Answer:
Approximately [tex]5.19 \times 10^{-5}\; \rm N[/tex].
Explanation:
Let [tex]G[/tex] denote the gravitational constant. ([tex]G \approx 6.67 \times 10^{-11} \; \rm N \cdot kg^{-2} \cdot m^{2}[/tex].)
Let [tex]M[/tex] and [tex]m[/tex] denote the mass of two objects separated by [tex]r[/tex].
By Newton's Law of Universal Gravitation, the gravitational attraction between these two objects would measure:
[tex]\displaystyle F = \frac{G \cdot M \cdot m}{r^{2}}[/tex].
In this question: [tex]M = 7 \times 10^{22}\; \rm kg[/tex] is the mass of the moon, while [tex]m = 1\; \rm kg[/tex] is the mass of the water. The two are [tex]r = 3\times 10^{5}\; \rm km[/tex] apart from one another.
Important: convert the unit of [tex]r[/tex] to standard units (meters, not kilometers) to reflect the unit of the gravitational constant [tex]G[/tex].
[tex]\displaystyle r = 3 \times 10^{5}\; \rm km \times \frac{10^{3}\; \rm m}{1\; \rm km} = 3 \times 10^{8}\; \rm m[/tex].
[tex]\begin{aligned} F &= \frac{G \cdot M \cdot m}{r^{2}} \\ &= \frac{6.67 \times 10^{-11}\; \rm N \cdot kg^{-2}\cdot m^{2} \times 7 \times 10^{22}\; \rm kg \times 1\; \rm kg}{(3 \times 10^{8}\; \rm m)^{2}} \\ &\approx 5.19 \times 10^{-5} \; \rm N\end{aligned}[/tex].
how does washing your clothes affect the weather?
Answer:
carbon dioxide is produced each year per household from washing and drying a load of washing every two days. These carbon dioxide negatively impact the environment and provoke climate change. Also, when washing clothes, around 90% of the energy goes into heating up the water
radiation is the main way of transferring heat in a vacuum b solid c gas d liquid
Answer:
gas
................
Explanation:
hope it helps u
An upright image which reduced in size 10 times occurred in a mirror. If the radius of
curvature of the mirror is 2 m, bow far is the object from the mirror?
Answer:
-10/9 m
Explanation:
Radius of curvature, R=2 m
Focal length of mirror, f=R/2=2/2=1 m
Let height of object=h
Height of image, h'=h-10h=-9h
We have to find the distance of object from the mirror.
Magnification, m= [tex]\frac{h'}{h}=-\frac{v}{u}[/tex]
[tex]m=\frac{-9h}{h}=-9[/tex]
Image is upright and small in size it means the mirror is convex.
Focal length of convex mirror is negative.
f=-1m
[tex]-9=-\frac{v}{u}[/tex]
[tex]v=9u[/tex]
Now, mirror formula
[tex]\frac{1}{v}+\frac{1}{u}=-\frac{1}{f}[/tex]
[tex]\frac{1}{9u}+\frac{1}{u}=\frac{1}{1}[/tex]
[tex]\frac{1+9}{9u}=-1[/tex]
[tex]10=-9u[/tex]
[tex]u=-\frac{10}{9} m[/tex]
Hence, the distance of object from the mirror is -10/9 m
a.
[2]
A train covers 450 km in 5 hr. between Station A and Station B.
What is the average speed of train in km/h and m/s.
Answer:
90 km/h
50 m/s
Explanation:
Distance = 450 km
Time = 5hrs
Speed = Distance/Time
450/5 = 90 km/h
1 km = 1,000 m
1 hr = 60m = 60 x 60 = 3,600 sec
but since it's 5hrs = 60 x 300m = 18,000
90 x 1,000 = 90,000/18,000 = 50 m/s
Can someone please help me with this physics question? I'm desperate!
A track team is practicing for a 4 x 100 m relay race. The first runner, Linda, is running at a constant speed of 8.6 m/s. The next runner, Jenny, will be starting from rest at the 80 m mark. She has an acceleration of 1.0m/s^2. Ideally the two runners meet at the 100m mark to hand over the baton. At this point, Jenny is still accelerating.
a) How long does it take Jenny to run from the 80-m mark to the 100-m mark?
b)At what distance behind Jenny should Linda be when Jenny starts running? (Assume for simplicity that there is no distance between the two runners when the switch happens.)
c)What’s Jenny’s speed at the 100m mark?
