao. Ang mga laro ay isang mahalagang bahagi ng lahat ng mga kultura at isa sa pinakamatandang anyo ng pakikipag-ugnay sa lipunan ng tao. Ang mga laro ay gawing pormal na pagpapahayag ng paglalaro na nagpapahintulot sa mga tao na lumampas sa agarang imahinasyon at magdirekta ng pisikal na aktibidad. Kasama sa mga karaniwang tampok ng mga laro ang kawalan ng katiyakan sa kinalabasan, napagkasunduang panuntunan, kumpetisyon, magkakahiwalay na lugar at oras, mga elemento ng kathang-isip, mga elemento ng pagkakataon, iniresetang mga layunin at personal na kasiyahan.
Nakukuha ng mga laro ang mga ideya at pananaw sa mundo ng kanilang mga kultura at ipinapasa sa hinaharap na henerasyon. Ang mga laro ay mahalaga bilang mga kaganapan sa pagbubuklod ng kultura at panlipunan, bilang mga tool sa pagtuturo at bilang mga marka ng katayuan sa lipunan. Bilang pampalipas ng oras ng pagkahari at ng mga piling tao, ang ilang mga laro ay naging karaniwang tampok ng kultura ng korte at binigyan din bilang mga regalo. Ang mga larong tulad ni Senet at ang Mesoamerican ball game ay madalas na pinuno ng mitiko at ritwal na relihiyosong kahalagahan. Ang mga larong tulad ng Gyan chauper at The Mansion of Happiness ay ginamit upang magturo ng mga aralin na pang-espiritwal at etikal habang sina Shatranj at Wéiqí (Go) ay nakita bilang isang paraan upang mapaunlad ang madiskarteng pag-iisip at kasanayan sa kaisipan ng mga elite sa politika at militar.
The mass percent of element X
in X(NO3)2 is 52.55%.
Chemical analysis of a pure
sample of X(NO3)2 shows that
it contains 67.50 g of element
X. What is the total mass of
the pure sample?
Answer:
128.4 g
Explanation:
Step 1: Given data
Mass percent of element X in X(NO₃)₂: 52.55%Mass of the element X in the sample: 67.50 gStep 2: Determine the total mass of the sample
The mass percent of element X in X(NO₃)₂ is 52.55%, that is, there are 52.55 g of X every 100 g of X(NO₃)₂. Then, the mass of X(NO₃)₂ that contains 67.50 g of X is:
67.50 g X × 100 g X(NO₃)₂/52.55 g X = 128.4 g X(NO₃)₂
How many moles of fluorine are in 100.0 g
2.38g of black copper(iii) oxide is completely reduced to by hydrogen to give copper and water. What are the number of atoms of copper formed? Equation for this reaction:
Cu203 + 3H2 → 2Cu + 3H20
Explanation:
here is the answer bae. Feel free to ask for more
What is one way in which a field investigation can differ from a classroom or laboratory experiment?
Answer:
□In field investigations, you are usually working with much larger animals than in the lab. In field investigations, it is much more difficult to separate your control and experimental groups.
There are many ways in which a field experiment can differ form of a classroom or a laboratory experiment, one of which can be the environmental condition.
What is a field experiment?A field experiment Is an experiment which is performed in practically Outside the classroom or a laboratory in live situtations .
Environmental factors may deter the results of a field experiment or may alter the physical conditions of the object, For example an anhydrous substance may become hygroscopic, Which may Alter the result of the field experiment.
Hence, field experiment can differ from a classroom or a laboratory experiment due to environmental conditions .
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How did the development of the earliest idea about atoms differ from the later work of scientists?
It was based on sound evidence.
There were explanations for the idea.
It was based on the thoughts of an early philosopher.
There were experiments conducted to support the idea.
Answer:
C. It was based on the thoughts of an early philosopher.
What is the mass of 8.12 ×10^23
Answer:
59.3g
Explanation:
Mole = no. Molecules/6.02×10^23
Mole = (8.12×10^23)/(6.02×10^23)
Mole = 1.35mole
Molar mass of CO2 = 12+ 2(16)
Molar mass= 12 + 32= 44g/mol
Mole = mass/molar mass
Mass = Mole × molar mass
Mass = 1.35× 44
Mass= 59.35g
Americium-241 is widely used in smoke detectors. The radiation released by this element ionizes particles that are then detected by a charged-particle collector. The half-life of 241Am is 432 years, and it decays by emitting alpha particles. How many alpha particles are emitted each second by a 5.54-g sample of 241Am
Answer:
Explanation:
Half life T is 432 years .
432 years = 432 x 365 x 24 x 60 x 60 s
= 1.36 x 10¹⁰ s .
No of atoms in 5.54 g of sample of Am N= 6.02 x 10²³ x 5.54 / 241
N = 138.38 x 10²⁰ atoms .
disintegration constant λ = .693 / half life
λ = .693 / 1.36 x 10¹⁰ s .
= .51 x 10⁻¹⁰ .
dN / dt = λN
= .51 x 10⁻¹⁰ x 138.38 x 10²⁰
= 70.57 x 10¹⁰ per second.
No of particles emitted = no of disintegration per second
No of particles emitted = 70.57 x 10¹⁰ per second.
