The number of bacteria in a culture is increasing according to the law of exponential growth. There are 125 bacteria in the culture after 2 hours and 350 bacteria after 4 hours.
The overall percent increase after 4 hours is 21% if the number of bacteria in a colony increases by 10% every 2 hours option (G) is correct.
What is the percentage?It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.
We have:
The number of bacteria in a colony increases by 10% every 2 hours.
Let there be 100 bacteria in the starting
In the first 2 hours :
= (100×10%) + 100
= 10 + 100
= 110
Again after 2 hours:
= (110×10%) + 110
= 11 + 110
= 121
= (121 - 100)
= 21
Thus, the overall percent increase after 4 hours is 21% if the number of bacteria in a colony increases by 10% every 2 hours option (G) is correct.
Learn more about the percentage here:
brainly.com/question/8011401
#SPJ5
The principle
P=6000 A=6810 T=3 years
Answer:
incomplete question
Step-by-step explanation:
that is what is wrong with your question
Answer:
r = 4.3%
Step-by-step explanation:
6810= 6000(x)^3
6810/6000= (x)^3
x = 1.043114431
r = 043114431
Which choices are equivalent to the quotient below? Check All That Apply.
Answer:
Option C. √5/3
Step-by-step explanation:
We'll begin by simplifying √15 / 3√3. This can be obtained as follow:
√15 / 3√3
Rationalise
√15 / 3√3 × (√3 /√3)
(√15 × √3) / (3√3 × √3)
√45 / (3 × 3)
√45 / 9
Recall:
√45 = √(9 × 5) = √9 × √5 = 3√5
Thus,
√45 / 9 = 3√5 / 9
√45 / 9 = √5 / 3
Therefore,
√15 / 3√3 = √5 / 3
Thus, option C gives the right answer to the question.
A construction crane lifts a bucket of sand originally weighing 145 lbs at a constant rate. Sand is lost from the bucket at a constant rate of .5lbs/ft. How much work is done in lifting the sand 80ft?
Answer: [tex]10,000\ lb.ft[/tex]
Step-by-step explanation:
Given
Initial weight of the bucket is [tex]145\ lb[/tex]
It is lifted at constant rate and rate of sand escaping is [tex]0.5\ lb/ft[/tex]
At any height weight of the sand is [tex]w(h)=145-0.5h[/tex]
Work done is given by the product of applied force and displacement or the area under weight-displacement graph
from the figure area is given by
[tex]\Rightarrow W=\int_{0}^{80}\left ( 145-0.5h \right )dh\\\\\Rightarrow W=\left | 145h-\dfrac{0.5h^2}{2} \right |_0^{80}\\\\\Rightarrow W=\left [ 145\times 80-\dfrac{0.5(80))^2}{2} \right ]-0\\\\\Rightarrow W=11,600-1600\\\\\Rightarrow W=10,000\ lb.ft[/tex]
Estimate the product of 0.235 and 13.467 to the nearest hundredth. Round each value to the nearest hundredth before multiplying. Your final answer should also be rounded to the nearest hundredth.
Answer:
0.235 = 0.24
13.467 = 13.47
0.24+13.47=13.71
A $22,000 loan was taken out. If $24,805 is due at the end of the loan after being compounded daily at 2.5%, how many
years was the loan for? (Round to the nearest tenth of a year)
Provide your answer below
9514 1404 393
Answer:
4.8 years
Step-by-step explanation:
Solving the compound interest formula for the number of years gives ...
t = log(A/P)/(n·log(1 +r/n))
where principal P invested at rate r compounded n times per year produces value A after t years.
t = log(24805/22000)/(365·log(1 +0.025/365)) ≈ 4.800
The loan was for 4.8 years.
find the missing length indicated
Answer:
192
Step-by-step explanation:
geometric mean theorem :
with p and q being the segments of the Hypotenuse, then
h = x = sqrt(p×q)
p = 144
q = 400-144 = 256
h = x = sqrt(144×256) = 12×16 = 192
the cost of 1 kg tomato is RS . 75.Find the cost of 14 kg
Answer:
Cost of 1kg tomato=rs.75
Cost of 14kg tomato=(75×14)
rs.1050
6x — Зу = 5
y - 2x = 8
How many solutions does the system have?
9514 1404 393
Answer:
none
Step-by-step explanation:
Multiplying the second equation by -3 gives ...
6x -3y = -24
Values of x and y that satisfy this equation cannot also satisfy the first equation ...
6x -3y = 5
There are no solutions to this system of equations.
__
The equations describe parallel lines. There is no point of intersection.