Answer:
a) 2·√10 seconds
b) Linda should be approximately 30.6 meters
c) Jenny's speed at the 100-m mark is approximately 6.325 m/s
Explanation:
The speed with which Linda is running = 8.6 m/s
The point Jenny starts = The 80-m mark
The acceleration of Jenny = 1.0 m/s²
a) The time it takes Jenny to run from the 80-m mark to the 100-m mark, t, is given as follows
Δs = u·t + (1/2)·a·t²
Δs = Distance = 100-m - 80-m = 20-m
u = The initial velocity of Jenny = 0
a = Jenny's acceleration = 1.0 m/s²
∴ 20 = 0×t + (1/2) × 1 × t² = t²/2
20 = t²/2
t = √(20 × 2) = 2·√10
The time it takes Jenny to run from the 80-m mark to the 100-m mark = 2·√10 seconds
b) The distance Linda runs in t = 2·√10 seconds, d = v × t
Given that Linda's velocity, v = 8.6 m/s, we have;
d = 8.0 × 2·√10 = 16·√10
The distance Linda runs in t = 2·√10 seconds = 16·√10 meters ≈ 50.6 meters
Therefore, Linda should be approximately (50.6 - 20) meters = 30.6 meters behind Jenny when Jenny starts running
c) Jenny's speed at the 100 m mark is given as follows;
v = u + a·t
t = 2·√10 seconds, a = 1.0 m/s², u = 0
∴ v = 0×t + 1.0×2·√10 = 2·√10 ≈ 6.325
Jenny's speed at the 100-m mark ≈ 6.325 m/s
Explain the term balance point as applies to the Wheatstone Bridge.
Answer:
Explanation: The Wheatstone bridge is the interconnection of four resistances forming a bridge. ... To find the value of unknown resistance the deflection on galvanometer made to zero by adjusting the variable resistor. This point is known as balance point of Wheatstone bridge
Which group of people was most directly affected by the twenty sixth amendment
If the mass of the Jupiter is 1.9*10 kg and radius is fbx loom what is acclerallon due to gravity on the supiter ?
Answer:
[tex]g=25.92\ m/s^2[/tex]
Explanation:
Given that,
The mass of the Jupiter,[tex]M=1.9\times 10^{27}\ kg[/tex]
The radius of Jupiter,[tex]r=69,911\ km=69911\times 10^3 km[/tex]
We need to find the acceleration due to gravity on Jupiter. The formula is
[tex]g=G\dfrac{M}{r^2}[/tex]
Put all the values,
[tex]g=6.67\times 10^{-11}\times \dfrac{1.9\times 10^{27}}{(69911\times 10^3)^2}\\\\g=25.92\ m/s^2[/tex]
So, the value of acceleration due to gravity on the Jupiter is [tex]25.92\ m/s^2[/tex].
2. A cinder block is sitting on a platform 20 m high. It weighs 16kg. The block has
_ joules of potential energy.
Answer:
3136 Joules
Explanation:
Applying,
P.E = mgh.............. Equation 1
Where P.E = potential energy, m = mass of the cinder block, h = height of the platform, g = acceleration due to gravity.
From the question,
Given: m = 16 kg, h = 20 m
Constant: g = 9.8 m/s²
Substitute these values into equation 1
P.E = 16(20)(9.8)
P.E = 3136 Joules
Hence the potential energy of the cinder block is 3136 Joules
A bullet from a gun at 30° to the horizontal remains in flight for 25s before touching the ground.Calculate the velocity of the projection.
Answer: The velocity of the bullet will be more than half of its earlier velocity
Explanation: I did it on a test and it was right because i calculated 30 degrees within 25 seconds and it was half times the velocity
i hope this helps sorry if i got it wrong
Calculate the conductivity of the wire having length 10m , radius 20mm and resistance 2.4umor
We know
Conductivity=Length×Radius×Resistance[tex]\\ \sf\longmapsto Conductivity=10m\times 20m\times 2.4[/tex]
[tex]\\ \sf\longmapsto Conductivity=400\Omega m[/tex]
A wire, 20m long, is heated from a temperature of 5°C to 55°C. If the change in length is 0.020m, calculate the linear expansivity of the wire.