Completa las siguientes reacciones, nombrando todos los compuestos que intervienen:
a) CH2=CH2 + energía
b) CH2=CH2 + H2O
c) CH2=CH2 + HCl
d) CH2=CH2 + Cl2
e) CH2=CH2 + H2
2 Completa las siguientes reacciones, nombrando todos los compuestos que intervienen:
a) CH4 + Cl2
b) CH2=CH2 + H2O
c) CH≡CH + H2
d) CH3-COOH + KOH
e) CH3OH + CH3-COOH
3 Completa y ajusta la siguientes reacciones nombrando todos los compuestos que intervienen en cada una de ellas:
a) CH3-COOH + NaOH
b) CH3-CH2I + NH3
c) CH2=CH2 + H2O
d) CH3-CH=CH2 + Br2
Answer:
1
Explanation:
hhihh2
palm wine taste sour when left to stand for some time why?
Answer:
When a wine bottle is uncorked, its contents are exposed to air, causing them to oxidize. ... Bacteria naturally present in grapes can turn either the sugars in grape juice or the alcohol in wine into acetic acid, giving it a vinegar taste (and eventually producing a wine vinegar).
Explanation:
Before the lab student needs to make necessary chemical reagent solutions, the teacher asked them to make 50.0mL of 1.0 M H2SO4 from a 6.0 M sock
M1=
V1=
M2=
V2=
Answer:
M1 = 6.0M
V1 = 8.33mL
M2 = 1.0M
V2 = 50.0mL
Explanation:
It is possible to find the volume that we need to prepare a diluted solution from a stock using the equation:
M1V1 = M2V2
Where M is molar concentration and V volume of 1, stock solution and 2, diluted solution.
Replacing:
M1 = 6.0M
V1 = Our incognite
M2 = 1.0M
V2 = 50.0mL
6.0M*V1 = 1.0M*50.0mL
V1 = 1.0M * 50.0mL / 6.0M
V1 = 8.33mL of the stock solution are needed
P4 + NaOH + H2O——> PH3 + Na2HPO3
Balance given equation by oxidation no. Method
Answer:
P4 + 4NaOH + 2H2O → 2PH3 + 2Na2HPO3
Explanation:
A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and the charge are both equal.
A chemical equation must balance according to the rule of conservation of mass. According to the rule, mass cannot be generated or removed during a chemical process.
Chemical equations must be balanced, which means that the atom types and numbers on both sides of the reaction arrow must match. Coefficients are the values added in front of formulas to balance equations; they multiply each atom in a formula.
Here the given equation is balanced as:
P₄ + 4NaOH + 2H₂O——> 2PH₃ + 2Na₂HPO₃
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In the electrolysis of water, how long will it take to produce 75.00 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 205.0 mA
answer is 2546 h
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What kind of magnet is an electromagnet?
A.permanent
B.temporary
C.semi permanent
D.none of the above
(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 7.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol.
Answer: The number of electrons in given amount of silver are [tex]1.839\times 10^{24}[/tex]
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
......(1)
We are given:
Mass of silver = 7.0 g
Molar mass of silver = 107.87 g/mol
Putting values in equation 1:
[tex]\text{Moles of silver}=\frac{7.0g}{107.87g/mol}=0.0650 mol[/tex]
According to the mole concept:
1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of particles.
Number of electrons per atom of silver = 47
So, 0.065 moles of silver will contain = [tex](0.065\times 6.022\times 10^{23}\times 47)=1.839\times 10^{24}[/tex] number of electrons
Hence, the number of electrons in given amount of silver are [tex]1.839\times 10^{24}[/tex]
How many molecules are there in 4.27 mol of tungsten(VI) oxide, WO3
Answer:
Molar mass of WO3 = 231.8382 g/mol Convert grams Tungsten(VI) Oxide to moles or moles Tungsten(VI) Oxide to grams Molecular weight calculation: 183.84 + 15.9994*3Explanation:
#hopeithelpsbrainliest me later.25.71 × 10²³ molecules are there in 4.27 mol of tungsten (VI) oxide, [tex]WO_3[/tex].
How to find the number of molecules ?To find the Number of molecules of substance multiply the number of moles of given substance by Avogadro number
Number of molecules = Number of moles × Avogadro's Number
Avogadro's NumberAvogadro's number [tex](N_{A})[/tex] is the number of particles in one mole of substance. 6.023 × 10²³ is known as Avogadro's constant / Avogadro's number.
Avogadro's number = 6.023 × 10²³ [tex]mol^{-}[/tex]
Now,
Number of molecules in 4.27 moles of [tex]WO_{3}[/tex]
= Number of moles of [tex]WO_{3}[/tex] × Avogadro's Number
= 4.27 × 6.023 × 10²³
= 25.71 × 10²³ molecules
Thus, we can say that 25.71 × 10²³ molecules are there in 4.27 moles of tungsten (VI) oxide, [tex]WO_3[/tex].
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What is the molarity of a solution that contains 40.
grams of CaBr2 in 1500 ml of solution?
A) 0.50 M
C) 0.13 M
B) 26.7 M
D) 0.03. M
Answer:
b
Explanation:
because it be an the only answer there