The final price of the textbook for an English literature course is 13.5% more than the listed price when tax and shipping costs are included. If the listed price is $147, what is the final price of the textbook?
(Round to the nearest dollar.)
Answer:
The final price of the textbook rounded to the nearest dollar is $167
Step-by-step explanation:
To solve this problem, we need to find out what 13.5% of $147 equals.
13.5% = 0.135
0.135 x $147 = $19.845
$147 + 19.845 = 166.845
Round to the nearest dollar to get $167
Write a quadratic equation with integer coefficients having the given numbers as solutions.
9514 1404 393
Answer:
x² -22 = 0
Step-by-step explanation:
The roots are opposites, so the equation is pretty simple.
x = ±√22
x² = 22 . . . . . square both sides
x² -22 = 0 . . . . your quadratic equation in standard form
Domain and range of g(x)= 5x-3/2x+1
Solve for domain and range?
Please help!!!!
CE is tangent to this circle, CD is a radius and ECB=48 what is BAC
Answer:
48degrees
Step-by-step explanation:
From the circle geometry shown, traingle BDC is an isosceles triangle which shows means that their base angels are the same. Hence;
<B = <C
<CBD + <BCD + <D = 180
<BCD + <BCD + <D =180
2<BCD + <BDC = 180
Get <BCD;
<BCD+ <ECB = 90
<BCD + 48 = 90
<BCD = 90 - 48
<BCD = 42degrees
Get <BDC
2<BCD + <BDC = 180
2(42)+ <BDC = 180
84 + <BDC = 180
<BDC = 180 - 84
<BDC = 96
Since angle at the centre is twice that at the circumference, then;
<BAC = 1/2(<BDC )
<BAC = 96/2
<BAC = 48degrees
The fuel efficiency of a vehicle is 28 miles per gallon and gasoline cost 2.25 per gallon. What is the cost per mile to drive the vehicle?
Answer:
$.08 per mile
Step-by-step explanation:
$2.25 gallon
------------ * ---------------
gallon 28 miles
$2.25
-------------
28 miles
$.080357143 per mile
Rounding to the nearest cent
$.08 per mile
a recent survey shows that 66% of college students have a cat and 37% have a HBO subscription. Assuming these two events are independent, what is the probability that a randomly selected student has neither a cat nor HBO
Answer:
[tex]P(C'\ and\ H') =0. 2178[/tex]
Step-by-step explanation:
Let
[tex]C \to[/tex] Student with cat
[tex]H \to[/tex] Student has HBO sub
[tex]P(C) = 66\% \\ P(H) = 37\%[/tex]
Required
[tex]P(C'\ and\ H')[/tex]
This is calculated as:
[tex]P(C'\ and\ H') = P(C') * P(H')[/tex]
Using complement rules, we have:
[tex]P(C'\ and\ H') = [1 - P(C)] * [1 - P(H)][/tex]
So, we have:
[tex]P(C'\ and\ H') = [1 - 66\%] * [1 - 37\%][/tex]
[tex]P(C'\ and\ H') = [33\%] * [66\%][/tex]
[tex]P(C'\ and\ H') =0. 2178[/tex]
13.
а/8 = $1.25
Can someone help explain
Answer:
a= $10.00
Step-by-step explanation:
It's very simple. Move /8 to the other side of the equation. It should give you $1.25 x 8. Solve the multiplication and you should get $10.00.
If I didn't make my explanation clear enough, please comment. I sometimes don't even explain myself very well.
Answer:
a = 10
Step-by-step explanation:
a/8 = 1.25
multiply both sides by 8 to isolate a.
(8)(a/8) = 1.25(8)
which gives you
a = 1.25(8)
which simplifies to
a = 10
Help on 3,5,7,9,11,13.15,17, please thank you
Answer:
3. 6a+60
5. 25+5w
7. 90-10t
11. 4.5-12c
13. f-2
15. 12z+1.5
Step-by-step explanation:
3.
6(a+10)
Multiply 6 by both factors in the parentheses, in this case, a and 10.
6*a = 6a
6*10 = 60
6(a+10) = 6a + 60
I only put the step- by- step explanation for #3, but you should be able to figure the rest out with that.
Find the missing side. Round your answer to the nearest tenth please help me
9514 1404 393
Answer:
16.9
Step-by-step explanation:
The marked sides are the hypotenuse and the one opposite the angle. The relevant trig function is ...