Answer:
0.01998⁰C;¹
Explanation:
you can see all steps in photo
Three capacitors 2uf, 5uf and 7uf are connected in series what is their equivalent capacitance
Answer:
C eq = .96uF
Explanation:
A mother is pulling a sled at constant velocity by means of a rope at 37°. The tension on the rope is 120 N. Mass of children plus sled is 55 kg. The mother has a mass of 61 kg.
a) Draw FBD for the sled with the kids as one object
b) Draw FBD for the mother
c) Find the normal force on the sled and on the mother
d) Find the kinetic friction acting on the sled and the static friction acting on the mother
e) Find the coefficient of kinetic friction for the sled
Answer:
Please find the complete solution in the attached file.
Explanation:
A basketball is shot by a player at a height of 2.0 m. The initial angle
was 53° above horizontal. At the highest point the ball was travelling 6
m/s. If he scored (the ball went through the rim that is 3.00 m above the
ground), what was the player’s horizontal distance from the basket?
Answer:
The answer is "8.28 m".
Explanation:
[tex]\to u \cos 53^{\circ}=6 \ \text{therefore the horizontal velocity is constant alaways}\\\\\therefore[/tex]
[tex]u= \frac{6 \times 5}{3}= \frac{30}{3}= 10\ \frac{m}{s}\\\\[/tex]
In the projectfile when vertical displacement is 1 then 5 m comes at farther sides
Using
[tex]S=ut-\frac{1}{2} gt^2\\\\1=u\sin 53^{\circ}\times t-5t^2\\\\1=8t-5t^2\\\\5t^2-8t+1=0\\\\ t=\frac{8\pm \sqrt{64-20}}{10} \\\\=\frac{8\pm 2\sqrt{11}}{10} \\\\t_2=\frac{8+2\sqrt{11}}{10} \\\\[/tex]
[tex]Distance=u \cos 53^{\circ}\times t_2\\\\[/tex]
[tex]=6 \times \frac{8\pm 2\sqrt{11}}{10} \\\\=\frac{24\pm 6\sqrt{11}}{5} \\\\= 8.28 \ m[/tex]
A pendulum, like a bobblehead, moves back and forth through a resting position. At what point on its path is the net force acting on the pendulum zero?
Group of answer choices
When the pendulum is displaced as far to the left as it can be.
When the pendulum is displaced as far to the right as it can be.
When the pendulum is at its resting position.
Never…there is always a net force acting on a pendulum
Answer:
[tex]\\ \longrightarrow\:\bf \purple{\dfrac{1}{v} = \dfrac{1}{ - 100} + \:\dfrac{1}{20} }[/tex]
When 100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C, about how much thermal energy
is absorbed by the ethyl alcohol? (Assume the density of ethyl alcohol to be 0.790 g/mL.)
Answer:
Q = 194.34 J
Explanation:
Given that,
100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C.
We need to find the amount of thermal energy absorbed by the ethyl alcohol.
The density of ethyl alcohol is 0.790 g/mL.
The formula for heat absorbed is given by :
[tex]Q=mc\Delta T\\\\As, d=\dfrac{m}{V}\\\\So,\\Q=dVc\Delta T\\\\Q=0.79\times 100\times 2.46\\\\Q=194.34\ J[/tex]
So, 194.34 J of thermal energy is absorbed by the ethyl alcohol.
What's Alpha beta gamma emission??
I don't know how to answer this question, can someone pls help?
- Explain how a wave can transmit energy to a medium without transporting matter.
Thank you for your time!
Answer:
Consider the energy the earth receives from the sun. The electromagnetic waves travel thru empty space until they interact with some medium surrounding the earth: ozone, atmosphere, solids, etc.
This is contrasted to longitudinal waves such as sound waves which can only travel thru the medium with which they interact.
The study of heat transformation into other forms of energy is called
Answer:
Thermodynamics.
Explanation:
Thermodynamics can be defined as the study of heat transformation into other forms of energy.
Conduction involves the transfer of electric charge or thermal energy due to the movement of particles.
Generally, when conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.
In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.
In Thermodynamics, heat are generally transformed to various forms of energy such as light energy.
The Law of Conservation of Energy states that energy cannot be destroyed but can only be converted or transformed from one form to another. Therefore, the sum of the initial kinetic energy and potential energy is equal to the sum of the final kinetic energy and potential energy.
Mathematically, it is given by the formula;
Ki + Ui = Kf + Uf .......equation 1
Where;
Ki and Kf are the initial and final kinetic energy respectively.
Ui and Uf are the initial and final potential energy respectively.
Additionally, the Law of Conservation of Energy is another way to describe the First Law of Thermodynamics and it states that the change of the internal energy of a system is equal to the sum of work and heat spent on it.
Mathematically, the First Law of Thermodynamics is given by the formula;
ΔU = Q − W
Where;
ΔU represents the change in internal energy of a system.
Q represents the net heat transfer in and out of the system.
W represents the sum of work (net work) done on or by the system.
at 10° Celsius the gas in a cylinder has a volume of .250 L the gas is allowed to expand to point .285L what must the final temperature be for the pressure to remain constant
11.4°C
Answer:
Solution given:
temperature [T1]=10°c
temperature [T2]=?
volume [V1]=250L
at volume [V2]=285L
now
By using Charles law
V1/T1=V2/T2
250/10=285/T2
T2=285/25
T2=11.4°C
the final temperature must be 11.4°C for the pressure to remain constantCan someone pleassse help me
Answer:
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tdgjbc
Tarzan swings back and forth on a
vine with a period of 7.27 s. How
long is the vine?
(Unit = m)
8CM I suppose because he swings and goes to the next vine
Hellllppppppppppppp!!!!!!
forced of friction increases with increase in the weight of vehicles
The primary circuit of a transformer has a voltage of 80 V and 300 windings. The secondary circuit has a voltage of 240. How many windings are there in the secondary circuit? *
Answer:
900 windings
Explanation:
Applying,
Vs/Vp = Ns/Np............. Equation 1
Where Vs = Secondary voltage, Vp = primary voltage, Ns = Number of turns in the secondary circuit, Np = number of turns in the primary circuit
make Ns the subject of the equation
Ns = VsNp/Vp........... Equation 2
From the question,
Given: Vs = 240 V, Np = 300 windings, Vp = 80 V
Substitute these values into equation 2
Ns = (240×300)/80
Ns = 900 windings
the units of work,energy and power are...............units
unit of work is joules
power - watt
energy - joules
If the density of a substance is 5g/cm3 and the volume is 10cm3,
determine the mass.
Answer:
(5g/cm³)*(10cm³) = 50g
Explanation:
This is just a conversion formula. Easy to find using dimensional analysis.
(5g/cm³)*(10cm³) = 50g
Answer:
[tex]\boxed {\boxed {\sf 50 \ grams}}[/tex]
Explanation:
Density is the amount of mass per unit volume, so the formula is:
[tex]d = \frac{m}{v}[/tex]
The density of the substance is 5 grams per cubic centimeter and the volume is 10 cubic centimeters.
d= 5 g/cm³ v= 10 cm³Substitute the values into the formula.
[tex]5 g/cm^3 = \frac{m}{10 \ cm^3}[/tex]
We are solving for the mass, so we have to isolate the variable m. It is being divided by 10 cubic centimeters. The inverse of division is multiplication, so we multiply both sides of the equation by 10 cm³.
[tex]10 \ cm^3 *5 g/cm^3 = \frac{m}{10 \ cm^3} * 10 \ cm^3[/tex]
[tex]10 \ cm^3 *5 g/cm^3 = m[/tex]
The units of cubic centimeters (cm³) cancel.
[tex]10 *5 g = m[/tex]
[tex]50 \ g=m[/tex]
The mass of the substance is 50 grams.
How would you find the resistance of a parallel circuit with n identical resistors?
9514 1404 393
Answer:
R/n
Explanation:
For a given voltage V across each resistor R, the current is V/R. Since there are n parallel paths, the total current is n(V/R). The effective resistance is ...
Reff = V/I = V/(nV/R)
Reff = R/n
why solid keep their shape?
Answer:
Solids can hold their shape because their molecules are tightly packed together. ... Atoms and molecules in liquids and gases are bouncing and floating around, free to move where they want. The molecules in a solid are stuck in a specific structure or arrangement of atoms
Hope this helps ☆*:. o(≧▽≦)o .:*☆
UNA MASA DE 0,5 KG ESTA SOBRE UNA PENDIENTE SUJETA MEDIANTE UNA CUERDA QUE IMPIDE UN DESLICE. ¿QUE FUERZA HACE LA CUERDA?
Answer:
Tension force acts along the inclined plane.
Explanation:
A MASS OF 0.5 KG IS ON A SLOPE FASTENED BY A ROPE THAT PREVENTS SLIDING. WHAT FORCE DOES THE ROPE MAKE?
A mass of 0.5 kg is fastened on a slope. So there are the two components of weight.
m g sin A acts along the plane in the downwards direction.
m g cos A acts perpendicular to the plane in upwards direction.
The force which acts of the rope as the mass is fastened is the tension force on the rope.
So, the tension force is there.