Sin = Opposite/Hypotenuse
Multiplying by the hypotenuse gives an equation for the opposite side.
x = 22·sin(50°)
x ≈ 16.9
1. Find the volume of the shipping box using the two methods and show your work plzzzzzzzz i neeeeeeeeeeeeeed help
Step-by-step explanation:
Measure the width, length and height of the shipping box in inches. Multiply the width, length and height of the box to calculate its volume in cubic inches. For example, if the box is 20 inches wide, 24 inches long and 16 inches high, then the volume is (20)(24)(16) = 7,680 cubic
Answer:
The volume of the shipping box would be 36 9/16
Step-by-step explanation:
One method to find the volume of the shipping box would be (l)(w)(h)
one we plug in our dimensions the equation would become 3 1/4 x 3 x 3 3/4
To simplify this we would first
Multiply
3 1/4 x 3 x 3 3/4 = 39/4 x 3 3/4
The bolded parts are the pieces we are working on
3 1/4 as an improper fraction is 13/4
13/4 x 3 = 13 x 3/4 = 39/4
- The second step would be to
Convert the mixed number to an improper fraction.
3 3/4 = ( 3 × 4 ) / 4 + 3/4 = 12 + 3 / 4 = 15/4
Now we have to Multiply
39/4 x 15/4 = 39 x 15 / 4 x 4 = 585/16
Lastly, we have to simplify
585/16 = 36 9/16
Convert 2546 in base 10 to base 5
Answer:
40141
Step-by-step explanation:
Describe and correct the error in determining the formula for the sequence below
Answer:An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. For instance, the sequence 5, 7, 9, 11, 13, 15.. . is an arithmetic progression with a common difference of 2.
Step-by-step explanation:
Apply Simpson's rule to approximate the value of integration 1 to 4 e^x In x dx with n = 3.
[tex]Here, h=41,0.25,y=1+x21
[/tex]
[tex]x y101.020.25 0.9413 0.250.94140.750.64510.5
[/tex]
[tex]By Simpson's Rule:
[/tex]
[tex]∫011+x2dx=4×31
[/tex]
[tex][(1+0.5)+4(0.941+0.941+0.64)+2(0.8)]
[/tex]
[tex]=121[9.424]=0.785
[/tex]
Complete the statement below. A Type II Error is made... Choose the correct answer below. A. A Type II Error is made when there's not enough evidence to reject the null hypothesis and the null hypothesis is true. B. A Type II Error is made when there's evidence to reject the null hypothesis, but the null hypothesis is true. C. A Type II Error is made when there's not enough evidence to reject the null hypothesis, but the null hypothesis is not true. D. A Type II Error is made anytime we do not reject the null hypothesis.
You are enrolling swimmers in a study on lung capacity. You want 25% of your sample to be those who compete at 100m or less distances and 50% to be swimmers who compete at 100m-500m distances and 25% to be swimmers who compete at >500m distances. You begin enrolling for your study at 5am at the pool. By 9 AM you have all of your 100-500m swimmers enrolled, and all of your >500m swimmers enrolled. This is an example of what type of sampling method
Answer:
Stratified sampling
Step-by-step explanation:
Samples may be classified as:
Convenient: Sample drawn from a conveniently available pool.
Random: Basically, put all the options into a hat and drawn some of them.
Systematic: Every kth element is taken. For example, you want to survey something on the street, you interview every 5th person, for example.
Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.
Stratified: Also divides the population into groups. However, then only some elements of the group are surveyed.
In this question:
People divided by groups, for each group(<100, >100<500, >500), a number(not all) is selected, so stratified sampling.
(d) (8x2 + 7y2 – z2 + 2yz + 3xz – 5xy) * (2x – 3y) vertical method
Answer:
(8x²+7y²–z²+2yz+3xz–5xy) × ( 2x–3y)
= (16x³+14xy²–2z²x+4yzx+6x²z–10x²y –24yx²–21y³+3z²y–6y²z–9xzy+15xy²)
=( 16x³+29xy²–2z²x–5xyz+6x²z–34x²y–21y³+3z²y–6y²z)
[tex] = 16 {x}^{3} - 21 {y}^{3} - 2 {z}^{2}x + 3 {z}^{2} y - 5xyz - 6 {y}^{2} z + 6 {x}^{2} z - 34 {x}^{2} y+ 29x {y}^{2} [/tex]
I hope I helped you^_^
7. Find HCF of: x'y and ly*
8. Find LCM of 4x - 20 and 6x - 30
9. Factorize Factorize: -m-+ 1 + me
10. Factorize: 4x100
11. Simplify: V18+ va 12. If a = 2, b = 3 and c= 4, fmd the value of a b c 13. Subtract: 125- 45 a--200+ 14. Simplify: ***
PLEASE HELP ME
Answer:
7 ans-HCF is y
Step-by-step explanation:
soln
first expression=X and y
second expression=l and y
so HCF means common so the Ans is y
How to divide using area model
Answer:
In mathematics, an area model is a rectangular diagram or model used for multiplication and division problems, in which the or the and define the length and width of the rectangle.
We can break one large of the rectangle into several smaller boxes, using number bonds, to make the calculation easier. Then we add to get the area of the whole, which is the or quotient.
To multiply two 2-digit numbers, using the area model, follow the given steps:
Write the multiplicands in expanded form as tens and ones.
For example, 27 as 20 and 7, and 35 as 30 and 5.
Draw a 2 × 2 grid, that is, a box with 2 rows and 2 columns.
Write the terms of one of the multiplicands on the top of the grid (box). One on the top of each cell.
On the left of the grid, write the terms of the other multiplicand. One on the side of each cell.
Write the product of the number on the tens in the first cell. Then write the product of the tens and ones in the second and third cell. Write the product of the ones in the fourth cell.
write the product in the cell
Finally, add all the partial products to get the final product.
Here, for example, the area model has been used to multiply 27 and 35.
area model multiplication
Let us see how to find the product of 3-digit number by a 2-digit number using the area model.
Find the Product using Area Model
Let us now use the area model for the division. Here, we divide 825 by 5.
Area Model Division 1
Area Model Division 2
Fun Facts
The area model is also known as the box model.
The area model of solving multiplication and division problems is derived from the concept of finding the area of a rectangle. Area of a rectangle = Length × Width.
Math Games for Kids
Math Games for Kids
Online Live Math Classes
SplashLearn Content
Resources
StudyPad®, Splash Math®, SplashLearn™ & Springboard™ are Trademarks of StudyPad, Inc.
Copyright © 2020 Studypad Inc. All Rights Reserved
urgent !!!! HELP NEEDED
Answer:
[tex]352\ yd^2[/tex]
Step-by-step explanation:
1. Approach
The surface area of a three-dimensional figure is the two-dimensional space around the figure. Simply put, if one was going to wrap the figure up in paper, the surface area is the amount of paper one would need to wrap the entirety of the figure. One can find the surface area of a figure by finding the area of each individual facet of the figure and then adding up the areas.
2. Finding the area of the triangular faces
The formula to find the area of a triangle is the following:
[tex]A_t=\frac{b*h}{2}[/tex]
Where (b) is the base of the figure, and (h) is the figure's height. Since there is only one type of triangular face, one only has to find the area of one triangular face and then multiply its measurement by four.
Triangle 1
[tex]A_t=\frac{b*h}{2}[/tex]
[tex]A_t=\frac{11*10.5}{2}[/tex]
[tex]A_1=\frac{115.5}{2}[/tex]
[tex]A_t=57.75[/tex]
3. Finding the area of the quadrilateral
The following formula can be used to find the area of a quadrilateral:
[tex]A_q=b*h[/tex]
Substitute the dimensions of the quadrilateral in and solve for its area:
[tex]A_q=b*h[/tex]
[tex]A_q=11*11[/tex]
[tex]A_q=121[/tex]
4. Find the total surface area of the figure
To find the total surface area of the figure, add up all of the area values of its faces. Remember the area of the triangular face is multiplied by four because there are four triangular faces.
[tex]4(A_t)+(A_q)=A[/tex]
[tex]4(57.75)+121=A[/tex]
[tex]231+121=A[/tex]
[tex]352=A[/tex]
A trader sold 90 oranges at 3 for GHC 0.75.
How much did she get from selling all the
oranges?
Answer:
GHC22.5
Step-by-step explanation:
90/3=30
30=0.75
30×0.75
=22.5
What are the divisible number(s) for 430?
Answer:
The numbers that 430 is divisible by are 1, 2, 5, 10, 43, 86, 215, and 430.
A particle is moving such that its height h at time t is given by h(t) = 2 + 8t - 3t^2 + 1/5t^3. The average velocity of the particle on the period [0,3] is
[tex]\\ \Large\sf\longmapsto h(t)[/tex]
[tex]\\ \Large\sf\longmapsto 2+8t-3t^2+\dfrac{1}{5}t^3[/tex]
[tex]\\ \Large\sf\longmapsto 2+8(3)-3(3)^2+\dfrac{1}{5}(3)^3[/tex]
[tex]\\ \Large\sf\longmapsto 2+24-3(9)+\dfrac{27}{5}[/tex]
[tex]\\ \Large\sf\longmapsto 26-27+5.4[/tex]
[tex]\\ \Large\sf\longmapsto -2+5.4[/tex]
[tex]\\ \Large\sf\longmapsto h(t)=3.4m[/tex]